I want to render child component when I click the button
Parents
const Parents:React.FC<PropTypes> = ({inputs}) => {
return(
<div>
<Button onClick={() => <Child props={inputs}/>}
</div>
)}
Child
const Child:React.FC<AnotherPropTypes> = ({props}) => {
// ...
}
I am using React, TypeScript and Material-UI for it.
My question is that, it does not seem like onClick event trigger Child component. How can I run child component when I click the button?
Any help appreciated!
Add state to your component. The click event sets the state, and the state is used to decide whether or not to render extra things.
const Parents:React.FC<PropTypes> = ({inputs}) => {
const [showChild, setShowChild] = useState(false);
return(
<div>
<Button onClick={() => setShowChild(true)} />
{showChild && <Child props={inputs}/>}
</div>
)
}
Related
I'm a bit surprised I'm having trouble finding this online, but I can't seem to find an example of how to do this in a React functional component. I have a React component that I would like to render when I click a button. Right now the function fires and I can see my console.log firing, however the component isn't rendering. My first guess was that it won't render because React doesn't know to update the view, however I added boolean via useState and it still won't render. What am I doing wrong?
Below is the relevant code. How can I get the component in addSection to render?
const FormGroup = ({index}) => {
const [additionalSection, setAdditionalSection] = useState(false);
const addSection = form => {
setAdditionalSection(true);
console.log('form', form);
return additionalSection && (
<div key={form.prop}>
<p>This should render</p>
<AdditiveSection
form={form}
register={register}
errors={errors}
/>
</div>
);
};
...
return (
...
<FormAdd>
<LinkButton
type="button"
onClick={() => addSection(form)}
>
span className="button--small">{form.button}</span>
</LinkButton>
</FormAdd>
);
You should change your state (or a prop in your useEffect dependency array in case you had one) in order to force a rerender. In this case:
setAdditionalSection(prevState=>!prevState);
A state change like the one you are calling, will trigger a re-render.
But all html to be rendered must be included in the functional components return statement.
The elements you want to render can be conditionally rendered like this:
const FormGroup = ({index}) => {
const [additionalSection, setAdditionalSection] = useState(false);
const addSection = form => {
setAdditionalSection(true);
console.log('form', form);
};
...
return (
...
<FormAdd>
<LinkButton
type="button"
onClick={() => addSection(form)}
>
<span className="button--small">{form.button}</span>
</LinkButton>
{additionalSection &&
<div key={form.prop}>
<p>This should render</p>
<AdditiveSection
form={form}
register={register}
errors={errors}
/>
</div>
}
</FormAdd>
);
Am trying to render a new component onclick a button in react js. Am using functional components and I can't handle it. Eg: am in the UserManagement component and on a button click I need to render another component named employee management.
You can conditionally render your component.
Example :
EmployeeManagement.js
const EmployeeManagement = () => {
....
return (
<div>
EmployeeManagement
</div>
);
}
UserManagement.js
const UserManagement = () => {
const [hasRender, setRender] = useState(false);
const onShow = React.useCallback(() => setRender(true), []);
return (
<>
<button onClick={onShow}>Show Employee Management</button>
{hasRender && <EmployeeManagement />}
</>
)
}
One way to do this would be to add a local state in UserManagement,
that holds a boolean value indication whether the component should be hidden or shown.
Then you will have something like:
function UserManagement() {
const [compIsShown, setCompIsShown] = useState(false);
return (
// Whatever else you're rendering.
<button onClick={() => setCompIsShown(true)}>...</button>
{compIsShown && <OtherComp />}
)
}
What will happen is that compIsShown will initialize as false,
so this condition compIsShown && <OtherComp /> will prevent it from rendering.
Then, when you click the button, the state will set, causing a re-render, except now the condition will be true, so <OtherComp> will be rendered.
There are other ways to go about this.
Depends mostly on the use-case.
use a visible state & toggle it in onClick:
const [visible, setVisible] = useState(false)
onClick = () => {setVisible(true)}
then render it like this:
{visible && <EmployeeManagement onClick={onClick} />}
I have a component with two children, one of them is a button that toggles a state (modalVisible) that decides whether the other child, a modal, is visible.
I'm having trouble sharing the on/off state across the parent and the modal child. I tried keeping the state in the parent and then passing it as a prop to the child, but it wasn't rerendering the child everytime the parent state changed.
<CommentsModal visible={modalVisible} />
Inside CommentsModal.js...
import Modal from 'react-native-modal';
...
const CommentsModal = ({visible}) => {
const [modalVisible, setModalVisible] = useState(visible);
...
return <Modal visible={modalVisible} />
}
I considered keeping the state entirely in the parent, without passing it into CommentsModal, like so:
function renderModal() {
if (modalVisible) {
return <CommentsModal visible={true} />
} else {
return <View />
}
}
But I realized that there has to be a state inside CommentsModal because I need an "X" button that toggles the modal off.
I'm not sure what the best way to do this is... I could do redux, but since there is a dynamic number of these modals; I don't want my store to be that complicated. The only way I can think of is to move all of the modal code into the parent component, then they can share states easily, but it seems dirty to me. Does anyone have a solution?
Your intuition to keep the state in the parent component is correct. To implement the x button all you need is to pass a onClose prop to the modal which would be a function that sets modalVisible to false. so you'll end up with something like this:
// parent component
const ParentComponent = () => {
const [modalVisible, setModalVisible] = useState(false);
const openModal = () => setModalVisible(true);
const closeModal = () => setModalVisible(false);
return (
<div>
<CommentsModal visible={modalVisible} onClose={closeModal} />
<button onClick={openModal}>open the modal</button>
<p>other children here...</p>
</div>
)
}
// CommentsModal
const CommentsModal = (props) => (
<Modal visible={props.visible}>
<button onClick={props.onClose}>X</button>
<p>more modal content here...</p>
</Modal>
)
I am working with a form in react, and what I would like is that when I click a button, I add a new component which is just an input to the screen. It all mostly works, as planned. The issue is with the following: the layout is that I have one main component, which then displays a child component. That child component is called from a map of a useState. (More after code snippet)
This is the code of the main component:
import React, { useState } from "react";
import SingleProfile from "./individual_profile";
const ProfileInformation = (props) => {
console.log("proflie render");
const [ProfilesBoolean, setProfilesBoolean] = useState(false);
const [profiles, setProfiles] = useState(props.Data['profiles'])
const FieldAdd = (event)=>{
event.preventDefault();
const copy = profiles;
copy.push({Network:'',url:''})
return(copy)
}
function CreateInput(){
return profiles.map((data, index) =><SingleProfile index={index} data={data} />)
}
const accordion = (event) => {
const NextElement = event.target.nextElementSibling;
if (!event.target.className.includes("display")) {
NextElement.style.maxHeight = NextElement.scrollHeight + "px";
} else {
NextElement.style.maxHeight = 0;
}
};
return (
<div className="AccordionItem">
<div
className={
ProfilesBoolean ? "AccordionHeader-display" : "AccordionHeader"
}
onClick={(e) => setProfilesBoolean(!ProfilesBoolean)}
id="ProfileForm"
>
Profiles
</div>
<div className="AccordionContent">
<div className="AccordionBody">
{
profiles.map((data, index) => (
<SingleProfile index={index} data={data} />
))
}
<button id="ProfileAdd" onClick={(e) => {setProfiles(FieldAdd(e))}}>
Add a profile
</button>
</div>
</div>
</div>
);
};
export default ProfileInformation;
When I click the button and onClick fires FieldAdd() the useState updates, with a new empty object as expected. However, it does not appear inside my <div className="AccordionBody"> as I would expect it to.
The following code is used to display components, by opening and closing the child div. When it is open is when you see the child components and the add button. If I click the div, to close and then click again to re-open it, the new child component appears.
<div
className={ProfilesBoolean ? "AccordionHeader-display" : "AccordionHeader"}
onClick={(e) => setProfilesBoolean(!ProfilesBoolean)}
id="ProfileForm"
>
Profiles
</div>;
Is it possible to have the child component appear without having to close and re-open the div?
Your clickHandler FieldAdd is incorrect. You are mutating the state directly which will not cause re-render.
use setProfiles to update the state in the clickHandler. Like this
const FieldAdd = (event)=>{
setProfiles(prev => [...prev, {Network:'',url:''}])
}
Trigger the onClick like this
<button id="ProfileAdd" onClick={(e) => {FieldAdd(e)}}>
Add a profile
</button>
...
I checked quite a lot of examples but found most of them having events fired in Child Component.
Can someone please suggest how can I call the Parent Component's function in child with the click event on Parent Component? Thanks.
Parent Component (app.js):
Class App extends Component {
handleClick = (e, id, text) => {
e.preventDefault();
this.setState({val: text})
}
render() {
return (
<div>
<Form val={this.state.val} Click={this.handleClick.bind(this) }/>
<Button onClick={(e) => this.handleClick(e, todo.id, todo.text)}>
<Icon>edit_icon</Icon>
</Button>
</div>
)
}
}
Child Component (form.js):
this.props.Click(); //where should i call this function since my button is in parent component
Class Form extends Component{
render() {
const { text } = this.state;
return (
<TextField
value={text}
color="secondary"
/>
)
}
}
}
If you want to call it in your Child component, you need an event to trigger it or maybe a condition. So, for example in your form.js, we will trigger it with a button click form your child component
render() {
const { text } = this.state;
return (
<TextField
value={text}
color="secondary"
/>
<Button onClick={this.props.Click} />
)
}
}
Maybe, using a Button in your child component is not a great choice for your case since you already have a Button to call the Click function in your parent component, this Button in child component I made is only for example
One way you can do this is use a ref to call the function..
// create the ref
constructor() {
super();
this.myFormRef = React.createRef()
}
// click handler for the button
handleClick = (e, id, text) => {
// here you have the child instance which gives you access to its functions
this.myFormRef.someChildMethodThatIsOnTheChildClass()
}
render() {
// notice here we use the ref on the form via... ref={this.myFormRef}
return (
<Form val={this.state.val} ref={this.myFormRef} Click={this.handleClick.bind(this) }/>
<Button onClick={(e) => this.handleClick(e, todo.id, todo.text)}>
<Icon>edit_icon</Icon>
</Button>
)
)
I would like to note though that it doesn't seem to make much sense as to why you want to do this. You should probably re-think your architecture. Also what is the button press supposed to be doing? submitting the form?