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I would to exclude first and last word from the string in JS regex. Please suggest.
Example strings
QueueName default_queue end
QueueName default queue end
I would like to match default_queue and default queue
You could use capture groups
var str = "QueueName default_queue end"
var matchArray = str.match(/^\w+\s+(.+)\s+\w+$/) // capture with paranthesis
console.log(matchArray[1]) // default_queue
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I have a long document with some headings I want to replace in a operation.
The headings have the following structure (there are two nouns, both in with a uppercase first character, separated with a whitespace, also the time is dynamic):
let string = 'Firstname Lastname [00:01:02]';
I want to insert some characters at the front and the end of this string, but want to keep the content.
So the desired output should be something like:
let string = '{Firstname Lastname [00:01:02]}:';
I tried a little bit around with RegEx and can catch the time with the following pattern:
\[[0-9]{2}:[0-9]{2}:[0-9]{2}
I figured it out by using captures in my RegEx.
/(\b[A-Z][a-z]* [A-Z][a-z]*( [A-Z])?\b\s\[[0-9]{2}:[0-9]{2}:[0-9]{2}\])/g
This RegEx captures the pattern of my headings into group one. In a replace operation I can then insert the desired content.
string.replace(regex, '{$1}:')
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I am willing to know how can I check if the a phone number contain the following prefixes +44, 0044 or 0 and if so it will be removed? I know I to remove a number of characters or a substring but how do I check if that substring is in the beginning?
Thanks in advance
You could with regex /^(\+44|0044|0)/g
function rem(str){
return str.replace(/^(\+44|0044|0)/g,'')
}
console.log(rem('0044987987'));
console.log(rem('04478687'));
console.log(rem('+447783'));
You can use indexOf to check the index of those prefix.
"+44-----".indexOf("+44") // returns 0
That should be enough for what you want.
You can simply test against a regex pattern.
Or use it for a replace.
const re_tel44 = /^[+]?0{0,2}(?:44)?(\d{5,})$/;
let phonenumber = '+4412345';
console.log(re_tel44.test(phonenumber));
if(re_tel44.test(phonenumber))
phonenumber = phonenumber.replace(re_tel44, '$1');
console.log(phonenumber);
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I have the following user queries:
Boeing AND Airbus OR twitter
Boeing AND Airbus
I need to split words in them by AND, OR so, in the end, I will have something like this:
"Boeing" AND "Airbus"
"Boeing" AND "Airbus" OR "twitter"
How can I do this with split or any other method?
Step by step:
split on space
Iterate through elements, if is NOT "and" or "OR" -> quote
const sentence = "Boeing AND Airbus OR twitter"
const split = sentence.split(" ");
const quoted = split.map(e => ["AND", "OR"].includes(e)?e:'"'+e+'"')
console.log(quoted.join(" "))
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I want the text which is outside of brackets, for eg.
Text is - Outside (inside)
and what I expect is - Outside
Can someone please help me to achieve this.
You can use slice & use indexOf to get the first (. This will extract all the characters before first (
let str = 'Outside (inside)'
let substr = str.slice(0, str.indexOf('('));
console.log(substr.trim())
If you wanted to remove all bracketed text from the string you could use
let str = 'Outside (inside)test(d 342 dd3d)dd(t423t t)dd()fasf(fsdfds32dfs)';
console.log(str.replace(/(\([\w\d ]*\))+/g, ''))
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How to split string with several char
i have to split a scope when there are spaces, comma, dash, etc..( ponctuation) and when words are concatenated ( without a space between variable)
For exemple
testOne="{{test.test}} {{test.test}}{{test.test}}";
The expected output is
"test.test test.testtest.test"
(There are two comma between the first and the second text.text)
You can use Regular Expression to get the result what you wanted.
testOne = "{{test.test}} {{test.test}}{{test.test}}";
console.log(testOne.match(/{{.*?}}/g).map(function(item) {
return item.replace(/[{}]/g, "");
}));
# [ 'test.test', 'test.test', 'test.test' ]
You can achieve your desired output with a simple replace
testOne.replace(/{{(.*?)}}/g, '$1');
// "test.test test.testtest.test"
Remember to set this back to testOne if you want it kept as that variable