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Passing an array of strings from JS to PHP

I have an array of strings in JS, and I want to send it to php (to be able to add it to db). This is my current code -> showing success message, but not showing the $_POST['array'] variable.
Keep in mind that that array I want to send has string values only and is called times
JS
function fetchDates(){
times = [];
var table = document.getElementById("timeScheduleBody");
var tableRows = table.getElementsByTagName("tr");
for(var j=0;j<tableRows.length;j++){
var tableCells = tableRows[j].getElementsByTagName("td");
for(var i = 0;i<tableCells.length;i++){
if(tableCells[i].getAttribute('class').includes("success")){
var arr = tableCells[i].getAttribute('value').split("-");
var date, hour, mins;
date = arr[0];
hour = arr[1];
mins = arr[2];
times.push(date);
times.push(hour);
times.push(mins);
}
}
}
window.alert(times);
//send array to PHP from jQuery
jQuery.ajax({
type: "post",
url: window.location.href,
data: {array:times},
success: function(){
alert("done");
}
});
}
PHP
<?php
if(isset($_POST['array'])){
$array = $_POST['array'];
echo $array[0];//just testing -> output: nothing
foreach($array as $d){
print '<script>window.alert($d);</script>';//also just to test -> output: nothing
}
}
?>

But you're not getting and showing the response of the ajax call, to see the response you have to get the response in the success function...
PHP (test.php - Create this file and put it in the same directory):
<?php
if(isset($_POST['array']))
print_r($_POST['array']);
?>
JQUERY:
$.ajax({
type: 'POST',
url: 'test.php',
data: { array: times },
success: function(response) {
alert(response);
}
});
You'll see the array content. You're sending the javascript array correctly, but if you want to see the response of the ajax call you have to get it in the success function and do something with it (alert it, add it to the DOM, etc.)

How to receive a data from the JSon method?

I have a method in my controller that submits some changes in the database after receiving a filename that being uploaded to the server. Also this method is getting the fileNameOrigin and fileNameUnique (to be downloaded for saving in the server folder)
public JsonResult Upload()
{
var upload = Request.Files[file];
string fileNameOrigin = System.IO.Path.GetFileName(upload.FileName);
string fileNameUnique = String.Format("{0}_" + fileNameOrigin,
DateTime.Now.ToString("yyyyMMddHHmmss"));
//there is more code that isn't needed in my case
return Json(fileNameOrigin, fileNameUnique);
}
So, here's the question - how to send and receive this data on the client side?
$('#uploadFile').on('change', function (e) {
e.preventDefault();
var files = document.getElementById('uploadFile').files;
if (files.length > 0) {
if (window.FormData !== undefined) {
var data = new FormData();
for (var x = 0; x < files.length; x++) {
data.append("file" + x, files[x]);
}
$.ajax({
type: "POST",
url: '#Url.Action("Upload", "ChatRooms")',
contentType: false,
processData: false,
data: data,
success: onSuccess, //here I need to receive data and do smth with it
error: onError
});
}
}
});

Create a anonymous object with the properties that are required and then pass that single object to the JSON method like:
var data = new {
FileNameOrigin = fileNameOrigin,
FileNameUnique = fileNameUnique
};
return Json(data);
In success callback of ajax, you can access it, for just to check it is working log it on console to see what server has returned like:
success: function(data) {
console.log(data);
},
you might also need to specify datatype in ajax call to json which dictates that JSON is expected from server to be returned in response to this ajax call:
dataType: "json"
Hope it helps!

AJAX Fileupload with jquery

I am currently trying to solve a problem.
I have several forms on a single page which get sent to the backend asynchronously via ajax.
Now some of them need to have a fileupload which doesnt break the process, so it alsoneeds to be handled asynchronously.
I am trying to figure it out like that :
// Allgemein Submit
$allgSubmit.click(function(){
event.preventDefault();
var gehrKundennummer = $('#gehrKundennummer').val();
var kundenklasse = $("input[type='radio'][name='kundenklasse']:checked").val();
var lkw12t = $('#lkw12t').val();
var lkw3t = $('#lkw3t').val();
var autobus = $('#autobus').val();
var firmenname1 = $('#firmenname1').val();
var firmenname2 = $('#firmenname2').val();
var uidnummer = $('#uidnummer').val();
var peselregon = $('#peselregon').val();
var firmenart = $('#firmenart option:selected').val();
var strasse = $('#strasse').val();
var ort = $('#ort').val();
var plz = $('#plz').val();
var land = $('#land').val();
var fd = new FormData();
var file = fd.append('file', $('#allg_firmen_dok').get(0).files[0]);
var allgArray = {
'gehrKundennummer':gehrKundennummer,
'kundenklasse':kundenklasse,
'lkw12t':lkw12t,
'lkw3t':lkw3t,
'autobus':autobus,
'firmenname1':firmenname1,
'firmenname2':firmenname2,
'uidnummer':uidnummer,
'peselregon':peselregon,
'firmenart':firmenart,
'strasse':strasse,
'ort':ort,
'plz':plz,
'land':land,
'file':file
};
//var data = new FormData();
//jQuery.each(jQuery('#allg_firmen_dok')[0].files, function(i, file) {
// data.append('file-'+i, file);
//});
console.log(allgArray);
$.ajax({
url: "PATHTOFILE/logic/logic_update_client_allg.php",
type: "POST",
data: allgArray,
processData: false, // tell jQuery not to process the data
contentType: false,
success: function(allgArray){
alert(allgArray);
var allgSave = $('#allgSave');
allgSave.text('Aktualisieren erfolgreich!');
allgSave.toggle();
},
error: function(){
var allgSave = $('#allgSave');
allgSave.text('Aktualisieren fehlgeschlagen!');
allgSave.toggle();
}
});
});
The console log of the array returns all values correctly except the one for "file"
it says undefined.
I don't know how to deal with it, are there any requirements that im missing?
Thanks for any kind of help
EDIT
var file = fd.append('file', $('#allg_firmen_dok').get(0).files[0]);
returns undefined

I think the variable fd = new FormData() is an Object and it has attribute "file". So it cannot pass the attribute "file" to another Object "allgArray"
You need to check about it before you call function
$.ajax({
url: "PATHTOFILE/logic/logic_update_client_allg.php",
type: "POST",
data: allgArray,
Think about the data you send! It maybe another instance to get data from "file" of "fd". Hope it help you! ^^
Btw, I used AJAX to send file last time
$(document).ready(function (e) {
$("#Form").on('submit',(function(e) {
e.preventDefault();
$.ajax({
url: "uploader.php", // Url to which the request is send
type: "POST", // Type of request to be send, called as method
data: new FormData(this), // Data sent to server, a set of key/value pairs (i.e. form fields and values)
contentType: false, // The content type used when sending data to the server.
cache: false, // To unable request pages to be cached
processData:false, // To send DOMDocument or non processed data file it is set to false
success: function(data) // A function to be called if request succeeds
{
console.log(data);
}
});
}));
});

add headers: { "Content-Type": "multipart/form-data" } in ajax option

How to send JavaScript collection to PHP variable?

I am trying to send data from form to PHP file using JavaScript. PHP file pushes this data to database. For now, almost all works well but I have a problem with array from getElementsByClassName. After sending to database I can see only "Array" but no values of this array.
Here's a JS:
function przekaz_form($wejscie) {
var datas = document.formularz.datas.value;
var klient = document.formularz.firma.value;
var comment = document.formularz.comment.value;
var collect = document.getElementsByClassName($wejscie);
var datan = document.formularz.datan.value;
var items = new Array();
for(var i = 0; i < collect.length; i++) {
items.push(collect.item(i).value);
}
jQuery.ajax({
url: 'addtobase.php',
type: 'post',
data:{
devices: items,
datas: datas,
klient: klient,
comment: comment,
datan: datan
},
success: function(output) {
alert('Success');
}
});
}

One way to do this is:
$inputData = json_decode(file_get_contents('php://input'));
Once you have the $inputData variable you can access the data in the JSON by:
$devices = (!is_null($inputData) && property_exists($inputData, "devices")) ? strip_tags($inputData->{"devices"}) : 0;
You should also try to better format the JSON : http://json.org/example

How to convert simple form submit to ajax call;

I have a form with input field which can be accessed like
var algorithm = document.forms["algoForm"]["algorithm"].value;
var input = document.forms["algoForm"]["input"].value;
and earlier call was
document.forms["algoForm"].submit();
and form was
<form name="algoForm" method="post" action="run.do">
It all run fine
Now I wanted convert it to the ajax call so that I can use the returned data from java code on the same page. So I used soemthing like
var algorithm = document.forms["algoForm"]["algorithm"].value;
var input = document.forms["algoForm"]["input"].value;
var data = 'algorithm = ' + algorithm + '&input = ' + input;
$.ajax(
{
url: "run.do",
type: "POST",
data: data,
success: onSuccess(tableData)
{ //line 75
alert(tableData);
}
}
);
However the above code doesn't run. Please help me make it run

Let's use jQuery's serialize to get the data out of the form and then use the jQuery's ajax function to send the data to the server:
var data = $("form[name=algoForm]").serialize();
$.ajax({
url: "run.do",
type: "POST",
data: data,
success: function(tableData){
alert(tableData);
}
});

data expects a literal object, so you need:
var data = {
'algorithm': algorithm,
'input': input
};

Instead of retrieving all the parameter value and then sending them separately (which can be done server side as well, using below code), Use this:
var $form = $("#divId").closest('form');
data = $form.serializeArray();
jqxhr = $.post("SERVLET_URL', data )
.success(function() {
if(jqxhr.responseText != ""){
//on response
}
});
}
divId is id of the div containing this form.
This code will send all the form parameters to your servlet. Now you can use request.getParameter in your servlet to get all the individual fields value on your servlet.
You can easily convert above jquery post to jquery ajax.
Hope this helps :)

// patching FORM - the style of data handling on server can remain untouched
$("#my-form").on("submit", function(evt) {
var data = {};
var $form = $(evt.target);
var arr = $form.serializeArray(); // an array of all form items
for (var i=0; i<arr.length; i++) { // transforming the array to object
data[arr[i].name] = arr[i].value;
}
data.return_type = "json"; // optional identifier - you can handle it on server and respond with JSON instead of HTML output
$.ajax({
url: $form.attr('action') || document.URL, // server script from form action attribute or document URL (if action is empty or not specified)
type: $form.attr('method') || 'get', // method by form method or GET if not specified
dataType: 'json', // we expect JSON in response
data: data // object with all form items
}).done(function(respond) {
console.log("data handled on server - response:", respond);
// your code (after saving)
}).fail(function(){
alert("Server connection failed!");
});
return false; // suppress default submit action
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

I don't know how but this one runs well,
var algorithm = document.forms["algoForm"]["algorithm"].value;
var input = document.forms["algoForm"]["input"].value;
$.post('run.do', {
algorithm : algorithm,
input : input
}, function(data) {
alert(data);
}
);