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Convert seconds to days, hours, minutes and seconds

I have a Javascript timing event with an infinite loop with a stop button.
It will display numbers when start button is click.Now I want this numbers converted to something like 4 hours, 3 minutes , 50 seconds
var c = 0;
var t;
var timer_is_on = 0;
function timedCount() {
document.getElementById('txt').value = c;
c = c + 1;
t = setTimeout(function() {
timedCount()
}, 1000);
}
function doTimer() {
if (!timer_is_on) {
timer_is_on = 1;
timedCount();
}
}
function stopCount() {
clearTimeout(t);
timer_is_on = 0;
}
$(".start").on("click", function() {
//var start = $.now();
//alert(start);
//console.log(start);
doTimer();
$(".end").show();
$(".hide_div").show();
});
$(".end").on("click", function() {
stopCount();
});
.hide_div {
display: none;
}
.end {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p class="start">Start</p>
<p class="end">End</p>
<p class="hide_div">
<input type="text" id="txt" />//display numbers eg 12345
</p>
How to convert numbers like 123456 to 1 day, 4 hours, 40 min, 45 seconds?

I suggest doing this way!:
function secondsToDhms(seconds) {
seconds = Number(seconds);
var d = Math.floor(seconds / (3600*24));
var h = Math.floor(seconds % (3600*24) / 3600);
var m = Math.floor(seconds % 3600 / 60);
var s = Math.floor(seconds % 60);
var dDisplay = d > 0 ? d + (d == 1 ? " day, " : " days, ") : "";
var hDisplay = h > 0 ? h + (h == 1 ? " hour, " : " hours, ") : "";
var mDisplay = m > 0 ? m + (m == 1 ? " minute, " : " minutes, ") : "";
var sDisplay = s > 0 ? s + (s == 1 ? " second" : " seconds") : "";
return dDisplay + hDisplay + mDisplay + sDisplay;
}

Use Math like this way, Second param in parseInt is for base, which is optional
var seconds = parseInt(123456, 10);
var days = Math.floor(seconds / (3600*24));
seconds -= days*3600*24;
var hrs = Math.floor(seconds / 3600);
seconds -= hrs*3600;
var mnts = Math.floor(seconds / 60);
seconds -= mnts*60;
console.log(days+" days, "+hrs+" Hrs, "+mnts+" Minutes, "+seconds+" Seconds");
Your given seconds 123456 would be 1 days, 10 Hrs, 17 Minutes, 36 Seconds not 1 days, 4 Hrs, 40 Minutes, 45 Seconds

function countdown(s) {
const d = Math.floor(s / (3600 * 24));
s -= d * 3600 * 24;
const h = Math.floor(s / 3600);
s -= h * 3600;
const m = Math.floor(s / 60);
s -= m * 60;
const tmp = [];
(d) && tmp.push(d + 'd');
(d || h) && tmp.push(h + 'h');
(d || h || m) && tmp.push(m + 'm');
tmp.push(s + 's');
return tmp.join(' ');
}
// countdown(3546544) -> 41d 1h 9m 4s
// countdown(436654) -> 5d 1h 17m 34s
// countdown(3601) -> 1h 0m 1s
// countdown(121) -> 2m 1s

My solution with map() and reduce():
const intervalToLevels = (interval, levels) => {
const cbFun = (d, c) => {
let bb = d[1] % c[0],
aa = (d[1] - bb) / c[0];
aa = aa > 0 ? aa + c[1] : '';
return [d[0] + aa, bb];
};
let rslt = levels.scale.map((d, i, a) => a.slice(i).reduce((d, c) => d * c))
.map((d, i) => ([d, levels.units[i]]))
.reduce(cbFun, ['', interval]);
return rslt[0];
};
const TimeLevels = {
scale: [24, 60, 60, 1],
units: ['d ', 'h ', 'm ', 's ']
};
const secondsToString = interval => intervalToLevels(interval, TimeLevels);
If you call secondsToString(123456), you can get "1d 10h 17m 36s "

Here is my solution, a simple function that will round to the nearest second!
var returnElapsedTime = function(epoch) {
//We are assuming that the epoch is in seconds
var hours = epoch / 3600,
minutes = (hours % 1) * 60,
seconds = (minutes % 1) * 60;
return Math.floor(hours) + " hours, " + Math.floor(minutes) + " minutes, " + Math.round(seconds) + " seconds";
}

Came up with my own variation to some of the solutions suggested in this thread.
if (!Number.prototype.secondsToDHM) {
Number.prototype.secondsToDHM = function() {
const secsPerDay = 86400;
const secsPerHour = 3600;
const secsPerMinute = 60;
var seconds = Math.abs(this);
var minus = (this < 0) ? '-' : '';
var days = Math.floor(seconds / secsPerDay);
seconds = (seconds % secsPerDay);
var hours = Math.floor(seconds / secsPerHour);
seconds = (seconds % secsPerHour);
var minutes = Math.floor(seconds / secsPerMinute);
seconds = (seconds % secsPerMinute);
var sDays = new String(days).padStart(1, '0');
var sHours = new String(hours).padStart(2, '0');
var sMinutes = new String(minutes).padStart(2, '0');
return `${minus}${sDays}D ${sHours}:${sMinutes}`;
}
}
var a = new Number(50000).secondsToDHM();
var b = new Number(100000).secondsToDHM();
var c = new Number(200000).secondsToDHM();
var d = new Number(400000).secondsToDHM();
console.log(a);
console.log(b);
console.log(c);
console.log(d);

This answer builds upon on Andris' approach to this question, but it doesn't have trailing commas if lesser units are not present.
It also borrows from this answer dealing with joining array values only if truthy:
https://stackoverflow.com/a/19903063
I'm not a javascript god and it's probably horribly over-engineered, but hopefully readable and correct!
function sformat(s) {
// create array of day, hour, minute and second values
var fm = [
Math.floor(s / (3600 * 24)),
Math.floor(s % (3600 * 24) / 3600),
Math.floor(s % 3600 / 60),
Math.floor(s % 60)
];
// map over array
return $.map(fm, function(v, i) {
// if a truthy value
if (Boolean(v)) {
// add the relevant value suffix
if (i === 0) {
v = plural(v, "day");
} else if (i === 1) {
v = plural(v, "hour");
} else if (i === 2) {
v = plural(v, "minute");
} else if (i === 3) {
v = plural(v, "second");
}
return v;
}
}).join(', ');
}
function plural(value, unit) {
if (value === 1) {
return value + " " + unit;
} else if (value > 1) {
return value + " " + unit + "s";
}
}
console.log(sformat(60)); // 1 minute
console.log(sformat(3600)); // 1 hour
console.log(sformat(86400)); // 1 day
console.log(sformat(8991)); // 2 hours, 29 minutes, 51 seconds
If you needed to convey the duration more 'casually' in words, you could also do something like:
var remaining_duration = sformat(117);
// if a value is returned, add some prefix and suffix
if (remaining_duration !== "") {
remaining_duration = "about " + remaining_duration + " left";
}
$(".remaining_duration").text(remaining_duration);
// returns 'about 1 minute, 57 seconds left'

I further tweaked the code by Svetoslav as follows:
function convertSecondsToReadableString(seconds) {
seconds = seconds || 0;
seconds = Number(seconds);
seconds = Math.abs(seconds);
const d = Math.floor(seconds / (3600 * 24));
const h = Math.floor(seconds % (3600 * 24) / 3600);
const m = Math.floor(seconds % 3600 / 60);
const s = Math.floor(seconds % 60);
const parts = [];
if (d > 0) {
parts.push(d + ' day' + (d > 1 ? 's' : ''));
}
if (h > 0) {
parts.push(h + ' hour' + (h > 1 ? 's' : ''));
}
if (m > 0) {
parts.push(m + ' minute' + (m > 1 ? 's' : ''));
}
if (s > 0) {
parts.push(s + ' second' + (s > 1 ? 's' : ''));
}
return parts.join(', ');
}

Short answer:
var s = (Math.floor(123456/86400) + ":" + (new Date(123456 * 1000)).toISOString().substr(11, 8)).split(":");
console.log(`${s[0]} days, ${s[1]} hours, ${s[2]} minutes, ${s[3]} seconds` )
Edit:
Let me break it down in parts :
Math.floor(123456/86400)
86400 is the the total seconds in a day (60 seconds * 60 minutes * 24 hours). Dividing the inputted seconds by this value gives us number of days. We just need the whole part so we use Math.floor because the fractional piece is handled by this part:
(new Date(123456 * 1000)).toISOString().substr(11, 8)
the explanation can be found here:
Convert seconds to HH-MM-SS with JavaScript?
It just outputs hh:mm:ss, no days. So the first part and this part is a perfect combination
We concatenate using a colon (:) as a separator. The string looks like this:
'1:10:17:36'
We split it into an array with .split(":");. Then finally, we format the elements of the array for the desired output.

I've tweaked the code that Andris posted https://stackoverflow.com/users/3564943/andris
// https://stackoverflow.com/questions/36098913/convert-seconds-to-days-hours-minutes-and-seconds
function app_ste_36098913_countdown_seconds_to_hr(seconds) {
seconds = seconds || 0;
seconds = Number(seconds);
seconds = Math.abs(seconds);
var d = Math.floor(seconds / (3600*24));
var h = Math.floor(seconds % (3600*24) / 3600);
var m = Math.floor(seconds % 3600 / 60);
var s = Math.floor(seconds % 60);
var parts = new Array();
if (d > 0) {
var dDisplay = d > 0 ? d + ' ' + (d == 1 ? "day" : "days") : "";
parts.push(dDisplay);
}
if (h > 0) {
var hDisplay = h > 0 ? h + ' ' + (h == 1 ? "hour" : "hours") : "";
parts.push(hDisplay)
}
if (m > 0) {
var mDisplay = m > 0 ? m + ' ' + (m == 1 ? "minute" : "minutes") : "";
parts.push(mDisplay)
}
if (s > 0) {
var sDisplay = s > 0 ? s + ' ' + (s == 1 ? "second" : "seconds") : "";
parts.push(sDisplay)
}
return parts.join(', ', parts);
}

You will probably find using epoch timestamps more straightforward: As detailed in Convert a Unix timestamp to time in JavaScript, the basic method is like so:
<script>
// Create a new JavaScript Date object based on the timestamp
// multiplied by 1000 so that the argument is in milliseconds, not seconds.
var date1 = new Date();
alert ('easy trick to waste a few seconds...' + date1);
// var date = date2 - date1;
// Hours part from the timestamp
var hours1 = date1.getHours();
// Minutes part from the timestamp
var minutes1 = "0" + date1.getMinutes();
// Seconds part from the timestamp
var seconds1 = "0" + date1.getSeconds();
var date2 = new Date();
// Hours part from the timestamp
var hours2 = date2.getHours();
// Minutes part from the timestamp
var minutes2 = "0" + date2.getMinutes();
// Seconds part from the timestamp
var seconds2 = "0" + date2.getSeconds();
// Will display time in 10:30:23 format
// var formattedTime = hours + ':' + minutes.substr(-2) + ':' + seconds.substr(-2);
var elapsedHrs = hours2 - hours1;
var elapsedMin = minutes2.substr(-2) -minutes1.substr(-2);
var elapsedSec = seconds2.substr(-2) - seconds1.substr(-2);
var elapsedTime = elapsedHrs + ' hours, ' + elapsedMin + ' minutes, ' + elapsedSec + ' seconds';
alert ('time between timestamps: ' + elapsedTime);
</script>
Be warned that this script needs some work since for now it will give negative values for things like date1 = 12:00:00 and date2 = 12:00:05, but I'll leave that to you fo now.
You should rewrite your code to take a timestamp ( var x = new Date(); ) at the start of your timer and one whenever you are done/want to check elapsed time, and subtract the two before parsing out elapsed seconds, minutes, hours etc as required.

This is my take at the question, even if it is an old topic.
You can use a loop to compute everything for you :
function time_remaining(date1, date2) {
let seconds = (date2 - date1) / 1000
let units = ["years", "days", "h", "min", "s"]
let limit_units = [365, 24, 60, 60, 1]
const reducer = (accumulator, curr) => accumulator * curr;
let time = []
for (let i = 0; i < units.length; i++) {
let divisor = limit_units.slice(i).reduce(reducer)
let value = Math.floor(seconds / divisor)
seconds = seconds - value * divisor
time.push(value)
}
return clean_time(time, units)
}
// at this point, you have your answer. However,
// we can improve the result by removing all none
// significative null units (i.e, if your countdown is
// only about hours, minutes and seconds, it is not
// going to include years and days.)
function clean_time(time, units) {
time = time.reverse()
while (time[time.length - 1] == 0) {
time.pop()
}
return [time.reverse(), units.slice(-time.length)]
}
let date1 = Date.parse("2023-07-09T17:50:33")
console.log(time_remaining(Date.now(), date1))

change date format function

I am trying to change a date format, would you please help me out to change the date format into this Mon, 12 Feb 2016 11:00?
Here is the code below:
function nicetime(a, out) {
var d = Math.round((+new Date - a) / 1000),
fuzzy = '',
n = 'mins',
d = d < 0 ? 0 : d;
if (out == 1) {
return d;
} else if (out == 0) {
var chunks = new Array();
chunks[0] = [60 * 60 * 24 * 365, 'year', 'years'];
chunks[1] = [60 * 60 * 24 * 30, 'month', 'months'];
chunks[2] = [60 * 60 * 24 * 7, 'week', 'weeks'];
chunks[3] = [60 * 60 * 24, 'day', 'days'];
chunks[4] = [60 * 60, 'hr', 'hrs'];
chunks[5] = [60, 'min', 'mins'];
var i = 0,
j = chunks.length;
for (i = 0; i < j; i++) {
s = chunks[i][0];
if ((xj = Math.floor(d / s)) != 0) {
n = xj == 1 ? chunks[i][1] : chunks[i][2];
break;
}
}
fuzzy += xj == 1 ? '1 ' + n : xj + ' ' + n;
if (i + 1 < j) {
s2 = chunks[i + 1][0];
if (((xj2 = Math.floor((d - (s * xj)) / s2)) != 0)) {
n2 = (xj2 == 1) ? chunks[i + 1][1] : chunks[i + 1][2];
fuzzy += (xj2 == 1) ? ' + 1 ' + n2 : ' + ' + xj2 + ' ' + n2;
}
}
fuzzy += ' ago';
return fuzzy;
}
}

Suppose , your date is "February 04, 2011 19:00:00"
function formatDate(date) {
var d = new Date(date);
var hh = d.getHours();
var m = d.getMinutes();
var s = d.getSeconds();
var dd = "AM";
var h = hh;
if (h >= 12) {
h = hh-12;
dd = "PM";
}
if (h == 0) {
h = 12;
}
m = m<10?"0"+m:m;
s = s<10?"0"+s:s;
/* if you want 2 digit hours:
h = h<10?"0"+h:h; */
var pattern = new RegExp("0?"+hh+":"+m+":"+s);
var replacement = h+":"+m;
/* if you want to add seconds
replacement += ":"+s; */
replacement += " "+dd;
return date.replace(pattern,replacement);
}
alert(formatDate("February 04, 2011 12:00:00"));

Interval Array not creating

I found this code but when insert anytime between x:15 - x:45 (x being any associated time) I do not get the intervals for those times.
var setIntervals = function (start, end, inc, oc) {
start = start.toString().split(':');
end = end.toString().split(':');
inc = parseInt(inc, 10);
oc = oc;
var pad = function (n) { return (n < 10) ? '0' + n.toString() : n; },
startHr = parseInt(start[0], 10),
startMin = parseInt(start[1], 10),
endHr = parseInt(end[0], 10),
endMin = parseInt(end[1], 10),
currentHr = startHr,
currentMin = startMin,
previous = currentHr + ':' + pad(currentMin),
current = '',
r = [];
do {
currentMin += inc;
if ((currentMin % 60) === 0 || currentMin > 60) {
currentMin = (currentMin === 60) ? 0 : currentMin - 60;
currentHr += 1;
}
current = currentHr + ':' + pad(currentMin);
r.push({"end":current, "start":previous, "OpenClosed":oc});
previous = current;
} while (currentHr !== endHr);
return r;
};
var closedTime=setIntervals("<?php echo $close_now ?>","<?php echo $close_end ?>","15", "closed");
var closeArray = [];
closeArray.push(closedTime);
Currently I only get the times from 1:30 - 2:00 but not up to 2:30... If I do 2:00 to 3:00 I get all the intervals.
https://jsfiddle.net/pbbsoxrz/
Added the issue into jsfiddle
Courteous of JavaScript Setting Time Difference through Loop In Array

Just change the while condition and add the part for the minutes with logical or.
while (currentHr !== endHr || currentMin !== endMin);
var setIntervals = function (start, end, inc, oc) {
start = start.toString().split(':');
end = end.toString().split(':');
inc = parseInt(inc, 10);
oc = oc;
var pad = function (n) { return (n < 10) ? '0' + n.toString() : n; },
currentHr = parseInt(start[0], 10),
currentMin = parseInt(start[1], 10),
endHr = parseInt(end[0], 10),
endMin = parseInt(end[1], 10),
previous = currentHr + ':' + pad(currentMin),
current = '',
r = [];
do {
currentMin += inc;
currentHr += currentMin / 60 | 0;
currentMin %= 60;
current = currentHr + ':' + pad(currentMin);
r.push({ start: previous, end: current, OpenClosed: oc });
previous = current;
} while (currentHr !== endHr || currentMin !== endMin); // <----------- change this!
return r;
};
var closedTime = setIntervals("12:15", "14:45", "15", "closed");
var closeArray = [];
closeArray.push(closedTime);
document.write('<pre>' + JSON.stringify(closeArray, 0, 4) + '</pre>');

Here's what you want:
var setIntervals = function(start, end, inc, oc) {
var date1 = new Date('2015-1-1 ' + start),
date2 = new Date('2015-1-1 ' + end),
r = [],
current,
previous;
// Make sure we increment is a positive number so we don't have an infinite loop
inc = Math.abs(parseInt(inc, 10));
do {
previous = ('0' + date1.getHours()).slice(-2) + ':' + ('0' + date1.getMinutes()).slice(-2);
date1.setTime(date1.getTime() + inc * 60 * 1000);
current = ('0' + date1.getHours()).slice(-2) + ':' + ('0' + date1.getMinutes()).slice(-2);
r.push({
"end": current,
"start": previous,
"OpenClosed": oc
});
} while (date1.getTime() < date2.getTime());
return r;
};
var closeArray = [setIntervals("13:30", "14:30", "15", "closed")];
console.log(closeArray);
The while condition of your original code causes the loop to end every time the two hours are equal.
This approach simplify things a bit.

looping and print a list of time

var firstAm = '<li>12:00 AM</li>';
$('#time').append(firstAm);
for (i = 1; i < 12; i++) {
var am = '<li>' + i + ':00 AM</li>';
$('#time').append(am);
}
With above code I produced 1 hour interval, but I wish to produce something like
12:15 AM
12:30 AM
12:45 AM
which have 15 min different.
Fiddle : http://jsfiddle.net/ycjkqc0g/1/

You could do something like
var date = new Date();
date.setHours(0, 0, 0, 0);
var end = new Date(date);
end.setHours(end.getHours() + 12);
while (date < end) {
var am = '<li>' + convert24HourTo12Hour(date.getHours()) + ':' + date.getMinutes() + ' AM</li>';
$('#time').append(am);
date.setMinutes(date.getMinutes() + 15);
}
function convert24HourTo12Hour(h) {
return (h + 11) % 12 + 1;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="time"></div>

You can add one more loop inside the for loop as,
for (i = 1; i < 12; i++) {
for ( min = 0; min < 3; min++ ) {
var am = '<li>' + i + ':' + min * 15 + 'AM</li>';
$('#time').append(am);
}
}
In the inner loop you are basically printing the time in minutes as 0, 15, 30 and 45.
If you want to print it as '00' for hour, then you can format the number min*15 to a two digit value and use it.

var d = new Date();
d.setHours(0,0,0);
var html = '';
for (i=0;i<12*4*2;i++) {
var h = ('0'+d.getHours()).slice(-2);
var m = ('0'+d.getMinutes()).slice(-2);
var s = ('0'+d.getSeconds()).slice(-2);
var ampm = '';
if (h >= 12) {
ampm = 'pm';
} else {
ampm = 'am';
}
html += '<li>' + h + ':' + m + ':' + s + ' ' + ampm + '</li>';
d.setMinutes(d.getMinutes() + 15);
}
$(html).wrap('<ul></ul>');
$('#time').append(html);

Amending the function to calculate into the new year and not return the value 12/33/2014

I need your help.
It seems that the function this_week('end') is returning a bad date of 12/33/2014 (mm/dd/yyyy) where it should properly read:
01/02/2015
function this_week(x) {
var today, todayNumber, fridayNumber, sundayNumber, monday, friday;
today = new Date();
todayNumber = today.getDay();
mondayNumber = 1 - todayNumber;
fridayNumber = 5 - todayNumber;
if (x === 'start') {
//var start_dd = today.getDate() + mondayNumber
var start_dd = today.getDate()
var start_mm = today.getMonth() + 1
var start_yyyy = today.getFullYear()
return start_mm + '/' + start_dd + '/' + start_yyyy
}
if (x === 'end') {
var end_dd = today.getDate() + fridayNumber
var end_mm = today.getMonth() + 1
var end_yyyy = today.getFullYear()
return end_mm + '/' + end_dd + '/' + end_yyyy
}
}
What needs to be done?

You have to use Date objects when increasing or decreasing the date..
function this_week(x) {
var date, todayNumber, fridayNumber;
date = new Date();
todayNumber = date .getDay();
mondayNumber = 1 - todayNumber;
fridayNumber = 5 - todayNumber;
if (x === 'start') {
date.setDate(date.getDate()+ mondayNumber);
}
else if (x === 'end') {
date.setDate(date.getDate()+ fridayNumber);
}
var end_dd = date.getDate().toString();
end_dd = (end_dd.length == 2)?end_dd:"0"+end_dd;
var end_mm = (date.getMonth() + 1).toString();
end_mm = (end_mm.length == 2)?end_mm:"0"+end_mm;
var end_yyyy = date.getFullYear().toString();
return end_mm + '/' + end_dd + '/' + end_yyyy;
}
document.write(this_week('end'));
Note that the month code for January is 0

For a much simpler version:
function this_week(x,d) {
var d = d || new Date(),
offset = 0;
switch (x){
case 'start':
offset = 1 - d.getDay();
break;
case 'end':
offset = 5 - d.getDay();
break;
}
d.setDate(d.getDate() + offset);
return d;
}
var oE = document.getElementById('o'),
tE = document.getElementById('t');
function $log(t){ oE.innerHTML += (t || '') + "\r\n"; }
function $fmt(d){ return [d.getMonth() + 1, d.getDate(), d.getFullYear() ].map(function(v){ return v < 10 ? '0' + v : v; }).join('/'); }
function c(el){ try { var d = new Date(el.value); tE.innerHTML = 'Start: ' + $fmt(this_week('start',d)) + '; End: ' + $fmt(this_week('end',d)); } catch (e) { tE.innerHTML = 'Invalid Date'; } }
$log( 'Fixed dates' );
var ds = [
new Date(2014, 12 - 1, 29),
new Date(2015, 1 - 1, 1)
];
for (var i = 0; i < ds.length; i++){
$log( $fmt(ds[i]) + ' start » ' + $fmt(this_week('start', ds[i])) );
$log( $fmt(ds[i]) + ' end » ' + $fmt(this_week('end', ds[i])) );
}
$log();
$log( 'Based on today:' );
$log( $fmt(this_week('start')) );
$log( $fmt(this_week('end')) );
$log();
$log('::All dates in mm/dd/yyyy format::');
<pre id="o"></pre>
<hr />
<input type="text" onchange="c(this);" placeholder="try me"><button>Try</button><span id="t"></span>

Assuming that a complete week may start on sunday or on monday, this function covers both:
function this_week(start, givendate, weekStartsOnsunday) {
givendate = givendate && givendate instanceof Date ? givendate : new Date;
var today = givendate.getDay(),
isSunday = !weekStartsOnsunday && today < 1,
diff = !start
? (isSunday ? -2 : (5 - today))
: (isSunday ? -6 : (1 - today));
// set date to begin/end of week and return it formatted
return (givendate.setDate(givendate.getDate() + diff), format(givendate));
}
// format mm/dd/yyyy with leading zero's using an Array and Array.map
function format(date) {
return [ date.getDate(),
date.getMonth()+1,
date.getFullYear()
].map(function (v) {return v <10 ? '0'+v : v;})
.join('/');
}
var log = Helpers.log2Screen;
// today and week starts on monday
log('`this_week()`: ', this_week());
log('`this_week(true)`: ',this_week(true));
// given date is sunday, week starts on monday
log('`this_week(false, new Date(\'2015/01/04\'))`: ',
this_week(false, new Date('2015/01/04')), ' (week ends on sunday)');
log('`this_week(true, new Date(\'2015/01/04\'))`: ',
this_week(true, new Date('2015/01/04')), ' (week ends on sunday)');
// given date is sunday, week starts on sunday
log('`this_week(false, new Date(\'2015/01/04\'), true)`: ',
this_week(false, new Date('2015/01/04'), true), ' (week starts on sunday)')
log('`this_week(true, new Date(\'2015/01/04\'), true)`: ',
this_week(true, new Date('2015/01/04'), true), ' (week starts on sunday)');
<script src="http://kooiinc.github.io/JSHelpers/Helpers-min.js"></script>