https://codepen.io/aholston/pen/ZJbrjd
The codepen link has commented code as well as actual instructions in HTML
Otherwise.... what I ultimately have to do is write a function that takes two params(a and b) and takes all the numbers between those two params (a-b) and put every number that can be added to the consecutive fowers and be equal to that number into a new array. Ex: 89 = 8^1 + 9^2 = 89 or 135 = 1^1 + 3^2 + 5^3 = 135
function sumDigPow(a, b) {
// Your code here
var numbers = [];
var checkNum = [];
var finalNum = [];
var total = 0;
for (var i = 1; i <= b; i++) {
if (i >= a && i <= b) {
numbers.push(i);
}
}
for (var x = 0; x < numbers.length; x++) {
var checkNum = numbers[x].toString().split('');
if (checkNum.length == 1) {
var together = parseInt(checkNum);
finalNum.push(together);
} else if (checkNum.length > 1) {
var together = checkNum.join('');
var togNumber = parseInt(together);
for (var y = checkNum.length; y > 0; y--) {
total += Math.pow(checkNum[y - 1], y);
}
if (total == togNumber) {
finalNum.push(togNumber);
}
}
}
return finalNum;
}
try this:
function listnum(a, b) {
var finalNum = [];
for (var i = a; i <= b; i++) {
var x = i;
var y = i;
var tot = 0;
j = i.toString().length;
while (y) {
tot += Math.pow((y%10), j--);
y = Math.floor(y/10);
}
if (tot == x)
finalNum.push(i);
}
return finalNum;
}
console.log(listnum(1, 200));
Okay, after debugging this is what I learned.
for (var y = checkNum.length; y > 0; y--) {
total += Math.pow(checkNum[y - 1], y);
}
if (total == togNumber) {
finalNum.push(togNumber);
}
}
}
return finalNum;
}
Everytime this loop happened, I neglected to reset the 'total' variable back to 0. So I was never getting the right answer for my Math.pow() because my answer was always adding to the previous value of total. In order to fix this, I added var total = 0; after i decided whether or not to push 'togNumber' into 'finalNum.' So my code looks like this..
for (var y = checkNum.length; y > 0; y--) {
total += Math.pow(checkNum[y - 1], y);
}
if (total == togNumber) {
finalNum.push(togNumber);}
}
var total = 0;
}
return finalNum;
}
I want to find the minimum number of characters of the first string that needs to be changed to enable me to make it an anagram of the second string.
1st problem it always return -1
function anagram(s) {
if (s % 2 == 0) {
var len = s.legnth;
var diff = [];
for (var x = 0; x < len / 2; x++) {
var y = s[x]++;
}
for (var x = len / 2; x < s.legnth; x++) {
var z = s[x]++;
}
y = y.sort().splice(",").tostring();
z = y.sort().splice(",").tostring();
for (var x = 0; i < z.length; x++) {
if (y[x] != z[x]) {
diff.push(y[x]);
}
}
return diff.length;
} else {
return -1;
}
}
function main() {
var q = parseInt(readLine());
for (var a0 = 0; a0 < q; a0++) {
var s = readLine();
var result = anagram(s);
process.stdout.write("" + result + "\n");
}
}
I tried to make a code that returns many "9" characters to a string according to an int value.
Ej.: If "y" is equal to 5, "w" should return "99999".
I used the "for" instruction, but it makes the tab freeze.
The code:
var w = "";
var y = "";
function Calc()
{
x = document.getElementById("inputX").value;
y = document.getElementById("inputY").value;
for (var i; i = y.length; i++)
{
w += 9;
}
}
Thanks! (and sorry for my bad english).
I have updated your code. I have changed the condition in the for loop and and initialized i variable.
function Calc()
{
var w = "";
var y = "";
x = document.getElementById("inputX").value;
y = document.getElementById("inputY").value;
for (var i = 0; i < y.length; i++)
{
w += 9;
}
console.log(w);
}
X : <input type="text" id="inputX"><br>
Y : <input type="text" id="inputY"><br>
<button type="button" onclick="Calc()">Calculate</button>
I want to calculate how many Y's & N's appear in an array / range defined:
Cell Range: D4:D42
function myFunction() {
var count = SpreadsheetApp.getActiveSheet().getRange(5, 3, 40, 1);
var numRows = count.getNumRows();
var numCols = count.getNumColumns();
var y = 0;
var n = 0;
for (var i = 1; i <= numRows; i++) {
for (var j = 1; j <= numCols; j++) {
var currentValue = count.getCell(i, j).getValue();
if (currentValue = "y") {
y = y + 1;
} else if (currentValue = "n") {
n = n + 1;
}
}
}
Browser.msgBox("There are " + y + " paid & " + n + " not paid");
}
This returns 40 Y's and 0 N's
Not sure what I am doing wrong here but I think it's a simple fix!
The problem is in this line:
if (currentValue = "y") {
You are assigning "y" to currentValue. To actually check for equality, you should try the "===" operator. Try this and see if it solves your problem:
function myFunction() {
var count = SpreadsheetApp.getActiveSheet().getRange(5, 4, 39, 1);
var numRows = count.getNumRows();
var numCols = count.getNumColumns();
var y = 0;
var n = 0;
for (var i = 1; i <= numRows; i++) {
for (var j = 1; j <= numCols; j++) {
var currentValue = count.getCell(i, j).getValue();
if (currentValue === "y") {
y = y + 1;
} else if (currentValue === "n") {
n = n + 1;
}
}
}
Browser.msgBox("There are " + y + " paid & " + n + " not paid");
}
I also updated the getRange() parameters to match D4:D42. In your code, they matched C5:C44. See the getRange() function documentation.
I have two text boxes. Each will take input up to thousand digits.
Now i want to add these two numbers. My question is what data type should i use to store the result?
I have tried this:
<script>
var x = 'Thousand digit of number'
var y = 'Thousand digit of number'
var z = x + y
</script>
but i am getting result in exponential form. How to store the result and display it?
Yet another solution, because it's faster and cleaner.
function add(A, B) {
const AL = A.length
const BL = B.length
const ML = Math.max(AL, BL)
let carry = 0, sum = ''
for (let i = 1; i <= ML; i++) {
let a = +A.charAt(AL - i)
let b = +B.charAt(BL - i)
let t = carry + a + b
carry = t/10 |0
t %= 10
sum = (i === ML && carry)
? carry*10 + t + sum
: t + sum
}
return sum
}
> add(
'9999999999999999999999999999999999999999999999999999999999999999999999999999',
'999999999999999999999999999999999999999'
)
> "10000000000000000000000000000000000000999999999999999999999999999999999999998"
Use BigInt as described here: https://stackoverflow.com/a/56370672/641913
const z = BigInt(x) + BigInt(y);
console.log(z.toString());
Here is another solution not so different from others you can find in the internet (consider that it doesn't work with negative numbers!):
function sums(arg1, arg2) {
var sum = "";
var r = 0;
var a1, a2, i;
// Pick the shortest string as first parameter and the longest as second parameter in my algorithm
if (arg1.length < arg2.length) {
a1 = arg1;
a2 = arg2;
}
else {
a1 = arg2;
a2 = arg1;
}
a1 = a1.split("").reverse();
a2 = a2.split("").reverse();
// Sum a1 and a2 digits
for (i = 0; i < a2.length; i++) {
var t = ((i < a1.length) ? parseInt(a1[i]) : 0) + parseInt(a2[i]) + r;
sum += t % 10;
r = t < 10 ? 0 : Math.floor(t / 10);
}
// Append the last remain
if (r > 0)
sum += r;
sum = sum.split("").reverse();
// Trim the leading "0"
while (sum[0] == "0")
sum.shift();
return sum.length > 0 ? sum.join("") : "0";
}
// Test
function testEquals(expected, actual) {
if (expected == actual)
console.log("OK: " + expected);
else
console.error("ERROR: " + expected + " != " + actual);
}
testEquals("100", sums("99", "1"));
testEquals("100", sums("00099", "0001"));
testEquals("10000000000", sums("9999999999", "1"));
testEquals("10000010101", sums("9999999999", "10102"));
testEquals("0", sums("0", "0"));
testEquals("1", sums("0", "1"));
testEquals("9", sums("8", "1"));
testEquals("9", sums("1", "8"));
testEquals("10000000000000000000000000000000000000000", sums("9999999999999999999999999999999999999999", "1"));
Input the numbers as string and add each characters each other as array something like this:
function add() {
document.getElementById("demo").innerHTML = "";
var x = document.getElementById("txt1").value;
var y = document.getElementById("txt2").value;
var len;
var lenx = x.length;
var leny = y.length;
var x1,y1,rem,div=0;
if(lenx>leny) len = lenx; else len = leny;
for(var i=0;i<len;i++){
if(i>=lenx) x1 = 0;
else x1 = parseInt(x[lenx-i-1]);
if(i>=leny) y1 = 0;
else y1 = parseInt(y[leny-i-1]);
rem = (x1+y1+div)%10;
div = Math.floor((x1 + y1+div)/10);
document.getElementById("demo").innerHTML = rem + document.getElementById("demo").innerHTML;
}
if(div>0){
document.getElementById("demo").innerHTML = div + document.getElementById("demo").innerHTML;
}
}
Here the code: https://jsfiddle.net/mtsL1k2x/5/
Note: this is only for natural numbers. You can modify depending on your inputs
Either use a big number library like https://mathjs.org/docs/datatypes/bignumbers.html , or you can use something lighter weight (but easy to understand) like http://www.discoversdk.com/knowledge-base/arbitrary-length-integer-addition-in-javascript
Well, if you want to do this without using BigInt or any third-party Library, then I don't think you need to convert to an array, you can use the charAt() function to add the individual characters at each point in the string. You would have to use the for loop starting from its maximum value and reducing till its lowest. The code snippet is below;
function add(a, b) {
let sum='';
let z,x;
let r=0;
if (a.length>=b.length){
z=a;
x=b;
}
else{
z=b;
x=a;
};
let p=x.length;
for (let i=z.length;i>0;i--){
let t=((p>0)?parseInt(x.charAt(p-1)):0)+parseInt(z.charAt(i-1))+r;
sum=(t%10)+sum;
r=t<10?0:Math.floor(t/10);
p=p-1;
};
if (r>0){sum=r+sum};
return sum;
};
function add(a, b) {
a = a.split("").reverse();
b = b.split("").reverse();
let maxLen=Math.max(a.length, b.length);
let sum = [];
let remainder = 0;
for (let i = 0; i < maxLen; i++) {
let x = parseInt(a[i]) ? parseInt(a[i]) : 0;
let y = parseInt(b[i]) ? parseInt(b[i]) : 0;
let digit = (x + y + remainder) % 10;
remainder = Math.floor((x + y + remainder) / 10);
sum.unshift(digit);
}
if (remainder) {sum.unshift(remainder)}
return sum.join("");
}
function add(x, y) {
//this function adds two extremely large numbers, negative and/or positive
var temp, borrow=false, bothNeg=false, oneNeg=false, neg=false;
if (x < 0 && y < 0) { bothNeg = true; x = -x; y = -y; }
else if (x < 0 || y < 0) {
oneNeg = true;
if (Math.abs(x) == Math.abs(y)) { x = 0; y = 0; }
else if (x < 0 && Math.abs(x) > Math.abs(y)) { neg = true; x = -x; y = -y; }
else if (x < 0 && Math.abs(x) < Math.abs(y)) { temp = y; y = x; x = temp; }
else if (y < 0 && Math.abs(x) < Math.abs(y)) { neg = true; temp = y; y = -x; x = -temp; }
}
x = parseInt(x*1000000000/10).toString();
y = parseInt(y*1000000000/10).toString();
var lenx=x.length, leny=y.length, len=(lenx>leny)?lenx:leny, sum="", div=0, x1, y1, rem;
for (var i = 0; i < len; i++) {
x1 = (i >= lenx) ? 0 : parseInt(x[lenx-i-1]);
y1 = (i >= leny) ? 0 : parseInt(y[leny-i-1]);
y1 = (isNaN(y1)) ? 0 : y1;
if (oneNeg) y1 = -y1;
if (borrow) x1 = x1 - 1;
if (y < 0 && x1 > 0 && Math.abs(x1) >= Math.abs(y1)) { borrow=false; div=0; }
if (y < 0 && y1 <= 0 && (x1 < 0 || Math.abs(x1) < Math.abs(y1))) { borrow=true; rem=(x1+y1+div+10)%10; div=10; }
else { rem=(x1+y1+div)%10; div=Math.floor((x1+y1+div)/10); }
sum = Math.abs(rem).toString() + sum;
}
if (div > 0) sum = div.toString() + sum;
sum = parseFloat(sum*10/1000000000);
if (bothNeg || neg) sum = -sum;
return sum;
}
<body>
<p>Click the button to calculate x.</p>
<button onclick="myFunction()">Try it</button>
<br/>
<br/>Enter first number:
<input type="text" id="txt1" name="text1">Enter second number:
<input type="text" id="txt2" name="text2">
<p id="demo"></p>
<script>
function myFunction() {
var y = document.getElementById("txt1").value;
var z = document.getElementById("txt2").value;
var x = +y + +z;
document.getElementById("demo").innerHTML = x;
}
</script>
https://jsfiddle.net/Sanjeevgaut/mtsL1k2x/