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Replace string pattern but keep part of it [closed]

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I have a long document with some headings I want to replace in a operation.
The headings have the following structure (there are two nouns, both in with a uppercase first character, separated with a whitespace, also the time is dynamic):
let string = 'Firstname Lastname [00:01:02]';
I want to insert some characters at the front and the end of this string, but want to keep the content.
So the desired output should be something like:
let string = '{Firstname Lastname [00:01:02]}:';
I tried a little bit around with RegEx and can catch the time with the following pattern:
\[[0-9]{2}:[0-9]{2}:[0-9]{2}

I figured it out by using captures in my RegEx.
/(\b[A-Z][a-z]* [A-Z][a-z]*( [A-Z])?\b\s\[[0-9]{2}:[0-9]{2}:[0-9]{2}\])/g
This RegEx captures the pattern of my headings into group one. In a replace operation I can then insert the desired content.
string.replace(regex, '{$1}:')

Is there way to change a substring in js? [closed]

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I have a string like:
def definition():
I want to change word def (for example), every instance of word def but not the "def"s that are part of other words
like this
console.log("def definition():".specialReplace("def", "abc"));
and result should be
abc definition():
not
abc abcinition():

Use String#replace or String#replaceAll with a regular expression:
const specialReplace = (str) => str.replaceAll(/\bdef\b/g, 'abc')
console.log(specialReplace("def definition")) // abc definition
console.log(specialReplace("def definition def")) // abc definition abc
In the regular expression, \b is a boundary type assertion that matches any word boundary, such as between a letter and a space.
Note that the same sequence \b is also used inside character class regular expression positions ([\b]), to match the backspace character.

How to retrieve substring which is outside of brackets in JS? [closed]

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I want the text which is outside of brackets, for eg.
Text is - Outside (inside)
and what I expect is - Outside
Can someone please help me to achieve this.

You can use slice & use indexOf to get the first (. This will extract all the characters before first (
let str = 'Outside (inside)'
let substr = str.slice(0, str.indexOf('('));
console.log(substr.trim())

If you wanted to remove all bracketed text from the string you could use
let str = 'Outside (inside)test(d 342 dd3d)dd(t423t t)dd()fasf(fsdfds32dfs)';
console.log(str.replace(/(\([\w\d ]*\))+/g, ''))

Replace the Word Before the search term [closed]

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I am trying to be able to use replace(searchvalue, newvalue); and a user input that would be the search term.
An example would be replace(input,"example text");
But what I want is to be able to have the search term, but instead of replacing the search term, replace the space in front of it.
Ex. is the sentence: "Hi, I am using js to create this!"
and user inputs "js" replace(input, "html and ");
but instead of replacing "js", replace the space in front. So the output sentence would be:
"Hi, I am using html and js to create this!"
Would there be anyway to do this with replace?

You can use a function to handle the replacement in string.replace.
var newString = 'Hi, I am using js to create this!'.replace('js', function(match) {
return 'html and ' + match;
});
console.log(newString); // ... using html and js ...
In the above example I prepend "html and " to the variable match (which has the value of "js"). There is a lot of flexibility when you use a regex instead of a string to find the match.
MDN

How to split string with several char [closed]

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How to split string with several char
i have to split a scope when there are spaces, comma, dash, etc..( ponctuation) and when words are concatenated ( without a space between variable)
For exemple
testOne="{{test.test}} {{test.test}}{{test.test}}";
The expected output is
"test.test test.testtest.test"
(There are two comma between the first and the second text.text)

You can use Regular Expression to get the result what you wanted.
testOne = "{{test.test}} {{test.test}}{{test.test}}";
console.log(testOne.match(/{{.*?}}/g).map(function(item) {
return item.replace(/[{}]/g, "");
}));
# [ 'test.test', 'test.test', 'test.test' ]

You can achieve your desired output with a simple replace
testOne.replace(/{{(.*?)}}/g, '$1');
// "test.test test.testtest.test"
Remember to set this back to testOne if you want it kept as that variable