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How can skip match with Regex

How can skip match with Regex i wanna to get ss and skip =
Code:
var patt = new RegExp("=ss","g");
var url = "https://mass.lass.com/?t=ss";
var x = url.match(patt);
console.log(x);
//result
=ss
i only need SS

Use a positive lookbehind. Instead of
new RegExp("=ss","g")
you can use
new RegExp("(?<==)ss", "g")

Try this function (more generic), it takes params and url as a parameters
const url = "https://mass.lass.com/?t=ss";
const getQueryParams = ( url, params ) => {
let reg = new RegExp( '[?&]' + params + '=([^&#]*)', 'i' );
let queryString = reg.exec(url);
return queryString ? queryString[1] : null;
};
console.log(getQueryParams(url, "t"))

Cut string url in javascript

I have a string like below
var indicator = -65(www.anyweb.com)
the number -65 can be any number too. How can I take out only the web url separately in javascript?

You need to extract the string after '(' and before ')'
var str = "-65(www.anyweb.com)";
str = str.substring(str.lastIndexOf("(")+1,str.lastIndexOf(")"));

You can use this example for string operations
var data = "-65(www.anyweb.com)";
var url = data.slice(data.indexOf('(')+1 ,data.indexOf(')')); console.log("URL :: ",url);

var domain = /\((.*?)\)/.exec("-65(www.anyweb.com)")[1];
console.log(domain);
The regex above will create a group with anything that's inside parenthesis.

You can use some simple string operations:
var str = "-65(www.anyweb.com)";
var url = "N/A";
// Find indices of open and close parentheses
var open = str.indexOf("(");
var close = str.lastIndexOf(")");
// If they were found then extract the URL from the string
if (open !== -1 && close !== -1) {
url = str.substring(open + 1, close);
}
console.log(url);
If you are more inclined to use regular expressions then this should do it:
var str = "-65(www.anyweb.com)";
var regex = /\((.*?)\)/; // Capture URL inside parentheses
var result = regex.exec(str); // Execute the regex against the string
var url = "N/A";
// If the URL was matched then assign it to the variable
if (result[1] !== undefined) {
url = result[1];
}
console.log(url);
You can also simply replace the stuff that you do not want:
var str = "-65(www.anyweb.com)";
str = str.replace(/^.*\(/, ""); // Remove everything before URL
str = str.replace(/\).*$/, ""); // Remove everything after URL
console.log(str);

Example 1 :
var data = "-65(www.anyweb.com)";
if(data.indexOf('(')!=-1){
var url = data.slice(data.indexOf('(')+1 ,data.indexOf(')'));
}
console.log("URL :: ",url);
Example 2 :
var data = "-65";
if(data.indexOf('(')!=-1){
var url = data.slice(data.indexOf('(')+1 ,data.indexOf(')'));
}
console.log("URL :: ",url);
Example 3 :
var data = "-65(www.anyweb.com)6764872";
if(data.indexOf('(')!=-1){
var url = data.slice(data.indexOf('(')+1 ,data.indexOf(')'));
}
console.log("URL :: ",url);

Separate string into multiple variables with JavaScript

Using JavaScript I want to take a string like this var hashStr = 'modal-123456' and assign the string left of the - to a variable and the string right of the - to another variable.
If the string does not contain a - then ignore it.
How can I best achieve this?
var hashStr = location.hash.replace('#', '');
// hashStr now === 'modal-123456'
var firstHalf = // modal
var secondHalf = // '123456'

You can use split API.
var hashStr = 'modal-123456'
var splitStr = hashStr.split('-');
console.log(splitStr[0])
console.log(splitStr[1])

Just use split.
var hashStr = 'modal-123456';
var [firstHalf, secondHalf] = hashStr.split("-");
console.log("first half:", firstHalf);
console.log("second half:", secondHalf);

Simply
var hashStr = location.hash.replace('#', '');
var firstHalf = hashStr.split("-")[0];
var secondHalf = hashStr.split("-")[1];
or
var hashStr = location.hash.replace('#', '').split("-");
var firstHalf = hashStr[0];
var secondHalf = hashStr[1];

Javascript string manipulation url

My problem is I am trying to extract certain things from the url. I am currently using
window.location.href.substr()
to grab something like "/localhost:123/list/chart=2/view=1"
What i have now, is using the index positioning to grab the chart and view value.
var chart = window.location.href.substr(-8);
var view = window.location.href.substr(-1);
But the problem comes in with I have 10 or more charts. The positioning is messed up. Is there a way where you can ask the code to get the string between "chart=" and the closest "/"?

var str = "/localhost:123/list/chart=2/view=1";
var data = str.match(/\/chart=([0-9]+)\/view=([0-9]+)/);
var chart = data[1];
var view = data[2];
Of course you may want to add in some validation checks before using the outcome of the match.
Inspired by Paul S. I have written a function version of my answer:
function getPathVal(name)
{
var path = window.location.pathname;
var regx = new RegExp('(?:/|&|\\?)'+name+'='+'([^/&,]+)');
var data = path.match(regx);
return data[1] || null;
}
getPathVal('chart');//2
Function should work for fetching params from standard get parameter syntax in a URI, or the syntax in your example URI

Here's a way using String.prototype.indexOf
function getPathVar(key) {
var str = window.location.pathname,
i = str.indexOf('/' + key + '=') + key.length + 2,
j = str.indexOf('/', i);
if (i === key.length + 1) return '';
return str.slice(i, j);
}
// assuming current path as described in question
getPathVar('chart');

You could split your string up, with "/" as delimiter and then loop through the resulting array to find the desired parameters. That way you can easily extract all parameters automatically:
var x = "/localhost:123/list/chart=2/view=1";
var res = {};
var spl = x.split("/");
for (var i = 0; i < spl.length; i++) {
var part = spl[i];
var index = part.indexOf("=");
if (index > 0) {
res[part.substring(0, index)] = part.substring(index + 1);
}
}
console.log(res);
// res = { chart: 2, view: 1}
FIDDLE

Regex to get last word in URL between / and /

How do I get the last word in a URL that is URL between / and / ?
For example:
http://mywebsite.com/extractMe/test
http://mywebsite.com/extractMe
http://mywebsite.com/settings/extractMe/test
http://mywebsite.com/settings/extractMe
Here I would want to get extractMe from the URL.

If the URL is consistent, why not just use:
// Option 1
var url = "http://mywebsite.com/extractMe/test";
var extractedText = url.split("/")[3];
​// Option 2
// If when a trailing slash is present you want to return "test", use this code
var url = "http://mywebsite.com/extractMe/test/";
var urlAry = url.split("/");
var extractedText = urlAry[urlAry.length - 2];
​// Option 3
// If when a trailing slash is present you want to return "extractMe", use this:
var url = "http://mywebsite.com/extractMe/test/";
var urlAry = url.split("/");
var positionModifier = (url.charAt(url.length-1) == "/") ? 3 : 2;
var extractedText = urlAry[urlAry.length - positionModifier];
Here's a working fiddle: http://jsfiddle.net/JamesHill/Arj9B/

it works with / or without it in the end :)
var url = "http://mywebsite.com/extractMe/test/";
var m = url.match(/\/([^\/]+)[\/]?$/);
console.log(m[1]);
output:
test

This accounts BOTH for URLS like http://mywebsite.com/extractMe/test and http://mywebsite.com/extractMe/
function processUrl(url)
{
var tk = url.split('/');
var n = tk.length;
return tk[n-2];
}
Edited.

Regular Expression way:
var str = "http://example.com/extractMe/test";
var match = str.match(/\/([^\/]+)\/[^\/]+$/);
if (match) {
console.log(match[1]);
}