Related
var values = [
{ name: 'Car',Data:'Required',value:'Vehicle' },
{ name: 'Auto',Data:'Required',value:'Vehicle'},
{ name: 'Bike',Data:'Required',value:'Vehicle'},
{ name: 'Car',Data:'Required',value:'Vehicle' }
];
Duplicate object will be:
{ name: 'Car',Data:'Required',value:'Vehicle' }
You can check if an array contains the same item on a different index and by that, understand that there is a duplicate:
const values = [
{ name: 'Car',Data:'Required',value:'Vehicle' },
{ name: 'Auto',Data:'Required',value:'Vehicle'},
{ name: 'Bike',Data:'Required',value:'Vehicle'},
{ name: 'Car',Data:'Required',value:'Vehicle' }
];
const duplicates = values.filter((item, idx) => values.findIndex(i => item.name === i.name && item.Data === i.Data && item.value === i.value) !== idx);
console.log(duplicates);
If you want to check all the properties of objects, you have to introduce a new function, and use it to filter your array:
var values = [
{ name: 'Car',Data:'Required',value:'Vehicle' },
{ name: 'Auto',Data:'Required',value:'Vehicle'},
{ name: 'Bike',Data:'Required',value:'Vehicle'},
{ name: 'Bike',Data:'Required',value:'Different VL'},
{ name: 'Car',Data:'Required',value:'Vehicle' }
];
Object.compare = function (obj1, obj2) {
//Loop through properties in object 1
for (var p in obj1) {
//Check property exists on both objects
if (obj1.hasOwnProperty(p) !== obj2.hasOwnProperty(p)) return false;
switch (typeof (obj1[p])) {
//Deep compare objects
case 'object':
if (!Object.compare(obj1[p], obj2[p])) return false;
break;
//Compare function code
case 'function':
if (typeof (obj2[p]) == 'undefined' || (p != 'compare' && obj1[p].toString() != obj2[p].toString())) return false;
break;
//Compare values
default:
if (obj1[p] != obj2[p]) return false;
}
}
//Check object 2 for any extra properties
for (var p in obj2) {
if (typeof (obj1[p]) == 'undefined') return false;
}
return true;
};
var doubles = values.filter((x,i,a) =>a.slice(0,i).find(y=>Object.compare(x,y)))
console.log(doubles)
Working ahead from the answer in:
https://stackoverflow.com/a/840808/11057988
var findDuplicates = (arr) => {
let sorted_arr = arr.slice().sort(sortFunc); // You can define the comparing function here.
// JS by default uses a crappy string compare.
// (we use slice to clone the array so the
// original array won't be modified)
let results = [];
for (let i = 0; i < sorted_arr.length - 1; i++) {
if (sortFunc(sorted_arr[i + 1], sorted_arr[i]) === 0) {
results.push(sorted_arr[i]);
}
}
return results;
}
var values = [
{ name: 'Car',Data:'Required',value:'Vehicle' },
{ name: 'Auto',Data:'Required',value:'Vehicle'},
{ name: 'Bike',Data:'Required',value:'Vehicle'},
{ name: 'Car',Data:'Required',value:'Vehicle' }
];
var sortFunc = (a, b) => {
return (a.name !== b.name) ? a.name.localeCompare(b.name)
: (a.Data !== b.Data) ? a.Data.localeCompare(b.Data)
: a.value.localeCompare(b.value);
};
console.log(`The duplicates are ${JSON.stringify(findDuplicates(values))}`);
// prints The duplicates are [{"name":"Car","Data":"Required","value":"Vehicle"}]
Couple of differences from original answer:
1. The sortFunc is defined as per your data.
2. Since your input is array of objects, the sortFunc is reused for equality check.
Let's say I have an object:
[
{
'title': "some title"
'channel_id':'123we'
'options': [
{
'channel_id':'abc'
'image':'http://asdasd.com/all-inclusive-block-img.jpg'
'title':'All-Inclusive'
'options':[
{
'channel_id':'dsa2'
'title':'Some Recommends'
'options':[
{
'image':'http://www.asdasd.com' 'title':'Sandals'
'id':'1'
'content':{
...
I want to find the one object where the id is 1. Is there a function for something like this? I could use Underscore's _.filter method, but I would have to start at the top and filter down.
Recursion is your friend. I updated the function to account for property arrays:
function getObject(theObject) {
var result = null;
if(theObject instanceof Array) {
for(var i = 0; i < theObject.length; i++) {
result = getObject(theObject[i]);
if (result) {
break;
}
}
}
else
{
for(var prop in theObject) {
console.log(prop + ': ' + theObject[prop]);
if(prop == 'id') {
if(theObject[prop] == 1) {
return theObject;
}
}
if(theObject[prop] instanceof Object || theObject[prop] instanceof Array) {
result = getObject(theObject[prop]);
if (result) {
break;
}
}
}
}
return result;
}
updated jsFiddle: http://jsfiddle.net/FM3qu/7/
Another (somewhat silly) option is to exploit the naturally recursive nature of JSON.stringify, and pass it a replacer function which runs on each nested object during the stringification process:
const input = [{
'title': "some title",
'channel_id': '123we',
'options': [{
'channel_id': 'abc',
'image': 'http://asdasd.com/all-inclusive-block-img.jpg',
'title': 'All-Inclusive',
'options': [{
'channel_id': 'dsa2',
'title': 'Some Recommends',
'options': [{
'image': 'http://www.asdasd.com',
'title': 'Sandals',
'id': '1',
'content': {}
}]
}]
}]
}];
console.log(findNestedObj(input, 'id', '1'));
function findNestedObj(entireObj, keyToFind, valToFind) {
let foundObj;
JSON.stringify(entireObj, (_, nestedValue) => {
if (nestedValue && nestedValue[keyToFind] === valToFind) {
foundObj = nestedValue;
}
return nestedValue;
});
return foundObj;
};
What worked for me was this lazy approach, not algorithmically lazy ;)
if( JSON.stringify(object_name).indexOf("key_name") > -1 ) {
console.log("Key Found");
}
else{
console.log("Key not Found");
}
If you want to get the first element whose id is 1 while object is being searched, you can use this function:
function customFilter(object){
if(object.hasOwnProperty('id') && object["id"] == 1)
return object;
for(var i=0; i<Object.keys(object).length; i++){
if(typeof object[Object.keys(object)[i]] == "object"){
var o = customFilter(object[Object.keys(object)[i]]);
if(o != null)
return o;
}
}
return null;
}
If you want to get all elements whose id is 1, then (all elements whose id is 1 are stored in result as you see):
function customFilter(object, result){
if(object.hasOwnProperty('id') && object.id == 1)
result.push(object);
for(var i=0; i<Object.keys(object).length; i++){
if(typeof object[Object.keys(object)[i]] == "object"){
customFilter(object[Object.keys(object)[i]], result);
}
}
}
Improved #haitaka answer, using the key and predicate
function deepSearch (object, key, predicate) {
if (object.hasOwnProperty(key) && predicate(key, object[key]) === true) return object
for (let i = 0; i < Object.keys(object).length; i++) {
let value = object[Object.keys(object)[i]];
if (typeof value === "object" && value != null) {
let o = deepSearch(object[Object.keys(object)[i]], key, predicate)
if (o != null) return o
}
}
return null
}
So this can be invoked as:
var result = deepSearch(myObject, 'id', (k, v) => v === 1);
or
var result = deepSearch(myObject, 'title', (k, v) => v === 'Some Recommends');
Here is the demo: http://jsfiddle.net/a21dx6c0/
EDITED
In the same way you can find more than one object
function deepSearchItems(object, key, predicate) {
let ret = [];
if (object.hasOwnProperty(key) && predicate(key, object[key]) === true) {
ret = [...ret, object];
}
if (Object.keys(object).length) {
for (let i = 0; i < Object.keys(object).length; i++) {
let value = object[Object.keys(object)[i]];
if (typeof value === "object" && value != null) {
let o = this.deepSearchItems(object[Object.keys(object)[i]], key, predicate);
if (o != null && o instanceof Array) {
ret = [...ret, ...o];
}
}
}
}
return ret;
}
If you're into the whole ES6 thing you can use
const findByKey = (obj, kee) => {
if (kee in obj) return obj[kee];
for(n of Object.values(obj).filter(Boolean).filter(v => typeof v === 'object')) {
let found = findByKey(n, kee)
if (found) return found
}
}
const findByProperty = (obj, predicate) => {
if (predicate(obj)) return obj
for(n of Object.values(obj).filter(Boolean).filter(v => typeof v === 'object')) {
let found = findByProperty(n, predicate)
if (found) return found
}
}
find by value is going to be a little different
let findByValue = (o, val) => {
if (o === val) return o;
if (o === NaN || o === Infinity || !o || typeof o !== 'object') return;
if (Object.values(o).includes(val)) return o;
for (n of Object.values(o)) {
const found = findByValue(n, val)
if (found) return n
}
}
then they can be used like this
const arry = [{ foo: 0 }, null, { bar: [{ baz: { nutherKey: undefined, needle: "gotcha!" } }]}]
const obj = { alice: Infinity, bob: NaN, charlie: "string", david: true, ebert: arry }
findByKey(obj, 'needle')
// 'gotcha!'
findByProperty(obj, val => val.needle === 'gotcha!')
// { nutherKey: undefined, needle: "gotcha!" }
findByValue(obj, 'gotcha!')
// { nutherKey: undefined, needle: "gotcha!" }
I found this page through googling for the similar functionalities. Based on the work provided by Zach and regularmike, I created another version which suits my needs.
BTW, teriffic work Zah and regularmike!
I'll post the code here:
function findObjects(obj, targetProp, targetValue, finalResults) {
function getObject(theObject) {
let result = null;
if (theObject instanceof Array) {
for (let i = 0; i < theObject.length; i++) {
getObject(theObject[i]);
}
}
else {
for (let prop in theObject) {
if(theObject.hasOwnProperty(prop)){
console.log(prop + ': ' + theObject[prop]);
if (prop === targetProp) {
console.log('--found id');
if (theObject[prop] === targetValue) {
console.log('----found porop', prop, ', ', theObject[prop]);
finalResults.push(theObject);
}
}
if (theObject[prop] instanceof Object || theObject[prop] instanceof Array){
getObject(theObject[prop]);
}
}
}
}
}
getObject(obj);
}
What it does is it find any object inside of obj with property name and value matching to targetProp and targetValue and will push it to the finalResults array.
And Here's the jsfiddle to play around:
https://jsfiddle.net/alexQch/5u6q2ybc/
I've created library for this purpose: https://github.com/dominik791/obj-traverse
You can use findFirst() method like this:
var foundObject = findFirst(rootObject, 'options', { 'id': '1' });
And now foundObject variable stores a reference to the object that you're looking for.
Another recursive solution, that works for arrays/lists and objects, or a mixture of both:
function deepSearchByKey(object, originalKey, matches = []) {
if(object != null) {
if(Array.isArray(object)) {
for(let arrayItem of object) {
deepSearchByKey(arrayItem, originalKey, matches);
}
} else if(typeof object == 'object') {
for(let key of Object.keys(object)) {
if(key == originalKey) {
matches.push(object);
} else {
deepSearchByKey(object[key], originalKey, matches);
}
}
}
}
return matches;
}
usage:
let result = deepSearchByKey(arrayOrObject, 'key'); // returns an array with the objects containing the key
You can use javascript some function inside a recursive function. The advantage of some is to stop looping once the child is founded. Do not use map that would be slow in large data.
const findChild = (array, id) => {
let result;
array.some(
(child) =>
(child.id === id && (result = child)) ||
(result = findChild(child.options || [], id))
);
return result;
};
findChild(array, 1)
Just use recursive function.
See example below:
const data = [
{
title: 'some title',
channel_id: '123we',
options: [
{
channel_id: 'abc',
image: 'http://asdasd.com/all-inclusive-block-img.jpg',
title: 'All-Inclusive',
options: [
{
channel_id: 'dsa2',
title: 'Some Recommends',
options: [
{
image: 'http://www.asdasd.com',
title: 'Sandals',
id: '1',
content: {},
}
]
}
]
}
]
}
]
function _find(collection, key, value) {
for (const o of collection) {
for (const [k, v] of Object.entries(o)) {
if (k === key && v === value) {
return o
}
if (Array.isArray(v)) {
const _o = _find(v, key, value)
if (_o) {
return _o
}
}
}
}
}
console.log(_find(data, 'channel_id', 'dsa2'))
We use object-scan for our data processing. It's conceptually very simple, but allows for a lot of cool stuff. Here is how you would solve your specific question
// const objectScan = require('object-scan');
const find = (id, input) => objectScan(['**'], {
abort: true,
rtn: 'value',
filterFn: ({ value }) => value.id === id
})(input);
const data = [{ title: 'some title', channel_id: '123we', options: [{ channel_id: 'abc', image: 'http://asdasd.com/all-inclusive-block-img.jpg', title: 'All-Inclusive', options: [{ channel_id: 'dsa2', title: 'Some Recommends', options: [{ image: 'http://www.asdasd.com', title: 'Sandals', id: '1', content: {} }] }] }] }];
console.log(find('1', data));
// => { image: 'http://www.asdasd.com', title: 'Sandals', id: '1', content: {} }
.as-console-wrapper {max-height: 100% !important; top: 0}
<script src="https://bundle.run/object-scan#13.8.0"></script>
Disclaimer: I'm the author of object-scan
Found the answer I was looking for, especially Ali Alnoaimi's solution. I made some small adjustments to allow for the search of the value as well
function deepSearchByKey(object, originalKey, originalValue, matches = []) {
if (object != null) {
if (Array.isArray(object)) {
for (let arrayItem of object) {
deepSearchByKey(arrayItem, originalKey, originalValue, matches);
}
} else if (typeof object == 'object') {
for (let key of Object.keys(object)) {
if (key == originalKey) {
if (object[key] == originalValue) {
matches.push(object);
}
} else {
deepSearchByKey(object[key], originalKey, originalValue, matches);
}
}
}
}
return matches;
}
To use:
let result = deepSearchByKey(arrayOrObject, 'key', 'value');
This will return the object containing the matching key and value.
#Iulian Pinzaru's answer was almost exactly what I needed, but it doesn't work if your objects have any null values. This version fixes that.
function deepSearch (object, key, predicate) {
if (object.hasOwnProperty(key) && predicate(key, object[key]) === true) return object
for (let i = 0; i < Object.keys(object).length; i++) {
const nextObject = object[Object.keys(object)[i]];
if (nextObject && typeof nextObject === "object") {
let o = deepSearch(nextObject, key, predicate)
if (o != null) return o
}
}
return null
}
function getPropFromObj(obj, prop) {
let valueToFindByKey;
if (!Array.isArray(obj) && obj !== null && typeof obj === "object") {
if (obj.hasOwnProperty(prop)) {
valueToFindByKey = obj[prop];
console.log(valueToFindByKey);
} else {
let i;
for (i = 0; i < Object.keys(obj).length; i++) {
getPropFromObj(obj[Object.keys(obj)[i]], prop);
}
}
}
return null;
}
const objToInvestigate = {
employeeInformation: {
employees: {
name: "surya",
age: 27,
job: "Frontend Developer",
},
},
};
getPropFromObj(objToInvestigate, "name");
Detecting the key in the deeply nested object.
Finally return the value of the detected key.
Improved answer to take into account circular references within objects.
It also displays the path it took to get there.
In this example, I am searching for an iframe that I know is somewhere within a global object:
const objDone = []
var i = 2
function getObject(theObject, k) {
if (i < 1 || objDone.indexOf(theObject) > -1) return
objDone.push(theObject)
var result = null;
if(theObject instanceof Array) {
for(var i = 0; i < theObject.length; i++) {
result = getObject(theObject[i], i);
if (result) {
break;
}
}
}
else
{
for(var prop in theObject) {
if(prop == 'iframe' && theObject[prop]) {
i--;
console.log('iframe', theObject[prop])
return theObject[prop]
}
if(theObject[prop] instanceof Object || theObject[prop] instanceof Array) {
result = getObject(theObject[prop], prop);
if (result) {
break;
}
}
}
}
if (result) console.info(k)
return result;
}
Running the following:
getObject(reader, 'reader')
gave the following output and the iframe element in the end:
iframe // (The Dom Element)
_views
views
manager
rendition
book
reader
NOTE: The path is in reverse order reader.book.rendition.manager.views._views.iframe
I'd like to suggest an amendment to Zach/RegularMike's answer (but don't have the "reputation" to be able to comment!). I found there solution a very useful basis, but suffered in my application because if there are strings within arrays it would recursively call the function for every character in the string (which caused IE11 & Edge browsers to fail with "out of stack space" errors). My simple optimization was to add the same test used in the "object" clause recursive call to the one in the "array" clause:
if (arrayElem instanceof Object || arrayElem instanceof Array) {
Thus my full code (which is now looking for all instances of a particular key, so slightly different to the original requirement) is:
// Get all instances of specified property deep within supplied object
function getPropsInObject(theObject, targetProp) {
var result = [];
if (theObject instanceof Array) {
for (var i = 0; i < theObject.length; i++) {
var arrayElem = theObject[i];
if (arrayElem instanceof Object || arrayElem instanceof Array) {
result = result.concat(getPropsInObject(arrayElem, targetProp));
}
}
} else {
for (var prop in theObject) {
var objProp = theObject[prop];
if (prop == targetProp) {
return theObject[prop];
}
if (objProp instanceof Object || objProp instanceof Array) {
result = result.concat(getPropsInObject(objProp, targetProp));
}
}
}
return result;
}
Some time ago I have made a small lib find-and, which is available on npm, for working with nested objects in a lodash manner. There's the returnFound function which returns the found object, or an object array if there's more than one object found.
E.g.,
const findAnd = require('find-and');
const a = [
{
'title': "some title",
'channel_id':'123we',
'options': [
{
'channel_id':'abc',
'image':'http://asdasd.com/all-inclusive-block-img.jpg',
'title':'All-Inclusive',
'options':[
{
'channel_id':'dsa2',
'title':'Some Recommends',
'options':[
{
'image':'http://www.asdasd.com',
'title':'Sandals',
'id':'1',
'content':{},
},
],
},
],
},
],
},
];
findAnd.returnFound(a, {id: '1'});
returns
{
'image':'http://www.asdasd.com',
'title':'Sandals',
'id':'1',
'content':{},
}
function getPath(obj, path, index = 0) {
const nestedKeys = path.split('.')
const selectedKey = nestedKeys[index]
if (index === nestedKeys.length - 1) {
return obj[selectedKey]
}
if (!obj.hasOwnProperty(selectedKey)) {
return {}
}
const nextObj = obj[selectedKey]
return Utils.hasPath(nextObj, path, index + 1)
}
You're welcome
By: Gorillaz
This function (main()) allows you to get all objects within a JSON whose key is user-defined. Here is an example:
function main(obj = {}, property) {
const views = [];
function traverse(o) {
for (var i in o) {
if (i === property) views.push(o[i]);
if (!!o[i] && typeof(o[i]) == "object") traverse(o[i]);
}
}
traverse(obj);
return views;
}
const obj = {
id: 'id at level 1',
level2: {
id: 'id at level 2',
level3: {
id: 'id at level 3',
level4: {
level5: {
id: 'id at level 5'
}
}
}
},
text: ''
}
console.log(main(obj, 'id'));
If you're already using Underscore, use _.find()
_.find(yourList, function (item) {
return item.id === 1;
});
Tell me, how correctly to check the existence of a key in associative arrays?
For example:
var mydata = {
key1: '',
key2: {
subkey1: {
subkey1_1: {
value1: ''
value2" '',
},
},
subkey2: '';
},
}
if ((mydata.key2 != undefined) && (mydata.key2.subkey1 != undefined) && (mydata.key2.subkey1.subkey1_1 != undefined))
mydata.key2.subkey1.subkey1_1.value1 = 'test';
Too long and confusing
((mydata.key2 != undefined) && (mydata.key2.subkey1 != undefined) && (mydata.key2.subkey1.subkey1_1 != undefined))
I would like to use a simpler function, like
safeSet(mydata.key2.subkey1.subkey1_1.value1, 'test');
or
if (is_undefined(mydata.key2.subkey1.subkey1_1.value1) == true)
mydata.key2.subkey1.subkey1_1.value1 = 'test'; // now - error if 'mydata.key2.subkey1.subkey1_1' not exist
You can create custom function using reduce() to test if nested property exists. You can just pass key as string.
var mydata = {
key1: '',
key2: {
subkey1: {
subkey1_1: {
value1: '',
value2: '',
},
},
subkey2: ''
},
}
function safeSet(key, data) {
return key.split('.').reduce(function(r, e) {
return r ? r[e] : undefined;
}, data) != undefined
}
console.log(safeSet('key2.subkey1.subkey1_1.value1', mydata))
You should use the in operator:
"key" in obj // true, regardless of the actual value
Or, if you want to particularly test for properties of the object instance (and not inherited properties), use hasOwnProperty:
obj.hasOwnProperty("key") // true
hope this would help you.
Source: http://www.advancesharp.com/questions/628/checking-if-an-associative-array-key-exists-in-javascript
Alternatively, you can make use of the .has() method of Lodash.
Then, you would only need to check:
if (_.has(mydata, 'key2.subkey1.subkey1_1.value1')
mydata.key2.subkey1.subkey1_1.value1 = 'test';
For trying to get something in a nested structure I'd do something like this:
function getPath(element, path) {
var handledSoFar = [];
for (var i = 0; i < path.length; i++) {
var property = path[i];
handledSoFar.push(property);
if (typeof element[property] === 'undefined') {
throw new Error('Path ' + handledSoFar.join('->') + ' is undefined');
}
element = object[property];
}
return element;
}
var mydata = {
key1: '',
key2: {
subkey1: {
subkey1_1: {
value1: '',
value2: 'hi'
}
},
subkey2: ''
}
};
// Prints 'hi'
console.log(getPath(mydata, ['key2', 'subkey1', 'subkey1_1', 'value2']));
// Throws error 'Path key2->subkey2->subkey1_1 is undefined'
console.log(getPath(mydata, ['key2', 'subkey1', 'subkey1_1', 'value2']));
Of course keeping track of the search in handledSoFar is optional but might be useful for development / debugging.
You can also use the lodash deep field selector: lodash.get (documentation)
const get = require('lodash.get');
const set = require('lodash.set');
if (!get(mydata, 'key2.subkey1.subkey1_1.value1')) {
set(mydata, 'key2.subkey1.subkey1_1.value1', 'test');
}
You could split the path and make a check if the following element exist. If not assign an object to the new property.
Return then the value of the property.
At the end assign the value.
function setValue(object, path, value) {
var fullPath = path.split('.'),
way = fullPath.slice(),
last = way.pop();
way.reduce(function (r, a) {
return r[a] = r[a] || {};
}, object)[last] = value;
}
var object = { key1: '', key2: { subkey1: { subkey1_1: { value1: '', value2: '' } }, subkey2: '' } };
setValue(object, 'key2.subkey1.subkey1_1.value1', 'test');
console.log(object);
The problem with the example function that you proposed:
safeSet(mydata.key2.subkey1.subkey1_1.value1, 'test');
or
is_undefined(mydata.key2.subkey1.subkey1_1.value1)
Is that the mydata.key2.subkey1... part is run before the function is called. So if one of the subkeys does not exist, an exception will be thrown before your code is reached.
You could get something similar using a callback though...
safeSet(function(val) { mydata.key2.subkey1.subkey1_1.value1 = val; }, 'test')
the implementation of safeSet would then be:
var safeSet = function(setterFunc, val) {
try {
setterFunc(val);
} catch (e) {
if (e instanceof TypeError) {
return false;
} else {
throw e;
}
}
return true;
}
safeSet returns true if the value was set, and false otherwise.
I read a lot about JS accessors here and figure out this gonna be good for me:
This is what I used for local fields:
TYPE_DEFAULT_VALUE= {
number: 0,
string: "",
array: [],
object: {},
};
typeOf = function (object) {
if (typeof object === "number" && isNaN(object))
return NaN;
try {
return Object.prototype.toString.call(object).slice(8, -1).toLowerCase();
}
catch(ex) {
return "N/A";
};
};
getAccessor = function(obj, key, type, defaultValue) {
if (defaultValue === undefined)
defaultValue = TYPE_DEFAULT_VALUE[type] === undefined ? null : TYPE_DEFAULT_VALUE[type];
return {
enumerable: true,
configurable: true,
get: function () {
if (obj[key] === undefined)
obj[key] = defaultValue;
return obj[key];
},
set: function (value) {
if (typeOf(value) === type)
obj[key] = value;
},
};
}
LocalFields = function (fields, object) {
/**
* field properties
* {
* type: [ required ] ( number | string | array | object | ... ),
* defaultValue: [ optional ]
* }
*/
if (! fields)
throw "Too few parameters ...";
if (! object)
object = this;
var obj = this;
var fieldsAccessor = {};
for(key in fields){
field = fields[key];
fieldHandler = key[0].toUpperCase() + key.substr(1);
if(! field.type)
throw "Type not set for field: " + key;
fieldsAccessor[fieldHandler] = getAccessor(obj, fieldHandler, field.type, field.defaultValue)
}
Object.defineProperties(object, fieldsAccessor);
}
Now for each Class I can just call something like:
Person = function(){
new LocalFields({
id: { type: "number" },
name: { type: "string" },
phone: { type: "array" },
}, this);
}
And then like VS getter and setter you'll call:
var alex = new Person();
alex.Name = "Alex Ramsi";
console.clear();
console.info(alex.Name);
this works for all types but there is a problem because getter and setter is the basic operation and what if I want to add an array field and call this append method or even prepend is there anyhow anyway to do that?
For example How can I call:
alex.Phone.append('+1234567890');
That's a good effort but you forgot that there is no append function for array list!
You can use push and any other array functionality. Check it again;
Let's say I have an object:
[
{
'title': "some title"
'channel_id':'123we'
'options': [
{
'channel_id':'abc'
'image':'http://asdasd.com/all-inclusive-block-img.jpg'
'title':'All-Inclusive'
'options':[
{
'channel_id':'dsa2'
'title':'Some Recommends'
'options':[
{
'image':'http://www.asdasd.com' 'title':'Sandals'
'id':'1'
'content':{
...
I want to find the one object where the id is 1. Is there a function for something like this? I could use Underscore's _.filter method, but I would have to start at the top and filter down.
Recursion is your friend. I updated the function to account for property arrays:
function getObject(theObject) {
var result = null;
if(theObject instanceof Array) {
for(var i = 0; i < theObject.length; i++) {
result = getObject(theObject[i]);
if (result) {
break;
}
}
}
else
{
for(var prop in theObject) {
console.log(prop + ': ' + theObject[prop]);
if(prop == 'id') {
if(theObject[prop] == 1) {
return theObject;
}
}
if(theObject[prop] instanceof Object || theObject[prop] instanceof Array) {
result = getObject(theObject[prop]);
if (result) {
break;
}
}
}
}
return result;
}
updated jsFiddle: http://jsfiddle.net/FM3qu/7/
Another (somewhat silly) option is to exploit the naturally recursive nature of JSON.stringify, and pass it a replacer function which runs on each nested object during the stringification process:
const input = [{
'title': "some title",
'channel_id': '123we',
'options': [{
'channel_id': 'abc',
'image': 'http://asdasd.com/all-inclusive-block-img.jpg',
'title': 'All-Inclusive',
'options': [{
'channel_id': 'dsa2',
'title': 'Some Recommends',
'options': [{
'image': 'http://www.asdasd.com',
'title': 'Sandals',
'id': '1',
'content': {}
}]
}]
}]
}];
console.log(findNestedObj(input, 'id', '1'));
function findNestedObj(entireObj, keyToFind, valToFind) {
let foundObj;
JSON.stringify(entireObj, (_, nestedValue) => {
if (nestedValue && nestedValue[keyToFind] === valToFind) {
foundObj = nestedValue;
}
return nestedValue;
});
return foundObj;
};
What worked for me was this lazy approach, not algorithmically lazy ;)
if( JSON.stringify(object_name).indexOf("key_name") > -1 ) {
console.log("Key Found");
}
else{
console.log("Key not Found");
}
If you want to get the first element whose id is 1 while object is being searched, you can use this function:
function customFilter(object){
if(object.hasOwnProperty('id') && object["id"] == 1)
return object;
for(var i=0; i<Object.keys(object).length; i++){
if(typeof object[Object.keys(object)[i]] == "object"){
var o = customFilter(object[Object.keys(object)[i]]);
if(o != null)
return o;
}
}
return null;
}
If you want to get all elements whose id is 1, then (all elements whose id is 1 are stored in result as you see):
function customFilter(object, result){
if(object.hasOwnProperty('id') && object.id == 1)
result.push(object);
for(var i=0; i<Object.keys(object).length; i++){
if(typeof object[Object.keys(object)[i]] == "object"){
customFilter(object[Object.keys(object)[i]], result);
}
}
}
Improved #haitaka answer, using the key and predicate
function deepSearch (object, key, predicate) {
if (object.hasOwnProperty(key) && predicate(key, object[key]) === true) return object
for (let i = 0; i < Object.keys(object).length; i++) {
let value = object[Object.keys(object)[i]];
if (typeof value === "object" && value != null) {
let o = deepSearch(object[Object.keys(object)[i]], key, predicate)
if (o != null) return o
}
}
return null
}
So this can be invoked as:
var result = deepSearch(myObject, 'id', (k, v) => v === 1);
or
var result = deepSearch(myObject, 'title', (k, v) => v === 'Some Recommends');
Here is the demo: http://jsfiddle.net/a21dx6c0/
EDITED
In the same way you can find more than one object
function deepSearchItems(object, key, predicate) {
let ret = [];
if (object.hasOwnProperty(key) && predicate(key, object[key]) === true) {
ret = [...ret, object];
}
if (Object.keys(object).length) {
for (let i = 0; i < Object.keys(object).length; i++) {
let value = object[Object.keys(object)[i]];
if (typeof value === "object" && value != null) {
let o = this.deepSearchItems(object[Object.keys(object)[i]], key, predicate);
if (o != null && o instanceof Array) {
ret = [...ret, ...o];
}
}
}
}
return ret;
}
If you're into the whole ES6 thing you can use
const findByKey = (obj, kee) => {
if (kee in obj) return obj[kee];
for(n of Object.values(obj).filter(Boolean).filter(v => typeof v === 'object')) {
let found = findByKey(n, kee)
if (found) return found
}
}
const findByProperty = (obj, predicate) => {
if (predicate(obj)) return obj
for(n of Object.values(obj).filter(Boolean).filter(v => typeof v === 'object')) {
let found = findByProperty(n, predicate)
if (found) return found
}
}
find by value is going to be a little different
let findByValue = (o, val) => {
if (o === val) return o;
if (o === NaN || o === Infinity || !o || typeof o !== 'object') return;
if (Object.values(o).includes(val)) return o;
for (n of Object.values(o)) {
const found = findByValue(n, val)
if (found) return n
}
}
then they can be used like this
const arry = [{ foo: 0 }, null, { bar: [{ baz: { nutherKey: undefined, needle: "gotcha!" } }]}]
const obj = { alice: Infinity, bob: NaN, charlie: "string", david: true, ebert: arry }
findByKey(obj, 'needle')
// 'gotcha!'
findByProperty(obj, val => val.needle === 'gotcha!')
// { nutherKey: undefined, needle: "gotcha!" }
findByValue(obj, 'gotcha!')
// { nutherKey: undefined, needle: "gotcha!" }
I found this page through googling for the similar functionalities. Based on the work provided by Zach and regularmike, I created another version which suits my needs.
BTW, teriffic work Zah and regularmike!
I'll post the code here:
function findObjects(obj, targetProp, targetValue, finalResults) {
function getObject(theObject) {
let result = null;
if (theObject instanceof Array) {
for (let i = 0; i < theObject.length; i++) {
getObject(theObject[i]);
}
}
else {
for (let prop in theObject) {
if(theObject.hasOwnProperty(prop)){
console.log(prop + ': ' + theObject[prop]);
if (prop === targetProp) {
console.log('--found id');
if (theObject[prop] === targetValue) {
console.log('----found porop', prop, ', ', theObject[prop]);
finalResults.push(theObject);
}
}
if (theObject[prop] instanceof Object || theObject[prop] instanceof Array){
getObject(theObject[prop]);
}
}
}
}
}
getObject(obj);
}
What it does is it find any object inside of obj with property name and value matching to targetProp and targetValue and will push it to the finalResults array.
And Here's the jsfiddle to play around:
https://jsfiddle.net/alexQch/5u6q2ybc/
I've created library for this purpose: https://github.com/dominik791/obj-traverse
You can use findFirst() method like this:
var foundObject = findFirst(rootObject, 'options', { 'id': '1' });
And now foundObject variable stores a reference to the object that you're looking for.
Another recursive solution, that works for arrays/lists and objects, or a mixture of both:
function deepSearchByKey(object, originalKey, matches = []) {
if(object != null) {
if(Array.isArray(object)) {
for(let arrayItem of object) {
deepSearchByKey(arrayItem, originalKey, matches);
}
} else if(typeof object == 'object') {
for(let key of Object.keys(object)) {
if(key == originalKey) {
matches.push(object);
} else {
deepSearchByKey(object[key], originalKey, matches);
}
}
}
}
return matches;
}
usage:
let result = deepSearchByKey(arrayOrObject, 'key'); // returns an array with the objects containing the key
You can use javascript some function inside a recursive function. The advantage of some is to stop looping once the child is founded. Do not use map that would be slow in large data.
const findChild = (array, id) => {
let result;
array.some(
(child) =>
(child.id === id && (result = child)) ||
(result = findChild(child.options || [], id))
);
return result;
};
findChild(array, 1)
Just use recursive function.
See example below:
const data = [
{
title: 'some title',
channel_id: '123we',
options: [
{
channel_id: 'abc',
image: 'http://asdasd.com/all-inclusive-block-img.jpg',
title: 'All-Inclusive',
options: [
{
channel_id: 'dsa2',
title: 'Some Recommends',
options: [
{
image: 'http://www.asdasd.com',
title: 'Sandals',
id: '1',
content: {},
}
]
}
]
}
]
}
]
function _find(collection, key, value) {
for (const o of collection) {
for (const [k, v] of Object.entries(o)) {
if (k === key && v === value) {
return o
}
if (Array.isArray(v)) {
const _o = _find(v, key, value)
if (_o) {
return _o
}
}
}
}
}
console.log(_find(data, 'channel_id', 'dsa2'))
We use object-scan for our data processing. It's conceptually very simple, but allows for a lot of cool stuff. Here is how you would solve your specific question
// const objectScan = require('object-scan');
const find = (id, input) => objectScan(['**'], {
abort: true,
rtn: 'value',
filterFn: ({ value }) => value.id === id
})(input);
const data = [{ title: 'some title', channel_id: '123we', options: [{ channel_id: 'abc', image: 'http://asdasd.com/all-inclusive-block-img.jpg', title: 'All-Inclusive', options: [{ channel_id: 'dsa2', title: 'Some Recommends', options: [{ image: 'http://www.asdasd.com', title: 'Sandals', id: '1', content: {} }] }] }] }];
console.log(find('1', data));
// => { image: 'http://www.asdasd.com', title: 'Sandals', id: '1', content: {} }
.as-console-wrapper {max-height: 100% !important; top: 0}
<script src="https://bundle.run/object-scan#13.8.0"></script>
Disclaimer: I'm the author of object-scan
Found the answer I was looking for, especially Ali Alnoaimi's solution. I made some small adjustments to allow for the search of the value as well
function deepSearchByKey(object, originalKey, originalValue, matches = []) {
if (object != null) {
if (Array.isArray(object)) {
for (let arrayItem of object) {
deepSearchByKey(arrayItem, originalKey, originalValue, matches);
}
} else if (typeof object == 'object') {
for (let key of Object.keys(object)) {
if (key == originalKey) {
if (object[key] == originalValue) {
matches.push(object);
}
} else {
deepSearchByKey(object[key], originalKey, originalValue, matches);
}
}
}
}
return matches;
}
To use:
let result = deepSearchByKey(arrayOrObject, 'key', 'value');
This will return the object containing the matching key and value.
#Iulian Pinzaru's answer was almost exactly what I needed, but it doesn't work if your objects have any null values. This version fixes that.
function deepSearch (object, key, predicate) {
if (object.hasOwnProperty(key) && predicate(key, object[key]) === true) return object
for (let i = 0; i < Object.keys(object).length; i++) {
const nextObject = object[Object.keys(object)[i]];
if (nextObject && typeof nextObject === "object") {
let o = deepSearch(nextObject, key, predicate)
if (o != null) return o
}
}
return null
}
function getPropFromObj(obj, prop) {
let valueToFindByKey;
if (!Array.isArray(obj) && obj !== null && typeof obj === "object") {
if (obj.hasOwnProperty(prop)) {
valueToFindByKey = obj[prop];
console.log(valueToFindByKey);
} else {
let i;
for (i = 0; i < Object.keys(obj).length; i++) {
getPropFromObj(obj[Object.keys(obj)[i]], prop);
}
}
}
return null;
}
const objToInvestigate = {
employeeInformation: {
employees: {
name: "surya",
age: 27,
job: "Frontend Developer",
},
},
};
getPropFromObj(objToInvestigate, "name");
Detecting the key in the deeply nested object.
Finally return the value of the detected key.
Improved answer to take into account circular references within objects.
It also displays the path it took to get there.
In this example, I am searching for an iframe that I know is somewhere within a global object:
const objDone = []
var i = 2
function getObject(theObject, k) {
if (i < 1 || objDone.indexOf(theObject) > -1) return
objDone.push(theObject)
var result = null;
if(theObject instanceof Array) {
for(var i = 0; i < theObject.length; i++) {
result = getObject(theObject[i], i);
if (result) {
break;
}
}
}
else
{
for(var prop in theObject) {
if(prop == 'iframe' && theObject[prop]) {
i--;
console.log('iframe', theObject[prop])
return theObject[prop]
}
if(theObject[prop] instanceof Object || theObject[prop] instanceof Array) {
result = getObject(theObject[prop], prop);
if (result) {
break;
}
}
}
}
if (result) console.info(k)
return result;
}
Running the following:
getObject(reader, 'reader')
gave the following output and the iframe element in the end:
iframe // (The Dom Element)
_views
views
manager
rendition
book
reader
NOTE: The path is in reverse order reader.book.rendition.manager.views._views.iframe
I'd like to suggest an amendment to Zach/RegularMike's answer (but don't have the "reputation" to be able to comment!). I found there solution a very useful basis, but suffered in my application because if there are strings within arrays it would recursively call the function for every character in the string (which caused IE11 & Edge browsers to fail with "out of stack space" errors). My simple optimization was to add the same test used in the "object" clause recursive call to the one in the "array" clause:
if (arrayElem instanceof Object || arrayElem instanceof Array) {
Thus my full code (which is now looking for all instances of a particular key, so slightly different to the original requirement) is:
// Get all instances of specified property deep within supplied object
function getPropsInObject(theObject, targetProp) {
var result = [];
if (theObject instanceof Array) {
for (var i = 0; i < theObject.length; i++) {
var arrayElem = theObject[i];
if (arrayElem instanceof Object || arrayElem instanceof Array) {
result = result.concat(getPropsInObject(arrayElem, targetProp));
}
}
} else {
for (var prop in theObject) {
var objProp = theObject[prop];
if (prop == targetProp) {
return theObject[prop];
}
if (objProp instanceof Object || objProp instanceof Array) {
result = result.concat(getPropsInObject(objProp, targetProp));
}
}
}
return result;
}
Some time ago I have made a small lib find-and, which is available on npm, for working with nested objects in a lodash manner. There's the returnFound function which returns the found object, or an object array if there's more than one object found.
E.g.,
const findAnd = require('find-and');
const a = [
{
'title': "some title",
'channel_id':'123we',
'options': [
{
'channel_id':'abc',
'image':'http://asdasd.com/all-inclusive-block-img.jpg',
'title':'All-Inclusive',
'options':[
{
'channel_id':'dsa2',
'title':'Some Recommends',
'options':[
{
'image':'http://www.asdasd.com',
'title':'Sandals',
'id':'1',
'content':{},
},
],
},
],
},
],
},
];
findAnd.returnFound(a, {id: '1'});
returns
{
'image':'http://www.asdasd.com',
'title':'Sandals',
'id':'1',
'content':{},
}
function getPath(obj, path, index = 0) {
const nestedKeys = path.split('.')
const selectedKey = nestedKeys[index]
if (index === nestedKeys.length - 1) {
return obj[selectedKey]
}
if (!obj.hasOwnProperty(selectedKey)) {
return {}
}
const nextObj = obj[selectedKey]
return Utils.hasPath(nextObj, path, index + 1)
}
You're welcome
By: Gorillaz
This function (main()) allows you to get all objects within a JSON whose key is user-defined. Here is an example:
function main(obj = {}, property) {
const views = [];
function traverse(o) {
for (var i in o) {
if (i === property) views.push(o[i]);
if (!!o[i] && typeof(o[i]) == "object") traverse(o[i]);
}
}
traverse(obj);
return views;
}
const obj = {
id: 'id at level 1',
level2: {
id: 'id at level 2',
level3: {
id: 'id at level 3',
level4: {
level5: {
id: 'id at level 5'
}
}
}
},
text: ''
}
console.log(main(obj, 'id'));
If you're already using Underscore, use _.find()
_.find(yourList, function (item) {
return item.id === 1;
});