I'm trying to set values using the following logic:
function compare(){
var values = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet().getDataRange().getValues();
for(n=0;n<values.length;++n){
var cell = values[n][0] ;
values[n][0].setValue("myValue");
}
}
But I can't set the value this way. I'm trying to use the cell[n][x] notation because its easier for what I have to do later on.
Thanks in advance for your help.
You can't use .setValues() because values[n][0] is not an object, it is just the value of a 2D-array. Just use values[n][0] = "my Value". At the end you will have editted your array, then you'll need to use range.setValues() to set the new values to your range.
Example:
function compare(){
var myRange = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet().getDataRange();
var values = myRange.getValues();
for(var n=0;n<values.length;n++){
values[n][0]="myValue "+n;
values[n][1]="myValue 2 "+n;
}
myRange.setValues(values)
}
Related
I would like to create a filter for a column in a spreadsheet, then retrieve the list of default criteria values created for the filter. I believe that my code returns a Filter object without any values for it.
function TestFilter(){
var spreadsheet = SpreadsheetApp.getActive();
var sheet = spreadsheet.getActiveSheet();
sheet.getRange(1, 2, sheet.getMaxRows(), 1).createFilter();
var filter = sheet.getFilter();
var output = filter.getColumnFilterCriteria(2).getCriteriaValues();
return output;
}
You can use the following functions for this:
getHiddenValues()
Returns the values to hide.
getVisibleValues()
Returns the values to show.
In case your filter is set to hide all of the possible values, you will obtain what you desire by using the function getHiddenValues().
However, this will not be possible if your filter is only hiding a subset of your values. For that case, you could use a Google Apps Script function such as the following below to obtain the distinct values:
function getDistinctValues(range) {
var values = range.getValues();
var unique = {};
for (var i=0; i<values.length; i++) {
for (var j=0; j<values[i].length; j++) {
var key = values[i][j];
if (key !== null && key !== undefined && key !== '')
unique[key] = true;
}
}
return Object.keys(unique);
}
The usage of it would be, in case you were attempting to obtain the distinct values on your A column:
var distinctValues = getDistinctValues(sheet.getRange("A2:A"));
Note that this function will return the values as Strings. In case you want to obtain the actual numeric value instead of a String, you can parse the values simply by using the following code:
var distinctValues = getDistinctValues(sheet.getRange("A2:A")).map(parseFloat);
I believe there is a bug with 2 out of 3 of these functions, by using something like this:
var filter = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("sheetName").getFilter();
var criteriaValues = filter.getColumnFilterCriteria(9).getCriteriaValues();
Logger.log("criteria Values length " + criteriaValues.length);
Logger.log(criteriaValues);
var visibleValues = filter.getColumnFilterCriteria(9).getVisibleValues();
Logger.log("visible Values length " + visibleValues.length);
Logger.log(visibleValues);
var hiddenValues = filter.getColumnFilterCriteria(9).getHiddenValues();
Logger.log("hidden Values length " + hiddenValues.length);
Logger.log(hiddenValues);
and setting a filter on column I (9th from the left) regardless of how many or which values I filter by, I only ever see the values that I've hidden from the column, the criteriaValues and visibleValues arrays are always empty, while hiddenValues always shows correctly the values that are filtered out.
If someone could double check this and confirm it would be great, otherwise, maybe I'm just doing something really silly, in which case please let me know as well :).
This is created based on https://developers.google.com/apps-script/reference/spreadsheet/filter-criteria.html
Blockquote
I am relatively new to creating custom functions in Google Scripts.
I need to be able to pass in an array of ranges into a function.
Please let me know if I am approaching this incorrectly.
I am getting a parse error when I reference it in Google Sheets as =ConcatEach(["A1:A2","B1:B2"],"$"]) (Without the quotes.)
(Also, the values are arbitrary. I know dollar signs go before the value.)
Anyway, here is what I have:
function ConcatEach(rangeString, concatString)
{
//var rangeString = ["A1:A2","B1:B2"];
//var concatString = "$";
var sheet = SpreadsheetApp.getActiveSpreadsheet();
var rangeValues=[];
for(i=0;i<rangeString.length;i++)
{
var range = sheet.getRange(rangeString[i]);
rangeValues.push(range.getValues());
}
//Logger.log(rangeValues);
for(i=0;i<rangeValues.length;i++)
{
for(j=0;j<rangeValues[i].length;j++)
{
if(rangeValues[i][j] != "")
{
rangeValues[i][j] = rangeValues[i][j] + concatString;
}
}
}
return rangeValues;
}
Any help would be super appreciated! Thank you!
you may pass rangeString as string with commas:
"A1:A2,B1:B2"
and then use JavaScript String split() Method:
var array = rangeString.split(",");
Logger.log(array); // you'll get array ['A1:A2', 'B1:B2']
I'm trying to figure out some collision, but the compiler keeps showing the error that .slice() is not a function. Here is the code:
var topPos1 = $('#player').css("top");
var rightPos1 = $('#player').css("right");
var topPos2 = $('#player').css("top");
var rightPos2 = $('#player').css("right");
var pos = topPos1.indexOf('px');
topPos1 = parseInt(topPos1.slice(0,pos));
My jQuery is loaded.
Maybe your topPos1 return nothing, if the $('#player') has no css value for top, assigning it to a value will result null or NaN.
You should use log the values to see if the result are correct.
you can't directly slice a number, you can convert it into string then slice after
like this:
topPos1 = parseInt(topPos1.toString().slice(0,pos));
You can just use .replace('px', '') - it will save you one function call
i am trying to pass non numeric index values through JSON but am not getting the data.
var ConditionArray = new Array();
ConditionArray[0] = "1";
ConditionArray[1] = "2";
ConditionArray[2] = "3";
ConditionArray['module'] = "Test";
ConditionArray['table'] = "tab_test";
var Data = JSON.stringify(ConditionArray);
When i alert the Data Variable it has the Values 1,2 and 3 but module and table are not included. How can this be added so that the whole string is passed.
EDIT : And what if i have some multidimensional elements also included like
ConditionArray[0] = new Array();
ConditionArray[0] = "11";
JSON structure only recognizes numeric properties of an Array. Anything else is ignored.
You need an Object structure if you want to mix them.
var ConditionArray = new Object();
This would be an better approach:
var values = {
array : ["1", "2", "3"],
module : "Test",
table : "tab_test"
};
var data = JSON.stringify(values);
Since javascript array accepts numeric index only. If you want non numeric index,use Object instead.
var ConditionArray = {};
ConditionArray[0] = "1";
ConditionArray[1] = "2";
ConditionArray[2] = "3";
ConditionArray['module'] = "Test";
ConditionArray['table'] = "tab_test";
var Data = JSON.stringify(ConditionArray);
Here is the working DEMO : http://jsfiddle.net/cUhha/
According to the algorithm for JSON.stringfy (step 4b), only the (numeric) indices of arrays are stringified.
This is because Array does not contain your elements.
When you do this:
ConditionArray['module'] = "Test";
You actually add a property to the ConditionArray, not elements. While JSON.stringify converts to string only elements of the ConditionArray. For example:
var arr = new Array;
arr['str'] = 'string';
console.log(arr.length) //outputs 0
You need to use an Object instead of Array
If you change the first line to
var ConditionArray = new Object();
you will achieve the desired outcome.
If for some reason you cannot convert your array into object, for instance you are working on a big framework or legacy code that you dont want to touch and your job is only to add som feature which requires JSON API use, you should consider using JSON.stringify(json,function(k,v){}) version of the API.
In the function you can now decide what to do with value of key is of a specific type.
this is the way how I solved this problem
Where tblItemsTypeform is array and arrange is de index of the array
:
let itemsData = [];
for(var i = 0; i <= this.tblItemsTypeform.length -1;i++){
let itemsForms = {
arrange: i,
values: this.tblItemsTypeform[i]
}
itemsData.push(itemsForms)
}
And finally use this in a variable to send to api:
var data = JSON.stringify(itemsData)
This is annoying me.
I'm setting an array in beginning of the doc:
var idPartner;
var myar = new Array();
myar[0] = "http://example.com/"+idPartner;
And I'm getting a number over the address, which is the id of partner. Great. But I'm trying to set it without success:
$.address.change(function(event) {
idPartner = 3;
alert(idPartner);
}
Ok. The alert is giving me the right number, but isn't setting it.
What's wrong?
Changing the value of the variable does not re-set the values within the array. That is just something javascript can't do automatically. You would have to re-generate the array for it to have the new id. Could you add the id to the value where you use the array instead of pre-setting the values in the array containing the id?
Edit: For example, you would do:
var myArray = [];
var myId = 0;
myArray[0] = "http://foo.com/id/";
and when you need to use a value from the array, you would do this:
var theVal = myArray[0] + myId;
Try this:
var myvar = ["http://site.com/"];
$.address.change(function(event) {
myvar[1] = 3;
}
then use myvar.join () where you need the full url.
The problem here is that at the line
myar[0] = "http://site.com/"+idPartner;
..you perform a string concatenation, meaning you copy the resulting string into the array at index position 0.
Hence, when later setting idPartnerit won't have any effect on the previously copied string. To avoid such effect you can either always construct the string again when the idPartnervariable updates or you create an object and you evaluate it when you need it like...
var MyObject = function(){
this.idPartner = 0; //default value
};
MyObject.prototype.getUrl = function(){
return "http://site.com/" + this.idPartner;
};
In this way you could use it like
var myGlblUrlObj = new MyObject();
$.address.change(function(event){
myGlblUrlObj.idPartner = ... /setting it here
});
at some later point you can then always get the correct url using
myGlblUrlObj.getUrl();
Now obviously it depends on the complexity of your situation. Maybe the suggested array solution might work as well, although I prefer having it encapsulated somewhere in an object for better reusability.
myar[0] = "http://site.com/" + idPartner;
After this line, myar[0] = "http://site.com/undefined" and it has nothing to do with the variable idPartner no more.
So, after that changing the value of idPartner will affect the value of myar[0].
You need to change the value of myar[0] itself.