NodeJS behavior of exporting class object - javascript

I am trying to understand the behavior of exporting class object instead of class name. Please help me make understand. Example
class Util {
method() {
return "method";
}
}
module.exports = new Util();
and then importing it like
import Util from 'Util';

I want to understand, how many times the object will be created?
Once, in the normal case. Modules are loaded and cached, and if they're imported by multiple other modules, those modules all see the same instance of the module doing the exporting.
When using CJS modules, the cache is require.cache and you can clear a module from the cache by deleting the property for it from the require.cache object, meaning that it will get loaded fresh the next time it's require'd. (I don't think it's possible to do that with ESM modules.)
Note: You're mixing CJS (module.exports =...) and ESM (import). I suggest you pick one and use it consistently, not least because you can't use require to import an ESM module.

Exporting the class will let you create new instances using new on any other modules that require/import it.
import MyModule from 'module';
// when exporting class:
const mdl = new MyModule();
console.log(mdl.constructor === MyModule); // => true
console.log(mdl.myValue); // => 'test'
console.log(MyModule.myValue); // => undefined
Exporting the instance will only export a single object that has this class as prototype. Module caching/resolution will ensure the same object is returned and the value is not re-calculated when re-importing from different modules.
import MyModule from 'module';
// when exporting instance
const mdl = new MyModule(); // TypeError: MyModule is not a constructor
console.log(MyModule.myValue); // => 'test'

First of all, the class syntax is just sugar on top of constructor functions.
If you export the Util "class", what you are exposing is that constructor function to be used with the new Util() syntax. Right?
In the other hand, if you export new Util(), instead of exporting the constructor function or the "class", you are exposing essentially an object constructed based on that constructor function's prototype object (or that "class") as it's prototype.

Related

Export a class or an object instance difference

I am confused, or I can say, I have no clue how the exporting actually works.
I have a React app, and I have some protected Routes. On login, I create a Client object instance and pass it to child components through Context, and then consume it.
Recently I saw an approach where the example code exported an object instance from a file directly and just imported it in files they wanted to consume it.
/** My approach **/
export default Example
/** The Object Instance approach **/
export default new Example()
What is the lifecycle of the object instance? Are there any disadvantages with the second approach, because it seems way easier?
If you export the class, with
export default Example
then consumers of the module will be able to instantiate their own instances, and each instance will be able to have its own data. For example
// 1.js
import TheClass from './TheClass';
const tc1 = new TheClass();
tc1.foo = 'foo';
// 2.js
import TheClass from './TheClass';
const tc2 = new TheClass();
tc2.foo = 'bar';
Both modules can continue to use tc1 and tc2 completely independently, since they're separate instances.
But if the original module exports an instance rather than a class, then all consumers of the module are forced to use the same instance:
// 1.js
import theInstance from '...';
theInstance.foo = 'foo';
// 2.js
import theInstance from '...';
// might not be a good idea to do theInstance.foo = 'bar' here
// because that will affect 1.js as well
// and will affect any other modules that imported the instance
In short - exporting the class is more reusable than exporting the instance. Sometimes potential reusability is something a script-writer will consider important, and sometimes it isn't. (And sometimes, even if you don't consider it useful initially, you may encounter a situation later that forces you to reconsider.)
And sometimes you want to make sure that there's only one instance ever in a script, in which case
export default new Example()
is a way to accomplish it.

Memory when importing js objects in react

I am new to react and its transpiled way of generating javascript.
In react side, I have a class Utility that uses a data object UserData organized as below -
UserDataObj.js
class UserData{
this.someobj = {};
//some function here
something(){
}
}
const UserDataObj = new UserData();
export {UserDataObj};
Utility.js
import {UserDataObj} from './data/UserDataObj';
class Utility {
doSomething(){
//UserDataObj.something();
}
}
const utility = new Utility();
export {utility};
I have another ReactApp UserApp.js, that also uses UserDataObj and Utility (although not good design wise) -
import {UserDataObj} from './data/UserDataObj';
import {utility} from './Utility';
class UserApp extends React.Component{
//does something with UserDataObj
// also does somethign with utility
}
My question is, how many utility and UserDataObj instances will be created in memory, when UserApp is rendered. My guess is, it should be only 1 instance for both. But I want to confirm if importing n times creates a new instance every time.
Any good read on this topic is greatly appreciated.
Thanks
This depends on the bundling tool, and not React. I imagine that the new browser ES Module resolution scheme works in the same way.
Most bundlers that I know of, and other import schemes such as Node.js' require module resolution will cache the import between files and always return the same exported objetcs. This is a requirement for prototype inheritance, for example, otherwise, it would mess up the instanceof operator.
That exported new Utility() instance will be the same for any module that imports it. In order to generate new instances, you would have to have a function.

Typescript module factory pattern

There is a well-known approach in node.js to leverage the module factory pattern. For, example:
m.js
function factoryMethod(module) {
// doing some stuff and returning object initialized with module parameter
}
app.js
var o = require('./m')(module);
// using o
How can I do the same in typescript. Actually, creating m.ts is not a problem:
m.ts
function factoryMethod(module: NodeModule): any {
// doing some stuff
}
export = factoryMethod;
But how should I use import syntax to use this module factory method like in javascript?
I'm not sure I quite get this common pattern. You're passing the module object from one module into another? All kinds of other objects are passed around like this, (e.g. app, db), but I don't like the idea of passing around the module object. I'd be tempted to call it an anti-pattern. Surely the module object should stay in the module to which it belongs.
That said, if you just want to import and call a function on the same line, you could do this using Node's require() function, just like regular JavaScript. Let's say you are passing an Express app rather than module.
const o = require('./m')(app);
However, you lose type-safety with this; o will be of type any. You would have to explicitly define the type of o.
const o: Module = require('./m')(app);
This is a bit silly. In fact, Module is likely to be defined in the module you are requiring anyway, so it is likely also self-defeating. My suggestion is this. Don't expect to use the same patterns you are used to in plain JS in TypeScript, which has its own patterns.
One thing you could do is import the function at the top, and then call it later. TypeScript uses ES2015-style modules, which don't allow you to import a function and call it on the same line. You will have to rewrite both files, since export = is not valid in ES2015.
// m.ts
interface Module {
// properties, methods, etc.
}
export function factoryMethod(app: Express.Application): Module {
let module = {};
// Initialize module methods, properties, etc.
return module;
}
The interface allow type inference in app.ts, which is an improvement of a kind.
// app.ts
import {factoryMethod} from './m';
// ...
let o = factoryMethod(app);
But this is still very silly. We don't need to define an interface and all that nonsense. Instead, we can use a class. Classes are very often the answer in TypeScript, and you'll find that most patterns in TypeScript involve them.
// m.ts
export class Module {
constructor(private app: Express.Application) { }
cache: string[];
someMethod(): Promise<Express.Response> {
// do something with this.app
}
}
And then in app.ts
import {Module} from './m';
// ...
let o = new Module(app);
Now we don't have to worry about interfaces and all that. The class itself is a type. This is quite a bit different from what you are likely to see in a typical Node app, but it is the sort of pattern you find all the time in TypeScript.
Hopefully that gives you some ideas.
import {factoryMethod} from './m.ts'
let module = factpryMethod('module');
I know this question is fairly old but I came across the same issue when converting an existing JS project to TypeScript that makes use of this pattern.
Instead of having to pre-define the module definition in an interface we can use the ReturnType helper to get a type definition of the return type of a function!
This is what the module might look like:
function initModule(arg1: number, arg2: number) {
function functionA() {
return arg1;
}
function functionB() {
return arg2;
}
return {
functionA,
functionB,
};
}
export default initModule;
export type SampleModule = ReturnType<typeof initFactory>;
And here is how we could use it:
import initModule, { SampleModule } from './factory';
const newModule: SampleModule = initModule(1, 2);
newModule.functionA(); // 1
newModule.functionB(); // 2
Seriously, how cool is TypeScript? :)

Pass options to ES6 module imports

Is it possible to pass options to ES6 imports?
How do you translate this:
var x = require('module')(someoptions);
to ES6?
There is no way to do this with a single import statement, it does not allow for invocations.
So you wouldn't call it directly, but you can basically do just the same what commonjs does with default exports:
// module.js
export default function(options) {
return {
// actual module
}
}
// main.js
import m from 'module';
var x = m(someoptions);
Alternatively, if you use a module loader that supports monadic promises, you might be able to do something like
System.import('module').ap(someoptions).then(function(x) {
…
});
With the new import operator it might become
const promise = import('module').then(m => m(someoptions));
or
const x = (await import('module'))(someoptions)
however you probably don't want a dynamic import but a static one.
Concept
Here's my solution using ES6
Very much inline with #Bergi's response, this is the "template" I use when creating imports that need parameters passed for class declarations. This is used on an isomorphic framework I'm writing, so will work with a transpiler in the browser and in node.js (I use Babel with Webpack):
./MyClass.js
export default (Param1, Param2) => class MyClass {
constructor(){
console.log( Param1 );
}
}
./main.js
import MyClassFactory from './MyClass.js';
let MyClass = MyClassFactory('foo', 'bar');
let myInstance = new MyClass();
The above will output foo in a console
EDIT
Real World Example
For a real world example, I'm using this to pass in a namespace for accessing other classes and instances within a framework. Because we're simply creating a function and passing the object in as an argument, we can use it with our class declaration likeso:
export default (UIFramework) => class MyView extends UIFramework.Type.View {
getModels() {
// ...
UIFramework.Models.getModelsForView( this._models );
// ...
}
}
The importation is a bit more complicated and automagical in my case given that it's an entire framework, but essentially this is what is happening:
// ...
getView( viewName ){
//...
const ViewFactory = require(viewFileLoc);
const View = ViewFactory(this);
return new View();
}
// ...
I hope this helps!
Building on #Bergi's answer to use the debug module using es6 would be the following
// original
var debug = require('debug')('http');
// ES6
import * as Debug from 'debug';
const debug = Debug('http');
// Use in your code as normal
debug('Hello World!');
I've landed on this thread looking up for somewhat similar and would like to propose a sort of solution, at least for some cases (but see Remark below).
Use case
I have a module, that is running some instantiation logic immediately upon loading. I do not like to call this init logic outside the module (which is the same as call new SomeClass(p1, p2) or new ((p1, p2) => class SomeClass { ... p1 ... p2 ... }) and alike).
I do like that this init logic will run once, kind of a singular instantiation flow, but once per some specific parametrized context.
Example
service.js has at its very basic scope:
let context = null; // meanwhile i'm just leaving this as is
console.log('initialized in context ' + (context ? context : 'root'));
Module A does:
import * as S from 'service.js'; // console has now "initialized in context root"
Module B does:
import * as S from 'service.js'; // console stays unchanged! module's script runs only once
So far so good: service is available for both modules but was initialized only once.
Problem
How to make it run as another instance and init itself once again in another context, say in Module C?
Solution?
This is what I'm thinking about: use query parameters. In the service we'd add the following:
let context = new URL(import.meta.url).searchParams.get('context');
Module C would do:
import * as S from 'service.js?context=special';
the module will be re-imported, it's basic init logic will run and we'll see in the console:
initialized in context special
Remark: I'd myself advise to NOT practice this approach much, but leave it as the last resort. Why? Module imported more than once is more of an exception than a rule, so it is somewhat unexpected behavior and as such may confuse a consumers or even break it's own 'singleton' paradigms, if any.
I believe you can use es6 module loaders.
http://babeljs.io/docs/learn-es6/
System.import("lib/math").then(function(m) {
m(youroptionshere);
});
You just need to add these 2 lines.
import xModule from 'module';
const x = xModule('someOptions');
Here's my take on this question using the debug module as an example;
On this module's npm page, you have this:
var debug = require('debug')('http')
In the line above, a string is passed to the module that is imported, to construct. Here's how you would do same in ES6
import { debug as Debug } from 'debug'
const debug = Debug('http');
Hope this helps someone out there.
I ran into an analogous syntax issue when trying to convert some CJS (require()) code to ESM (import) - here's what worked when I needed to import Redis:
CJS
const RedisStore = require('connect-redis')(session);
ESM Equivalent
import connectRedis from 'connect-redis';
const RedisStore = connectRedis(session);
You can pass parameters in the module specifier directly:
import * as Lib from "./lib?foo=bar";
cf: https://flaming.codes/en/posts/es6-import-with-parameters

What does exports mean in javascript? [duplicate]

What is the purpose of Node.js module.exports and how do you use it?
I can't seem to find any information on this, but it appears to be a rather important part of Node.js as I often see it in source code.
According to the Node.js documentation:
module
A reference to the current
module. In particular module.exports
is the same as the exports object. See
src/node.js for more information.
But this doesn't really help.
What exactly does module.exports do, and what would a simple example be?
module.exports is the object that's actually returned as the result of a require call.
The exports variable is initially set to that same object (i.e. it's a shorthand "alias"), so in the module code you would usually write something like this:
let myFunc1 = function() { ... };
let myFunc2 = function() { ... };
exports.myFunc1 = myFunc1;
exports.myFunc2 = myFunc2;
to export (or "expose") the internally scoped functions myFunc1 and myFunc2.
And in the calling code you would use:
const m = require('./mymodule');
m.myFunc1();
where the last line shows how the result of require is (usually) just a plain object whose properties may be accessed.
NB: if you overwrite exports then it will no longer refer to module.exports. So if you wish to assign a new object (or a function reference) to exports then you should also assign that new object to module.exports
It's worth noting that the name added to the exports object does not have to be the same as the module's internally scoped name for the value that you're adding, so you could have:
let myVeryLongInternalName = function() { ... };
exports.shortName = myVeryLongInternalName;
// add other objects, functions, as required
followed by:
const m = require('./mymodule');
m.shortName(); // invokes module.myVeryLongInternalName
This has already been answered but I wanted to add some clarification...
You can use both exports and module.exports to import code into your application like this:
var mycode = require('./path/to/mycode');
The basic use case you'll see (e.g. in ExpressJS example code) is that you set properties on the exports object in a .js file that you then import using require()
So in a simple counting example, you could have:
(counter.js):
var count = 1;
exports.increment = function() {
count++;
};
exports.getCount = function() {
return count;
};
... then in your application (web.js, or really any other .js file):
var counting = require('./counter.js');
console.log(counting.getCount()); // 1
counting.increment();
console.log(counting.getCount()); // 2
In simple terms, you can think of required files as functions that return a single object, and you can add properties (strings, numbers, arrays, functions, anything) to the object that's returned by setting them on exports.
Sometimes you'll want the object returned from a require() call to be a function you can call, rather than just an object with properties. In that case you need to also set module.exports, like this:
(sayhello.js):
module.exports = exports = function() {
console.log("Hello World!");
};
(app.js):
var sayHello = require('./sayhello.js');
sayHello(); // "Hello World!"
The difference between exports and module.exports is explained better in this answer here.
Note that the NodeJS module mechanism is based on CommonJS modules which are supported in many other implementations like RequireJS, but also SproutCore, CouchDB, Wakanda, OrientDB, ArangoDB, RingoJS, TeaJS, SilkJS, curl.js, or even Adobe Photoshop (via PSLib).
You can find the full list of known implementations here.
Unless your module use node specific features or module, I highly encourage you then using exports instead of module.exports which is not part of the CommonJS standard, and then mostly not supported by other implementations.
Another NodeJS specific feature is when you assign a reference to a new object to exports instead of just adding properties and methods to it like in the last example provided by Jed Watson in this thread. I would personally discourage this practice as this breaks the circular reference support of the CommonJS modules mechanism. It is then not supported by all implementations and Jed example should then be written this way (or a similar one) to provide a more universal module:
(sayhello.js):
exports.run = function() {
console.log("Hello World!");
}
(app.js):
var sayHello = require('./sayhello');
sayHello.run(); // "Hello World!"
Or using ES6 features
(sayhello.js):
Object.assign(exports, {
// Put all your public API here
sayhello() {
console.log("Hello World!");
}
});
(app.js):
const { sayHello } = require('./sayhello');
sayHello(); // "Hello World!"
PS: It looks like Appcelerator also implements CommonJS modules, but without the circular reference support (see: Appcelerator and CommonJS modules (caching and circular references))
Some few things you must take care if you assign a reference to a new object to exports and /or modules.exports:
1. All properties/methods previously attached to the original exports or module.exports are of course lost because the exported object will now reference another new one
This one is obvious, but if you add an exported method at the beginning of an existing module, be sure the native exported object is not referencing another object at the end
exports.method1 = function () {}; // exposed to the original exported object
exports.method2 = function () {}; // exposed to the original exported object
module.exports.method3 = function () {}; // exposed with method1 & method2
var otherAPI = {
// some properties and/or methods
}
exports = otherAPI; // replace the original API (works also with module.exports)
2. In case one of exports or module.exports reference a new value, they don't reference to the same object any more
exports = function AConstructor() {}; // override the original exported object
exports.method2 = function () {}; // exposed to the new exported object
// method added to the original exports object which not exposed any more
module.exports.method3 = function () {};
3. Tricky consequence. If you change the reference to both exports and module.exports, hard to say which API is exposed (it looks like module.exports wins)
// override the original exported object
module.exports = function AConstructor() {};
// try to override the original exported object
// but module.exports will be exposed instead
exports = function AnotherConstructor() {};
the module.exports property or the exports object allows a module to select what should be shared with the application
I have a video on module_export available here
When dividing your program code over multiple files, module.exports is used to publish variables and functions to the consumer of a module. The require() call in your source file is replaced with corresponding module.exports loaded from the module.
Remember when writing modules
Module loads are cached, only initial call evaluates JavaScript.
It's possible to use local variables and functions inside a module, not everything needs to be exported.
The module.exports object is also available as exports shorthand. But when returning a sole function, always use module.exports.
According to: "Modules Part 2 - Writing modules".
the refer link is like this:
exports = module.exports = function(){
//....
}
the properties of exports or module.exports ,such as functions or variables , will be exposed outside
there is something you must pay more attention : don't override exports .
why ?
because exports just the reference of module.exports , you can add the properties onto the exports ,but if you override the exports , the reference link will be broken .
good example :
exports.name = 'william';
exports.getName = function(){
console.log(this.name);
}
bad example :
exports = 'william';
exports = function(){
//...
}
If you just want to exposed only one function or variable , like this:
// test.js
var name = 'william';
module.exports = function(){
console.log(name);
}
// index.js
var test = require('./test');
test();
this module only exposed one function and the property of name is private for the outside .
There are some default or existing modules in node.js when you download and install node.js like http, sys etc.
Since they are already in node.js, when we want to use these modules we basically do like import modules, but why? because they are already present in the node.js. Importing is like taking them from node.js and putting them into your program. And then using them.
Whereas Exports is exactly the opposite, you are creating the module you want, let's say the module addition.js and putting that module into the node.js, you do it by exporting it.
Before I write anything here, remember, module.exports.additionTwo is same as exports.additionTwo
Huh, so that's the reason, we do like
exports.additionTwo = function(x)
{return x+2;};
Be careful with the path
Lets say you have created an addition.js module,
exports.additionTwo = function(x){
return x + 2;
};
When you run this on your NODE.JS command prompt:
node
var run = require('addition.js');
This will error out saying
Error: Cannot find module addition.js
This is because the node.js process is unable the addition.js since we didn't mention the path. So, we have can set the path by using NODE_PATH
set NODE_PATH = path/to/your/additon.js
Now, this should run successfully without any errors!!
One more thing, you can also run the addition.js file by not setting the NODE_PATH, back to your nodejs command prompt:
node
var run = require('./addition.js');
Since we are providing the path here by saying it's in the current directory ./ this should also run successfully.
A module encapsulates related code into a single unit of code. When creating a module, this can be interpreted as moving all related functions into a file.
Suppose there is a file Hello.js which include two functions
sayHelloInEnglish = function() {
return "Hello";
};
sayHelloInSpanish = function() {
return "Hola";
};
We write a function only when utility of the code is more than one call.
Suppose we want to increase utility of the function to a different file say World.js,in this case exporting a file comes into picture which can be obtained by module.exports.
You can just export both the function by the code given below
var anyVariable={
sayHelloInEnglish = function() {
return "Hello";
};
sayHelloInSpanish = function() {
return "Hola";
};
}
module.export=anyVariable;
Now you just need to require the file name into World.js inorder to use those functions
var world= require("./hello.js");
The intent is:
Modular programming is a software design technique that emphasizes
separating the functionality of a program into independent,
interchangeable modules, such that each contains everything necessary
to execute only one aspect of the desired functionality.
Wikipedia
I imagine it becomes difficult to write a large programs without modular / reusable code. In nodejs we can create modular programs utilising module.exports defining what we expose and compose our program with require.
Try this example:
fileLog.js
function log(string) { require('fs').appendFileSync('log.txt',string); }
module.exports = log;
stdoutLog.js
function log(string) { console.log(string); }
module.exports = log;
program.js
const log = require('./stdoutLog.js')
log('hello world!');
execute
$ node program.js
hello world!
Now try swapping ./stdoutLog.js for ./fileLog.js.
What is the purpose of a module system?
It accomplishes the following things:
Keeps our files from bloating to really big sizes. Having files with e.g. 5000 lines of code in it are usually real hard to deal with during development.
Enforces separation of concerns. Having our code split up into multiple files allows us to have appropriate file names for every file. This way we can easily identify what every module does and where to find it (assuming we made a logical directory structure which is still your responsibility).
Having modules makes it easier to find certain parts of code which makes our code more maintainable.
How does it work?
NodejS uses the CommomJS module system which works in the following manner:
If a file wants to export something it has to declare it using module.export syntax
If a file wants to import something it has to declare it using require('file') syntax
Example:
test1.js
const test2 = require('./test2'); // returns the module.exports object of a file
test2.Func1(); // logs func1
test2.Func2(); // logs func2
test2.js
module.exports.Func1 = () => {console.log('func1')};
exports.Func2 = () => {console.log('func2')};
Other useful things to know:
Modules are getting cached. When you are loading the same module in 2 different files the module only has to be loaded once. The second time a require() is called on the same module the is pulled from the cache.
Modules are loaded in synchronous. This behavior is required, if it was asynchronous we couldn't access the object retrieved from require() right away.
ECMAScript modules - 2022
From Node 14.0 ECMAScript modules are no longer experimental and you can use them instead of classic Node's CommonJS modules.
ECMAScript modules are the official standard format to package JavaScript code for reuse. Modules are defined using a variety of import and export statements.
You can define an ES module that exports a function:
// my-fun.mjs
function myFun(num) {
// do something
}
export { myFun };
Then, you can import the exported function from my-fun.mjs:
// app.mjs
import { myFun } from './my-fun.mjs';
myFun();
.mjs is the default extension for Node.js ECMAScript modules.
But you can configure the default modules extension to lookup when resolving modules using the package.json "type" field, or the --input-type flag in the CLI.
Recent versions of Node.js fully supports both ECMAScript and CommonJS modules. Moreover, it provides interoperability between them.
module.exports
ECMAScript and CommonJS modules have many differences but the most relevant difference - to this question - is that there are no more requires, no more exports, no more module.exports
In most cases, the ES module import can be used to load CommonJS modules.
If needed, a require function can be constructed within an ES module using module.createRequire().
ECMAScript modules releases history
Release
Changes
v15.3.0, v14.17.0, v12.22.0
Stabilized modules implementation
v14.13.0, v12.20.0
Support for detection of CommonJS named exports
v14.0.0, v13.14.0, v12.20.0
Remove experimental modules warning
v13.2.0, v12.17.0
Loading ECMAScript modules no longer requires a command-line flag
v12.0.0
Add support for ES modules using .js file extension via package.json "type" field
v8.5.0
Added initial ES modules implementation
You can find all the changelogs in Node.js repository
let test = function() {
return "Hello world"
};
exports.test = test;

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