i am creating two ajax functions one in the traditional method and one with jquery. but when i do this the traditional method gets called first and in return i dont get some of my desired outcomes. how can i make the traditional ajax method to be translated into jquery?
here is my traditional ajax method:
function countFollowers() {
var xmlHttp = GetXmlHttpObject();
var url = "checkFollowers.php?username=" + document.followForm.follow_id.value;
xmlHttp.onreadystatechange = function() {
if (xmlHttp.readyState == 4) {
var r = xmlHttp.responseText.trim();
if (r != "error") {
document.getElementById('followersCount').innerHTML = xmlHttp.responseText;
error = true;
return false;
}
}
}
xmlHttp.open("GET", url, true);
xmlHttp.send(null);
if (error == true) {
return false;
}
}
here is my jquery ajax:
jQuery(document).ready(function($) {
$('.msg-icon').on('click', function(e) {
e.preventDefault(); //prevent a normal postback and allow ajax to run instead
var follow_id = $(this).find('input[name="follow_id"]').val();
$.ajax({
data: follow_id,
type: "post",
url: "followingsystem.php?follow=" + follow_id,
success: function(data) {
}
});
});
});
here is what i come up with so far to make the two ajax functions in the same on click function:
jQuery(document).ready(function($){
$('.msg-icon').on('click', function(e){
e.preventDefault(); //prevent a normal postback and allow ajax to run instead
var follow_id = $(this).find('input[name="follow_id"]').val();
$.ajax({
data: follow_id,
type: "post",
url: "followingsystem.php?follow="+follow_id,
success: function(data) {
}
});
$.ajax({
data: follow_id,
type: "post",
url: "checkFollowers.php?username="+follow_id,
success: function(data) {
}
});
});
});
but it is still not executing the response text that is coming from my php file
php code:
<?php
include("functions.php");
include("session.php");
require("connection.php");
if(isset($_GET['username'])){
$username =$_GET['username'];
$result= $db->prepare("SELECT * FROM users WHERE username=?");
$result->bindValue(1,$username);
$result->execute();
$row = $result->fetch();
if($result){
echo "Followers </br>". $row["followers_count"];
}
else{
echo "error";
}
}
?>
how will i get it to echo the $row["followers_count"] inside my span element?
You said in the comments you wanted to run the two requests sequentially instead of in parallel. Here's an all-round better way to organise your code which both allows that, and makes the code more re-usable, more maintainable and testable, and easier to understand in general.
I've used the Promise/Deferred interface provided by jQuery and AJAX as the way to chain the requests in sequence. Notice how each call is separated into each own function (so it's re-usable), but that function returns the Deferred object from the AJAX request, so you can use it to do something else when the request finishes.
Also based on your PHP I think the call to checkfollowers needs to be a GET (because PHP checks $_GET for the input value, and that's what your original XHR call was), and also you need to set the data with an explicit "username" parameter name so it'll be recognised.
It's not clear whether your call to followingsystem.php is correct or not because I can't see the PHP code for it.
jQuery(document).ready(function($) {
$('.msg-icon').on('click', function(e) {
e.preventDefault(); //prevent a normal postback and allow ajax to run instead
var follow_id = $(this).find('input[name="follow_id"]').val();
var request = follow(follow_id); //run the initial request, get back the Deferred object representing that request.
request.done(function() { //when the first request is done, run the second one.
checkFollowers(follow_id);
});
});
});
function follow(follow_id) {
return $.ajax({
data: { follow: follow_id},
type: "post",
url: "followingsystem.php?follow=" + follow_id
});
}
function checkFollowers(follow_id) {
return $.ajax({
data: { username: follow_id },
type: "get",
url: "checkFollowers.php",
success: function(data) {
document.getElementById('followersCount').innerHTML = data;
}
});
}
Related
I'm working on this ajax request with CodeIgniter 3. What I'm doing is press on checkbox and the event calls the function changVisib(). as you will see in the snippet, everything goes well because alert() is called.
But $.ajax() call is completely ignored. I tried $.post(). but no response.
I have searched the web for similar issues, but mine seems different. That's why I'm obliged to ask.
function changVisib(elem, picId) {
if (elem.type === 'checkbox') {
var cva = 0;
if (elem.checked) {
cva = 1;
} else {
cva = 0;
}
alert('ok up to here');
$.ajax({
type: "POST",
url: "<?php echo base_url()?>admin/gallery_update",
data: {id: picId, shown: cva},
dataType: "json"
});
}
}
Other jQuery functions work perfectly well. But the call to ajax, post, get seems not to work.
You need to add a success handler so that you know that the ajax request finished
function changVisib(elem, picId) {
if (elem.type === 'checkbox') {
var cva = 0;
if (elem.checked) {
cva = 1;
} else {
cva = 0;
}
alert('ok up to here');
$.ajax({
type: "POST",
url: "<?php echo base_url()?>admin/gallery_update",
data: {id: picId, shown: cva},
dataType: "json",
success: function(data){
alert( "success" );
}
});
}
}
data - the return data from the ajax request
Read more about the ajax jquery method here
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Loops_and_iteration#for...in_statement
I just discovered where the issue was. ajax queries were ignored because I was using the slim version of jQuery.
I have come to learn that jquery-3.5.1.slim.min.js does not include ajax and effects, according to https://jquery.com/download/.
Bear with me I'm my javascript is a little rusty. So I'm trying to use a call by ajax to a PHP file and give it a plan type then make sense of it check to see if it then return a true or false if some allowed slots are less than some slots used up for the plan. Here is the Form in XHTML.
<form method="post" action="/membership-change-success" id="PaymentForm">
<input type="hidden" name="planChosen" id="planChosen" value="" />
</form>
On the same file. The ( < PLAN CHOICE > ) gets parsed out to the current plan.
<script>
var hash = window.location.hash;
var currentPlan = "( < PLAN CHOICE > )";
$(".planChoice").click(function(event){
var isGood=confirm('Are you sure you want to change your plan?');
var success;
$("#planChosen").val($(this).data("plan"));
$.ajax({
url: '/ajax/planCheck.php',
type: "POST",
dataType: 'json',
data: ({plan: $(this).data("plan")}),
success: function (data) { //This is what is not working I can't get it to return true
success = data;
}
});
if(success) {
if (isGood) {
$("#PaymentForm").submit();
}
window.location = '/membership-change-success';
} else {
alert('Please make sure you deactivate your listings to the appropriate amount before you Downgrade.')
}
});
My PHP for the ajax response looks like this.
<?php
require ('../includes/common.php');
include_once ('../includes/db-common.php');
require ('../includes/config.php');
$membership = new membership($dbobject);
$listing = new listing($dbobject);
$totalAvailableListings = ($membership->get_listingsAmount($_POST['plan']));
if($totalAvailableListings>=$listing->get_active_listings($user->id)){
echo json_encode(true); // I've tried with out jason_encode too
} else {
echo json_encode(false);
}
And that's pretty much it if you have any suggestions please let me know.
So I've tried to do it another way.
$(".planChoice").click(function (event) {
var isGood = confirm('Are you sure you want to change your plan?');
var success;
$("#planChosen").val($(this).data("plan"));
if (false) {
if (isGood) {
$("#PaymentForm").submit();
alert('you did it');
}
} else {
alert(isSuccessful($(this).data("plan")));
//alert('Please make sure you deactivate your listings to the appropriate amount before you downgrade.');
}
});
and I have an ajax function
function isSuccessful(plan) {
return $.ajax({
url: '/ajax/planCheck.php',
type: "POST",
dataType: 'json',
data: {plan: plan}
});
}
The alert tells me this [object XMLHttpRequest]
any suggestions?
$.ajax() returns results asynchronously. Use .then() chained to $.ajax() call to perform task based on response
$.ajax({
url: '/ajax/planCheck.php',
type: "POST",
dataType: 'json',
data: {plan: $(this).data("plan")}
})
.then(function(success) {
if (success) {
$("#PaymentForm").submit();
}
// if `form` is submitted why do we need to set `.location`?
// window.location = '/membership-change-success';
} else {
alert('Please make sure you deactivate your listings to the appropriate amount before you Downgrade.')
}
}, function err(jqxhr, textStatus, errorThrown) {
console.log(errorThrow)
})
You should use the following form for your ajax call
$.ajax({
url: '/ajax/planCheck.php',
type: "POST",
dataType: 'json',
data: ({plan: $(this).data("plan")}),
success: success = data
})
.done(function(response) {
if(success) {
if (isGood) {
$("#PaymentForm").submit();
}
window.location = '/membership-change-success';
}
else {
alert('Please make sure you deactivate your listings to the
appropriate amount before you Downgrade.')
}
});
the .done() clause ensures that you perform that code after the ajax call is finished and the response is obtained.
I've got this variable $type and I want it to be month or year.
It should be changed by pressing a div.
I've tried creating an onclick event with an ajax call.
The ajax call and the variable are in the same script (index.php)
Inside the onclick function:
var curr_class = $(this).attr('class');
$.ajax({
type: "POST",
url: "index.php",
data: {
type: curr_class
},
dataType: 'text',
success: function(data) {
// Test what is returned from the server
alert(data);
}
});
But the alert returns the whole html page.
When I console.log the data (create a var data = { type:curr_class }) and console.log *that data* it returnstype = month` (which is correct)
while I just want it to return month or year
So on top of the page I can call
if(empty($_POST['type'])){
$type = 'month';
} else {
$type = $_POST['type'];
}
and change the PHP variable so I can use it in the rest of my script.
But how can I accomplish this?
With kind regards,
as you are sending request to the same page so as a result full page is return .You will have to send it to another page and from that page return the type variable
if(empty($_POST['type'])){
$type = 'month';
} else {
$type = $_POST['type'];
echo $type;
keep this code in separate file and make an ajax call to that page
//Try This It's Work
Get Value
Get Value
$(".btn-my").click(function(){
var curr_class = $(this).data('title');
$.ajax({
type: "POST",
url: "index.php",
data: {
type: curr_class
},
dataType: 'text',
success: function(data) {
// Test what is returned from the server
alert(data);
}
});
});
Sorry for the title but I had no idea how to call it.
I got some ajax call function that on success adds some HTML elements to the page:
function ajax_submit_append(form_data, url, result, complete) {
$.ajax({
url: url,
type: 'POST',
data: form_data,
success: function(msg) {
var res = $(msg).filter('span.redirect');
if($(res).html() != null){
window.location.replace($(res).html());
return false;
}
$(result).append(msg);
},
complete: complete()
});
};
Function does something on success where the most important is the .append and then this ajax function is called in some button .click function like this:
$(function() {
$("#product_list_add_btn").click(function(e){
ajax_submit_append(
form_data = {
product_name: $('.selectpicker option:selected').val(),
amount: $('#amount').val()},
"<?php echo site_url('admin_panel/new_order/add_product'); ?>",
'#add_product_result',
calculateSum
);
return false;
});
});
What I want to achieve is that calculateSum function (sums table columns) is called after .append is done via ajax.
For now, when I add calculateSum to ajax complete event it is still called before new row is added to the table with .append
Edit: I present You calculateSum, but I believe there is nothing faulty there.
function calculateSum() {
var sum = 0;
// iterate through each td based on class and add the values
$(".countit").each(function() {
var value = $(this).text();
// add only if the value is number
if(!isNaN(value) && value.length != 0) {
sum += parseFloat(value);
}
});
$('#total_price').text(sum);
alert("test");
};
If I had to guess, I would say its something with click event?
How to fix this?
Try using jqXHR's done() method:
function ajax_submit_append(form_data, url, result, complete) {
$.ajax({
url: url,
type: 'POST',
data: form_data,
success: function(msg) {
var res = $(msg).filter('span.redirect');
if($(res).html() != null){
window.location.replace($(res).html());
return false;
}
$(result).append(msg);
}
}).done(complete);
};
Ajax code
$("#login_btn").click(function() {
var url = "core/login.php";
$.ajax({
type: "POST",
url: url,
data: $("#sr").serialize(),
success: function(data) {
var responseData = jQuery.parseJSON(data);
$('.oops').html('<div class="error">'+responseData.oops+'</div>');
alert(responseData.good);
if(responseData.good === 1) {
alert(good)
location.reload();
}
}
});
});
Php code if everything passes
else {
$_SESSION['id'] = $login;
$good = 1;
exit();
}
How come it's not freshing the page with location.reload? Should I be using .done .try?
Dont refresh, the whole idea of using ajax is that you dont need to.
You can set your sessions in the ajax php script and pull new content based on the change in session.
That being said, you are missing a ';' at
alert(good);