I have an HTML form in a JSP file in my WebContent/jsps folder. I have a servlet class servlet.java in my default package in src folder. In my web.xml it is mapped as /servlet.
I have tried several URLs in action attribute of the HTML form:
<form action="/servlet">
<form action="/servlet.java">
<form action="/src/servlet.java">
<form action="../servlet.java">
But none of those work. They all keep returning a HTTP 404 error like below in Tomcat 6/7/8:
HTTP Status 404 — /servlet
Description: The requested resource (/servlet) is not available.
Or as below in Tomcat 8.5/9:
HTTP Status 404 — Not Found
Message: /servlet
Description: The origin server did not find a current representation for the target resource or is not willing to disclose that one exists
Or as below in Tomcat 10:
HTTP Status 404 — Not Found
Type: Status Report
Message: The requested resource (/servlet) is not available
Description: The origin server did not find a current representation for the target resource or is not willing to disclose that one exists
Why is it not working?
Introduction
This can have a lot of causes which are broken down in following sections:
Put servlet class in a package
Set servlet URL in url-pattern
#WebServlet works only on Servlet 3.0 or newer
javax.servlet.* doesn't work anymore in Servlet 5.0 or newer
Make sure compiled *.class file is present in built WAR
Test the servlet individually without any JSP/HTML page
Use domain-relative URL to reference servlet from HTML
Use straight quotes in HTML attributes
Put servlet class in a package
First of all, put the servlet class in a Java package. You should always put publicly reuseable Java classes in a package, otherwise they are invisible to classes which are in a package, such as the server itself. This way you eliminate potential environment-specific problems. Packageless servlets work only in specific Tomcat+JDK combinations and this should never be relied upon.
In case of a "plain" IDE project, the class needs to be placed in its package structure inside the "Java Sources" folder, not inside "Web Content" folder, which is for web files such as JSP. Below is an example of the folder structure of a default Eclipse Dynamic Web Project as seen in Navigator view (the "Java Sources" folder is in such project by default represented by src folder):
EclipseProjectName
|-- src
| `-- com
| `-- example
| `-- YourServlet.java
|-- WebContent
| |-- WEB-INF
| | `-- web.xml
| `-- jsps
| `-- page.jsp
:
In case of a Maven project, the class needs to be placed in its package structure inside main/java and thus not main/resources, this is for non-class files and absolutely also not main/webapp, this is for web files. Below is an example of the folder structure of a default Maven webapp project as seen in Eclipse's Navigator view:
MavenProjectName
|-- src
| `-- main
| |-- java
| | `-- com
| | `-- example
| | `-- YourServlet.java
| |-- resources
| `-- webapp
| |-- WEB-INF
| | `-- web.xml
| `-- jsps
| `-- page.jsp
:
Note that the /jsps subfolder is not strictly necessary. You can even do without it and put the JSP file directly in webcontent/webapp root, but I'm just taking over this from your question.
Set servlet URL in url-pattern
The servlet URL is specified as the "URL pattern" of the servlet mapping. It's absolutely not per definition the classname/filename of the servlet class. The URL pattern is to be specified as value of #WebServlet annotation.
package com.example; // Use a package!
import jakarta.servlet.annotation.WebServlet; // or javax.*
import jakarta.servlet.http.HttpServlet; // or javax.*
#WebServlet("/servlet") // This is the URL of the servlet.
public class YourServlet extends HttpServlet { // Must be public and extend HttpServlet.
// ...
}
In case you want to support path parameters like /servlet/foo/bar, then use an URL pattern of /servlet/* instead. See also Servlet and path parameters like /xyz/{value}/test, how to map in web.xml?
Do note that it's considered a bad practice to use a Servlet URL pattern of /* or / in an attempt to have a "front controller". So do not abuse these URL patterns in an attempt to try to catch all URLs. For an in depth explanation see also Difference between / and /* in servlet mapping url pattern.
#WebServlet works only on Servlet 3.0 or newer
In order to use #WebServlet, you only need to make sure that your web.xml file, if any (it's optional since Servlet 3.0), is declared conform Servlet 3.0+ version and thus not conform e.g. 2.5 version or lower. It should absolutely also not have any <!DOCTYPE> line. Below is a Servlet 6.0 compatible one (which matches Tomcat 10.1+, WildFly 27+ (Preview), GlassFish/Payara 7+, etc) in its entirety:
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns="https://jakarta.ee/xml/ns/jakartaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="https://jakarta.ee/xml/ns/jakartaee https://jakarta.ee/xml/ns/jakartaee/web-app_6_0.xsd"
version="6.0"
>
<!-- Config here. -->
</web-app>
And below is a Servlet 5.0 compatible one (which matches Tomcat 10.0.x, WildFly 22+ (Preview), GlassFish/Payara 6+, etc).
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns="https://jakarta.ee/xml/ns/jakartaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="https://jakarta.ee/xml/ns/jakartaee https://jakarta.ee/xml/ns/jakartaee/web-app_5_0.xsd"
version="5.0"
>
<!-- Config here. -->
</web-app>
And below is a Servlet 4.0 compatible one (which matches Tomcat 9+, WildFly 11+, GlassFish/Payara 5+, etc).
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd"
version="4.0"
>
<!-- Config here. -->
</web-app>
Or, in case you're not on Servlet 3.0+ yet (e.g. Tomcat 6 or older), then remove the #WebServlet annotation.
package com.example;
import javax.servlet.http.HttpServlet;
public class YourServlet extends HttpServlet {
// ...
}
And register the servlet instead in web.xml like this:
<servlet>
<servlet-name>yourServlet</servlet-name>
<servlet-class>com.example.YourServlet</servlet-class> <!-- Including the package thus -->
</servlet>
<servlet-mapping>
<servlet-name>yourServlet</servlet-name>
<url-pattern>/servlet</url-pattern> <!-- This is the URL of the servlet. -->
</servlet-mapping>
Note thus that you should not use both ways. Use either annotation based configuarion or XML based configuration. When you have both, then XML based configuration will override annotation based configuration.
javax.servlet.* doesn't work anymore in Servlet 5.0 or newer
Since Jakarta EE 9 / Servlet 5.0 (Tomcat 10, TomEE 9, WildFly 22 Preview, GlassFish 6, Payara 6, Liberty 22, etc), the javax.* package has been renamed to jakarta.* package.
In other words, please make absolutely sure that you don't randomly put JAR files of a different server in your WAR project such as tomcat-servlet-api-9.x.x.jar merely in order to get the javax.* package to compile. This will only cause trouble. Remove it altogether and edit the imports of your servlet class from
import javax.servlet.*;
import javax.servlet.annotation.*;
import javax.servlet.http.*;
to
import jakarta.servlet.*;
import jakarta.servlet.annotation.*;
import jakarta.servlet.http.*;
In case you're using Maven, you can find examples of proper pom.xml declarations for Tomcat 10+, Tomcat 9-, JEE 9+ and JEE 8- in this answer: How to properly configure Jakarta EE libraries in Maven pom.xml for Tomcat? The alternative is to downgrade the server to an older version, e.g. from Tomcat 10 back to Tomcat 9 or older, but this is clearly not the recommended way to go.
Make sure compiled *.class file is present in built WAR
In case you're using a build tool such as Eclipse and/or Maven, then you need to make absolutely sure that the compiled servlet class file resides in its package structure in /WEB-INF/classes folder of the produced WAR file. In case of package com.example; public class YourServlet, it must be located in /WEB-INF/classes/com/example/YourServlet.class. Otherwise you will face in case of #WebServlet also a 404 error, or in case of <servlet> a HTTP 500 error like below:
HTTP Status 500
Error instantiating servlet class com.example.YourServlet
And find in the server log a java.lang.ClassNotFoundException: com.example.YourServlet, followed by a java.lang.NoClassDefFoundError: com.example.YourServlet, in turn followed by jakarta.servlet.ServletException: Error instantiating servlet class com.example.YourServlet.
An easy way to verify if the servlet is correctly compiled and placed in classpath is to let the build tool produce a WAR file (e.g. rightclick project, Export > WAR file in Eclipse) and then inspect its contents with a ZIP tool. If the servlet class is missing in /WEB-INF/classes, or if the export causes an error, then the project is badly configured or some IDE/project configuration defaults have been mistakenly reverted (e.g. Project > Build Automatically has been disabled in Eclipse).
You also need to make sure that the project icon has no red cross indicating a build error. You can find the exact error in Problems view (Window > Show View > Other...). Usually the error message is fine Googlable. In case you have no clue, best is to restart from scratch and do not touch any IDE/project configuration defaults. In case you're using Eclipse, you can find instructions in How do I import the javax.servlet / jakarta.servlet API in my Eclipse project?
Test the servlet individually without any JSP/HTML page
Provided that the server runs on localhost:8080, and that the WAR is successfully deployed on a context path of /contextname (which defaults to the IDE project name, case sensitive!), and the servlet hasn't failed its initialization (read server logs for any deploy/servlet success/fail messages and the actual context path and servlet mapping), then a servlet with URL pattern of /servlet is available at http://localhost:8080/contextname/servlet.
You can just enter it straight in browser's address bar to test it invidivually. If its doGet() is properly overriden and implemented, then you will see its output in browser. Or if you don't have any doGet() or if it incorrectly calls super.doGet(), then a "HTTP 405: HTTP method GET is not supported by this URL" error will be shown (which is still better than a 404 as a 405 is evidence that the servlet itself is actually found).
Overriding service() is a bad practice, unless you're reinventing a MVC framework — which is very unlikely if you're just starting out with servlets and are clueless as to the problem described in the current question ;) See also Design Patterns web based applications.
Regardless, if the servlet already returns 404 when tested invidivually, then it's entirely pointless to try with a HTML form instead. Logically, it's therefore also entirely pointless to include any HTML form in questions about 404 errors from a servlet.
Use domain-relative URL to reference servlet from HTML
Once you've verified that the servlet works fine when invoked individually, then you can advance to HTML. As to your concrete problem with the HTML form, the <form action> value needs to be a valid URL. The same applies to <a href>, <img src>, <script src>, etc. You need to understand how absolute/relative URLs work. You know, an URL is a web address as you can enter/see in the webbrowser's address bar. If you're specifying a relative URL as form action, i.e. without the http:// scheme, then it becomes relative to the current URL as you see in your webbrowser's address bar. It's thus absolutely not relative to the JSP/HTML file location in server's WAR folder structure as many starters seem to think.
So, assuming that the JSP page with the HTML form is opened by http://localhost:8080/contextname/jsps/page.jsp (and thus not by file://...), and you need to submit to a servlet located in http://localhost:8080/contextname/servlet, here are several cases (note that you can here safely substitute <form action> with <a href>, <img src>, <script src>, etc):
Form action submits to an URL with a leading slash.
<form action="/servlet">
The leading slash / makes the URL relative to the domain, thus the form will submit to
http://localhost:8080/servlet
But this will likely result in a 404 as it's in the wrong context.
Form action submits to an URL without a leading slash.
<form action="servlet">
This makes the URL relative to the current folder of the current URL, thus the form will submit to
http://localhost:8080/contextname/jsps/servlet
But this will likely result in a 404 as it's in the wrong folder.
Form action submits to an URL which goes one folder up.
<form action="../servlet">
This will go one folder up (exactly like as in local disk file system paths!), thus the form will submit to
http://localhost:8080/contextname/servlet
This one must work!
The canonical approach, however, is to make the URL domain-relative so that you don't need to fix the URLs once again when you happen to move the JSP files around into another folder.
<form action="${pageContext.request.contextPath}/servlet">
This will generate
<form action="/contextname/servlet">
Which will thus always submit to the right URL.
Use straight quotes in HTML attributes
You need to make absolutely sure you're using straight quotes in HTML attributes like action="..." or action='...' and thus not curly quotes like action=”...” or action=’...’. Curly quotes are not supported in HTML and they will simply become part of the value. Watch out when copy-pasting code snippets from blogs! Some blog engines, notably Wordpress, are known to by default use so-called "smart quotes" which thus also corrupts the quotes in code snippets this way. On the other hand, instead of copy-pasting code, try simply typing over the code yourself. Additional advantage of actually getting the code through your brain and fingers is that it will make you to remember and understand the code much better in long term and also make you a better developer.
See also:
Our servlets wiki page - Contains some hello world examples
How to call servlet class from HTML form
doGet and doPost in Servlets
How do I pass current item to Java method by clicking a hyperlink or button in JSP page?
Other cases of HTTP Status 404 error:
HTTP Status 404 - Servlet [ServletName] is not available
HTTP Status 404 - The requested resource (/ProjectName/) is not available
HTTP Status 404 - The requested resource (/) is not available
JSP in /WEB-INF returns "HTTP Status 404 The requested resource is not available"
Referencing a resource placed in WEB-INF folder in JSP file returns HTTP 404 on resource
Browser can't access/find relative resources like CSS, images and links when calling a Servlet which forwards to a JSP
Scenario #1: You accidentially re-deployed from the command line while tomcat was already running.
Short Answer: Stop Tomcat, delete target folder, mvn package, then re-deploy
Scenario #2: request.getRequestDispatcher("MIS_SPELLED_FILE_NAME.jsp")
Short Answer: Check file name spelling, make sure case is correct.
Scenario #3: Class Not Found Exceptions
(Answer put here because: Question# 17982240 )
(java.lang.ClassNotFoundException for servlet in tomcat with eclipse )
(was marked as duplicate and directed me here )
Short Answer #3.1: web.xml has wrong package path in servlet-class tag.
Short Answer #3.2: java file has wrong import statement.
Below is further details for Scenario #1:
1: Stop Tomcat
Option 1: Via CTRL+C in terminal.
Option 2: (terminal closed while tomcat still running)
------------ 2.1: press:Windows+R --> type:"services.msc"
------------ 2.2: Find "Apache Tomcat #.# Tomcat#" in Name column of list.
------------ 2.3: Right Click --> "stop"
2: Delete the "target" folder.
(mvn clean will not help you here)
3: mvn package
4: YOUR_DEPLOYMENT_COMMAND_HERE
(Mine: java -jar target/dependency/webapp-runner.jar --port 5190 target/*.war )
Full Back Story:
Accidentially opened a new git-bash window and
tried to deploy a .war file for my heroku project via:
java -jar target/dependency/webapp-runner.jar --port 5190 target/*.war
After a failure to deploy, I realized I had two git-bash windows open,
and had not used CTLR+C to stop the previous deployment.
I was met with:
HTTP Status 404 – Not Found Type Status Report
Message /if-student-test.jsp
Description The origin server did not find a current representation
for the target resource or is not willing to disclose that one
exists.
Apache Tomcat/8.5.31
Below is further details for Scenario #3:
SCENARIO 3.1:
The servlet-class package path is wrong
in your web.xml file.
It should MATCH the package statement at top
of your java servlet class.
File: my_stuff/MyClass.java:
package my_stuff;
File: PRJ_ROOT/src/main/webapp/WEB-INF/web.xml
<servlet-class>
my_stuff.MyClass
</servlet-class>
SCENARIO 3.2:
You put the wrong "package" statement
at top of your myClass.java file.
For example:
File is in: "/my_stuff" folder
You mistakenly write:
package com.my_stuff
This is tricky because:
1: The maven build (mvn package) will not report any errors here.
2: servlet-class line in web.xml can have CORRECT package path. E.g:
<servlet-class>
my_stuff.MyClass
</servlet-class>
Stack Used:
Notepad++ + GitBash + Maven + Heroku Web App Runner + Tomcat9 + Windows10:
Check if you have entered the correct URL Mapping as specified in the Web.xml
For example:
In the web.xml, your servlet declaration maybe:
<servlet>
<servlet-name>ControllerA</servlet-name>
<servlet-class>PackageName.ControllerA</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ControllerA</servlet-name>
<url-pattern>/theController</url-pattern>
</servlet-mapping>
What this snippet does is <url-pattern>/theController</url-pattern>will set the name that will be used to call the servlet from the front end (eg: form) through the URL. Therefore when you reference the servlet in the front end, in order to ensure that the request goes to the servlet "ControllerA", it should refer the specified URL Pattern "theController" from the form.
eg:
<form action="theController" method="POST">
</form>
If you're using IntelliJ, this is what fixed it for me:
Go to the Tomcat configuration:
Configuration > Deployment Tab
Scroll down and add / to the Application Context dropdown
Solution for HTTP Status 404 in NetBeans IDE:
Right click on your project and go to your project properties, then click on run, then input your project relative URL like index.jsp.
Project->Properties
Click on Run
Relative URL:/index.jsp (Select your project root URL)
My issue was that my method was missing the #RequestBody annotation. After adding the annotation I no longer received the 404 exception.
Do the following two steps. I hope, it will solve the "404 not found" issue in tomcat server during the development of java servlet application.
Step 1: Right click on the server(in the server explorer tab)->Properties->Switch Location from workspace metadata to tomcat server
Step 2: Double Click on the server(in the server explorer tab)->Select Use tomcat installation option inside server location menu
I removed the old web library such that are spring framework libraries. And build a new path of the libraries. Then it works.
An old thread, but since I didn't find it elsewhere, here is one more possibility:
If you're using servlet-api 3.0+, then your web.xml must NOT include metadata-complete="true" attribute
This tells tomcat to map the servlets using data given in web.xml instead of using the #WebServlet annotation.
First of all, run your IDE as Admin. After that, right click the project folder -> Project Facets and make sure that the Java Version is set correct. On my PC. (For Example 1.8) Now it should work.
Don't just start your server, for example Wildfly, using the cmd. It has to be launched within the IDE and now visit your localhost URL. Example: http://localhost:8080/HelloWorldServlet/HelloWorld
The fix that worked for me is(if you are using Maven): Rightclick your project, Maven -> Update project. This might give you some other error with the JDK and other Libraries(in my case, MySQL connector), but once you fix them, your original problem should be fixed!
If you would like to open a servlet with javascript without using 'form' and 'submit' button, here is the following code:
var button = document.getElementById("<<button-id>>");
button.addEventListener("click", function() {
window.location.href= "<<full-servlet-path>>" (eg. http://localhost:8086/xyz/servlet)
});
Key:
1) button-id : The 'id' tag you give to your button in your html/jsp file.
2) full-servlet-path: The path that shows in the browser when you run the servlet alone
Mapping in web.xml is what i have done :-
If there's another package made for new program then we must mention :-
packagename.filename between opening and closing of servlet-class tag in xml file.
If you are mapping your files in xml and they are not working or showing errors , then comment on the annotation line of code in the respective files.
Both methods dont work with one another , so either i use annotation method of files mentioned when we create servlet or the way of mapping , then i delete or comment the annotation line. Eg:
<servlet>
<servlet-name>s1</servlet-name>
<servlet-class>performance.FirstServ</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>s1</servlet-name>
<url-pattern>/FirstServ</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>s2</servlet-name>
<servlet-class>performance.SecondServ</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>s2</servlet-name>
<url-pattern>/SecondServ</url-pattern>
</servlet-mapping>
Commenting the annotation line of code in the respective file,if mapping in xml is done.
//#WebServlet("/FirstServ")
//#WebServlet("/SecondServ")
If someone is here who is using MySQL and felt that the code was working the previous day and now it doesn't, then I guess you must open MySQL CLI or MySQL Workbench and just make the connection to the database once. Once it gets connected, then the database also gets connected to the Java Application. I used to get the Hibernate Dialect error stating something wrong with com.mysql.jdbc.Driver. I think MySQL in some computers has a startup problem. This solved for me.
If you are a student and new to Java there might be some issue going on with your web.xml file.
Try removing the web.xml file.
Secondly check that your path variables are properly set or not.
Restart tomcat server Or your PC.
Your problem will be surely solved.
I was facing this issue too, I was receiving a 404 when accessing a URL pattern that I knew was linked to a Servlet. The reason is because I had 2 Servlets with their #WebServlet name parameter set as the same string.
#WebServlet(name = "ServletName", urlPatterns = {"/path"})
public class ServletName extends HttpServlet {}
#WebServlet(name = "ServletName", urlPatterns = {"/other-path"})
public class OtherServletName extends HttpServlet {}
Both of the name parameters are the same. If you're using the name parameter, make sure they are unique compared to all other Servlets on your application.
I had the same issue. Tried all of this but didn't help. I managed to solve this issue by adding element tags to beginning and end of the xml file. ill leave my xml file below for reference.
<?xml version="1.0" encoding="UTF-8"?>
<element>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee
http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
version="3.1">
<servlet>
<servlet-name>InsertServlet</servlet-name>
<servlet-class>com.worklog.InsertServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>InsertServlet</servlet-name>
<url-pattern>/insert</url-pattern>
</servlet-mapping>
</web-app>
</element>
I was having the same issue. I was developing a mvc based REST API where there was no explicit html configuration or files. The API was using Swagger to generate a user interface. The problem started when I introduced Swagger version "3.0.0". I reverted back to Swagger "2.9.2" This solved my problem.
<!-- Swagger -->
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-swagger-ui</artifactId>
<version>2.9.2</version>
</dependency>
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-swagger2</artifactId>
<version>2.9.2</version>
</dependency>
Please check context root cannot be empty.
If you're using eclipse:
right click, select properties, then web project settings. Check the context root cannot be empty
Related
I'm trying publish a website in a subfolder (exemple.com/sitename) usign Traefik.
The site is build with Next JS.
What is happening when I run deploy is that all script links in the builded site disregard the folder (sitename). For example, js script named generatedfile.js is being accessed by the link example.com/generatedfile.js, the corret way would be example.com/sitename/generatedfile.js
My traefik args:
-l traefik.frontend.rule="Host:example.com; PathPrefixStrip:/sitename" -l traefik.frontend.entryPoints="http, https" -l traefik.frontend.headers.SSLRedirect="true"
I had tried add basePath to my next.config.js, but when I do this, I only access de site in the link exemple.com/sitename/sitename
next.config.js:
module.exports = withFonts({
basePath: '/sitename'
});
I'm using docker to deploy in AWS.
I've been trying to solve this all day, I don't even know what else to try to solve it.
Sorry for my english, it's not my first language.
PathPrefixStrip means match the path and strip the matched string before forwarding the request to your application. Use PathPrefix instead.
Looks like you're using v1.x of Traefik. Here's the documentation explaining the difference better: https://doc.traefik.io/traefik/v1.7/basics/
It's worth mentioning that if you have multiple routing rules, Traefik sorts them by their string length in a descending order and goes through them to match the incoming request. In other words, /api is matched before /.
I was about to upload my almost finished website and went on to purchase a VPS Hosting.
Hostgator confirmed that they support Node.js and I found myself in a big question mark.
Am i uploading it correctly or what is failing?
Folder View contains: Index.ejs
Folder Public contains: All the CSS, JS, Images and Form related to Index.ejs
Upon calling the Website everything renders properly until i get into the add to cart section and this line of code appear:
<% items.Salat.forEach(function(item){ %>
and so on
<%= item.description %>
Your VPS' operating system appears to have come with a webserver preinstalled. It has a phpinfo.php file which suggests it has an extension set up for running PHP programs. (There's a good chance that it is Apache HTTPD with mod_php).
Server-side programs that use Node.js run directly through Node.js and not through an extension on an existing webserver.
Typically you would either disable the existing webserver and run the one written in Node.js instead or configure the existing webserver to act as a reverse proxy which forwards requests to the Node.js server.
Either way, you can't just drop your JS source code into the webserver's directory root and have it execute it.
This issue seems to be well documented but all solutions people suggest on posts don't work for me :/
I managed to fix urls giving 404 on my localhost by applying
--history-api-fallback
to the "scripts" package.json
however when I move the production over to my apache2 setup, any url I manually type or refresh returns 404, on site navigation works fine.
for example, http://www.craftmc.net/ works but http://www.craftmc.net/login returns 404, despite that url working if i navigate to it on site.
I saw a post saying use this .htaccess,
https://hastebin.com/alifavacil.apache
Sadly it didn't work. :/
navigation in question - https://hastebin.com/xevecefoda.xml
You need to configure Apache to serve your app on all URLs that it's supposed to handle.
By default, Apache will only serve your app when the user requests the specific path where the app is located, say for example www.example.com
If you now try to visit www.example.com/user/123, Apache will try to find a file named "123.html" inside the "user" folder. You have to tell Apache that what it should do is reply with your app even if the path requested by the browser doesn't actually point to your app within the filesystem on the server.
You can do this in several ways, but a common one is to use mod_rewrite. For example, you might try something along these lines:
DocumentRoot "/var/www/example.com"
AliasMatch "^/myapp" "/opt/myapp-1.2.3"
<Directory "/opt/myapp-1.2.3">
RewriteEngine On
RewriteBase "/myapp/"
RewriteRule "^index\.html$" "welcome.html"
</Directory>
For more information about mod_rewrite and the various directives it uses, refer to the documentation, and/or google.
I have a requirement where i need to undeploy war files in weblogic using command line, the below code does it for me :
java weblogic.Deployer -adminurl t3://localhost:8001 -user weblogic -password password123 -name <name> -undeploy
But the file names change after every deployment, i,e (file 1.0.0 and file 1.1.1).
i need a command in such a way so that it undeploys all the files present in that server.
can any body let me know how to undeploy all files at a single go ?
Thanks in advance,
Vishal
I have found out how to undeploy all the apps :
List Apps:
import sys
connect('weblogic','weblogic10','http://autowfm-vmh:7259')
cd("AppDeployments")
app = ls(returnMap='true')
domainRuntime()
cd("AppRuntimeStateRuntime/AppRuntimeStateRuntime")
i=1
f = open('filename.txt','w')
for appName in app:
print >>f, appName
i=i+1
f.close()
exit()
Undeploy :
import os
connect('weblogic','weblogic','http://localhost:7001')
target='AdminServer'
f = open(r'D:\filename.txt','r')
print f
for i in range(10):
line=f.readline()
line1=line[:-1]
appName='./'+line1
print '*****************'+appName
undeploy(appName=line1)
exit()
If you want to script a more generic answer you can list all the apps via:
java -cp /opt/ora/mw/wlserver_10.3/server/lib/weblogic.jar weblogic.Deployer
-adminurl t3://host:port -username weblogic -password weblogic1 -listapps
And then parse that output to begin removing apps.
The <name> should be the module name not the file (war or ear) name. Using the -undeploycommand without the -targets and -submoduletargets flags completely removes the application or standalone module from all WebLogic Server instances and untargets all JMS sub-module resources.
BTW, Adding the -graceful option would allow current HTTP clients to complete their work before undeploying.
Note: Undeploying a deployment unit does not remove the original source files used for deployment. It only removes the deployment's configuration from the domain, as well as any deployment files that WebLogic Server created during deployment (for example, files copied with stage deployment mode and files uploaded to the Administration Server).
I have found out how to undeploy all the apps without using files
def undeployWars():
cd("AppDeployments")
namesWars = ls(returnMap='true')
for nameWar in namesWars:
undeploy(nameWar)
connect('weblogic', 'weblogic01', 't3://localhost:7001')
undeployWars()
disconnect()
exit()
I was assigned with the task of integrating new designs into an old app , the app was built on 3.2.8 and i did an upgrade to 3.2.13 . What puzzles me is the js part , i have done everything i could by searching on SO and vice versa but no luck .Already looked into this and this one but somehow the js isn't being served .Following are the parts of code that might be useful -
app/views/layouts/application.html.erb :
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.0/jquery.min.js"></script>
<%= javascript_include_tag "html5shiv.js" %>
<%= javascript_include_tag "fancybox.js" %>
app/views/home/index.html.erb
<script type="text/javascript" src="/javascripts/html5shiv.js"></script>
<script type="text/javascript" src="/javascripts/fancybox.js"></script>
Error I get:
Started GET "/js/jquery.fancybox.js" for 127.0.0.1 at 2014-05-14 17:17:33 +0530
ActionController::RoutingError (No route matches [GET] "/js/jquery.fancybox.js"):
Updated Error -
Started GET "/assets/html5shiv.js" for 127.0.0.1 at 2014-05-14 17:17:33 +0530
Served asset /html5shiv.js - 304 Not Modified (0ms)
[2014-05-14 17:17:33] WARN Could not determine content-length of response body. Set content-length of the response or set Response#chunked = true
Any suggestion or pointers are most welcome . More details will be provided on asking .Thanks in advance , hoping to get it solved :)
First of all I'm not sure why you're including your scripts twice but I would recommend against it. Secondly, are you using the asset pipeline? If you are (and I strongly recommend that you do) simply add the following to your application.js file:
//= require html5shiv
//= require fancybox
And the correct files should be included in your concatenated javascript file.
Also, the error you're receiving doesn't seem to be connected to the code you posted (as you specify no links to assets living under /js), but I do believe that when you attempt to link to scripts living at /javascripts (as opposed to assets/javascripts) you might get a routing error like the one you posted.
So, remove the references to your scripts and simply add them to your manifest (application.js) and you should be fine.