This question already has answers here:
Is floating point math broken?
(31 answers)
Closed 3 years ago.
Using the parseFloat method converted the string value from the DB to float and multiplied by 100. But the output looks odd. Following the piece of code which I've used.
parseFloat(upliftPer) * 100 //upliftPer value read from DB and its value is 0.0099
So when it multiplied with 100 getting 0.9900000000000001 I suppose to get 0.99 but some junk values getting appended. Also I went ahead and did the same in the console log of chrome browser still the same result. I have attached screenshots for reference. Solution I needed is 0.0099 * 100 should result 0.99. I cant apply round / toFixed since I need more precision.
This is because of JavaScript internal casting to double type. There's always a certain degree of noise due to floating point inaccuracy. Here's some information on that.
You can just round it up using toFixed(x) with as much decimal spaces of precision as you want (or as much as JavaScript would allow you).
It is not related to JavaScript nor to any programming language.
It’s because of the conversion from decimal floating-point to binary representation: the process ends up in an infinite process that has to be truncated because of the limited number of bits available for storing the numbers (and thus, of the limited amount of memory in computers)
Check out the process of conversion and take a look at this converter that tells you how much error there is during conversion
As #sebasaenz pointed out in his answer, you can use toFixed(x) to round up your number and get rid of junk
Related
I'm trying to write a function that would fetch me the number of decimal places after the decimal point in a floating-point literal using the answer as a reference from here.
Although this seems to work fine when tried in the browser consoles, in the Node.js environment while running test cases, the precision is truncated only up to 14 digits.
let data = 123.834756380650877834678
console.log(data) // 123.83475638065088
And the function returns 14 as the answer.
Why is the rounding off happening at rest? Is it a default behavior?
The floating-point format used in JavaScript (and presumably Node.js) is IEEE-754 binary64. When 123.834756380650877834678 is used in source code, it is converted to the nearest representable value, which is 123.834756380650873097692965529859066009521484375.
When this is converted to a string with default formatting, JavaScript uses just enough digits to uniquely distinguish the value. For 123.834756380650873097692965529859066009521484375, this should produce “123.83475638065087”. If you are getting “123.83475638065088”, which differs in the last digit, then the software you are using does not conform to the JavaScript specification (ECMAScript).
In any case, the binary64 format does not have sufficient precision to preserve the information that the original numeral, “123.834756380650877834678”, has 21 digits after the decimal point.
The code you link to also does not and cannot compute the number of digits in an original numeral. It computes the number of digits needed to uniquely distinguish the value represented after conversion to binary64. For sufficiently short numerals without trailing zeros after the decimal point, this is the same as the number of digits after the decimal point in the original numeral. For others, it may not be.
it is default behavior of JavaScript.I think it will be same in node.js.
in JS The maximum number of decimals is 17.
for more details take a look at here
Hello guys I'm working on javascript file about astronomical calculations so I need more precisions.
I have a lot operations for each line and I want like result more precision (also ten or twenty decimal after comma).
In JavaScript if I do not declare number of decimal (for example using .ToFixed(n)), how many positions after the comma, the language consider during the calculation?
For example:
var a= 1.123456789*3.5; // result 3.9320987615
var b= a/0.321;
var c= b*a;
// c => 48.16635722800571
It will be the result?
Like using all decimal after comma for each variables of javascript does approximations ?
Why in other questions users suggests to use decimal.js or other libraries?
I'm sorry if my question seems stupid but for me is important.
I hope you can help me.
Sorry for my english !
Javascript uses IEEE-754 double-precision, that means it only calculates numbers to around 15 decimal digits of precision, any more than that gets cut off. If you need more precision you have to use decimal.js or another similar library. Other questions recommend decimal.js or other libraries is because it is easy to put into your program and can provide as much precision as you want.
The reason it isn't implemented in the computer by default is that it takes a lot more effort for the computer to calculate to 20 digits over 15 digits because the computer is built to compute only to 15 decimal digits. If you want to read more on it I would recommend reading Arbitrary Precision Arithmetic on Wikipedia.
Simply because the toFixed() method converts a number into a string, keeping a specified number of decimals. So, the returned value will be a string not a number.
I have a WCF service operation that returns an object with long and List<string> properties. When I test the operation in a WCF application, everything works fine and the values are correct. However, I need to be able to call the service using jQuery and JSON format. The value of the long property apparently changes when I read it back in the OnSucceed function.
After searching I've found that JSON.stringify changes big values. So in code like this:
alert(JSON.stringify(25001509088465005));
...it will show the value as 25001509088465004.
What is happening?
Demo here: http://jsfiddle.net/naveen/tPKw7/
JavaScript represents numbers using IEEE-754 double-precision (64 bit) format. As I understand it this gives you 53 bits precision, or fifteen to sixteen decimal digits. Your number has more digits than JavaScript can cope with, so you end up with an approximation.
Do you need to do maths operations on this big number? Because if its just some kind of ID you can return it as a string and avoid the problem.
It's kinda hard to believe -- but I can't find info about the largest possible integer allowed in node.js, in either Google or SO. There are plenty of articles on the largest integer in browser Javascript, but I just wonder things could be different in node.js.
Can anyone give some pointer? Thanks!
There are plenty of articles on the largest integer in browser Javascript, but I just wonder things could be different in node.js.
No. JavaScript is JavaScript, a language defined by specification. So the answers you find for "browser JavaScript" also apply to NodeJS.
The maximum integer value that can be represented by a IEEE-754 double-precision binary floating point number (the kind JavaScript uses) is 1.7976931348623157 x 10308, which is available in JavaScript as Number.MAX_VALUE.
The maximum integer that you can reliably add 1 to and not get the same value back due to a loss of precision is Number.MAX_SAFE_INTEGER, which is 9,007,199,254,740,991. That is, 9007199254740991 + 1 is 9007199254740992, but 9007199254740992 + 1 is also 9007199254740992. There are much larger integers that can be held (see above), but the gaps between them grow as the value increases.
This question already has answers here:
How to deal with floating point number precision in JavaScript?
(47 answers)
Closed 8 years ago.
Is there any way to solve this problem?
Because floating points are represented in binary, not decimal. Some decimal numbers will not be represented precisely. And unfortunately, since Javascript only has one Number class, it's not a very good tool for this job. Other languages have decent decimal libraries designed to avoid precisely this kind of error. You're going to have to either accept one-cent errors, implement a solution server-side, or work very hard to fix this.
See:
JavaScript floating point number problem
Binary representation of floating point number php/java (Server side)
Because floats (read: doubles) in javascript are not very accurate, you could round the number to use fewer decimals to hide the issue. A very hackish way to do that is to do:
var num = 1.3*1.3;
Math.round(num * 100)/100;