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passing a form data inside a modal into controller button outside the form without javascript

I am using Codeigniter Framework and now, i have a modal with a form inside of it. Now in my modal footer, i put the submit form for it. It is already outside of the modal. Now why is it doesn't submit in my controller?. I put a var_dump in my controller for it to echo when it was submitted, I am sending it thru without javascript.
Here is my modal with form:
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Add Category</h4>
</div>
<div class="modal-body">
<div class="container-fluid">
<form id="frm_category" class="form-horizontal" method="POST" action="Admin_controls/insertCategory">
<div class="form-group">
<label for="cat_name">Category: </label>
<input type="text" class="form-control" name="cat_name">
</div>
<div class="form-group">
<label for="cat_desc">Description: </label>
<input type="text" class="form-control" name="cat_desc">
</div>
</form>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-success" value="submit" form="frm_category">Add</button>
<button type="button" class="btn btn-danger" data-dismiss="modal">Close</button>
</div>
</div>
Here is my controller:
public function insertCategory() {
$data = array (
'Category_name' => $this->input->post('cat_name'),
'Category_desc' => $this->input->post('cat_desc')
);
var_dump($data);
}

You should place your submit button before </form>. other wise you need javascript to submit your form
you can use the following code
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Add Category</h4>
</div>
<div class="modal-body">
<div class="container-fluid">
<form id="frm_category" class="form-horizontal" method="POST" action="Admin_controls/insertCategory">
<div class="form-group">
<label for="cat_name">Category: </label>
<input type="text" class="form-control" name="cat_name">
</div>
<div class="form-group">
<label for="cat_desc">Description: </label>
<input type="text" class="form-control" name="cat_desc">
</div>
</form>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-success" value="submit" onclick="myFunction()">Add</button>
<button type="button" class="btn btn-danger" data-dismiss="modal">Close</button>
</div>
</div>
<script>
function myFunction() {
document.getElementById("frm_category").submit();
}
</script>

You should change the button type to submit. So it can submit the form.
Submit button should be inside of form tag
I have modified your modal code. And I hope it will work
×
Add Category
Category:
Description:
Add
Close

If you want to insert a data then you should follow this step:
To POST or GET you should have add that action attribute in side the <form> tag.
Now For post you need to give address of your controller into the <form action = "<?= base_url('your_controller/your_function') ?>" method="post">.
Now at the controller side:
public function your_function(){
// By using this you can get all posted data at once
$your_post_data = $this->input->post();
// By using this you get the post data seperatedly
$your_post_data = $this->input->post('user_name'); // your form input name
//Now for sending data to the model for database querys
$this->load->model ('your_model');
$data = $this->your_model->your_model_function($your_post_data);
}
if you don't want to load model every time then you can add the model in to __construct
public function __construct() {
parent::__construct ();
$this->load->model ('your_model');
// So now on you just need to call the model name in your function.
}
public function your_function(){
// By using this you can get all posted data at once
$your_post_data = $this->input->post();
// By using this you get the post data seperatedly
$your_post_data = $this->input->post('user_name'); // your form input name
$data = $this->your_model->your_model_function($your_post_data);
}
Now Inside the model:( i am giving example for insert)
public function your_model_function($your_post_data ){
$this->db->insert_batch('your_table_name', $your_post_data );
//If you want to understing of query execuation
// for thie you need to enable the log from config.php form config folde.
//Remove comment from log_message after emeble the log message
//log_message('debug', 'Last Insert query: ' . print_r($this->db->last_query(), TRUE).' Inserted Data: '.print_r($your_post_data, TRUE));
if($this->db->affected_rows() > 0){
return TRUE;
} else {
return FALSE;
}
}
For Mode detail regarding querys please visit this CI documentation
Your Code should be:
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Add Category</h4>
</div>
<form id="frm_category" class="form-horizontal" method="POST" action="<?= base_utl('Admin_controls/insertCategory') ?>">
<div class="modal-body">
<div class="container-fluid">
<div class="form-group">
<label for="cat_name">Category: </label>
<input type="text" class="form-control" name="cat_name">
</div>
<div class="form-group">
<label for="cat_desc">Description: </label>
<input type="text" class="form-control" name="cat_desc">
</div>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-success" value="submit" form="frm_category">Add</button>
<button type="button" class="btn btn-danger" data-dismiss="modal">Close</button>
</div>
</form>
</div>
Your controller should be:
public function insertCategory() {
// You should have to validate befor insert
$this->load->model ('your_model');
$your_post_data = $this->input->post();
$insert_status = $this->your_model->your_model_function($your_post_data);
if($insert_status == TRUE){
//return to your view or load the view
$this->load->view ('your_view_directory');
} else {
// Send Error Message
}
For Validation Visit this CI documentation

how to post modal information to a api using jquery,javascript,ajax

I have a modal, e.g the modal is in modal.html, the method i wrote in a javascript file modal.js. when I am trying to submit data through modal, it is not working properly. the code is below. please help me someone.
/modal.html
<div class="col-md-12 text-right">
<button type="button" data-toggle="modal" data-target="#myModal">Update User Information</button>
<div class="modal fade" id="myModal" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Enter User Information</h4>
</div>
<div class="modal-body">
<div class="form-group">
<input type="text" class="form-control" id="user_name" placeholder="User name">
</div>
<div class="form-group">
<input type="email" class="form-control" id="email_id" placeholder="Enter email">
</div>
<div class="form-group">
<input type="text" class="form-control" id="address" placeholder="Enter Address">
</div>
</div>
<div class="modal-footer">
<button type="submit" class="btn btn-default" id="myFormSubmit">Submit</button>
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
</div>
/modal.js
$(function() {
$('#myFormSubmit').click(function () {
$.post("/api/adduserInfo/v1",
{
user_name : $("#user_name").val(),
email : $("#email_id").val(),
address : $("#address").val()
});
});
});

You can use something like this (you will have to get the parametres via post on the server side):
<!-- FORM -->
<form id="idform">
<!-- FORM INPUTS -->
<input class="btn btn-large btn-primary" value="Submit" type="submit">
</form>
<script>
// Variable to hold request
var request;
$("#idform").submit(function(event) {
// Prevent default posting of form - put here to work in case of errors
event.preventDefault();
// Abort any pending request
if (request) {
request.abort();
}
var $form = $(this);
// Let's select and cache all the fields
var $inputs = $form.find("input, select, button, textarea");
// Serialize the data in the form
var serializedData = $form.serialize();
$.ajax({
url: '/api/adduserInfo/v1',
type: 'post',
data: serializedData,
beforeSend: function () {
$("#divtoaddresult").html("Processing, please wait...");
},
success: function (response) {
$("#divtoaddresult").html(response);
}
});
});
</script>

AJAX submit on multiple input field w/ edit & save button

I would like to have ajax submit (without reloading the page) on multiple inputs.
So I have a form which has several input fields with edit and save buttons. When a user click on edit, it focuses on that input field and save with ajax.
The question is, how to make the save button with ajax submit without reloading the page and only that edited field will be changed on save.
Here's my html and js:
HTML
<br>
<br>
<label>Fullname</label>
<div class="input-group">
<input type="text" class="form-control" placeholder="Fullname" value="John Doe" readonly> <span class="input-group-btn">
<button class="btn btn-default btn-edit" type="button">EDIT</button>
<button class="btn btn-default btn-save" type="button">SAVE</button>
<button class="btn btn-default btn-cancel" type="button">CANCEL</button>
</span>
</div>
<br>
<label>Nickname</label>
<div class="input-group">
<input type="text" class="form-control" placeholder="Nickname" value="John" readonly> <span class="input-group-btn">
<button class="btn btn-default btn-edit" type="button">EDIT</button>
<button class="btn btn-default btn-save" type="button">SAVE</button>
<button class="btn btn-default btn-cancel" type="button">CANCEL</button>
</span>
</div>
JS
jQuery(document).ready(function () {
$('.btn-save, .btn-cancel').hide();
var inputVal;
$('.btn-edit').click(function () {
$(this).closest('div').find('.btn-edit').hide();
$(this).closest('div').find('.btn-save, .btn-cancel').show();
$(this).closest('div').find('input').removeAttr('readonly').focus();
inputVal = $(this).closest('div').find('input').val();
});
$('.btn-save').click(function () {
$(this).closest('div').find('input').attr('readonly', 'readonly');
$(this).closest('div').find('.btn-save, .btn-cancel').hide();
$(this).closest('div').find('.btn-edit').show();
});
$('.btn-cancel').click(function () {
$(this).closest('div').find('input').val(inputVal);
$(this).closest('div').find('input').attr('readonly', 'readonly');
$(this).closest('div').find('.btn-save, .btn-cancel').hide();
$(this).closest('div').find('.btn-edit').show();
});
});
I created a demo on JSFiddle. Please help....
DEMO

In your save button put ajax request onclick:
$('.btn-save').click(function () {
$(this).closest('div').find('input').attr('readonly', 'readonly');
$(this).closest('div').find('.btn-save, .btn-cancel').hide();
$(this).closest('div').find('.btn-edit').show();
var inputValue=$(this).closest('div').find('input').val();
$.ajax({ URL:"submit url",
type:"POST",
data:{ inputValue:inputValue },
success:function(data){
// do whatever you want with the response
}
});
});
Please read more about jQuery ajax documentation as what Euphoria said.

I use onclick function on submit but form action is not responding

here is function
function myFunction(button) {
var oldValue = button.value;
button.setAttribute('disabled', true);
button.value = '...processing...';
setTimeout(function () {
button.value = oldValue;
button.removeAttribute('disabled');
}, 3000)
}
and here is form-
<form id="addform" action="index.php/adminuser/insert_state" method="post">
<div class="form-group">
Contact Number
<input type="text" required="" name="contact" class="form-control">
</div>
<div></div>
<div class="form-group">
<button class="btn btn-info" type="submit" id="submit" onclick="myFunction(this)">Submit </button>
</div>
</form>
but form action is not working...please help me how to use disabled button and form action in a single form..
Thanks for help in advance.

How to get form's id, only which submitted

I have 4 forms in my html, and required that form's id which submitted. But every time constantly first form's id comes in output.
My HTML is:
<form name="form" id="filterHeadByFamNum" class="form-horizontal" role="form">
<div class="form-group">
<label>Family Number</label> <input type="text" name="familyNumber" placeholder="Family Number" class="form-control">
</div>
<button type="button" class="btn btn-primary" onclick="filterByFamNum();return false;">Submit</button>
</form>
<form name="form" id="filterHeadByMemName" class="form-horizontal" role="form">
<div class="form-group">
<label>Head Name</label> <input type="text" name="head" placeholder="Head Name" class="form-control">
</div>
<button type="button" class="btn btn-primary" id="head" onclick="filterByMemName();return false;">Submit</button>
</form>
<form name="form" id="filterMemberByPhone" class="form-horizontal" role="form">
<div class="form-group">
<label>Phone Number</label> <input type="text" name="phone" placeholder="Phone Number" class="form-control">
</div>
<button type="button" class="btn btn-primary" onclick="filterByPhone();return false;">Submit</button>
</form>
<form name="form" id="filterMemberByCNIC" class="form-horizontal" role="form">
<div class="form-group">
<label>CNIC</label> <input type="text" name="cnic" placeholder="CNIC" class="form-control">
</div>
<button type="button" class="btn btn-primary" onclick="filterByCNIC();return false;">Submit</button>
</form>
and my js is
function filterByFamNum(){
var name = $(this.form).attr('id');
console.log(name);
}
function filterByMemName(){
var name = $(this.form).attr('id');
console.log(name);
}
function filterByPhone(){
var name = $(this.form).attr('id');
console.log(name);
}
function filterByCNIC(){
var name = $(this.form).attr('id');
console.log(name);
}
Ouptut of every form submit is constantly filterHeadByFamNum

Rather than adding event listeners to the buttons, just listen for the submit event on the form:
$('form').on('submit', function () {
var id = this.id;
console.log(id);
});
..or without jQuery:
Array.prototype.forEach.call(document.querySelectorAll('form'), function (el) {
el.addEventListener('submit', function () {
var id = el.id;
console.log(id);
});
});

I would use #JoshCrozier's solution for this problem but just for the sake of completion and/or if you're adamant about using your solution instead. Here it is:
jsbin DEMO -> http://jsbin.com/yiteludomu/2
Add this as a parameter in each of your javascript functions to send the button you're clicking.
<button type="button" class="btn btn-primary" onclick="filterByFamNum(this);return false;">Submit</button>
here is how you handle button click .. observe btn which is the clicked button.
function filterByFamNum(btn){
var name = $(btn).parent('form').attr('id');
alert(name);
}

var submittedForms = [];
$('form').on('submit', function () {
submittedForms.push(this.id);
});
submittedForms array will hold the ids of all the submitted form.