This question already has answers here:
How do I replace all occurrences of a string in JavaScript?
(78 answers)
Closed 1 year ago.
I have a simple javascript code as follows
var url = '#Url.Action("Action", "Controller", new { id = "_id_", id2 = "_id2_", id3 = "_id3_", id4 = "_id4", ... })';
used in the ajax calls where idxx is replaced with other values
However the var url is generated with "...&id2=id2&..." etc.
and i just learned that javascript string.replace() works only on the first occurance
wondering if there's another way to code the var url rather than replace multiple times ?
the solution has to be universally executable i.e. run in older browsers as well
You can use Replace all which will replace all occurrences
var test = 'id=_id&id=_id&id=test';
var replacedStr = test.replaceAll('_id','teststr');
console.log(replacedStr);
.
Related
This question already has answers here:
How to get URL parameter using jQuery or plain JavaScript?
(34 answers)
Closed 4 years ago.
I have this url
https://myapp.tezze-now.com/sp?id=form&table=user&sys_id=cb6688db0d79b5e9619&view=sp
I need to get text of table name from the url when page loads.
I tried this
location.href.split('&')[1]
It returns "table=user". but I need the table name alone as user.
How can I get this?
Try using URL.searchParams
// location.href
let str = "https://myapp.tezze-now.com/sp?id=form&table=user&sys_id=cb6688db0d79b5e9619&view=sp";
console.log((new URL(str)).searchParams.get("table"));
Split it once more:
location.href.split('&')[1].split('=')[1]
Or you could use Url class (no support in IE):
var url = "https://myapp.tezze-now.com/sp?id=form&table=user&sys_id=cb6688db0d79b5e9619&view=sp"; //window.location.href
var url = new URL(url);
var table = url.searchParams.get("table");
console.log(table);
location.href.split('table=')[1].split('&')[0]
Don't assume the parameter order ;)
This question already has answers here:
Get the values from the "GET" parameters (JavaScript) [duplicate]
(63 answers)
Closed 5 years ago.
I have a string (which is the value of href attribute) like this:
var url = '/myweb/search?s=islamic_sources&q=test';
It also sometimes looks like these:
url = '/myweb/search?q=test';
url = '/myweb/search?q=test&g=sth';
Here
^[^?]+.*?&?q=([^$|&]+)
is what I've tried so far, and I need to match test in those three lines. But sadly seems $ doesn't mean end of line in my pattern. How can I fix it?
You can simply use:
url.match(/q=([^&]*)/)
This will return an array. If not empty, test will be at index 1.
var url1 = '/myweb/search?s=islamic_sources&q=test';
var url2 = '/myweb/search?q=test';
var url3 = '/myweb/search?q=test&g=sth';
console.log(url1.match(/q=([^&]*)/)[1]);
console.log(url2.match(/q=([^&]*)/)[1]);
console.log(url3.match(/q=([^&]*)/)[1]);
the regex is /q=[^&]+/ and execute it in the url, then take first match, split it on =, then take second part.
I created it as a function below.
var url1 = '/myweb/search?s=islamic_sources&q=test';
var url2 = '/myweb/search?q=test';
var url3 = '/myweb/search?q=test&g=sth';
function retMatch(url){
var re=/q=[^&]+/;
return re.exec(url1)[0].split('=')[1];
}
console.log(retMatch(url1));
console.log(retMatch(url2));
console.log(retMatch(url3));
This question already has answers here:
Getting parts of a URL with JavaScript
(5 answers)
Closed 5 years ago.
url:
http://xxxxxx.com/video/view/12345
Can I take 12345 in the url using javascript?
Please help me
Use RegExp, Array#match and negative lookahead.
var str = 'http://xxxxxx.com/video/view/12345';
console.log(str.match(/(?!view\/)\d+/)[0]);
You can also try this if you're sure that it'll always be in last:
var num = location.pathname.split('/').pop(); // "12345"
and further: parseInt(num);
You can parse your URL with the following code. Then just get the last part.
var url = 'http://xxxxxx.com/video/view/12345';
var url_parts = url.replace(/\/\s*$/,'').split('/');
console.log(url_parts[url_parts.length - 1]); // last part
This question already has answers here:
How can I delete a query string parameter in JavaScript?
(27 answers)
Closed 6 years ago.
i have a url like this
test.html?dir=asc&end_date=2016-09-23&order=created_at&start_date=2016-08-14
i want to remove the parameter using the following javascript
function removeParam(uri) {
uri = uri.replace(/([&\?]start_date=*$|start_date=*&|[?&]start_date=(?=#))/, '');
return uri.replace(/([&\?]end_date=*$|end_date=*&|[?&]end_date=(?=#))/, '');
}
but it didn't work, anyone know what's wrong with that?
in modern browsers you can do this quite simply
var x = new URL(location.origin + '/test.html?dir=asc&end_date=2016-09-23&order=created_at&start_date=2016-08-14');
x.searchParams.delete('start_date');
x.searchParams.delete('end_date');
var uri = x.pathname.substr(1) + x.search; // substr(1) because you don't have a leading / in your original uri
at least, I think it's simpler
Your RegExp is no match!
If you want remove end_date, you should:
uri.replace(/(end_date=)([^*&]+)/, 'end_date=')
And so on.
This question already has answers here:
Remove querystring from URL
(11 answers)
Closed 7 years ago.
How would I remove part of a URL with jQuery, when the said part is changeable?
E.g. how can I remove this from my URL: ?modal=name
when 'name' might be name1 name2 or name3
I guess I will need to split the URL, but how do I do this when the modal name might be anything?
var url = 'http://yourdomain.com/search?modal=name';
alert(url.substring(0, url.indexOf('?')));
Demo
As you have asked "How to remove the part of a URL" using jQuery
Here is a basic workaround for you:
//the URL ( decode it just for GOOD practice)
var someRandomUrl = decodeURI("http://example.com?modal=name");
//here we do the splitting
var splittedParts = someRandomUrl.split("?");
// the first part of the array will be URL you will require
var theURL = splittedParts[0];
// the second part of the array will be the Query String
var theQuery = splittedParts[1];
alert(theURL);