I stored some values in HTML table to MySQL database. It successfully stored in the database, but when I fetched the data using Json decode(), the Html table nothing shows any data in the web page, but nothing error occurred.
Here is the php code:
<table class="table table-bordered mb-0">
<thead>
<tr>
<th>Medicine Name</th>
<th>Morning</th>
<th>Noon</th>
<th>Noght</th>
</tr>
</thead>
<tbody>
<?php
require_once 'auth/dbconnection.php';
$sql = "SELECT * FROM prescription";
if($result = mysqli_query($conn, $sql)){
if(mysqli_num_rows($result) > 0){
$medRecords = json_decode($row['med_records'],true);
if (is_array($medRecords) || is_object($medRecords)) {
foreach($medRecords as $key => $object) {
?> <tr>
<td><?php echo $object->medname ?></td>
<td><?php echo $object->morning ?></td>
<td><?php echo $object->noon ?></td>
<td><?php echo $object->night ?></td>
</tr>
<?php
} }}}
?>
</tbody>
</table>
Here is my database table
I don't know where I went wrong. How to improve the code segments?
Notice that you missing the fetch itself: $result->fetch_assoc()
You using the var $row but from where?
I think you code should be as:
$sql = "SELECT * FROM prescription";
if($result = mysqli_query($conn, $sql)){
if(mysqli_num_rows($result) > 0){
while ($row = $result->fetch_assoc()) { <---- Notice this line
$medRecords = json_decode($row['med_records'],true);
if (is_array($medRecords) || is_object($medRecords)) {
foreach($medRecords as $key => $object) {
...
Related
So I have built a very basic application system. I have made one page where I can see all the applications in a table via MySQL query. I have also made so I can click a button to either approve or deny the application. Dependning on which button I press, the row with that specific user will be moved do the approved or denied table in the database. But, I want to display an alert when pressing the different buttons at the same time they send the row id to the PHP code.
Here is my code for the application table site: (register.php)
<?php
$query = "SELECT * FROM ansokningar";
$query_run = mysqli_query($link, $query);
?>
<table class="table table-bordered" id="dataTable" width="100%" cellspacing="0">
<thead>
<tr>
<th> ID </th>
<th> Förnamn </th>
<th>Efternamn </th>
<th>Mejladress</th>
<th>Ålder</th>
<th>Ansökt som</th>
<th>Läs Ansökning</th>
<th>Godkänn</th>
<th>Neka</th>
</tr>
</thead>
<tbody>
<?php
if(mysqli_num_rows($query_run) > 0)
{
while($row = mysqli_fetch_assoc($query_run))
{
?>
<tr>
<td><?php echo $row['id']; ?></td>
<td><?php echo $row['fornamn']; ?></td>
<td><?php echo $row['efternamn']; ?></td>
<td><?php echo $row['mejladress']; ?></td>
<td><?php echo $row['alder']; ?></td>
<td><?php echo $row['intresseradavyrket']; ?></td>
<td>
<form action="register.php" method="post">
<input type="hidden" id="deleteid" name="delete" value="<?php echo $row['id']; ?>">
<center> <button id="delete" type="submit" name="delete" class="btn btn-danger btn-circle btn-sm">
<i class="fas fa-trash"></i></button></center>
</form>
</td>
</tr>
<?php
}
}
else {
echo $ingaansokning;
}
mysqli_close($link);
?>
And here is my PHP code for moving the row: (neka.php)
<?PHP require '../db/dbconfig.php';
if(isset($_POST['id']))
{
$id = $_POST['id'];
$query = "
INSERT INTO nekade SELECT * FROM ansokningar WHERE id='$id';
DELETE FROM ansokningar WHERE id='$id';
";
$query_run = $link->multi_query($query);
if($query_run)
{
$_SESSION['success'] = '';
header('Location: ../../register.php');
exit();
How do I send the row ID from the first page to the second and display one alert when it's done?
I have tried this on the first page (register.php) but it doesn't work:
<script>
$(function(){
$('#delete').click(function() {
var id = <?php echo $row['id']; ?>;
$.ajax({
type: 'POST',
url: 'includes/ansokningar/neka.php',
data:{id: id},
success: function(data){
Swal.fire(
'Grattis!',
'Din ansökan är nu skickad!',
'success'
)
}
})
})
});
(Without the ajax stuff it works to move the user to the other table)
Thanks!
I want to print information that depends on the $stud_no using iframe. When I show the iframe in the table, it generates a correct $stud_no. But when I click the print button it only shows the First $stud_no. It's like the button didn't GET the id in admin_print-app-form-view.php
admin_print-app-form.php
<table id="dataTable2" class="text-center">
<thead class="text-capitalize">
<tr>
<th>NO.</th>
<th>LAST NAME</th>
<th>FIRST NAME</th>
<th>MIDDLE NAME</th>
<th>SEX</th>
<th>CONTACT NO.</th>
<th>ENTRY</th>
<th>ACTION</th>
</tr>
</thead>
<tbody>
<?php
$sql = "SELECT * FROM stud_acc";
$result = $con->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$iframeId = 'studframe' . $row['stud_no'];
$stud_no = $row['stud_no'];
$lastname = $row['lastname'];
$firstname = $row['firstname'];
$middlename = $row['middlename'];
$sex = $row['sex'];
$contact = $row['contact'];
$entry = $row['entry'];?>
<tr>
<td><?php echo $stud_no ?></td>
<td><?php echo $lastname ?></td>
<td><?php echo $firstname ?></td>
<td><?php echo $middlename ?></td>
<td><?php echo $sex ?></td>
<td><?php echo $contact ?></td>
<td><?php echo $entry ?></td>
<td>
<iframe src="admin_print-app-form-view.php?id=<?php echo "$stud_no"?>" name="frame" id="<?= $iframeId ?>" style="visibility:hidden;height:0px;width:0px"></iframe>
<button type="button" class="btn btn-roundedtb btn-info" onclick="document.getElementById('<?= $iframeId ?>').print();"><i class="fa fa-print"></i><span class="icon-name"> Print</span></button>
</td>
</tr>
} }?>
</tbody>
</table>
admin_print-app-form-view.php
<?php
session_start();
include("connection.php");
$stud_no = $_GET['id'];
?>
This is the print preview.The number in the Red circle should be the $stud_no that I clicked, but it always gives me first stud_no
The issue is that when you give the same name and id to every iframe, javascript will only give you the first match it finds, returning the same iframe for all buttons.
We need to give them unique id's (we can skip the name altogether).
Note: This code assumes that stud_no is a unique value, like the tables primary key.
In your while-loop, create a unique id:
while($row = $result->fetch_assoc()) {
// Create a unique id using the stud_no
$iframeId = 'studframe' . $row['stud_no'];
Now give the iframe that id:
<iframe ... id="<?= $iframeId ?>" ... ></iframe>
And make sure the button refers to that id:
<button ... onclick="document.title=''; document.getElementById('<?= $iframeId ?>').print();">...</button>
In the above code, I've created unique id's by prefixing them with studframe and then added the stud_no so it becomes id="studframe1", id="studframe2" and so on.
Then when referring to that specific iframe, we're fetching the iframe based on that unique id.
I have a table that I wish to display in my .php file, as it will display every number of each row but when it comes to a brand new year, it will changes to begin at 1 once again.
.php file html code:
<table id="example">
<thead>
<tr>
<th style="width: 40px">Year</th>
<th style="width: 40px">Id</th>
</tr>
</thead>
<tbody>
<?php
include('include/config1.php');
$query = "SELECT * from table ORDER BY Id DESC";
$result = mysqli_query($db, $query);
while ($row = mysqli_fetch_assoc($result)) {
?>
<tr>
<td><?php
if($row['status']!=3){ //display the year from the date according to status
echo date("Y",strtotime($row['sdate'])); }
else{
echo date("Y",strtotime($row['ssdate']));
} ?>
//the years are the same for both columns in each row
</td>
<td>//The ID that auto starts from 1 every year with an increment of 1 to the newest (not the same as the unique id from the table </td>
<?php}?>
</tbody>
</table>
What kind of javascript functions I must implement to make this work?
NOTE: all the data inserted into the MySQL table will not be removed from the database, the status will only change to delete, that's all.
First of all, If you want your records to be sorted year after year, you also have to sort by the date field!
"SELECT * from table ORDER BY sdate,Id DESC";
And secondly you will have to remember your previous year in a loop, and compare it to the current. If it is different, then reset your ID to 1
<?php
include('include/config1.php');
$query = "SELECT * from table ORDER BY sdate, Id DESC";
$result = mysqli_query($db, $query);
$currentYear = null;
$data = [];
while ($row = mysqli_fetch_assoc($result)) {
$year = ($row['status'] == 3) ? date("Y", strtotime($row['ssdate'])) : date("Y", strtotime($row['sdate']));
$data[$year][] = $row;
}
?>
<table id="example">
<thead>
<tr>
<th style="width: 40px">Year</th>
<th style="width: 40px">Id</th>
<th style="width: 80px">Machine No</th>
<th style="width: 80px">Project Name</th>
<th style="width: 80px">PIC</th>
<th style="width: 80px">Purpose of Service</th>
</tr>
</thead>
<tbody>
<?php
foreach ($data as $year => $oneYear) {
for ($i = count($oneYear); $i >= 1; $i--) {
?>
<tr>
<td><?= $year ?></td>
<td><?= $i ?></td>
<td><?= $oneYear[$i]['Machine_No']; ?></td>
<td><?= $oneYear[$i]['projectName']; ?></td>
<td><?= $oneYear[$i]['pic']; ?></td>
<td><?= substr(str_replace('\r\n', "\r\n", $row['Purpose_of_Service']), 0, 50); ?></td>
</tr>
<?php
}
}
?>
</tbody>
</table>
Based on #Dmitriy Gritsenko's Help I've managed to did it, but the problem is that the other data from the columns of the table couldn't be display
<table id="example" >
<thead>
<tr>
<th style="width: 40px">Year</th>
<th style="width: 40px">Id</th>
<th style="width: 80px">Machine No</th>
<th style="width: 80px">Project Name</th>
<th style="width: 80px">PIC</th>
<th style="width: 80px">Purpose of Service</th>
</tr>
</thead>
<tbody>
<?php
include('include/config1.php');
$query = "SELECT * from table ORDER BY sdate DESC, Id DESC";
$result = mysqli_query($db, $query);
$currentYear = null;
$data = [];
while ($row = mysqli_fetch_assoc($result)) {
$year = ($row['status'] == 3) ? date("Y", strtotime($row['ssdate'])) : date("Y", strtotime($row['sdate']));
$data[$year][] = $row;
}
foreach ($data as $year => $oneYear) {
for ($i = count($oneYear); $i >= 1; $i--) {
?>
<tr>
<td><?= $year ?></td>
<td><?= $i ?></td>
<td><?php echo $row['Machine_No']; ?></td>
<td><?php echo $row['projectName']; ?></td>
<td><?php echo $row['pic']; ?></td>
<td><?php
$row['Purpose_of_Service'] =substr( $row['Purpose_of_Service'],0,50);
echo (str_replace('\r\n', "\r\n", $row['Purpose_of_Service']));
?>
</td>
<?php
}}
?>
</tbody>
</table>
<table>
<tr>
<th>image</th>
</tr>
<?php
$query = "SELECT * FROM collage";
$result = mysqli_query($con, $query);
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><img src="img/collage/<?php echo $row['file'] ?>"></td>
</tr>
<?php
}
?>
</table>
hello genius programmers!
my above code display images like this:
and i wanted it to become like this :
Set <tr></tr> out of <?php ?>
try this
<table>
<tr>
<th>image</th>
</tr>
<tr>
<?php
$query = "SELECT * FROM collage";
$result = mysqli_query($con, $query);
while($row = mysqli_fetch_array($result))
{
?>
<td><img src="img/collage/<?php echo $row['file'] ?>"></td>
<?php
}
?>
</tr>
</table>
You are currently looping for table rows. You need an inner loop for table cells in order to get the table design you've mentioned.
Here is a reference: http://www.w3schools.com/html/html_tables.asp
It will be something like this:
<?php
$query = "SELECT * FROM collage";
$result = mysqli_query($con, $query);
while($row = mysqli_fetch_array($result))
{
?>
<td><img src="img/collage/<?php echo $row['file'] ?>"></td>
<?php
}
?>
i have a trouble with the datatables there.
I trying to add a datatables with responsive as the image
It's ok when i put it as a separate file but when i add the data from my database, i can not press on the plus icon to show detail about the member as the image
i just change the data and i don't know why it doesn't work.
Can you help?
This is my code: (i did close php tag for the first open php but i dont know why i can not post it on here)
<?php
$stt= 1;
$sql= "SELECT * from users ORDER BY level DESC";
//thuc hien cau lenh voi bien conn lay tu file connection.php
$query= mysqli_query($conn, $sql);
while ($data=mysqli_fetch_array($query)){
<tr>
<th scope="row"><?php echo $stt++?></th>
<td><?php echo $data["firstname"]?></td>
<td><?php echo $data["lastname"]?></td>
<td><?php echo $data["username"]?></td>
<td><?php echo $data["email"]?></td>
<td><?php echo $data["phone"]?></td>
<td>
<?php
if($data["level"] == 1){
echo "Administrator";
}else{
echo "Member";
}
?>
</td>
<td>
Detail
</td>
</tr>
<?php
}
?>
Please change your code
<th scope="row"><?php echo $stt++?></th>
to
<td scope="row"><?php echo $stt++?></td>
change th to td will fix your problem.