Recently I've been working in a project where I need to keep the code as cleanest as possible. That's why I'm working in a component which needs to extends some characteristics from another one, but I also need to pass some props to obtain some behavior in return. But there is a problem: I'm adding a prop in the constructor, but there is a function that doesn't receive/seem have that prop:
class SampleClassOne extends PureComponent<Props>{
Constructor(Props){
console.log(props) // In this console.log, the variable aditionalVar appears
super(props){
{
}
functionOne(){
const {
varOne,
varTwo,
varThree,
aditionalVar
} = this.props
console.log(this.props) // In this console.log, the variable aditionalVar does not appear
render(){
...
}
}
}
class SampleClassTwo extends SampleClassOne {
Constructor(Props){
super({...props, aditionalVar: true}) // This is where I'm adding the new variable
}
}
}
I don't know if I'm clear with the question I'm asking... how can I make sure that new variables I'm adding from components that extends from others can be received by all the component that extends its class.
Thanks for your help
I'getting undefined this error in the constructor.
Let me know what is the reason behind this. I read from the sources either compiler automatically creates the constructor and available this reference or need to manually add the constructor with super() as the first statement.
class A extends Component {
constructor() {
// this undefined error
console.log('construtor');
this.state = {name: ''}
}
}
The reason why this cannot be allowed before super() is because this is uninitialized if super() is not called. However even if we are not using this we need a super() inside a constructor because ES6 class constructors MUST call super if they are subclasses. Thus, you have to call super() as long as you have a constructor. (But a subclass does not have to have a constructor).
sending props in super is not mandatory. If you do not want to use this.props then you can simply call super().
class A extends React.Component {
constructor(props) {
super(props);
console.log('construtor');
this.state = {name: ''}
}
}
The subclasses must have super in constructor for initializing purpose. Access of 'this' can't be allowed without super().
class A extends React.Component {
constructor(props) {
super(props);
console.log('construtor');
this.state = { name: ''}
}
}
This question already has answers here:
What's the difference between "super()" and "super(props)" in React when using es6 classes?
(10 answers)
Closed 6 years ago.
I guess I'm not very good at JavaScript.
This is how I've seen react components initialised. The initial set state is done within the constructor.
export class Counter extends React.Component {
constructor(props) {
super(props);
this.state = {count: props.initialCount};
}
why is there always a super(props). Is this required? Is calling super necessary at all? What would happen if super isn't called?
You need to pass props in super only if you want to access this.props in constructor of the class.
class Base extends React.Component {
constructor(props) {
console.log('Base', props);
}
render() {
return <div>Base {this.props.name}</div>;
}
}
class Sub extends Base {
constructor(props) {
super({
name: 'New name prop'
});
console.log('Sub', arguments);
}
}
var sub = <Sub name="Gomic" />
React.render(sub, document.getElementById('container'));
Props are by default not assigned in the constructor. They are assinged in the method React.createElement. So super(props) should be called only when the superclass's constructor manually assings props to this.props. When you just extend the React.Component calling super(props) method will do nothing with props.
Reference:
https://discuss.reactjs.org/t/should-we-include-the-props-parameter-to-class-constructors-when-declaring-components-using-es6-classes/2781/2
When is it important to pass props to super(), and why?
class MyComponent extends React.Component {
constructor(props) {
super(); // or super(props) ?
}
}
There is only one reason when one needs to pass props to super():
When you want to access this.props in constructor.
Passing:
class MyComponent extends React.Component {
constructor(props) {
super(props)
console.log(this.props)
// -> { icon: 'home', … }
}
}
Not passing:
class MyComponent extends React.Component {
constructor(props) {
super()
console.log(this.props)
// -> undefined
// Props parameter is still available
console.log(props)
// -> { icon: 'home', … }
}
render() {
// No difference outside constructor
console.log(this.props)
// -> { icon: 'home', … }
}
}
Note that passing or not passing props to super has no effect on later uses of this.props outside constructor. That is render, shouldComponentUpdate, or event handlers always have access to it.
This is explicitly said in one Sophie Alpert's answer to a similar question.
The documentation—State and Lifecycle, Adding Local State to a Class, point 2—recommends:
Class components should always call the base constructor with props.
However, no reason is provided. We can speculate it is either because of subclassing or for future compatibility.
(Thanks #MattBrowne for the link)
In this example, you are extending the React.Component class, and per the ES2015 spec, a child class constructor cannot make use of this until super() has been called; also, ES2015 class constructors have to call super() if they are subclasses.
class MyComponent extends React.Component {
constructor() {
console.log(this); // Reference Error
}
render() {
return <div>Hello {this.props.name}</div>;
}
}
By contrast:
class MyComponent extends React.Component {
constructor() {
super();
console.log(this); // this logged to console
}
render() {
return <div>Hello {this.props.name}</div>;
}
}
More detail as per this excellent stack overflow answer
You may see examples of components created by extending the React.Component class that do not call super() but you'll notice these don't have a constructor, hence why it is not necessary.
class MyOtherComponent extends React.Component {
render() {
return <div>Hi {this.props.name}</div>;
}
}
One point of confusion I've seen from some developers I've spoken to is that the components that have no constructor and therefore do not call super() anywhere, still have this.props available in the render() method. Remember that this rule and this need to create a this binding for the constructor only applies to the constructor.
When you pass props to super, the props get assigned to this. Take a look at the following scenario:
constructor(props) {
super();
console.log(this.props) //undefined
}
How ever when you do :
constructor(props) {
super(props);
console.log(this.props) //props will get logged.
}
When implementing the constructor() function inside a React component, super() is a requirement. Keep in mind that your MyComponent component is extending or borrowing functionality from the React.Component base class.
This base class has a constructor() function of its own that has some code inside of it, to setup our React component for us.
When we define a constructor() function inside our MyComponent class, we are essentially, overriding or replacing the constructor() function that is inside the React.Component class, but we still need to ensure that all the setup code inside of this constructor() function still gets called.
So to ensure that the React.Component’s constructor() function gets called, we call super(props). super(props) is a reference to the parents constructor() function, that’s all it is.
We have to add super(props) every single time we define a constructor() function inside a class-based component.
If we don’t we will see an error saying that we have to call super(props).
The entire reason for defining this constructor() funciton is to initialize our state object.
So in order to initialize our state object, underneath the super call I am going to write:
class App extends React.Component {
constructor(props) {
super(props);
this.state = {};
}
// React says we have to define render()
render() {
return <div>Hello world</div>;
}
};
So we have defined our constructor() method, initialized our state object by creating a JavaScript object, assigning a property or key/value pair to it, assigning the result of that to this.state. Now of course this is just an example here so I have not really assigned a key/value pair to the state object, its just an empty object.
Dan Abramov wrote an article on this topic:
Why Do We Write super(props)?
And the gist of it is that it's helpful to have a habit of passing it to avoid this scenario, that honestly, I don't see it unlikely to happen:
// Inside React
class Component {
constructor(props) {
this.props = props;
// ...
}
}
// Inside your code
class Button extends React.Component {
constructor(props) {
super(); // 😬 We forgot to pass props
console.log(props); // ✅ {}
console.log(this.props); // 😬 undefined
}
// ...
}
As per source code
function ReactComponent(props, context) {
this.props = props;
this.context = context;
}
you must pass props every time you have props and you don't put them into this.props manually.
super() is used to call the parent constructor.
super(props) would pass props to the parent constructor.
From your example, super(props) would call the React.Component constructor passing in props as the argument.
More information on super:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/super
For react version 16.6.3, we use super(props) to initialize state element name : this.props.name
constructor(props){
super(props);
}
state = {
name:this.props.name
//otherwise not defined
};
Here we won't get this in the constructor so it will return undefined, but we will be able to fetch this outside the constructor function
class MyComponent extends React.Component {
constructor() {
console.log(this); // Reference Error i.e return undefined
}
render() {
return <div>Hello {this.props.name}</div>;
}
}
If we are using super(), then we can fetch the "this" variable inside the constructor as well
class MyComponent extends React.Component {
constructor() {
super();
console.log(this); // this logged to console
}
render() {
return <div>Hello {this.props.name}</div>;
}
}
So when we are using super(); we will be able to fetch this but this.props will be undefined in the constructor. But other than constructor, this.props will not return undefined.
If we use super(props), then we can use this.props value inside the constructor as well
Sophie Alpert's Answer
If you want to use this.props in the constructor, you need to pass
props to super. Otherwise, it doesn’t matter because React sets .props
on the instance from the outside immediately after calling the
constructor.
Here is the fiddle I've made:jsfiddle.net. It shows that props are assigned not in the constructor by default. As I understand they are assinged in the method React.createElement. Hence super(props) should be called only when the superclass's constructor manually assings props to this.props. If you just extend the React.Component calling super(props) will do nothing with props. Maybe It will be changed in the next versions of React.
I'm brand new to React and I'm using it in combination with ES6 classes. I have a class that inherits from React.Component and renders DOM based on a single property in its state. Here's how that looks:
class LoadingScreen extends React.Component {
constructor(props) {
super(props);
this.state = { state: 'isHidden' };
showTrying() {
this.setState({ state: 'isTrying' });
}
hideAll() {
this.setState({ state: 'isHidden' });
}
render() {
switch (this.state.state) {
case 'isHidden':
return null;
case 'isTrying':
// Returns a bunch of DOM elements
}
}
In a parent class, that is not a React component (I'm attempting to migrate existing code that uses no framework), I want to:
Create an instance of LoadingScreen
Call React.render to insert it in the DOM
Call methods such as hide or showTrying on that instance to update its state
I've tried:
this.loadingScreen = new LoadingScreen();
React.render(this.loadingScreen, mountNode); // React invalid component error
// Later on...
this.loadingScreen.showTrying();
And also tried:
this.loadingScreen = React.render(React.createElement("LoadingScreen"), mountNode);
// Later on...
this.loadingScreen.showTrying(); // Undefined is not a function
Clearly I'm missing something fundamental here. :)
It would be more common that you'd set a property on the LoadingScreen component instance to control the visibility of the internal representation rather than adjusting the state via a function call on the object instance.
class LoadingScreen extends React.Component {
constructor(props) {
super(props);
}
render() {
switch (this.props.mode) {
case 'isHidden':
return null;
case 'isTrying':
// Returns a bunch of DOM elements
}
}
}
LoadingScreen.propTypes = {
mode: React.PropTypes.string
};
LoadingScreen.defaultProps = {
mode: 'isTrying'
};
Then, from the parent, you'd do something like this for example:
var currentMode = "isTrying";
React.render(<LoadingScreen mode={ currentMode } />, mountNode);
Or, another pattern is that the parent container/component uses the value of the property (I've called mode) to just not create and render the LoadingScreen component at all.
If the LoadingScreen needs to, you could copy the property value into local state as you've done.
Your second approach was close.
The first argument to React.createElement can either be a string (div, span, etc.) or a subclass of React.Component. In your case, the first argument should be LoadingScreen.
this.loadingScreen = React.render(React.createElement(LoadingScreen), mountNode);
this.loadingScreen.showTrying();