My data looks like:
PHARMACY {
Name: "Walter",
City: "London"
UserQuestion: [
{
text: "BlaBlaBla",
type: "Prescription"
},
{
text: "BlaBlaBla",
type: "Medicine request"
},
{
text: "BlaBlaBla",
type: "Prescription"
}
]
}
I have to remove from the Pharmacy Walter only the Questions regarding the "Prescription type" between the several questions, so i have to logically remove UserQuestion[0] and UserQuestion[2] .
I tried this code
db.pharmacy.update({Name:"Walter"}, {$unset: {type:"Prescription"}} , {multi: true});
but doesn't work, so I tried with the remove method
db.pharmacy.remove({$and: [{Name:"Walter"}, {"UserQuestion.type":"Prescription} ] } );
I hope my problem is clear, Thanks you.
You need arrayFilters
Try this query:
db.collection.update({
"Name": "Walter"
},
{
"$unset": {
"UserQuestions.$[af].type": ""
}
},
{
"arrayFilters": [
{
"af.type": "Prescription"
}
],
"multi": true
})
This query first find the element that match the name. After that, delete the field type using $unset for every element that match the arrayFilter. And this filter is set just below. We eant those element that .type is Prescription.
Example here
Edit to explain why $operator doesn't works:
Note that using position operator $ the query will not work because, as is explained in the documentation this operator return only the first element that matches the query. And you want to update every element into array that matches, not only the first.
Example that doesn't work here
Note how only one object remove the field type.
What is the output you got with
db.pharmacy.update({Name:"Walter"}, {$unset: {type:"Prescription"}} , {multi: true});
Were there any matches? My guess is there were matches but no updates.
Try this?
db.pharmacy.update({"Name":"Walter"}, {$unset: {"UserQuestion.type":"Prescription"}} , {multi: true});
db.pharmacy.find({"UserQuestion.type":"Prescription"},{Name":1});
Related
If I have this schema...
person = {
name : String,
favoriteFoods : Array
}
... where the favoriteFoods array is populated with strings. How can I find all persons that have "sushi" as their favorite food using mongoose?
I was hoping for something along the lines of:
PersonModel.find({ favoriteFoods : { $contains : "sushi" }, function(...) {...});
(I know that there is no $contains in mongodb, just explaining what I was expecting to find before knowing the solution)
As favouriteFoods is a simple array of strings, you can just query that field directly:
PersonModel.find({ favouriteFoods: "sushi" }, ...); // favouriteFoods contains "sushi"
But I'd also recommend making the string array explicit in your schema:
person = {
name : String,
favouriteFoods : [String]
}
The relevant documentation can be found here: https://docs.mongodb.com/manual/tutorial/query-arrays/
There is no $contains operator in mongodb.
You can use the answer from JohnnyHK as that works. The closest analogy to contains that mongo has is $in, using this your query would look like:
PersonModel.find({ favouriteFoods: { "$in" : ["sushi"]} }, ...);
I feel like $all would be more appropriate in this situation. If you are looking for person that is into sushi you do :
PersonModel.find({ favoriteFood : { $all : ["sushi"] }, ...})
As you might want to filter more your search, like so :
PersonModel.find({ favoriteFood : { $all : ["sushi", "bananas"] }, ...})
$in is like OR and $all like AND. Check this : https://docs.mongodb.com/manual/reference/operator/query/all/
In case that the array contains objects for example if favouriteFoods is an array of objects of the following:
{
name: 'Sushi',
type: 'Japanese'
}
you can use the following query:
PersonModel.find({"favouriteFoods.name": "Sushi"});
In case you need to find documents which contain NULL elements inside an array of sub-documents, I've found this query which works pretty well:
db.collection.find({"keyWithArray":{$elemMatch:{"$in":[null], "$exists":true}}})
This query is taken from this post: MongoDb query array with null values
It was a great find and it works much better than my own initial and wrong version (which turned out to work fine only for arrays with one element):
.find({
'MyArrayOfSubDocuments': { $not: { $size: 0 } },
'MyArrayOfSubDocuments._id': { $exists: false }
})
Incase of lookup_food_array is array.
match_stage["favoriteFoods"] = {'$elemMatch': {'$in': lookup_food_array}}
Incase of lookup_food_array is string.
match_stage["favoriteFoods"] = {'$elemMatch': lookup_food_string}
Though agree with find() is most effective in your usecase. Still there is $match of aggregation framework, to ease the query of a big number of entries and generate a low number of results that hold value to you especially for grouping and creating new files.
PersonModel.aggregate([
{
"$match": {
$and : [{ 'favouriteFoods' : { $exists: true, $in: [ 'sushi']}}, ........ ] }
},
{ $project : {"_id": 0, "name" : 1} }
]);
There are some ways to achieve this. First one is by $elemMatch operator:
const docs = await Documents.find({category: { $elemMatch: {$eq: 'yourCategory'} }});
// you may need to convert 'yourCategory' to ObjectId
Second one is by $in or $all operators:
const docs = await Documents.find({category: { $in: [yourCategory] }});
or
const docs = await Documents.find({category: { $all: [yourCategory] }});
// you can give more categories with these two approaches
//and again you may need to convert yourCategory to ObjectId
$in is like OR and $all like AND. For further details check this link : https://docs.mongodb.com/manual/reference/operator/query/all/
Third one is by aggregate() function:
const docs = await Documents.aggregate([
{ $unwind: '$category' },
{ $match: { 'category': mongoose.Types.ObjectId(yourCategory) } }
]};
with aggregate() you get only one category id in your category array.
I get this code snippets from my projects where I had to find docs with specific category/categories, so you can easily customize it according to your needs.
For Loopback3 all the examples given did not work for me, or as fast as using REST API anyway. But it helped me to figure out the exact answer I needed.
{"where":{"arrayAttribute":{ "all" :[String]}}}
In case You are searching in an Array of objects, you can use $elemMatch. For example:
PersonModel.find({ favoriteFoods : { $elemMatch: { name: "sushiOrAnytthing" }}});
With populate & $in this code will be useful.
ServiceCategory.find().populate({
path: "services",
match: { zipCodes: {$in: "10400"}},
populate: [
{
path: "offers",
},
],
});
If you'd want to use something like a "contains" operator through javascript, you can always use a Regular expression for that...
eg.
Say you want to retrieve a customer having "Bartolomew" as name
async function getBartolomew() {
const custStartWith_Bart = await Customers.find({name: /^Bart/ }); // Starts with Bart
const custEndWith_lomew = await Customers.find({name: /lomew$/ }); // Ends with lomew
const custContains_rtol = await Customers.find({name: /.*rtol.*/ }); // Contains rtol
console.log(custStartWith_Bart);
console.log(custEndWith_lomew);
console.log(custContains_rtol);
}
I know this topic is old, but for future people who could wonder the same question, another incredibly inefficient solution could be to do:
PersonModel.find({$where : 'this.favouriteFoods.indexOf("sushi") != -1'});
This avoids all optimisations by MongoDB so do not use in production code.
I've a collection of countries with country calling code in the country object. How can I find a country using calling code with a mobile number?
const countries = [
{
name: 'UAE',
callingCode: 971
},
{
name: 'USA',
callingCode: 1
},
{
name: 'UK',
callingCode: 44
}
];
const number = '971524500000'; // Input
How can I find country for the given mobile using regex in mongoose javascript;
[https://en.wikipedia.org/wiki/List_of_country_calling_codes][1]
Take a look at the link above on country calling codes, and specifically see the section "Tree List".
One solution would be to implement a schema in Mongo based on this tree in order to decode the country codes.
So, a table could be created to store Mongo documents containing a field "1x" "2x" "21x" etc (the Y axis in the Tree List table).
Each of these documents could contain an array of sub-documents from x=0 to x=9 (the x axis in the Tree List table). The sub-document can contain the country name/code you are looking for. You can use a direct index into the array in the Mongo document for an efficient lookup.
I think you'll find this to be a pretty efficient implementation and should cover all the bases.
If you can restructure your array to an object this would be the fastest
const countries =
{
971: 'UAE',
1: 'USA',
44: 'UK',
}
;
var code = 44;
console.log(countries[code]);
const countries = [
{
name: 'UAE',
callingCode: 971
},
{
name: 'USA',
callingCode: 1
},
{
name: 'UK',
callingCode: 44
}
];
var myFound =countries.filter(myFunc.bind(this,44));
function myFunc(code,element) {
if(element.callingCode == code){
return element;
}
}
console.log(myFound);
On MongoDB v 4.2 - you can use $let & $regexFind to do this :
db.collection.aggregate([
{
$match: {
$expr: {
$eq: [
{
$let: {
vars: {
value: {
$regexFind: {
input: "971524500000", // pass in as string
regex: { $toString: "$callingCode" }
}
}
},
in: "$$value.idx",
}
},
0
]
}
}
}
]);
Test : MongoDB-Playground
Explanation :
General Use-case :
In general regex searches - Will have an input which will be sub-string of actual string, Ex.:-
Actual string in DB : 'We can do it in mongo'
Input : mongo (/mongo/ - will work)
Your Use-case :
From above case as mongo exists in actual string/value of db field then you can get that document, But your case is different :
Actual string in DB : mongo
Input : 'We can do it in mongo'
This doesn't work that way, So using normal /We can do it in mongo/ isn't going help you here (Also doing few tricks with regex). So we need to make a trick to $regexFind operator. Unlike mongo documentation we need take 971524500000 into input field & regex as string value of callingCode field which is vice-versa to what's given in documentation.
So once we do that, We would get something like below :
{
"match" : "971", /** value of callingCode field */
"idx" : 0, /** Index of `971` in '971524500000' */
"captures" : []
},{
"match" : "1",
"idx" : 2,
"captures" : []
},
null /** 3rd doc no match */
As country code has to be at first of given number we need docs where "idx" : 0 - So we're using $let to get index of returned object & checking against 0 & eventually getting respective docs using $match.
Note :
There is something you need to look into, Just in case if you've docs like below :
{
"_id": ObjectId("5e8f67091aa1cc3d2158ade1"),
"name": "USA",
"callingCode": 1.0
},
{
"_id": ObjectId("5e8f67091aa1cc3d2158ade3"),
"name": "somecountry",
"callingCode": 197.0
}
& input is 1971524500000, then this query will bring both docs in result. This will be the case you need to check on. Anyhow I would suggest to try this query, rather than getting all documents for collection to the code & extract required o/p this might be better to do.
So I have a nested array of objects in my MongoDB document and I would like to add a new object to the array only if a certain field (in this case, eventId) is unique. My question is very similar to this post, only I cannot seem to get that solution to work in my case.
Here is what the documents (UserModel) look like:
{
"portal" : {
"events" : [
{
"important" : false,
"completed" : false,
"_id" : ObjectId("5c0c2a93bb49c91ef8de0b21"),
"eventId" : "5bec4a7361853025400ee9e9",
"user_notes" : "My event note"
},
...and so on
]
}
}
And here is my (so far unsuccessful) Mongoose operation:
UserModel.findByIdAndUpdate(
userId,
{ "portal.events.eventId": { $ne: req.body.eventId } },
{ $addToSet: { "portal.events": req.body } },
{ new: true }
);
Basically I am trying to use '$ne' to check if the field is unique, and then '$addToSet' (or '$push', I believe they are functionally equivalent in this case) to add the new object.
Could anyone point me in the right direction?
Cheers,
Gabe
If you look into the documentation on your method you will see that the parameters passed are not in the proper order.
findByIdAndUpdate(id, update, options, callback)
I would use update instead and have your id and portal.events.eventId": { $ne: req.body.eventId } part of the initial filter followed by $addToSet: { "portal.events": req.body }
Something among these lines:
UserModel.update(
{
"_id": mongoose.Types.ObjectId(userId),
"portal.events.eventId": { $ne: req.body.eventId }
},
{ $addToSet: { "portal.events": req.body } },
{ new: true }
);
You need to include your eventId check into condition part of your query. Because you're usig findByIdAndUpdate you can only pass single value matched against _id as a condition. Therefore you have to use findOneAndUpdate to specify custom filtering condition, try:
UserModel.findOneAndUpdate(
{ _id: userId, "portal.events.eventId": { $ne: req.body.eventId } },
{ $addToSet: { "portal.events": req.body } },
{ new: true }
);
I'm trying to achieve a "getOrCreate" behavior using "findAndModify".
I'm working in nodejs using the native driver.
I have:
var matches = db.collection("matches");
matches.findAndModify({
//query
users: {
$all: [ userA_id, userB_id ]
},
lang: lang,
category_id: category_id
},
[[ "_id", "asc"]], //order
{
$setOnInsert: {
users: [userA_id, userB_id],
category_id: category_id,
lang: lang,
status: 0
}
},
{
new:true,
upsert:true
}, function(err, doc){
//Do something with doc
});
What i was trying to do is:
"Find specific match with specified users, lang and category... if not found, insert a new one with specified data"
Mongo is throwing this error:
Error getting/creating match { [MongoError: exception: cannot infer query fields to set, path 'users' is matched twice]
name: 'MongoError',
message: 'exception: cannot infer query fields to set, path \'users\' is matched twice',
errmsg: 'exception: cannot infer query fields to set, path \'users\' is matched twice',
code: 54,
ok: 0 }
Is there a way to make it work?
It's impossible?
Thank you :)
It's not the "prettiest" way to handle this, but current restrictions on the selection operators mean you would need to use a JavaScript expression with $where.
Substituting your vars for values for ease of example:
matches.findAndModify(
{
"$where": function() {
var match = [1,2];
return this.users.filter(function(el) {
return match.indexOf(el) != -1;
}).length >= 2;
},
"lang": "en",
"category_id": 1
},
[],
{
"$setOnInsert": {
"users": [1,2],
"lang": "en",
"category_id": 1
}
},
{
"new": true,
"upsert": true
},
function(err,doc) {
// do something useful here
}
);
As you might suspect, the "culprit" here is the positional $ operator, even though your operation does not make use of it.
And the problem specifically is because of $all which is looking for the possible match at "two" positions in the array. In the event that a "positional" operator was required, the engine cannot work out ( presently ) which position to present. The position should arguably be the "first" match being consistent with other operations, but it is not currently working like that.
Replacing the logic with a JavaScript expression circumvents this as the JavaScript logic cannot return a matched position anyway. That makes the expression valid, and you can then either "create" and array with the two elements in a new document or retrieve the document that contains "both" those elements as well as the other query conditions.
P.S Little bit worried about your "sort" here. You may have added it because it is "mandatory" to the method, however if you do possibly expect this to match "more than one" document and need "sort" to work out which one to get then your logic is slightly flawed.
When doing this to "find or create" then you really need to specifiy "all" of the "unique" key constraints in your query. If you don't then you are likely to run into duplicate key errors down the track.
Sort can in fact be an empty array if you do not actually need to "pick" a result from many.
Just something to keep in mind.
I've been looking at this documentation, and I tried to implement it here:
customers.find({'name':tenantName,'scripts.author':author},'scripts',function(err,data2){
But this doesn't find what I want it to find. and I get back every element of scripts whether scripts.author matches or not.
What am I doing wrong?
My data looks like this
{
name: "something"
scripts:[
{author:"something", data:"data"},
{author:"something else" data:"data2"},
{author:"something", data:"data3"}
]
}
I'd like to get all the scripts where author matches what I give it
There are a few things wrong here for you to understand about matching in queries like this. First of all, what your were trying to do was this:
customer.find(
{ "name":tenantName, "scripts.author": author },
{ "scripts.$" },
function(err,data2) {
// work here
})
And that would use the positional $ operator to match the element. But the problem here is that will only match the first element of the array. This is covered in the documentation. The result will be like this:
{ "scripts" : [ { "author" : "something", "data" : "data" } ] }
If you need to match muliple elements, then you need to use the aggregate function in order to filter the array contents:
customer.aggregate([
// Match just the documents you want
{ "$match": { "name": tenantName, "scripts.author": author } },
// Unwind the array
{ "$unwind": "$scripts" },
// Match to filter just the array elements
{ "$match": { "scripts.author": author } },
// Push back the array elements
{ "$group": {
"_id": "$_id",
"name": { "$first": "$name" },
"scripts": { "$push": "$scripts" }
}}
],
function(err,result) {
})
And the results there will be the two elements that match "something" as the author.
Why all of this? Well there is the limitation on what can be done with projection that was mentioned. But the main reason is that you are not matching elements in the array, but you are matching the document that "contains" the matching elements in the array.
So if you really want to filter the results, this is how you do it.