This question already has answers here:
Getting content between curly braces in JavaScript with regex
(5 answers)
Closed 2 years ago.
I need to match a specific regex syntax and split them so that we can match them to an equivalent value from a dictionary.
Input:
{Expr "string"}
{Expr "string"}{Expr}
Current code:
value.match(/\{.*\}$/g)
Desired Output:
[{Expr "string"}]
[{Expr "string"},{Expr}]
Use a non-greedy quantifier .*?. And don't use $, because that forces it to match all the way to the end of the string.
value = '{Expr "string"}{Expr}'
console.log(value.match(/\{.*?\}/g));
One option, assuming your version of JavaScript support it, would be to split the input on the following regex pattern:
(?<=\})(?=\{)
This says to split at each }{ junction between two terms.
var input = "{Expr \"string\"}{Expr}";
var parts = input.split(/(?<=\})(?=\{)/);
console.log(parts);
Related
This question already has answers here:
Regular expression to stop at first match
(9 answers)
Closed 7 months ago.
I am trying to perform this transformation to a string (using javascript):
Input:
[hello]{world}and[good]{night}
Output:
<span class="top">hello<span class="bottom">world</span></span>and<span class="top">good<span class="bottom">night</span></span>
To do that I am using the following regex:
text.replace(/\[(.*)\]\{(.*)\}/gim, "<span class='top'>$1<span class='bottom'>$2</span></span>")
It works correctly when only setting one occurrence of the pattern in a string [hello]{world}
But if I add a string with more than one, the regex matches the first [] and the last {} instead, and prints this:
<span class='top'>hello]{world}and[good<span class='bottom'>night</span></span>
How can I tell regex to match the first pattern and the second pattern instead of matching it as one bigger pattern?
Note that between the [] and {} I expect there to be no text. So [hello]world and good{night} should not be matched.
You need to put ? after .* to make the quantifier lazy, instead of greedy.
const text = '[hello]{world}and[good]{night}'
const result = text.replace(/\[(.*?)\]\{(.*?)\}/gim, "<span class='top'>$1<span class='bottom'>$2</span></span>")
console.log(result)
This question already has an answer here:
javascript regexp replace not working, but string replace works
(1 answer)
Closed 1 year ago.
Hello team I am new to JS so I am trying to use RegEx with replacing to take input from the user and replace it if it doesn't match the RegEx I have to be able to put 7 digits or 6 digits followed with one letter currently I am doing this
someID.replace('^(([0-9]{1,7})|([0-9]{1,6}[a-zA-Z]{1}))$')
I am not able to replace the current string with the RegEx expression if I enter
12345678900 it remain the same in that situation I need to be 1234567 after the replace or if I have 12345678asd to be 123456a. How can I achieve that by only replace function and a RegEx expresion
You need to use a different regex and a dirrent replace function.
You will also need to get rid of $ if you want to be able to successfully match the string, without worrying about how it ends.
const sampleIDs = [
"123456789000",
"123456abc",
];
sampleIDs.forEach(id => {
const clean = id.match(/^\d{6}[\d\D]/);
console.log(clean[0]);
});
This question already has answers here:
How do I do a case-insensitive string comparison?
(15 answers)
javascript includes() case insensitive
(11 answers)
Closed 2 years ago.
I'm using the following code to search sub string in a string
mystring.search(new RegExp(substring, 'i'))
Reason why I am using new RegExp is, I want to search case insensitive. However, when there is a string like
var mystring = '10" stick';
and I want to search 10", the code above does not return any result. It's clearly because of new RegExp and double quote. Is there any particular flag that needs to be passed in new RegExp? I googled a lot but couldn't find any solution. What am I missing?
search returns match position, maybe ur confused by this.
So, try this out,
const myString = '10" stick';
console.log(myString.match(new RegExp('10"', 'i'))[0])
console.log(myString.match(new RegExp('ick', 'i'))[0])
console.log(myString.match(new RegExp('asd"', 'i'))) // non-matching
It returns the match or null if theres non. AND it matches 10" in 10" stick
see String.prototype.search mdn
This question already has answers here:
Replace forward slash "/ " character in JavaScript string?
(9 answers)
Why this javascript regex doesn't work?
(1 answer)
Closed 4 years ago.
I have a string field 01/01/1986 and I am using replace method to replace all occurrence of / with -
var test= '01/01/1986';
test.replace('//g','-')
but it does't give desire result. Any pointer would be helpful.
You just have a couple issues: don't put the regex in quotes. That turns it into a string instead of a regex and looks for that literal string. Then use \/ to escape the /:
var test= '01/01/1986';
console.log(test.replace(/\//g,'-'))
A quick way is to use split and join.
var test= '01/01/1986';
var result = test.split('/').join('-');
console.log(result);
Note too that you need to save the result. The original string itself will never be modified.
This question already has answers here:
How do I replace an asterisk in Javascript using replace()?
(6 answers)
Closed 7 years ago.
I am trying to replace the same string *a*a consistently with *a.
Tried many variations of something like this, but none really worked:
s = s.replace( /\b*a*a\b/g, "*a");
So far running this leads to all xzy*a being replaced with xyz
* is a special regex character. If you want to match only an actual asterisk, then you have to escape it like this:
s = s.replace( /\*a\*a/g, "*a");
Working demo: http://jsfiddle.net/jfriend00/gvgshwyz/
An asterisk is a special regex character.
You just have to escape it like this: \*a in place of *a