Comparing a string array with object array [closed] - javascript

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I want to compare two arrays
array1=["123',"456"];
array2=[{id":"001",name:"prashant"},{id:"123",name:"jhh"},{id:"123444",name"baak"},{id:"456",name"sxs"}];
my objective is to extract the objects from array2 whose ids match the values in array1.
Can someone help me with the optimal solution?

First of all your second array (array2) is syntactically invalid.
You can try with Array.prototype.filter() and Array.prototype.includes()
var array1=["123","456"];
var array2 = [{id:"001",name:"prashant"},{id:"123",name:"jhh"},{id:"123444",name:"baak"},{id:"456",name:"sxs"}];
var res = array2.filter(i => array1.includes(i.id));
console.log(res);

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Javascript: check multiple elements in array [closed]

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I have an array: a=[10,11,12,13]. How can check elements from a[0] to a[2] if they >0 in the shortest way and don't use for loop? Does anyone have any ideas? Thank you.
You can slice the array to get the items within the specified indexes, then use filter to filter out the items that don't match the condition and check whether the length of the resulting array is the length of the range.
const a = [10, 11, 12, 13]
const isValid = a.slice(0, 3).filter(e => e > 0).length == 3
//last index in slice is exclusive
console.log(isValid)

convert a javascript object's value-field to array [closed]

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suppose the object is obj ={foo:"bla,bla2,bla3",bar:"bla,bla5"}
I want to convert it to 'obj={foo:["bla","bla2","bla3"],bar:["bla","bla5"]}'
Don't know why you want to do that, but here you can just loop through obj with a for...in loop and split the strings by commas:
const obj = {foo:"bla,bla2,bla3",bar:"bla,bla5"};
for (name in obj) {
obj[name] = obj[name].split(',');
}
console.log(obj)

How to Filter an array of strings based on first word in the string in javascript? [closed]

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With the following array of strings in javascript, is there a way to use the .filter to filter by the first word?
['Desk_One', 'Desk_Two', 'Desk_Three', 'Chair_One', 'Chair_Two']
For example to .filter(x = 'Desk_*')
['Desk_One', 'Desk_Two', 'Desk_Three']
Maybe this needs to be a regex
You can use startsWith() function like this:
let array = ['Desk_One', 'Desk_Two', 'Desk_Three', 'Chair_One', 'Chair_Two'];
let result = array.filter((item)=>item.startsWith(array[0].split('_')[0]));
console.log(result)

Get the minimum value from the array [closed]

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I am trying to get the minimum value from an array without changing the way the the value are aligned.
function removeSmallest(numbers){
var min=Math.min.apply(null,numbers);
var indexvalue=numbers.indexOf(min);
delete numbers[indexvalue];
return numbers;
}
Two issues:
Math.min.apply(null, numbers) should be Math.min.apply(Math, numbers) (note Math instead of null)
Normally, delete is not the right tool for arrays (see this question's answers for details; use splice to remove array entries if you're going to modify the array in place:
numbers.splice(indexvalue, 1);
You might also consider creating and returning a new array instead of mutating and returning the same array you received.

How do I get length of my Json Object [closed]

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Below is my JSON object
{"Decision":[{"recid":"1183","reason":"Approved as Requested","decision":"Approved","approvalamt":"","comment":""},{"recid":"662","reason":"3","decision":"Rejected","approvalamt":"","comment":""},{"recid":"752","reason":"Approved People Resources; But No Funding Approved","decision":"Approved","approvalamt":"","comment":""}]}
How do I get length of this.In this example it should return me 3.
My Object name is DecisionObj which have above listed elements.
var string = '{"Decision":[{"recid":"1183","reason":"Approved as Requested","decision":"Approved","approvalamt":"","comment":""},{"recid":"662","reason":"3","decision":"Rejected","approvalamt":"","comment":""},{"recid":"752","reason":"Approved People Resources; But No Funding Approved","decision":"Approved","approvalamt":"","comment":""}]}';
var object = JSON.parse(string);
alert(object.Decision.length);
Arrays have length property. You can use that.
var length = DecisionObj.length;

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