I am trying to basically ignore the case sensitivity for my db2 sql select * query, so that I can populate the products to my catalogue page. Ex. If I type in my search bar 'squeege', I want the item 'Squeege' to populate, even if there is a difference in Upper/lower case. What is the best way to do this, based on the code I have below?
var searchProduct = "select * from LISTOFPRODUCTS where ITEM LIKE '%" + searchValue + "%'"
Thanks in advance for the help :)
I think this could work:
var searchProduct = "select * from LISTOFPRODUCTS where UPPER(ITEM) LIKE UPPER('%" + searchValue + "%'")
Also the same with LOWER()
Note that the trick is parse both values to UPPER() or LOWER() to match them.
You can use the function LOWER().
For example:
var searchProduct = "select * from LISTOFPRODUCTS where LOWER(ITEM) LIKE '%" + searchValue + "%'"
You can also consider using REGEXP_LIKE which has a case-insensitive option i
Related
Usually we will use SQL queries like below, we will pass params with predifined number $1
queryRunner.query('SELECT * FROM sample_data WHERE code IN ($1)', ['1'])
But I want to pass multiple params without predifined $1. Any way to resolve this?
queryRunner.query('SELECT * FROM sample_data WHERE code IN ($$)', ['1','2','3'])
One approach dynamically builds the IN clause based on the expected number of parameters. Consider:
var params = ['1','2','3'];
var inClause = '?' + ', ?'.repeat(params.length - 1);
var sql = 'SELECT * FROM sample_data WHERE code IN (' + inClause + ')';
console.log(sql);
Once we have a statement with the right number of placeholders, we can simply bind the collection or array with no trouble.
sql query does not accept array as value when it is used in a placeholder, It only returns one result even though result is greater than 1. Not using a placeholder and withouting escaping it works perfectly returns the right amount of results.
//works
SELECT * FROM users WHERE userId IN (" + followerIds.join() + ");";
//does not work
SELECT * FROM users WHERE userId IN (?);";
con.query(queryFollowerstTable, [followeringIsd.join()],function(err,result)..
All I had to do was parse followerIds.join() to an int and It worked.
followerIdsParsed = followerIds.join().split(',').map(Number);
followingIdsParsed = followingIds.join().split(',').map(Number);
var queryFollowerstTable = "SELECT * FROM users WHERE userId IN (?); SELECT *
FROM users WHERE userId IN (?);";
con.query(queryFollowerstTable, [followerIdsParsed, followingIdsParsed],
function(err, result) {..
Change
con.query(queryFollowerstTable, [followeringIds.join()],function(err,result)
to
con.query(queryFollowerstTable, followeringIds.join(),function(err,result)
In your original example:
SELECT * FROM users WHERE userId IN (" + followerIds.join() + ");";
You are passing in a string not an array
I have a query like this.
SELECT * FROM player_details where name in ('messi','neymar','suarez','alves')
I want to execute this query in titanium.
I tried like this
var in = ['messi','neymar','suarez','alves'];
db.execute('SELECT * FROM player_details where name in ?',in);
But above code producing error.
How can i add IN and NOT IN condition in sqlite in titanium ?
A single parameter ? replaces a single expression.
When you have four values, you need four parameters:
db.execute('SELECT * FROM player_details where name in (?,?,?,?)', in);
If the length of the array is dynamic try something like this:
var params = ["messi", "neymar", "suarez", "alves"],
qMarks = new Array(params.length).join("?,") + "?";
db.execute("SELECT * FROM player_details WHERE name in (" + qMarks + ");", params);
How do escape a MySQL LIKE statement in node-mysql?
Something along the lines of
"SELECT * FROM card WHERE name LIKE '%" + connection.escape(req.body.search) + "%'"
Results in
'SELECT * FROM card WHERE name LIKE \'%\'hello\'%\''
Which is a syntax error. If I use the alternative syntax of
connection.query("SELECT * FROM card WHERE name LIKE '%?%'", req.body.search, function () {});
Results in a similar syntax error. I've also tried
connection.query("SELECT * FROM card WHERE name LIKE ?", '%' + req.body.search + '%', function () {});
Which just ends up escaping the '%' sign.
Not sure why it's escaping the % in your last example, because that works fine for me:
// lifted from my code:
var value = 'ee20e966289cd7';
connection.query('SELECT * from django_session where session_key like ?', '%' + value + '%', ...)
// Result:
[ { session_key: '713ee20e966289cd71b936084a1e613e', ... } ]
When I turn on debugging in the driver (pass debug:true as argument to mysql.createConnection), it doesn't escape the percent sign:
{ command: 3,
sql: 'SELECT * from django_session where session_key like \'%ee20e966289cd7%\'' }
(it does escape the single quote, but that's for display purposes only)
(using mysql#2.0.0-alpha8)
i've had success with something like
"SELECT * FROM card WHERE name LIKE " + connection.escape('%'+req.body.search+'%')
How about
mysql.format("SELECT * FROM card WHERE name LIKE CONCAT('%', ?, '%')", req.body.search)
?
you can always do
variable = '%${variable}%'
"SELECT * FROM 'table' WHERE ('foo' LIKE ?);",
[variable], callback =>
I had the same problem and solved it like this:
function search(searchTerm) {
let replacement = `'%${searchTerm}%'`;
let sqlStatement = `SELECT * from clients where firstName LIKE ${replacement}`;
const [rows, fields, error] = connection.query(sqlStatement);
return rows;
}
Simple and easy way:
`SELECT * FROM card WHERE name LIKE ` + connection.escape(`%${req.body.search}%`)
I need to use an array of elements in query in jQuery. My query is:
"SELECT * FROM `projects` WHERE `Tags` LIKE CONCAT('%', ',', ('" + id + "'), ',', '%')"
Where id is an dynamic array, so I basically need:
"SELECT * FROM `projects` WHERE `Tags` LIKE CONCAT('%', ',', ('" + id[0] + "'), ',', '%') **OR LIKE id[1] OR LIKE id[2]**..."
if I'll use a forEach loop, it will return rows depending only on one of the elements in array, it is not support Like .. Or Like .. logic
var idArr = id.split(",");
idArr.forEach(function (id) {
_runQuery("SELECT * FROM `projects` WHERE `Tags` LIKE CONCAT('%', ',', '" + id + "', ',', '%')", function (rows) {....}
Given an array
var id = [1,2,3,4,5];
Try this
" WHERE tags LIKE '%"+ id.join("%' OR tags LIKE '%")+'%');
See it here: http://jsfiddle.net/XzXnf/
The simplest answer to your question is: Tags should probably be a separate table, then you would have:
"SELECT * from projects as p join tags as t on t.project_id = p.id where t.tag in (id[0], id[1], id[2]....)"
Of course, you can generate the required id string via a join easily enough (id.join(", ") will probably do it.
Alternatively, as #codingbiz points out, you can use a more complex id.join() call to expand the required OR's, but there are limits to that approach, and this is about as complex a query as you can reasonably make before normalising starts to look like a really good idea.