I've been learning about prototype in Javascript from a Pluralsight course. And I have some confusion about it.
Here's the example. I have 2 constructors Person and Student:
function Person(firstName, lastName, age) {
this.firstName = firstName;
this.lastName = lastName;
this.age = age;
this.getFullName = function() {
console.log(this.firstName + this.lastName)
}
}
function Student(firstName, lastName, age) {
this._enrolledCourses = [];
this.enroll = function (courseId) {
this._enrolledCourses.push(courseId);
};
this.getCourses = function () {
return this._enrolledCourses;
};
}
Then create an instance of Student:
let michael = new Student("Michael", "Nguyen", 22);
Now, in the tutorial, it says that in order for michael to inherit everything from Person, there are 2 steps:
Step 1: Create prototype chain:
Student.prototype = Object.create(Person.prototype);
Student.prototype.constructor = Student;
Step 2: call Person inside Student:
function Student(firstName, lastName, age) {
Person.call(this, firstName, lastName, age); <---- this line
this._enrolledCourses = [];
this.enroll = function (courseId) {
this._enrolledCourses.push(courseId);
};
this.getCourses = function () {
f;
return this._enrolledCourses;
};
}
However, if I remove step 1 and only follow with step 2, the result remains the same. michael is still able to inherit everything from Person. The thing is, what's the point of step 1 anyway? If I remove step 2 and only get along with step 1, michael won't be able to inherit anything from Person.
FYI, here's the course url: https://app.pluralsight.com/course-player?clipId=f1feb535-bbdd-4255-88e3-ed7079f81e4e
This is because your constructors are adding all the properties to this, you're not using the prototypes.
Normally, methods are added to the prototype, not each instance, e.g.
function Person(firstName, lastName, age) {
this.firstName = firstName;
this.lastName = lastName;
this.age = age;
}
Person.prototype.getFullName = function() {
console.log(this.firstName + this.lastName)
}
If you don't create the prototype chain, Student won't inherit a method defined this way.
class Person{
constructor(name,age){
this.name = name;
this.age = age;
}
get getName(){
return this.name;
}
set setName(name){
if (typeof name === 'number'){
this.name = name;
}else{
this.name = 'joesy';
}
}
}
const p1 = new Person('jack',9);
console.log(`${p1.name}`);
p1.name = 11;
console.log(`${p1.name}`);
I want to be able to check that the parameter passed into the set method is a number and not a string, but it seems that no matter how I write the if statement inside setName(), calling p1.name = value will always set value to x.
Javascript objects can have two different types of properties:
data properties and
accessor properties (getter/setter).
Data properties simply store values assigned to them (if they are writable) and return these stored values when read.
Accessor properties do not store values at all. Instead they work as functions that are executed whenever read access (getter) or write access/assignment to the property (setter) happens.
Here's a basic example:
class Person {
constructor(firstName, lastName) {
// data properties
this.firstName = firstName;
this.lastName = lastName;
}
// accessor property
get fullName() {
return `${this.firstName} ${this.lastName}`;
}
set fullName(name) {
let [firstName, lastName] = name.split(' ');
this.firstName = firstName;
this.lastName = lastName;
}
}
const p1 = new Person('John', 'Doe');
const p2 = new Person();
p2.fullName = 'Christine Smith';
console.log(p1.firstName, p1.lastName, p1.fullName);
console.log(p2.firstName, p2.lastName, p2.fullName);
I have been learning about inheritance in JavaScript, and could not understand a line of code in the tutorial at https://www.tutorialsteacher.com/javascript/inheritance-in-javascript.
The code is as follows:
function Person(firstName, lastName) {
this.FirstName = firstName || "unknown";
this.LastName = lastName || "unknown";
}
Person.prototype.getFullName = function () {
return this.FirstName + " " + this.LastName;
}
function Student(firstName, lastName, schoolName, grade)
{
Person.call(this, firstName, lastName);
this.SchoolName = schoolName || "unknown";
this.Grade = grade || 0;
}
//Student.prototype = Person.prototype;
Student.prototype = new Person();
Student.prototype.constructor = Student;
var std = new Student("James","Bond", "XYZ", 10);
alert(std.getFullName()); // James Bond
alert(std instanceof Student); // true
alert(std instanceof Person); // true
The part I do not understand is the line right after the commented line, which is:
Student.prototype = new Person();
To my understanding, when an object instance is created, its __proto__ property points to the class's prototype object.
Following this logic, shouldn't the code be:
Student.prototype = new Person().__proto__; ?
I would really appreciate some clarification!
There's a functional difference. Your way assigns Student's prototype as a reference to Person's. Mutations to either prototype will occur in both. In contrast, when you assign as in the example, you're passing a new Object with a (deep) copy of Person's prototype. Have a look at the following screenshots.
I have just started to learn OOP. I am still trying to understand how everything works. I am trying to make a new function that will basically allow me to create a new object by passing the parameters of said class.
Is this even possible, and if so what am I doing wrong?
As stated, still learning so any advice will be appreciated.
class Person {
constructor(name) {
this.persName = name;
}
myName() {
return "My name is " + this.persName;
}
}
function getPers(_perName, fullName) {
_personName = new Person(fullName);
}
$(document).ready(function() {
getPers(John, "John Doe");
});
You can follow the following exapmle. Please note there is not much logic init. The example is just to show you how OOP can work. Of cause, there are many other and better ways to got with that, but for the first try, it should be good to use.
class Person {
//declare the constructor with required name values and optional age value
constructor(firstName, lastName, age = 0) {
this.firstName = firstName;
this.lastName = lastName;
this.age = age;
}
//declare a typically setter, e.g. for age
setAge(age) {
this.age = age;
}
//declare a getter for the person with age
getPerson() {
return this.firstName + ' ' + this.lastName + ' is ' + this.age + ' years old.';
}
}
//here you got with some function within you need to define a new person
function getCreatedPerson(firstName, lastName, age = 0) {
//define the person with required firstname and lastname
const person = new Person(firstName, lastName);
//use the setter to set age of person
person.setAge(age);
//return the person by using the person getter
return person.getPerson();
}
//here you can call the createdPerson function
$(document).ready(function() {
console.log(getCreatedPerson('John', 'Doe', 32));
});
Hope it helps a bit to understand how it could work.
Yes, you can take the fullname as a parameter to your function and pass it through to the OOP method or constructor you're calling.
But you can't take a "reference to a variable" as an argument, like you tried with _perName/_personName. Instead, use the return keyword to return the created object:
function createPerson(fullName) {
return new Person(fullName);
}
$(document).ready(function() {
var john = createPerson("John Doe");
… // use john
});
Let's say I receive some JSON object from my server, e.g. some data for a Person object:
{firstName: "Bjarne", lastName: "Fisk"}
Now, I want some methods on top of those data, e.g. for calculating the fullName:
fullName: function() { return this.firstName + " " + this.lastName; }
So that I can
var personData = {firstName: "Bjarne", lastName: "Fisk"};
var person = PROFIT(personData);
person.fullName(); // => "Bjarne Fisk"
What I basically would want to do here, is to add a method to the object's prototype. The fullName() method is general, so should not be added to the data object itself. Like..:
personData.fullName = function() { return this.firstName + " " + this.lastName; }
... would cause a lot of redundancy; and arguably "pollute" the data object.
What is the current best-practice way of adding such methods to a simple data object?
EDIT:
Slightly off topic, but if the problem above can be solved, it would be possible to do some nice pseudo-pattern matching like this:
if ( p = Person(data) ) {
console.log(p.fullName());
} else if ( d = Dog(data) ) {
console.log("I'm a dog lol. Hear me bark: "+d.bark());
} else {
throw new Exception("Shitty object");
}
Person and Dog will add the methods if the data object has the right attributes. If not, return falsy (ie. data does not match/conform).
BONUS QUESTION: Does anyone know of a library that either uses or enables this (ie makes it easy)? Is it already a javascript pattern? If so, what is it called; and do you have a link that elaborates? Thanks :)
Assuming your Object comes from some JSON library that parses the server output to generate an Object, it will not in general have anything particular in its prototype ; and two objects generated for different server responses will not share a prototype chain (besides Object.prototype, of course ;) )
If you control all the places where a "Person" is created from JSON, you could do things the other way round : create an "empty" Person object (with a method like fullName in its prototype), and extend it with the object generated from the JSON (using $.extend, _.extend, or something similar).
var p = { first : "John", last : "Doe"};
function Person(data) {
_.extend(this, data);
}
Person.prototype.fullName = function() {
return this.first + " " + this.last;
}
console.debug(new Person(p).fullName());
There is another possibility here. JSON.parse accepts a second parameter, which is a function used to revive the objects encountered, from the leaf nodes out to the root node. So if you can recognize your types based on their intrinsic properties, you can construct them in a reviver function. Here's a very simple example of doing so:
var MultiReviver = function(types) {
// todo: error checking: types must be an array, and each element
// must have appropriate `test` and `deserialize` functions
return function(key, value) {
var type;
for (var i = 0; i < types.length; i++) {
type = types[i];
if (type.test(value)) {
return type.deserialize(value);
}
}
return value;
};
};
var Person = function(first, last) {
this.firstName = first;
this.lastName = last;
};
Person.prototype.fullName = function() {
return this.firstName + " " + this.lastName;
};
Person.prototype.toString = function() {return "Person: " + this.fullName();};
Person.test = function(value) {
return typeof value.firstName == "string" &&
typeof value.lastName == "string";
};
Person.deserialize = function(obj) {
return new Person(obj.firstName, obj.lastName);
};
var Dog = function(breed, name) {
this.breed = breed;
this.name = name;
}
Dog.prototype.species = "canine";
Dog.prototype.toString = function() {
return this.breed + " named " + this.name;
};
Dog.test = function(value) {return value.species === "canine";};
Dog.deserialize = function(obj) {return new Dog(obj.breed, obj.name);};
var reviver = new MultiReviver([Person, Dog]);
var text = '[{"firstName": "John", "lastName": "Doe"},' +
'{"firstName": "Jane", "lastName": "Doe"},' +
'{"firstName": "Junior", "lastName": "Doe"},' +
'{"species": "canine", "breed": "Poodle", "name": "Puzzle"},' +
'{"species": "canine", "breed": "Wolfhound", "name": "BJ"}]';
var family = JSON.parse(text, reviver)
family.join("\n");
// Person: John Doe
// Person: Jane Doe
// Person: Junior Doe
// Poodle named Puzzle
// Wolfhound named BJ
This depends on you being able to unambiguously recognizing your types. For instance, if there were some other type, even a subtype of Person, which also had firstName and lastName properties, this would not work. But it might cover some needs.
If you're dealing with plain JSON data then the prototype of each person object would simply be Object.prototype. In order to make it into an object with a prototype of Person.prototype you'd first of all need a Person constructor and prototype (assuming you're doing Javascript OOP in the traditional way):
function Person() {
this.firstName = null;
this.lastName = null;
}
Person.prototype.fullName = function() { return this.firstName + " " + this.lastName; }
Then you'd need a way to turn a plain object into a Person object, e.g. if you had a function called mixin which simply copied all properties from one object to another, you could do this:
//example JSON object
var jsonPerson = {firstName: "Bjarne", lastName: "Fisk"};
var person = new Person();
mixin(person, jsonPerson);
This is just one way of solving the problem but should hopefully give you some ideas.
Update: Now that Object.assign() is available in modern browsers, you could use that instead of writing your own mixin function. There's also a shim to make Object.assign() work on older browsers; see https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/assign#Polyfill.
You should probably not do this.
JSON allows you to serialize a state, not a type. So in your use case, you should do something like this :
var Person = function ( data ) {
if ( data ) {
this.firstName = data.firstName;
this.lastName = data.lastName;
}
};
Person.prototype.fullName = function ( ) {
return this.firstName + ' ' + this.lastName;
};
//
var input = '{"firstName":"john", "lastName":"Doe"}';
var myData = JSON.parse( input );
var person = new Person( myData );
In other words you want to change prototype (a.k.a. class) of existing object.
Technically you can do it this way:
var Person = {
function fullName() { return this.firstName + " " + this.lastName; }
};
// that is your PROFIT function body:
personData.__proto__ = Person ;
After that if you will get true on personData instanceof Person
Use the new-ish Object.setPrototypeOf(). (It is supported by IE11 and all the other browsers now.)
You could create a class/prototype that included the methods you want, such as your fullName(), and then
Object.setPrototypeOf( personData, Person.prototype );
As the warning (on MDN page linked above) suggests, this function is not to be used lightly, but that makes sense when you are changing the prototype of an existing object, and that is what you seem to be after.
I don't think it is common to transport methods with data, but it seems like a great idea.
This project allows you to encode the functions along with your data, but it is not considered standard, and requires decoding with the same library of course.
https://github.com/josipk/json-plus
Anonymous objects don't have a prototype. Why not just have this:
function fullName(obj) {
return obj.firstName + ' ' + obj.lastName;
}
fullName(person);
If you absolutely must use a method call instead of a function call, you can always do something similar, but with an object.
var Person = function (person) { this.person = person; }
Person.prototype.fullName = function () {
return this.person.firstName + ' ' + this.person.lastName;
}
var person = new Person(personData);
person.fullName();
You don't need to use prototypes in order to bind a custom method in your barebone object.
Here you have an elegant example that don't pollute your code avoiding redundant code
var myobj = {
title: 'example',
assets:
{
resources: ['zero', 'one', 'two']
}
}
var myfunc = function(index)
{
console.log(this.resources[index]);
}
myobj.assets.giveme = myfunc
myobj.assets.giveme(1);
Example available in https://jsfiddle.net/bmde6L0r/