I am creating a form which will be submitted through the use of jQuery AJAX, but I am for some reason only able to submit the form once. To submit again I have to refresh page?
How do i accomplish the form and script so I do not have to refresh?
Here is the form:
<form role="form" class="form-horizontal validate" name="create_form" id="create_form">
<div class="form-group">
<label class="col-sm-2 control-label" for="name">Name</label>
<div class="col-sm-10">
<input type="text" class="form-control" id="name" name="name" data-validate="required" data-message-required="Remeber to fill name" placeholder="">
</div>
</div>
<div class="form-group-separator"></div>
<div class="form-group">
<button id="submit_btn" class="btn btn-success">Create</button>
<button type="reset" class="btn btn-white">Reset</button>
</div>
</form>
And here is the AJAX part:
$(document).ready(function(){
$("#submit_btn").on("click", function () {
$.ajax({
type: 'POST',
url: 'data/create.php',
cache: false,
data: $('#create_form').serialize()
})
.done(function(data){
$("#name").val("");
})
.fail(function() {
console.log("ERROR");
});
// Prevent refreshing the whole page page
return false;
});
});
Hoping for help and thanks in advance :-)
use submit instead of click.
$('#submit_btn').on('submit', function(e) {
e.preventDefault();
... //rest of the code
});
I don't really see why you are wanting to run your script on document load. I would suggest you to include the script's source in the html and include an onClick attribute to the button element and then assign the event handler function call to it to be fired every time you click the Submit button.
<button onclick="myFunction()">Click me</button>
<script>
function myFunction() {
document.getElementById("demo").innerHTML = "Hello World";
}
</script>
Related
I’m trying to figure out why $("#submitButton").submit(function() {}); is not working.
I have this <form>:
<div class="card p-2">
<form>
<div class="input-group">
<label for="inputPasswordAgain" class="sr-only">Password</label>
<input type="password" id="inputPasswordAgain" class="form-control" placeholder="Please enter your password again!" required>
<div class="input-group-append">
<button type="submit" id="submitButton" name="submitButton" class="btn btn-secondary btn-block">Submit Changes</button>
</div>
</div>
</form>
</div>
I’ve written this AJAX code in jQuery to pass values to the server.
<script type="text/javascript">
$(document).ready(function() {
$("#submitButton").click(function() {
var data = {};
var i;
for (i = 0; i < $("#sessionQuantity").html(); i++) {
data[i] = $("#" + i).val();
}
$.ajax({
type: "POST",
url: "updateViewing-helper.php",
data: data,
success: function() {}
});
});
});
</script>
Everything works fine if I use .click(function(){…}), but this will call the updateViewing-helper.php without submitting the form with the <input> and <button> elements. This means the user can skip putting their password in, and just click the button.
I tried to use .submit(function(){…}), then use e.preventDefault(), then pass all values into AJAX, then call the updateViewing-helper.php via AJAX, then I can check for the password matching server-side.
But the .submit event is not working: there is not alert or anything.
Call submit on form not on the button
First give id to form
<form id="myForm">
Then call submit on this id
$( document ).ready(function() {
$("#myForm").submit(function(){
});
});
I am using http://www.formvalidator.net/index.html to validate my form but the form gets submitted even when the validation get failed.
Form code:
<form name="add-todo" class="form-horizontal" action="" method="post">
<h5>Add New Item</h5>
<div class="form-group">
<div class="col-md-12">
<input type="text" data-validation="required" class="form-control" id="todo-text-input" name="todo-text">
</div>
</div>
<div class="form-group">
<div class="col-md-12">
<button type="submit" class="btn btn-primary btn-add">Add</button>
</div>
</div>
</form>
jQuery code:
$(document).ready(function() {
$.validate({
modules: 'security'
});
$('form[name=add-todo]').submit(function(e) {
e.preventDefault();
var text = $("#todo-text-input").val();
$('.btn-add').text('Saving ....');
$.ajax({
url: this.action,
type: this.method,
data: {
text: text
},
success: function(response) {
$("#todo-text-input").empty();
$('.messages').removeClass('hide-element');
$('.alert').addClass('alert-success');
$('.alert').text('To do item added successfully.');
$('.alert').fadeTo(2000, 500).slideUp(500, function() {
$('.alert').slideUp(500);
});
}
});
});
});
dont use submit button. You can use
<button type="button" class="btn btn-primary btn-add">Add</button>
after that check your validation status. if its valid then submit the form.
<input type="text" data-validation="required" class="form-control" id="todo-text-input" name="todo-text">
In your input field you don't need to use data-validation="required" just use required like
<input type="text" required class="form-control" id="todo-text-input" name="todo-text">
Please change you form validation code configuration like this:
$.validate({
form : '#registration-form',
modules : 'security',
onSuccess : function($form) {
alert('The form '+$form.attr('id')+' is valid!');
// write your ajax code to submit form data on server
return false; // Will stop the submission of the form
}
});
For more info follow:
http://www.formvalidator.net/index.html#configuration
I am getting problem to save my form data in the database. I am done small code on that which is shown below, when i enter data in form and click on my submit button it not work.
$(".btn").click(function(e) {
e.preventDefault();
var form = $("#frm");
$.ajax({
url: '/Form/Index',
data: form.serialize(),
type: 'POST',
success: function(data) {
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form role="form" id="frm">
<div class="form-group">
<div class="col-sm-6 col-lg-12 col-md-12">
<div class="form-group">
<label for="name" style="color:black;">Product Name</label>
<input type="text" class="form-control" id="name"
placeholder="Product Name" style="color:black;">
</div>
<div class="form-group">
<label for="name" style="color:black;">Product Date</label>
<input type="text" class="form-control" id="Text1"
placeholder="Date" style="color:black;">
</div>
<div class="form-group">
<label for="name" style="color:black;">Product Price</label>
<input type="text" class="form-control" id="Text2"
placeholder="Date" style="color:black;">
</div>
</div>
</div>
<button type="submit" class="btn btn-default" id="ok" >Submit</button>
</form>
Above is my code please give me solution on that
As I've checked you code, client side code is working fine, The only problem I can imagine in this case is you url path.
make sure you are providing correct url path.
You should check if its hitting the that page or not.
Which Framework you are using. Different framework has different syntax to pass the value in URL. Check the path you are getting in the page source page view in URL parameter or you can check the error in console log after the submit. It may be not getting the correct path of your action.
Make sure ajax library loaded successfully, and try to have alert messages to have forward step where you reached, have this test:
$(".btn").click(function(e) {
e.preventDefault();
var form = $("#frm");
$.ajax({
url: '/Form/Index',
data: form.serialize(),
type: 'POST',
success: function(data) {
},
beforeSend: function() {
alert('before send alert')
},
error: function (request, status, error) {
alert(error);
},
});
});
if beforeSend not executed so your issue is related to ajax library.
use this :
$("#ok").click(function(e) {
// your code
}
Refer to id in javascript rather than class attribute.
If you refer class attribute than once it has click javascript perform preventDefault on that class so that if not refresh your page, The button is not working.
Put preventDefault function at last of your function.
Remove the type="submit" from button
You have to get the form submit with id and serialize the form data
`
$("#formid").submit(function(e) {
var url = "urlpathtohandlerequest";
$.ajax({
type: "POST",
url: url,
data: $("#formid").serialize(),
success: function(response)
{
alert(response);
}
});
e.preventDefault(); // stops default submit.
});
`
UPDATE - the contact form is found at this URL.
I am trying to get the following contact form to function, using this tutorial.
I manage to get everything to work as expected on my computer using apache webserver.
After uploading the files to an online website, the ajax function does not kick in.
I seems like the e.preventDefault(); stops working after the upload, and the form is redirected to a new site,and not just being processed on the site without the reload.
I have also been trying to use the return false; instead of e.preventDefault(); without any success.
Her is my code:
.html
<form method="post" action='mail/mail.php'>
<label>Name</label>
<input name="name" id="name" placeholder="Name.." required="true" class="input-field">
<label>Mail</label>
<input type="email" name="email" placeholder="Mail.." required="true" class="input-field">
<label>Msg</label>
<textarea name="message" id="message" class="textarea-field" required="true"></textarea>
<input type="submit" id="submit" name="submit" value="Send">
</form>
<div id="loading">
Sender melding...
</div>
<div id="success">
</div>
.js
$(function(){
$('form').submit(function(e){
var thisForm = $(this);
//Prevent the default form action
//return false;
e.preventDefault();
//Hide the form
$(this).fadeOut(function(){
//Display the "loading" message
$("#loading").fadeIn(function(){
//Post the form to the send script
$.ajax({
type: 'POST',
url: thisForm.attr("action"),
data: thisForm.serialize(),
//Wait for a successful response
success: function(data){
//Hide the "loading" message
$("#loading").fadeOut(function(){
//Display the "success" message
$("#success").text(data).fadeIn();
});
}
});
});
});
})
Please help!
That's because your JS is missing a closing });. Please check this demo to confirm that the default action is indeed prevented and the ajax does kick in. However, I was expecting a POST but instead I am seeing an OPTIONS request.
NOTE: Giving an element a name or id attribute value of submit is bad practice. You cannot for example use JavaScript to submit the form via default form submission -- this.submit() or $('form')[0].submit() without getting the error ...submit() is not a function .....
$(function() {
$('form').submit(function(e) {
var thisForm = $(this);
//Prevent the default form action
//return false;
e.preventDefault();
//Hide the form
$(this).fadeOut(function() {
//Display the "loading" message
$("#loading").fadeIn(function() {
//Post the form to the send script
$.ajax({
type: 'POST',
url: thisForm.attr("action"),
data: thisForm.serialize(),
//Wait for a successful response
success: function(data) {
//Hide the "loading" message
$("#loading").fadeOut(function() {
//Display the "success" message
$("#success").text(data).fadeIn();
});
}
});
});
});
});
}); // <==== MISSING THIS
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<form method="post" action='mail/mail.php'>
<label>Name</label>
<input name="name" id="name" placeholder="Name.." required="true" class="input-field">
<label>Mail</label>
<input type="email" name="email" placeholder="Mail.." required="true" class="input-field">
<label>Msg</label>
<textarea name="message" id="message" class="textarea-field" required="true"></textarea>
<input type="submit" id="submit" name="submit" value="Send">
</form>
<div id="loading">
Sender melding...
</div>
<div id="success">
</div>
Since you are submitting via AJAX anyway, you may find it easier to change your input type to button, and bind to click instead of form submit, to avoid the default submit behaviour you are trying to circumvent.
I'm using Ajax to submit the login form without refreshing the page. I've added a function to see whether the data returns 'error' (which comes up when the user enters an incorrect email/password). If it does not return 'error', the user has been logged in and will be transferred to the page within 2 seconds.
The problem is that my button acts like a double-click button and I cannot see why. This is my JS file:
$(function() {
$("#goLogin").click(function() {
$.ajax({
type: "POST",
url: "db-requests/db-login.php",
data: $("#loginForm").serialize(),
success: function(data,textStatus,jqXHR){ finishLogin(data,textStatus,jqXHR); }
});
});
});
function finishLogin( data , textStatus ,jqXHR ) {
if ( data == "error" ) {
$('.errorMsg').fadeIn(500).hide();
$('.succesMsg').fadeOut(300).hide();
} else {
$('.succesMsg').fadeIn(500).show();
$('.errorMsg').fadeOut(300).hide();
setTimeout("location.href = 'protected.php';",2000);
}
}
I've tried placing it between the document_ready tags, but that isn't working either.
Part of the HTML code:
<div class="login form">
<div class="login-header">Please Login</div>
<form method="post" id="loginForm" name="form">
<label for="email" class="short">Email*</label>
<input type="text" name="email" id="email" class="required" placeholder="" />
<label for="password" class="short">Password *</label>
<input type="password" name="password" id="password" class="required" placeholder="" maxlength="15" />
</form>
<div id="login-functions">
<div class="loginbtn-container">
<input type="submit" id="goLogin" name="goLogin" class="button green" value="Login" />
</div>
<div class="login form actions">
<p class="register account">Register an account</p>
<p class="request password">Lost your password?</p>
</div>
</div>
</div>
<div class="errorMsg">Incorrect. Please recheck your details</div>
<div class="succesMsg"><b>You've been logged in!</b> Please wait while we transfer you</div>
$('.errorMsg').fadeIn(500).hide();
$('.succesMsg').fadeOut(300).hide();
did you mean tto hide both? I see the click is working fine, though you should ideally do submit
Take your submit inside the form, and prevent normal form submit using preventDefault()
$("#goLogin").submit(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "db-requests/db-login.php",
data: $("#loginForm").serialize(),
success: function(data,textStatus,jqXHR){ finishLogin(data,textStatus,jqXHR); }
});
});
Please move your submit button inside the form closing tag first
<input type="submit" id="goLogin" name="goLogin" class="button green" value="Inloggen" />
The above button is placed after the </form> tag.
Because you click on input type submit and progress Ajax on it; it cause submit 2 times.
To avoid it, you can use as Zach Leighton said above ; or use as below
$("#goLogin").click(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "db-requests/db-login.php",
data: $("#loginForm").serialize(),
success: function(data,textStatus,jqXHR){ finishLogin(data,textStatus,jqXHR); }
});
});