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I have only one number like "100000"
I wan't to split this number same as [20000,20000,20000,20000,20000] in array
so if number is 138000 then it should be like [20000,20000,20000,20000,20000,20000,18000]
How to do this?
let num = 118000,
num_array = [];
while (num > 0) {
if (num >= 20000) {
num_array.push(20000);
num -= 20000;
} else {
num_array.push(num);
break;
}
}
console.log(num_array);
I think this is what you want, please post what you tried, so that it helps to understand where you failed.
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my question is probably simple for most but its troubling me and ive been googling for sometime now.
I dont want allow copy or paste content and emoji characters in input fields.
var checkTf = function() {
let charcode_max = 255;
let tf = document.getElementById("tf");
for (let i = tf.value.length - 1; i >= 0; i--) {
if (tf.value[i].charCodeAt(0) > charcode_max) {
tf.value = tf.value.substr(0, i) + tf.value.substr(i + 1);
}
}
}
<html>
<head></head>
<body>
<textarea id="tf" oninput="checkTf()"></textarea>
</body>
</html>
You may increase charcode_max.
https://jsfiddle.net/qx4dt5bz/
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i want to find any english word (min 4 letters) in one string.
Eg: hello123fdwelcome => ["hello", "welcome"];
Could you suggest for me any solution or javascript lib to match english word.
Thanks
You can use this list of words https://github.com/dwyl/english-words
var input = "hello123fdwelcome";
var fs = require('fs');
fs.readFile("words.txt", function(words) {
var words = words.toString().split('\n').filter(function(word) {
return word.length >= 4;
});
var output = [];
words.forEach(word) {
if (input.match(word)) {
output.push(word);
}
});
console.log(output);
});
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I need to find an element that's text value is 0.
I do:
var d = $('.content').find('div');
if(d.text().length === 0){
//do something
}
Is there a way to put the above logic in the selector?
I've tried:
var d = $('.content').find('div:empty');
But no luck as the div may have other empty html tags in.
Use a filter
var elems = $('.content').find('div').filter(function() { return $(this).text() == 0 });
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I'm taking online class to learn JS and I'm stuck. The quiz is asking me to:
Returns the cube of the sum of an input and 2.
So I coded this:
var returnCubed = function(num){ return (num + 2) * 3;};
But it doesn't pass. What else can I do to take in a parameter, add two to it, then cube it? Or am I not understanding the directions?
Try
var returnCubed = function(num){
return (num+2) * (num+2) * (num+2);
};
*3 will always multiply with 3.
Hope this can solve your problem.
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returns the index where pattern starts in string (or -1 if not found).
The search is to be case sensitive if the 3rd parameter is true otherwise it is case insensitive.
Examples
index("abAB12","AB",true) returns 2 but index("abAB12","AB",false) returns 0
index("abAB12","BA",true) returns -1 and index("abAB12","BA",false) returns 1
Maybe something like:
var str = "abAB12";
var i = str.indexOf("AB");
if (i < str.length / 2) {
//stuff
} else {
//other stuff
}