I figured out, after loooooooong research how to get my date into decimal years. Now, what I want to do is figure out is how to convert decimal years for example 2020.39123 into something like 11/24/2020.
My preferred output format is mm/dd/yyyy. Not the long Date() output of Wed Sep 02 2020 15:24 GMT-0300 (Time zone name).
My code so far is:
function myFunction() {
var d = Date.parse("March 21, 2012");
var minutes = 1000 * 60;
var hours = minutes * 60;
var days = hours * 24;
var years = days * 365;
var y = Math.round(d / years);
document.getElementById("demo").innerHTML = y;
}
Get the month of your date add before the string "0" and take the last 2 chars to get the month as 2-digit-value. Don't forget to add 1 for month because JS counts 0-11. Same formatting procedure for the date. Just add at the end the fullyear.
function myFunction() {
let d = new Date("March 21, 2012");
let date = ('0' + (d.getMonth() +1)).slice(-2) + '/' + ('0' + d.getDate()).slice(-2) + '/' + d.getFullYear();
document.getElementById("demo").innerHTML = date;
}
myFunction();
<div id='demo'></div>
The algorithm in the OP is simplistic and doesn't account for days not being 24 hours long where daylight saving is observed. Also, not all years are 365 days long.
A more accurate algorithm would consider the actual number of milliseconds in a year and create a fraction from that. If the resolution is to be whole days, then the values should be rounded to the next whole day and 3 decimal places is sufficient. Otherwise, ECMAScript numbers don't have sufficient precision to preserve the value to millisecond accuracy and the decimal year won't be converted back to a date accurately (a variance of 1 ms can change the date to a different day).
E.g
// Conversion of a Date to decimal year
// Resolution is to day only
function toDecimalYear(date) {
// Copy date so don't affect original and set to start of day
let d = new Date(date);
d.setHours(0,0,0,0);
let year = d.getFullYear();
let yearStart = new Date(year, 0, 1);
let dayNum = Math.round((d - yearStart) / 8.64e7);
let daysInYear = Math.round((new Date(year + 1, 0, 1) - yearStart) / 8.64e7);
return +(year + dayNum / daysInYear).toFixed(3);
}
// Convert decimal year to Date
// Resolution is to nearest whole day
function fromDecimalYear(num) {
let year = parseInt(num);
let yearStart = new Date(year, 0, 1);
let daysInYear = Math.round((new Date(year + 1, 0, 1) - yearStart) / 8.64e7);
let dayNum = Math.round((num - year) * daysInYear)
yearStart.setDate(1 + dayNum);
return yearStart;
}
// Formatter
let f = date => date.toLocaleString('default',{
year: 'numeric',
month: 'short',
day: 'numeric',
hour: '2-digit',
hour12: false,
minute: '2-digit',
second: '2-digit',
millisecond: 'numeric'
});
// OP example
console.log('2020.39123 => ' + f(fromDecimalYear(2020.39123)));
// Current date - set to start of day
let d = new Date();
d.setHours(0,0,0,0);
console.log(f(d) + ' = ' + toDecimalYear(d));
// Other test dates
[new Date(2012, 0, 1), // 01 Jan 2012
new Date(2012, 2, 12), // 12 Mar 2012
new Date(2012, 11, 31) // 31 Dec 2012
].forEach(date => {
let dy = toDecimalYear(date);
console.log(
'Start date : ' + f(date)
+ '\nAs decimal years: ' + dy
+ '\nBack to date : ' + f(fromDecimalYear(dy))
)
});
I think a better way to represent dates using years is to use year.dayNumber rather than fractional year. So 1 Jan 2020 is 2020.001, 1 Feb is 2020.032, etc. But then year month day is the same number of characters: 20200101, 20200201, etc.
I have some code, that is doing pretty much all i need it to do. Its calculating 3 days in the future, excluding dates, and then displaying my "estimated dispatch date"
The date, however displays in full date and time, instead of just date.
Day Month Date Year 12:02:57 GMT+0100 (British Summer Time)
Can anyone help with the code below, so that it excludes local time and only displays the future date, excluding weekend, DD/MM/YYYY or, in the below format;
Monday 20th June
Thanks in advance!
function addDates(startDate,noOfDaysToAdd){
var count = 0;
while(count < noOfDaysToAdd){
endDate = new Date(startDate.setDate(startDate.getDate() + 1));
if(endDate.getDay() != 0 && endDate.getDay() != 6){
//Date.getDay() gives weekday starting from 0(Sunday) to 6(Saturday)
count++;
}
}
return startDate;
}
var today = new Date();
var daysToAdd = 3;
document.write ('Estimated Dispatch Date: ' + addDates(today,daysToAdd));
You can use the toDateString method to display just the date portion of your Date object, but you will need to use a few other methods for full control over the format of your date string...
You can display just the date, month and year parts of your local date and time with a few extra lines of code using the getDate, getMonth, and getFullYear methods to help with the formatting. You could try passing specific formatting parameters to toLocaleString, but this may display different results in different browsers. For example, the code below outputs a date in the format dd/mm/yyyy in Chrome but that output is not guaranteed across browsers.
new Date().toLocaleString('en-GB', {year: 'numeric', month: 'numeric', day: 'numeric'})
Not sure I am following how you want to handle weekend dates, so the below handles the date formatting that you want in the formatDate function separately from the addDays function where it just handles weekend dates by rolling the date forward to a Monday if the initially calculated date lands on a Saturday or Sunday.
// format input date to dd/mm/yyyy
const formatDate = (date) => {
const d = date.getDate(); // day of the month
const m = date.getMonth(); // month index from 0 (Jan) to 11 (Dec)
const yyyy = date.getFullYear(); // 4 digit year
const dd = (d < 10 ? '0' : '') + d; // format date to 2 digit
const mm = (m + 1 < 10 ? '0' : '') + (m + 1); // convert index to month and format 2 digit
return `${dd}/${mm}/${yyyy}`;
};
// add input days to today and adjust for weekend output
const addDays = (today, days) => {
const now = today.getTime() // now in UTC milliseconds
const ms = 24 * 60 * 60000; // milliseconds in one day
const date = new Date((days * ms) + now); // today plus input days
const day = date.getDay(); // weekday index from 0 (Sun) to 6 (Sat)
// adjust weekend results to next weekday
if (day === 0 || day === 6) {
let adj = day === 0 ? 1 : 2;
return new Date(((days + adj) * ms) + now);
}
return date;
};
document.write('Estimated Dispatch Date: ' + formatDate(addDays(new Date(), 3)));
i would like to ask, if someone know to to make in JS or PHP time of date.
Or how long we're together, like 70 days or 2 month and some days, and all day add 1 more day. I have something whats work, but on begging of that time is - .
I spent a lot time with making something what should work. But nothing.
There is that code with that -
<script charset="UTF-8">
function daysTill() {
var day= 8
var month= 12
var year= 2016
var event= "relationship with my ♥"
var end = "days of"
var daystocount=new Date(year, month -1, day)
today=new Date()
if (today.getMonth()==month && today.getDate()>day)
daystocount.setFullYear(daystocount.getFullYear())
var oneday=1000*60*60*24
var write = (Math.ceil((daystocount.getTime()-today.getTime())/(oneday)))
document.write('<strong>'+write +'</strong> '+end+' '+event)
}
daysTill();
</script>
if someone know, please help me. Thanks ♥
The getTime() method returns the time in milliseconds so to convert it to days you divide that by 86400000 (1000 for seconds * 60 for minutes * 60 for hours * 24 for days):
var relationship = new Date("2016/12/08");
var today = new Date();
var days = Math.ceil((today.getTime() - relationship.getTime()) / 86400000);
document.write(days + " days have pass since the start of the relationship.");
Try to use "JavaScript date maths"
// new Date(year, month (0-11!), day, hours, minutes, seconds, milliseconds);
var dateFuture = new Date(2017, 3, 1, 9, 0, 0, 0);
var dateLongAgo = new Date(2001, 8, 11, 8, 46, 0, 0);
var dateNow = new Date();
//86400000 millis per day
//floor --> all unter a full day shall be 'no day'
var daysSince = Math.floor((dateNow-dateLongAgo)/86400000);
var daysUntil = Math.floor((dateFuture-dateNow)/86400000);
console.log("long ago\t", dateLongAgo);
console.log("now is\t\t",dateNow);
console.log("then\t\t",dateFuture);
console.log("days since\t",daysSince);
console.log("days until\t", daysUntil);
If you don't mind using external libraries, Carbon is a nice tool extending DateTime
http://carbon.nesbot.com/docs/
It returns many kinds very nicely formatted dates -- months, days, hours etc included.
Want to improve this post? Provide detailed answers to this question, including citations and an explanation of why your answer is correct. Answers without enough detail may be edited or deleted.
Is there an easy way of taking a olain JavaScript Date (e.g. today) and going back X days?
So, for example, if I want to calculate the date 5 days before today.
Try something like this:
var d = new Date();
d.setDate(d.getDate()-5);
Note that this modifies the date object and returns the time value of the updated date.
var d = new Date();
document.write('Today is: ' + d.toLocaleString());
d.setDate(d.getDate() - 5);
document.write('<br>5 days ago was: ' + d.toLocaleString());
var dateOffset = (24*60*60*1000) * 5; //5 days
var myDate = new Date();
myDate.setTime(myDate.getTime() - dateOffset);
If you're performing lots of headachy date manipulation throughout your web application, DateJS will make your life much easier:
http://simonwillison.net/2007/Dec/3/datejs/
It goes something like this:
var d = new Date(); // today!
var x = 5; // go back 5 days!
d.setDate(d.getDate() - x);
I noticed that the getDays+ X doesn't work over day/month boundaries. Using getTime works as long as your date is not before 1970.
var todayDate = new Date(), weekDate = new Date();
weekDate.setTime(todayDate.getTime()-(7*24*3600000));
If you want it all on one line instead.
5 days from today
//past
var fiveDaysAgo = new Date(new Date().setDate(new Date().getDate() - 5));
//future
var fiveDaysInTheFuture = new Date(new Date().setDate(new Date().getDate() + 5));
5 days from a specific date
var pastDate = new Date('2019-12-12T00:00:00');
//past
var fiveDaysAgo = new Date(new Date().setDate(pastDate.getDate() - 5));
//future
var fiveDaysInTheFuture = new Date(new Date().setDate(pastDate.getDate() + 5));
I wrote a function you can use.
function AddOrSubractDays(startingDate, number, add) {
if (add) {
return new Date(new Date().setDate(startingDate.getDate() + number));
} else {
return new Date(new Date().setDate(startingDate.getDate() - number));
}
}
console.log('Today : ' + new Date());
console.log('Future : ' + AddOrSubractDays(new Date(), 5, true));
console.log('Past : ' + AddOrSubractDays(new Date(), 5, false));
I find a problem with the getDate()/setDate() method is that it too easily turns everything into milliseconds, and the syntax is sometimes hard for me to follow.
Instead I like to work off the fact that 1 day = 86,400,000 milliseconds.
So, for your particular question:
today = new Date()
days = 86400000 //number of milliseconds in a day
fiveDaysAgo = new Date(today - (5*days))
Works like a charm.
I use this method all the time for doing rolling 30/60/365 day calculations.
You can easily extrapolate this to create units of time for months, years, etc.
get moment.js. All the cool kids use it. It has more formatting options, etc. Where
var n = 5;
var dateMnsFive = moment(<your date>).subtract(n , 'day');
Optional! Convert to JS Date obj for Angular binding.
var date = new Date(dateMnsFive.toISOString());
Optional! Format
var date = dateMnsFive.format("YYYY-MM-DD");
A few of the existing solutions were close, but not quite exactly what I wanted. This function works with both positive or negative values and handles boundary cases.
function addDays(date, days) {
return new Date(
date.getFullYear(),
date.getMonth(),
date.getDate() + days,
date.getHours(),
date.getMinutes(),
date.getSeconds(),
date.getMilliseconds()
);
}
Without using the second variable, you can replace 7 for with your back x days:
let d=new Date(new Date().getTime() - (7 * 24 * 60 * 60 * 1000))
I made this prototype for Date so that I could pass negative values to subtract days and positive values to add days.
if(!Date.prototype.adjustDate){
Date.prototype.adjustDate = function(days){
var date;
days = days || 0;
if(days === 0){
date = new Date( this.getTime() );
} else if(days > 0) {
date = new Date( this.getTime() );
date.setDate(date.getDate() + days);
} else {
date = new Date(
this.getFullYear(),
this.getMonth(),
this.getDate() - Math.abs(days),
this.getHours(),
this.getMinutes(),
this.getSeconds(),
this.getMilliseconds()
);
}
this.setTime(date.getTime());
return this;
};
}
So, to use it i can simply write:
var date_subtract = new Date().adjustDate(-4),
date_add = new Date().adjustDate(4);
I like doing the maths in milliseconds. So use Date.now()
var newDate = Date.now() + -5*24*3600*1000; // date 5 days ago in milliseconds
and if you like it formatted
new Date(newDate).toString(); // or .toUTCString or .toISOString ...
NOTE: Date.now() doesn't work in older browsers (eg IE8 I think). Polyfill here.
UPDATE June 2015
#socketpair pointed out my sloppiness. As s/he says "Some day in year have 23 hours, and some 25 due to timezone rules".
To expand on that, the answer above will have daylightsaving inaccuracies in the case where you want to calculate the LOCAL day 5 days ago in a timezone with daylightsaving changes and you
assume (wrongly) that Date.now() gives you the current LOCAL now time, or
use .toString() which returns the local date and therefore is incompatible with the Date.now() base date in UTC.
However, it works if you're doing your math all in UTC, eg
A. You want the UTC date 5 days ago from NOW (UTC)
var newDate = Date.now() + -5*24*3600*1000; // date 5 days ago in milliseconds UTC
new Date(newDate).toUTCString(); // or .toISOString(), BUT NOT toString
B. You start with a UTC base date other than "now", using Date.UTC()
newDate = new Date(Date.UTC(2015, 3, 1)).getTime() + -5*24*3600000;
new Date(newDate).toUTCString(); // or .toISOString BUT NOT toString
split your date into parts, then return a new Date with the adjusted values
function DateAdd(date, type, amount){
var y = date.getFullYear(),
m = date.getMonth(),
d = date.getDate();
if(type === 'y'){
y += amount;
};
if(type === 'm'){
m += amount;
};
if(type === 'd'){
d += amount;
};
return new Date(y, m, d);
}
Remember that the months are zero based, but the days are not. ie new Date(2009, 1, 1) == 01 February 2009, new Date(2009, 1, 0) == 31 January 2009;
Some people suggested using moment.js to make your life easier when handling dates in js. Time has passed since those answers and it is noteworthy, that the authors of moment.js now discourage its use. Mainly due to its size and lack of tree-shaking-support.
If you want to go the library route, use an alternative like Luxon. It is significantly smaller (because of its clever use of the Intl object and support for tree-shaking) and just as versatile as moment.js.
To go back 5 days from today in Luxon, you would do:
import { DateTime } from 'luxon'
DateTime.now().minus({ days: 5 });
function addDays (date, daysToAdd) {
var _24HoursInMilliseconds = 86400000;
return new Date(date.getTime() + daysToAdd * _24HoursInMilliseconds);
};
var now = new Date();
var yesterday = addDays(now, - 1);
var tomorrow = addDays(now, 1);
See the following code, subtract the days from the current date. Also, set the month according to substracted date.
var today = new Date();
var substract_no_of_days = 25;
today.setTime(today.getTime() - substract_no_of_days* 24 * 60 * 60 * 1000);
var substracted_date = (today.getMonth()+1) + "/" +today.getDate() + "/" + today.getFullYear();
alert(substracted_date);
I have created a function for date manipulation. you can add or subtract any number of days, hours, minutes.
function dateManipulation(date, days, hrs, mins, operator) {
date = new Date(date);
if (operator == "-") {
var durationInMs = (((24 * days) * 60) + (hrs * 60) + mins) * 60000;
var newDate = new Date(date.getTime() - durationInMs);
} else {
var durationInMs = (((24 * days) * 60) + (hrs * 60) + mins) * 60000;
var newDate = new Date(date.getTime() + durationInMs);
}
return newDate;
}
Now, call this function by passing parameters. For example, here is a function call for getting date before 3 days from today.
var today = new Date();
var newDate = dateManipulation(today, 3, 0, 0, "-");
Use MomentJS.
function getXDaysBeforeDate(referenceDate, x) {
return moment(referenceDate).subtract(x , 'day').format('MMMM Do YYYY, h:mm:ss a');
}
var yourDate = new Date(); // let's say today
var valueOfX = 7; // let's say 7 days before
console.log(getXDaysBeforeDate(yourDate, valueOfX));
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>
The top answers led to a bug in my code where on the first of the month it would set a future date in the current month. Here is what I did,
curDate = new Date(); // Took current date as an example
prvDate = new Date(0); // Date set to epoch 0
prvDate.setUTCMilliseconds((curDate - (5 * 24 * 60 * 60 * 1000))); //Set epoch time
I like the following because it is one line. Not perfect with DST changes but usually good enough for my needs.
var fiveDaysAgo = new Date(new Date() - (1000*60*60*24*5));
Using Modern JavaScript function syntax
const getDaysPastDate = (daysBefore, date = new Date) => new Date(date - (1000 * 60 * 60 * 24 * daysBefore));
console.log(getDaysPastDate(1)); // yesterday
A easy way to manage dates is use Moment.js
You can use add. Example
var startdate = "20.03.2014";
var new_date = moment(startdate, "DD.MM.YYYY");
new_date.add(5, 'days'); //Add 5 days to start date
alert(new_date);
Docs http://momentjs.com/docs/#/manipulating/add/
for me all the combinations worked fine with below code snipplet ,
the snippet is for Angular-2 implementation ,
if you need to add days , pass positive numberofDays , if you need to substract pass negative numberofDays
function addSubstractDays(date: Date, numberofDays: number): Date {
let d = new Date(date);
return new Date(
d.getFullYear(),
d.getMonth(),
(d.getDate() + numberofDays)
);
}
I get good mileage out of date.js:
http://www.datejs.com/
d = new Date();
d.add(-10).days(); // subtract 10 days
Nice!
Website includes this beauty:
Datejs doesn’t just parse strings, it slices them cleanly in two
If you want to both subtract a number of days and format your date in a human readable format, you should consider creating a custom DateHelper object that looks something like this :
var DateHelper = {
addDays : function(aDate, numberOfDays) {
aDate.setDate(aDate.getDate() + numberOfDays); // Add numberOfDays
return aDate; // Return the date
},
format : function format(date) {
return [
("0" + date.getDate()).slice(-2), // Get day and pad it with zeroes
("0" + (date.getMonth()+1)).slice(-2), // Get month and pad it with zeroes
date.getFullYear() // Get full year
].join('/'); // Glue the pieces together
}
}
// With this helper, you can now just use one line of readable code to :
// ---------------------------------------------------------------------
// 1. Get the current date
// 2. Subtract 5 days
// 3. Format it
// 4. Output it
// ---------------------------------------------------------------------
document.body.innerHTML = DateHelper.format(DateHelper.addDays(new Date(), -5));
(see also this Fiddle)
To calculate relative time stamps with a more precise difference than whole days, you can use Date.getTime() and Date.setTime() to work with integers representing the number of milliseconds since a certain epoch—namely, January 1, 1970. For example, if you want to know when it’s 17 hours after right now:
const msSinceEpoch = (new Date()).getTime();
const fortyEightHoursLater = new Date(msSinceEpoch + 48 * 60 * 60 * 1000).toLocaleString();
const fortyEightHoursEarlier = new Date(msSinceEpoch - 48 * 60 * 60 * 1000).toLocaleString();
const fiveDaysAgo = new Date(msSinceEpoch - 120 * 60 * 60 * 1000).toLocaleString();
console.log({msSinceEpoch, fortyEightHoursLater, fortyEightHoursEarlier, fiveDaysAgo})
reference
function daysSinceGivenDate (date) {
const dateInSeconds = Math.floor((new Date().valueOf() - date.valueOf()) / 1000);
const oneDayInSeconds = 86400;
return Math.floor(dateInSeconds / oneDayInSeconds); // casted to int
};
console.log(daysSinceGivenDate(new Date())); // 0
console.log(daysSinceGivenDate(new Date("January 1, 2022 03:24:00"))); // relative...
First arg is the date to start with and second is how mush day you want to increase or reduce to the date
example (1)- pass -1 to reduce date by one day
example (2)- pass 1 to increase date by one day
const EditDay = (date: Date, num: number): Date => {
return new Date(date.getTime() + num * 24 * 60 * 60 * 1000)
}
When setting the date, the date converts to milliseconds, so you need to convert it back to a date:
This method also take into consideration, new year change etc.
function addDays( date, days ) {
var dateInMs = date.setDate(date.getDate() - days);
return new Date(dateInMs);
}
var date_from = new Date();
var date_to = addDays( new Date(), parseInt(days) );
You can using Javascript.
var CurrDate = new Date(); // Current Date
var numberOfDays = 5;
var days = CurrDate.setDate(CurrDate.getDate() + numberOfDays);
alert(days); // It will print 5 days before today
For PHP,
$date = date('Y-m-d', strtotime("-5 days")); // it shows 5 days before today.
echo $date;
Hope it will help you.
I converted into millisecond and deducted days else month and year won't change and logical
var numberOfDays = 10;//number of days need to deducted or added
var date = "01-01-2018"// date need to change
var dt = new Date(parseInt(date.substring(6), 10), // Year
parseInt(date.substring(3,5), 10) - 1, // Month (0-11)
parseInt(date.substring(0,2), 10));
var new_dt = dt.setMilliseconds(dt.getMilliseconds() - numberOfDays*24*60*60*1000);
new_dt = new Date(new_dt);
var changed_date = new_dt.getDate()+"-"+(new_dt.getMonth()+1)+"-"+new_dt.getFullYear();
Hope helps