Related
I need to sort JavaScript objects by key.
Hence the following:
{ 'b' : 'asdsad', 'c' : 'masdas', 'a' : 'dsfdsfsdf' }
Would become:
{ 'a' : 'dsfdsfsdf', 'b' : 'asdsad', 'c' : 'masdas' }
The other answers to this question are outdated, never matched implementation reality, and have officially become incorrect now that the ES6 / ES2015 spec has been published.
See the section on property iteration order in Exploring ES6 by Axel Rauschmayer:
All methods that iterate over property keys do so in the same order:
First all Array indices, sorted numerically.
Then all string keys (that are not indices), in the order in which they were created.
Then all symbols, in the order in which they were created.
So yes, JavaScript objects are in fact ordered, and the order of their keys/properties can be changed.
Here’s how you can sort an object by its keys/properties, alphabetically:
const unordered = {
'b': 'foo',
'c': 'bar',
'a': 'baz'
};
console.log(JSON.stringify(unordered));
// → '{"b":"foo","c":"bar","a":"baz"}'
const ordered = Object.keys(unordered).sort().reduce(
(obj, key) => {
obj[key] = unordered[key];
return obj;
},
{}
);
console.log(JSON.stringify(ordered));
// → '{"a":"baz","b":"foo","c":"bar"}'
Use var instead of const for compatibility with ES5 engines.
JavaScript objects1 are not ordered. It is meaningless to try to "sort" them. If you want to iterate over an object's properties, you can sort the keys and then retrieve the associated values:
var myObj = {
'b': 'asdsadfd',
'c': 'masdasaf',
'a': 'dsfdsfsdf'
},
keys = [],
k, i, len;
for (k in myObj) {
if (myObj.hasOwnProperty(k)) {
keys.push(k);
}
}
keys.sort();
len = keys.length;
for (i = 0; i < len; i++) {
k = keys[i];
console.log(k + ':' + myObj[k]);
}
Alternate implementation using Object.keys fanciness:
var myObj = {
'b': 'asdsadfd',
'c': 'masdasaf',
'a': 'dsfdsfsdf'
},
keys = Object.keys(myObj),
i, len = keys.length;
keys.sort();
for (i = 0; i < len; i++) {
k = keys[i];
console.log(k + ':' + myObj[k]);
}
1Not to be pedantic, but there's no such thing as a JSON object.
A lot of people have mention that "objects cannot be sorted", but after that they are giving you a solution which works. Paradox, isn't it?
No one mention why those solutions are working. They are, because in most of the browser's implementations values in objects are stored in the order in which they were added. That's why if you create new object from sorted list of keys it's returning an expected result.
And I think that we could add one more solution – ES5 functional way:
function sortObject(obj) {
return Object.keys(obj).sort().reduce(function (result, key) {
result[key] = obj[key];
return result;
}, {});
}
ES2015 version of above (formatted to "one-liner"):
const sortObject = o => Object.keys(o).sort().reduce((r, k) => (r[k] = o[k], r), {})
Short explanation of above examples (as asked in comments):
Object.keys is giving us a list of keys in provided object (obj or o), then we're sorting those using default sorting algorithm, next .reduce is used to convert that array back into an object, but this time with all of the keys sorted.
Guys I'm figuratively shocked! Sure all answers are somewhat old, but no one did even mention the stability in sorting! So bear with me I'll try my best to answer the question itself and go into details here. So I'm going to apologize now it will be a lot to read.
Since it is 2018 I will only use ES6, the Polyfills are all available at the MDN docs, which I will link at the given part.
Answer to the question:
If your keys are only numbers then you can safely use Object.keys() together with Array.prototype.reduce() to return the sorted object:
// Only numbers to show it will be sorted.
const testObj = {
'2000': 'Articel1',
'4000': 'Articel2',
'1000': 'Articel3',
'3000': 'Articel4',
};
// I'll explain what reduces does after the answer.
console.log(Object.keys(testObj).reduce((accumulator, currentValue) => {
accumulator[currentValue] = testObj[currentValue];
return accumulator;
}, {}));
/**
* expected output:
* {
* '1000': 'Articel3',
* '2000': 'Articel1',
* '3000': 'Articel4',
* '4000': 'Articel2'
* }
*/
// if needed here is the one liner:
console.log(Object.keys(testObj).reduce((a, c) => (a[c] = testObj[c], a), {}));
However if you are working with strings I highly recommend chaining Array.prototype.sort() into all of this:
// String example
const testObj = {
'a1d78eg8fdg387fg38': 'Articel1',
'z12989dh89h31d9h39': 'Articel2',
'f1203391dhj32189h2': 'Articel3',
'b10939hd83f9032003': 'Articel4',
};
// Chained sort into all of this.
console.log(Object.keys(testObj).sort().reduce((accumulator, currentValue) => {
accumulator[currentValue] = testObj[currentValue];
return accumulator;
}, {}));
/**
* expected output:
* {
* a1d78eg8fdg387fg38: 'Articel1',
* b10939hd83f9032003: 'Articel4',
* f1203391dhj32189h2: 'Articel3',
* z12989dh89h31d9h39: 'Articel2'
* }
*/
// again the one liner:
console.log(Object.keys(testObj).sort().reduce((a, c) => (a[c] = testObj[c], a), {}));
If someone is wondering what reduce does:
// Will return Keys of object as an array (sorted if only numbers or single strings like a,b,c).
Object.keys(testObj)
// Chaining reduce to the returned array from Object.keys().
// Array.prototype.reduce() takes one callback
// (and another param look at the last line) and passes 4 arguments to it:
// accumulator, currentValue, currentIndex and array
.reduce((accumulator, currentValue) => {
// setting the accumulator (sorted new object) with the actual property from old (unsorted) object.
accumulator[currentValue] = testObj[currentValue];
// returning the newly sorted object for the next element in array.
return accumulator;
// the empty object {} ist the initial value for Array.prototype.reduce().
}, {});
If needed here is the explanation for the one liner:
Object.keys(testObj).reduce(
// Arrow function as callback parameter.
(a, c) =>
// parenthesis return! so we can safe the return and write only (..., a);
(a[c] = testObj[c], a)
// initial value for reduce.
,{}
);
Docs for reduce: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/Reduce
Why use parenthesis on JavaScript return statements: http://jamesknelson.com/javascript-return-parenthesis/
Why Sorting is a bit complicated:
In short Object.keys() will return an array with the same order as we get with a normal loop:
const object1 = {
a: 'somestring',
b: 42,
c: false
};
console.log(Object.keys(object1));
// expected output: Array ["a", "b", "c"]
Object.keys() returns an array whose elements are strings
corresponding to the enumerable properties found directly upon object.
The ordering of the properties is the same as that given by looping
over the properties of the object manually.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/keys
Sidenote - you can use Object.keys() on arrays as well, keep in mind the index will be returned:
// simple array
const arr = ['a', 'b', 'c'];
console.log(Object.keys(arr)); // console: ['0', '1', '2']
But it is not as easy as shown by those examples, real world objects may contain numbers and alphabetical characters or even symbols (please don't do it).
Here is an example with all of them in one object:
// This is just to show what happens, please don't use symbols in keys.
const testObj = {
'1asc': '4444',
1000: 'a',
b: '1231',
'#01010101010': 'asd',
2: 'c'
};
console.log(Object.keys(testObj));
// output: [ '2', '1000', '1asc', 'b', '#01010101010' ]
Now if we use Array.prototype.sort() on the array above the output changes:
console.log(Object.keys(testObj).sort());
// output: [ '#01010101010', '1000', '1asc', '2', 'b' ]
Here is a quote from the docs:
The sort() method sorts the elements of an array in place and returns
the array. The sort is not necessarily stable. The default sort order
is according to string Unicode code points.
The time and space complexity of the sort cannot be guaranteed as it
is implementation dependent.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort
You have to make sure that one of them returns the desired output for you. In reallife examples people tend to mix up things expecially if you use different information inputs like APIs and Databases together.
So what's the big deal?
Well there are two articles which every programmer should understand:
In-place algorithm:
In computer science, an in-place algorithm is an algorithm which transforms input using no auxiliary data structure. However a small amount of extra storage space is allowed for auxiliary variables. The input is usually overwritten by the output as the algorithm executes. In-place algorithm updates input sequence only through replacement or swapping of elements. An algorithm which is not in-place is sometimes called not-in-place or out-of-place.
So basically our old array will be overwritten! This is important if you want to keep the old array for other reasons. So keep this in mind.
Sorting algorithm
Stable sort algorithms sort identical elements in the same order that
they appear in the input. When sorting some kinds of data, only part
of the data is examined when determining the sort order. For example,
in the card sorting example to the right, the cards are being sorted
by their rank, and their suit is being ignored. This allows the
possibility of multiple different correctly sorted versions of the
original list. Stable sorting algorithms choose one of these,
according to the following rule: if two items compare as equal, like
the two 5 cards, then their relative order will be preserved, so that
if one came before the other in the input, it will also come before
the other in the output.
An example of stable sort on playing cards. When the cards are sorted
by rank with a stable sort, the two 5s must remain in the same order
in the sorted output that they were originally in. When they are
sorted with a non-stable sort, the 5s may end up in the opposite order
in the sorted output.
This shows that the sorting is right but it changed. So in the real world even if the sorting is correct we have to make sure that we get what we expect! This is super important keep this in mind as well. For more JavaScript examples look into the Array.prototype.sort() - docs: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort
It's 2019 and we have a 2019 way to solve this :)
Object.fromEntries(Object.entries({b: 3, a:8, c:1}).sort())
ES6 - here is the 1 liner
var data = { zIndex:99,
name:'sravan',
age:25,
position:'architect',
amount:'100k',
manager:'mammu' };
console.log(Object.entries(data).sort().reduce( (o,[k,v]) => (o[k]=v,o), {} ));
This works for me
/**
* Return an Object sorted by it's Key
*/
var sortObjectByKey = function(obj){
var keys = [];
var sorted_obj = {};
for(var key in obj){
if(obj.hasOwnProperty(key)){
keys.push(key);
}
}
// sort keys
keys.sort();
// create new array based on Sorted Keys
jQuery.each(keys, function(i, key){
sorted_obj[key] = obj[key];
});
return sorted_obj;
};
This is an old question, but taking the cue from Mathias Bynens' answer, I've made a short version to sort the current object, without much overhead.
Object.keys(unordered).sort().forEach(function(key) {
var value = unordered[key];
delete unordered[key];
unordered[key] = value;
});
after the code execution, the "unordered" object itself will have the keys alphabetically sorted.
Using lodash this will work:
some_map = { 'b' : 'asdsad', 'c' : 'masdas', 'a' : 'dsfdsfsdf' }
// perform a function in order of ascending key
_(some_map).keys().sort().each(function (key) {
var value = some_map[key];
// do something
});
// or alternatively to build a sorted list
sorted_list = _(some_map).keys().sort().map(function (key) {
var value = some_map[key];
// return something that shall become an item in the sorted list
}).value();
Just food for thought.
Suppose it could be useful in VisualStudio debugger which shows unordered object properties.
(function(s) {
var t = {};
Object.keys(s).sort().forEach(function(k) {
t[k] = s[k]
});
return t
})({
b: 2,
a: 1,
c: 3
});
The same as inline version:
(function(s){var t={};Object.keys(s).sort().forEach(function(k){t[k]=s[k]});return t})({b:2,a:1,c:3})
I am actually very surprised that over 30 answers were given, and yet none gave a full deep solution for this problem. Some had shallow solution, while others had deep but faulty (it'll crash if undefined, function or symbol will be in the json).
Here is the full solution:
function sortObject(unordered, sortArrays = false) {
if (!unordered || typeof unordered !== 'object') {
return unordered;
}
if (Array.isArray(unordered)) {
const newArr = unordered.map((item) => sortObject(item, sortArrays));
if (sortArrays) {
newArr.sort();
}
return newArr;
}
const ordered = {};
Object.keys(unordered)
.sort()
.forEach((key) => {
ordered[key] = sortObject(unordered[key], sortArrays);
});
return ordered;
}
const json = {
b: 5,
a: [2, 1],
d: {
b: undefined,
a: null,
c: false,
d: true,
g: '1',
f: [],
h: {},
i: 1n,
j: () => {},
k: Symbol('a')
},
c: [
{
b: 1,
a: 1
}
]
};
console.log(sortObject(json, true));
Underscore version:
function order(unordered)
{
return _.object(_.sortBy(_.pairs(unordered),function(o){return o[0]}));
}
If you don't trust your browser for keeping the order of the keys, I strongly suggest to rely on a ordered array of key-value paired arrays.
_.sortBy(_.pairs(c),function(o){return o[0]})
function sortObjectKeys(obj){
return Object.keys(obj).sort().reduce((acc,key)=>{
acc[key]=obj[key];
return acc;
},{});
}
sortObjectKeys({
telephone: '069911234124',
name: 'Lola',
access: true,
});
Maybe a bit more elegant form:
/**
* Sorts a key-value object by key, maintaining key to data correlations.
* #param {Object} src key-value object
* #returns {Object}
*/
var ksort = function ( src ) {
var keys = Object.keys( src ),
target = {};
keys.sort();
keys.forEach(function ( key ) {
target[ key ] = src[ key ];
});
return target;
};
// Usage
console.log(ksort({
a:1,
c:3,
b:2
}));
P.S. and the same with ES6+ syntax:
function ksort( src ) {
const keys = Object.keys( src );
keys.sort();
return keys.reduce(( target, key ) => {
target[ key ] = src[ key ];
return target;
}, {});
};
Here is a one line solution (not the most efficient but when it comes to thin objects like in your example I'd rather use native JS functions then messing up with sloppy loops)
const unordered = { 'b' : 'asdsad', 'c' : 'masdas', 'a' : 'dsfdsfsdf' }
const ordered = Object.fromEntries(Object.entries(unordered).sort())
console.log(ordered); // a->b->c
// if keys are char/string
const sortObject = (obj) => Object.fromEntries(Object.entries(obj).sort( ));
let obj = { c: 3, a: 1 };
obj = sortObject(obj)
// if keys are numbers
const sortObject = (obj) => Object.fromEntries(Object.entries(obj).sort( (a,b)=>a-b ));
let obj = { 3: 'c', 1: 'a' };
obj = sortObject(obj)
const sortObjectByKeys = (object, asc = true) => Object.fromEntries(
Object.entries(object).sort(([k1], [k2]) => k1 < k2 ^ !asc ? -1 : 1),
)
const object = { b: 'asdsad', c: 'masdas', a: 'dsfdsfsdf' }
const orderedObject = sortObjectByKeys(object)
console.log(orderedObject)
recursive sort, for nested object and arrays
function sortObjectKeys(obj){
return Object.keys(obj).sort().reduce((acc,key)=>{
if (Array.isArray(obj[key])){
acc[key]=obj[key].map(sortObjectKeys);
}
if (typeof obj[key] === 'object'){
acc[key]=sortObjectKeys(obj[key]);
}
else{
acc[key]=obj[key];
}
return acc;
},{});
}
// test it
sortObjectKeys({
telephone: '069911234124',
name: 'Lola',
access: true,
cars: [
{name: 'Family', brand: 'Volvo', cc:1600},
{
name: 'City', brand: 'VW', cc:1200,
interior: {
wheel: 'plastic',
radio: 'blaupunkt'
}
},
{
cc:2600, name: 'Killer', brand: 'Plymouth',
interior: {
wheel: 'wooden',
radio: 'earache!'
}
},
]
});
Here is a clean lodash-based version that works with nested objects
/**
* Sort of the keys of an object alphabetically
*/
const sortKeys = function(obj) {
if(_.isArray(obj)) {
return obj.map(sortKeys);
}
if(_.isObject(obj)) {
return _.fromPairs(_.keys(obj).sort().map(key => [key, sortKeys(obj[key])]));
}
return obj;
};
It would be even cleaner if lodash had a toObject() method...
There's a great project by #sindresorhus called sort-keys that works awesome.
You can check its source code here:
https://github.com/sindresorhus/sort-keys
Or you can use it with npm:
$ npm install --save sort-keys
Here are also code examples from his readme
const sortKeys = require('sort-keys');
sortKeys({c: 0, a: 0, b: 0});
//=> {a: 0, b: 0, c: 0}
sortKeys({b: {b: 0, a: 0}, a: 0}, {deep: true});
//=> {a: 0, b: {a: 0, b: 0}}
sortKeys({c: 0, a: 0, b: 0}, {
compare: (a, b) => -a.localeCompare(b)
});
//=> {c: 0, b: 0, a: 0}
Object.keys(unordered).sort().reduce(
(acc,curr) => ({...acc, [curr]:unordered[curr]})
, {}
)
Use this code if you have nested objects or if you have nested array obj.
var sortObjectByKey = function(obj){
var keys = [];
var sorted_obj = {};
for(var key in obj){
if(obj.hasOwnProperty(key)){
keys.push(key);
}
}
// sort keys
keys.sort();
// create new array based on Sorted Keys
jQuery.each(keys, function(i, key){
var val = obj[key];
if(val instanceof Array){
//do for loop;
var arr = [];
jQuery.each(val,function(){
arr.push(sortObjectByKey(this));
});
val = arr;
}else if(val instanceof Object){
val = sortObjectByKey(val)
}
sorted_obj[key] = val;
});
return sorted_obj;
};
As already mentioned, objects are unordered.
However...
You may find this idiom useful:
var o = { 'b' : 'asdsad', 'c' : 'masdas', 'a' : 'dsfdsfsdf' };
var kv = [];
for (var k in o) {
kv.push([k, o[k]]);
}
kv.sort()
You can then iterate through kv and do whatever you wish.
> kv.sort()
[ [ 'a', 'dsfdsfsdf' ],
[ 'b', 'asdsad' ],
[ 'c', 'masdas' ] ]
Just use lodash to unzip map and sortBy first value of pair and zip again it will return sorted key.
If you want sortby value change pair index to 1 instead of 0
var o = { 'b' : 'asdsad', 'c' : 'masdas', 'a' : 'dsfdsfsdf' };
console.log(_(o).toPairs().sortBy(0).fromPairs().value())
Sorts keys recursively while preserving references.
function sortKeys(o){
if(o && o.constructor === Array)
o.forEach(i=>sortKeys(i));
else if(o && o.constructor === Object)
Object.entries(o).sort((a,b)=>a[0]>b[0]?1:-1).forEach(e=>{
sortKeys(e[1]);
delete o[e[0]];
o[e[0]] = e[1];
});
}
Example:
let x = {d:3, c:{g:20, a:[3,2,{s:200, a:100}]}, a:1};
let y = x.c;
let z = x.c.a[2];
sortKeys(x);
console.log(x); // {a: 1, c: {a: [3, 2, {a: 1, s: 2}], g: 2}, d: 3}
console.log(y); // {a: [3, 2, {a: 100, s: 200}}, g: 20}
console.log(z); // {a: 100, s: 200}
This is a lightweight solution to everything I need for JSON sorting.
function sortObj(obj) {
if (typeof obj !== "object" || obj === null)
return obj;
if (Array.isArray(obj))
return obj.map((e) => sortObj(e)).sort();
return Object.keys(obj).sort().reduce((sorted, k) => {
sorted[k] = sortObj(obj[k]);
return sorted;
}, {});
}
Solution:
function getSortedObject(object) {
var sortedObject = {};
var keys = Object.keys(object);
keys.sort();
for (var i = 0, size = keys.length; i < size; i++) {
key = keys[i];
value = object[key];
sortedObject[key] = value;
}
return sortedObject;
}
// Test run
getSortedObject({d: 4, a: 1, b: 2, c: 3});
Explanation:
Many JavaScript runtimes store values inside an object in the order in which they are added.
To sort the properties of an object by their keys you can make use of the Object.keys function which will return an array of keys. The array of keys can then be sorted by the Array.prototype.sort() method which sorts the elements of an array in place (no need to assign them to a new variable).
Once the keys are sorted you can start using them one-by-one to access the contents of the old object to fill a new object (which is now sorted).
Below is an example of the procedure (you can test it in your targeted browsers):
/**
* Returns a copy of an object, which is ordered by the keys of the original object.
*
* #param {Object} object - The original object.
* #returns {Object} Copy of the original object sorted by keys.
*/
function getSortedObject(object) {
// New object which will be returned with sorted keys
var sortedObject = {};
// Get array of keys from the old/current object
var keys = Object.keys(object);
// Sort keys (in place)
keys.sort();
// Use sorted keys to copy values from old object to the new one
for (var i = 0, size = keys.length; i < size; i++) {
key = keys[i];
value = object[key];
sortedObject[key] = value;
}
// Return the new object
return sortedObject;
}
/**
* Test run
*/
var unsortedObject = {
d: 4,
a: 1,
b: 2,
c: 3
};
var sortedObject = getSortedObject(unsortedObject);
for (var key in sortedObject) {
var text = "Key: " + key + ", Value: " + sortedObject[key];
var paragraph = document.createElement('p');
paragraph.textContent = text;
document.body.appendChild(paragraph);
}
Note: Object.keys is an ECMAScript 5.1 method but here is a polyfill for older browsers:
if (!Object.keys) {
Object.keys = function (object) {
var key = [];
var property = undefined;
for (property in object) {
if (Object.prototype.hasOwnProperty.call(object, property)) {
key.push(property);
}
}
return key;
};
}
I transfered some Java enums to javascript objects.
These objects returned correct arrays for me. if object keys are mixed type (string, int, char), there is a problem.
var Helper = {
isEmpty: function (obj) {
return !obj || obj === null || obj === undefined || Array.isArray(obj) && obj.length === 0;
},
isObject: function (obj) {
return (typeof obj === 'object');
},
sortObjectKeys: function (object) {
return Object.keys(object)
.sort(function (a, b) {
c = a - b;
return c
});
},
containsItem: function (arr, item) {
if (arr && Array.isArray(arr)) {
return arr.indexOf(item) > -1;
} else {
return arr === item;
}
},
pushArray: function (arr1, arr2) {
if (arr1 && arr2 && Array.isArray(arr1)) {
arr1.push.apply(arr1, Array.isArray(arr2) ? arr2 : [arr2]);
}
}
};
function TypeHelper() {
var _types = arguments[0],
_defTypeIndex = 0,
_currentType,
_value;
if (arguments.length == 2) {
_defTypeIndex = arguments[1];
}
Object.defineProperties(this, {
Key: {
get: function () {
return _currentType;
},
set: function (val) {
_currentType.setType(val, true);
},
enumerable: true
},
Value: {
get: function () {
return _types[_currentType];
},
set: function (val) {
_value.setType(val, false);
},
enumerable: true
}
});
this.getAsList = function (keys) {
var list = [];
Helper.sortObjectKeys(_types).forEach(function (key, idx, array) {
if (key && _types[key]) {
if (!Helper.isEmpty(keys) && Helper.containsItem(keys, key) || Helper.isEmpty(keys)) {
var json = {};
json.Key = key;
json.Value = _types[key];
Helper.pushArray(list, json);
}
}
});
return list;
};
this.setType = function (value, isKey) {
if (!Helper.isEmpty(value)) {
Object.keys(_types).forEach(function (key, idx, array) {
if (Helper.isObject(value)) {
if (value && value.Key == key) {
_currentType = key;
}
} else if (isKey) {
if (value && value.toString() == key.toString()) {
_currentType = key;
}
} else if (value && value.toString() == _types[key]) {
_currentType = key;
}
});
} else {
this.setDefaultType();
}
return isKey ? _types[_currentType] : _currentType;
};
this.setTypeByIndex = function (index) {
var keys = Helper.sortObjectKeys(_types);
for (var i = 0; i < keys.length; i++) {
if (index === i) {
_currentType = keys[index];
break;
}
}
};
this.setDefaultType = function () {
this.setTypeByIndex(_defTypeIndex);
};
this.setDefaultType();
}
var TypeA = {
"-1": "Any",
"2": "2L",
"100": "100L",
"200": "200L",
"1000": "1000L"
};
var TypeB = {
"U": "Any",
"W": "1L",
"V": "2L",
"A": "100L",
"Z": "200L",
"K": "1000L"
};
console.log('keys of TypeA', Helper.sortObjectKeys(TypeA));//keys of TypeA ["-1", "2", "100", "200", "1000"]
console.log('keys of TypeB', Helper.sortObjectKeys(TypeB));//keys of TypeB ["U", "W", "V", "A", "Z", "K"]
var objectTypeA = new TypeHelper(TypeA),
objectTypeB = new TypeHelper(TypeB);
console.log('list of objectA = ', objectTypeA.getAsList());
console.log('list of objectB = ', objectTypeB.getAsList());
Types:
var TypeA = {
"-1": "Any",
"2": "2L",
"100": "100L",
"200": "200L",
"1000": "1000L"
};
var TypeB = {
"U": "Any",
"W": "1L",
"V": "2L",
"A": "100L",
"Z": "200L",
"K": "1000L"
};
Sorted Keys(output):
Key list of TypeA -> ["-1", "2", "100", "200", "1000"]
Key list of TypeB -> ["U", "W", "V", "A", "Z", "K"]
The one line:
Object.entries(unordered)
.sort(([keyA], [keyB]) => keyA > keyB)
.reduce((obj, [key,value]) => Object.assign(obj, {[key]: value}), {})
Pure JavaScript answer to sort an Object. This is the only answer that I know of that will handle negative numbers. This function is for sorting numerical Objects.
Input
obj = {1000: {}, -1200: {}, 10000: {}, 200: {}};
function osort(obj) {
var keys = Object.keys(obj);
var len = keys.length;
var rObj = [];
var rK = [];
var t = Object.keys(obj).length;
while(t > rK.length) {
var l = null;
for(var x in keys) {
if(l && parseInt(keys[x]) < parseInt(l)) {
l = keys[x];
k = x;
}
if(!l) { // Find Lowest
var l = keys[x];
var k = x;
}
}
delete keys[k];
rK.push(l);
}
for (var i = 0; i < len; i++) {
k = rK[i];
rObj.push(obj[k]);
}
return rObj;
}
The output will be an object sorted by those numbers with new keys starting at 0.
I am trying to create a deep copy map method for my Redux project that will work with objects rather than arrays. I read that in Redux each state should not change anything in the previous states.
export const mapCopy = (object, callback) => {
return Object.keys(object).reduce(function (output, key) {
output[key] = callback.call(this, {...object[key]});
return output;
},
{});
}
It works:
return mapCopy(state, e => {
if (e.id === action.id) {
e.title = 'new item';
}
return e;
})
However it does not deep copy inner items so I need to tweak it to:
export const mapCopy = (object, callback) => {
return Object.keys(object).reduce(function (output, key) {
let newObject = {...object[key]};
newObject.style = {...newObject.style};
newObject.data = {...newObject.data};
output[key] = callback.call(this, newObject);
return output;
}, {});
}
This is less elegant as it requires to know which objects are passed.
Is there a way in ES6 to use the spread syntax to deep copy an object?
Use JSON for deep copy
var newObject = JSON.parse(JSON.stringify(oldObject))
var oldObject = {
name: 'A',
address: {
street: 'Station Road',
city: 'Pune'
}
}
var newObject = JSON.parse(JSON.stringify(oldObject));
newObject.address.city = 'Delhi';
console.log('newObject');
console.log(newObject);
console.log('oldObject');
console.log(oldObject);
No such functionality is built-in to ES6. I think you have a couple of options depending on what you want to do.
If you really want to deep copy:
Use a library. For example, lodash has a cloneDeep method.
Implement your own cloning function.
Alternative Solution To Your Specific Problem (No Deep Copy)
However, I think, if you're willing to change a couple things, you can save yourself some work. I'm assuming you control all call sites to your function.
Specify that all callbacks passed to mapCopy must return new objects instead of mutating the existing object. For example:
mapCopy(state, e => {
if (e.id === action.id) {
return Object.assign({}, e, {
title: 'new item'
});
} else {
return e;
}
});
This makes use of Object.assign to create a new object, sets properties of e on that new object, then sets a new title on that new object. This means you never mutate existing objects and only create new ones when necessary.
mapCopy can be really simple now:
export const mapCopy = (object, callback) => {
return Object.keys(object).reduce(function (output, key) {
output[key] = callback.call(this, object[key]);
return output;
}, {});
}
Essentially, mapCopy is trusting its callers to do the right thing. This is why I said this assumes you control all call sites.
From MDN
Note: Spread syntax effectively goes one level deep while copying an array. Therefore, it may be unsuitable for copying multidimensional arrays as the following example shows (it's the same with Object.assign() and spread syntax).
Personally, I suggest using Lodash's cloneDeep function for multi-level object/array cloning.
Here is a working example:
const arr1 = [{ 'a': 1 }];
const arr2 = [...arr1];
const arr3 = _.clone(arr1);
const arr4 = arr1.slice();
const arr5 = _.cloneDeep(arr1);
const arr6 = [...{...arr1}]; // a bit ugly syntax but it is working!
// first level
console.log(arr1 === arr2); // false
console.log(arr1 === arr3); // false
console.log(arr1 === arr4); // false
console.log(arr1 === arr5); // false
console.log(arr1 === arr6); // false
// second level
console.log(arr1[0] === arr2[0]); // true
console.log(arr1[0] === arr3[0]); // true
console.log(arr1[0] === arr4[0]); // true
console.log(arr1[0] === arr5[0]); // false
console.log(arr1[0] === arr6[0]); // false
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.js"></script>
I often use this:
function deepCopy(obj) {
if(typeof obj !== 'object' || obj === null) {
return obj;
}
if(obj instanceof Date) {
return new Date(obj.getTime());
}
if(obj instanceof Array) {
return obj.reduce((arr, item, i) => {
arr[i] = deepCopy(item);
return arr;
}, []);
}
if(obj instanceof Object) {
return Object.keys(obj).reduce((newObj, key) => {
newObj[key] = deepCopy(obj[key]);
return newObj;
}, {})
}
}
You can use structuredClone() like the following:
const myOriginal = {
title: "Full Stack JavaScript Developer",
info: {
firstname: "Abolfazl",
surname: "Roshanzamir",
age: 34
}
};
const myDeepCopy = structuredClone(myOriginal);
structuredClone()
You can use structuredClone() that is a built-in function for deep-copying.
Structured cloning addresses many (although not all) shortcomings of the JSON.stringify() technique.
Structured cloning can handle cyclical data structures,
support many built-in data types, and is generally more robust and often faster.
However, it still has some limitations that may catch you off-guard:
1-Prototypes : If you use structuredClone() with a class instance,
you’ll get a plain object as the return value, as structured cloning discards the object’s prototype chain.
2-Functions: If your object contains functions, they will be quietly discarded.
3- Non-cloneables: Some values are not structured cloneable, most notably Error and DOM nodes. It will cause structuredClone() to throw.
const myDeepCopy = structuredClone(myOriginal);
JSON.stringify
If you simply want to deep copy the object to another object,
all you will need to do is JSON.stringify the object and parse it using JSON.parse afterward.
This will essentially perform deep copying of the object.
let user1 = {
name: 'Abolfazl Roshanzamir',
age: 34,
university: {
name: 'Shiraz Bahonar University'
}
};
let user2 = JSON.parse(JSON.stringify(user1));
user2.name = 'Andy Madadian';
user2.university.name = 'Kerman Bahonar University'
console.log(user2);
// { name: 'Andy Madadian', age: 33, university: { name: 'Kerman Bahonar University' } }
console.log(user1);
// { name: 'Abolfazl Roshanzamir', age: 33, university: { name: 'Shiraz Bahonar University' } }
Spread operator / Object.assign()
One way to create a shallow copy in JavaScript using the object spread operator ... or Object.assign() like the following:
const myShallowCopySpread = {...myOriginal};
const myShallowCopyObjectAssign=Object.assign({},obj)
Performance
When it comes to performance the creator Surma has pointed out that JSON.Parse() can be a bit faster for small objects. But when you have a large object, complex object
structuredClone() starts to get significantly faster.
Browser support is pretty fantastic And even is supported by Node.js.
const a = {
foods: {
dinner: 'Pasta'
}
}
let b = JSON.parse(JSON.stringify(a))
b.foods.dinner = 'Soup'
console.log(b.foods.dinner) // Soup
console.log(a.foods.dinner) // Pasta
Using JSON.stringify and JSON.parse is the best way. Because by using the spread operator we will not get the efficient answer when the json object contains another object inside it. we need to manually specify that.
Here's my deep copy algorithm.
const DeepClone = (obj) => {
if(obj===null||typeof(obj)!=='object')return null;
let newObj = { ...obj };
for (let prop in obj) {
if (
typeof obj[prop] === "object" ||
typeof obj[prop] === "function"
) {
newObj[prop] = DeepClone(obj[prop]);
}
}
return newObj;
};
// use: clone( <thing to copy> ) returns <new copy>
// untested use at own risk
function clone(o, m){
// return non object values
if('object' !==typeof o) return o
// m: a map of old refs to new object refs to stop recursion
if('object' !==typeof m || null ===m) m =new WeakMap()
var n =m.get(o)
if('undefined' !==typeof n) return n
// shallow/leaf clone object
var c =Object.getPrototypeOf(o).constructor
// TODO: specialize copies for expected built in types i.e. Date etc
switch(c) {
// shouldn't be copied, keep reference
case Boolean:
case Error:
case Function:
case Number:
case Promise:
case String:
case Symbol:
case WeakMap:
case WeakSet:
n =o
break;
// array like/collection objects
case Array:
m.set(o, n =o.slice(0))
// recursive copy for child objects
n.forEach(function(v,i){
if('object' ===typeof v) n[i] =clone(v, m)
});
break;
case ArrayBuffer:
m.set(o, n =o.slice(0))
break;
case DataView:
m.set(o, n =new (c)(clone(o.buffer, m), o.byteOffset, o.byteLength))
break;
case Map:
case Set:
m.set(o, n =new (c)(clone(Array.from(o.entries()), m)))
break;
case Int8Array:
case Uint8Array:
case Uint8ClampedArray:
case Int16Array:
case Uint16Array:
case Int32Array:
case Uint32Array:
case Float32Array:
case Float64Array:
m.set(o, n =new (c)(clone(o.buffer, m), o.byteOffset, o.length))
break;
// use built in copy constructor
case Date:
case RegExp:
m.set(o, n =new (c)(o))
break;
// fallback generic object copy
default:
m.set(o, n =Object.assign(new (c)(), o))
// recursive copy for child objects
for(c in n) if('object' ===typeof n[c]) n[c] =clone(n[c], m)
}
return n
}
Here is the deepClone function which handles all primitive, array, object, function data types
function deepClone(obj){
if(Array.isArray(obj)){
var arr = [];
for (var i = 0; i < obj.length; i++) {
arr[i] = deepClone(obj[i]);
}
return arr;
}
if(typeof(obj) == "object"){
var cloned = {};
for(let key in obj){
cloned[key] = deepClone(obj[key])
}
return cloned;
}
return obj;
}
console.log( deepClone(1) )
console.log( deepClone('abc') )
console.log( deepClone([1,2]) )
console.log( deepClone({a: 'abc', b: 'def'}) )
console.log( deepClone({
a: 'a',
num: 123,
func: function(){'hello'},
arr: [[1,2,3,[4,5]], 'def'],
obj: {
one: {
two: {
three: 3
}
}
}
}) )
function deepclone(obj) {
let newObj = {};
if (typeof obj === 'object') {
for (let key in obj) {
let property = obj[key],
type = typeof property;
switch (type) {
case 'object':
if( Object.prototype.toString.call( property ) === '[object Array]' ) {
newObj[key] = [];
for (let item of property) {
newObj[key].push(this.deepclone(item))
}
} else {
newObj[key] = deepclone(property);
}
break;
default:
newObj[key] = property;
break;
}
}
return newObj
} else {
return obj;
}
}
const cloneData = (dataArray) => {
newData= []
dataArray.forEach((value) => {
newData.push({...value})
})
return newData
}
a = [{name:"siva"}, {name:"siva1"}] ;
b = myCopy(a)
b === a // false`
I myself landed on these answers last day, trying to find a way to deep copy complex structures, which may include recursive links. As I wasn't satisfied with anything being suggested before, I implemented this wheel myself. And it works quite well. Hope it helps someone.
Example usage:
OriginalStruct.deep_copy = deep_copy; // attach the function as a method
TheClone = OriginalStruct.deep_copy();
Please look at https://github.com/latitov/JS_DeepCopy for live examples how to use it, and also deep_print() is there.
If you need it quick, right here's the source of deep_copy() function:
function deep_copy() {
'use strict'; // required for undef test of 'this' below
// Copyright (c) 2019, Leonid Titov, Mentions Highly Appreciated.
var id_cnt = 1;
var all_old_objects = {};
var all_new_objects = {};
var root_obj = this;
if (root_obj === undefined) {
console.log(`deep_copy() error: wrong call context`);
return;
}
var new_obj = copy_obj(root_obj);
for (var id in all_old_objects) {
delete all_old_objects[id].__temp_id;
}
return new_obj;
//
function copy_obj(o) {
var new_obj = {};
if (o.__temp_id === undefined) {
o.__temp_id = id_cnt;
all_old_objects[id_cnt] = o;
all_new_objects[id_cnt] = new_obj;
id_cnt ++;
for (var prop in o) {
if (o[prop] instanceof Array) {
new_obj[prop] = copy_array(o[prop]);
}
else if (o[prop] instanceof Object) {
new_obj[prop] = copy_obj(o[prop]);
}
else if (prop === '__temp_id') {
continue;
}
else {
new_obj[prop] = o[prop];
}
}
}
else {
new_obj = all_new_objects[o.__temp_id];
}
return new_obj;
}
function copy_array(a) {
var new_array = [];
if (a.__temp_id === undefined) {
a.__temp_id = id_cnt;
all_old_objects[id_cnt] = a;
all_new_objects[id_cnt] = new_array;
id_cnt ++;
a.forEach((v,i) => {
if (v instanceof Array) {
new_array[i] = copy_array(v);
}
else if (v instanceof Object) {
new_array[i] = copy_object(v);
}
else {
new_array[i] = v;
}
});
}
else {
new_array = all_new_objects[a.__temp_id];
}
return new_array;
}
}
Cheers#!
I would suggest using the spread operator. You'll need to spread a second time if you need to update the second level. Attempting to update the newObject using something like newObject.address.city will throw an error if address did not already exist in oldObject.
const oldObject = {
name: 'A',
address: {
street: 'Station Road',
city: 'Pune'
}
}
const newObject = {
...oldObject,
address: {
...oldObject.address,
city: 'Delhi'
}
}
console.log(newObject)
This is a very old question but I think in 2022 there are many ways to solve this. However, if you want a simple, fast and vanilla JS solution check this out:
const cloner = (o) => {
let idx = 1
const isArray = (a) => a instanceof Array
const isObject = (o) => o instanceof Object
const isUndefined = (a) => a === undefined
const process = v => {
if (isArray(v)) return cloneArray(v)
else if (isObject(v)) return cloneObject(v)
else return v
}
const register = (old, o) => {
old.__idx = idx
oldObjects[idx] = old
newObjects[idx] = o
idx++
}
const cloneObject = o => {
if (!isUndefined(o.__idx)) return newObjects[o.__idx]
const obj = {}
for (const prop in o) {
if (prop === '__idx') continue
obj[prop] = process(o[prop])
}
register(o, obj)
return obj
}
const cloneArray = a => {
if (!isUndefined(a.__idx)) return newObjects[a.__idx]
const arr = a.map((v) => process(v))
register(a, arr)
return arr
}
const oldObjects = {}
const newObjects = {}
let tmp
if (isArray(o)) tmp = cloneArray(o)
else if (isObject(o)) tmp = cloneObject(o)
else return o
for (const id in oldObjects) delete oldObjects[id].__idx
return tmp
}
const c = {
id: 123,
label: "Lala",
values: ['char', 1, {flag: true}, [1,2,3,4,5], ['a', 'b']],
name: undefined
}
const d = cloner(c)
d.name = "Super"
d.values[2].flag = false
d.values[3] = [6,7,8]
console.log({ c, d })
It's recursive and self-contained, all the functions needed are defined in the function cloner().
In this snippet we are handling Array and Object types if you want to add more handlers you can add specify handlers like Date and clone it like new Date(v.getTime())
For me Array and Object are the types that I use the most in my implementations.
I am trying to create a deep copy map method for my Redux project that will work with objects rather than arrays. I read that in Redux each state should not change anything in the previous states.
export const mapCopy = (object, callback) => {
return Object.keys(object).reduce(function (output, key) {
output[key] = callback.call(this, {...object[key]});
return output;
},
{});
}
It works:
return mapCopy(state, e => {
if (e.id === action.id) {
e.title = 'new item';
}
return e;
})
However it does not deep copy inner items so I need to tweak it to:
export const mapCopy = (object, callback) => {
return Object.keys(object).reduce(function (output, key) {
let newObject = {...object[key]};
newObject.style = {...newObject.style};
newObject.data = {...newObject.data};
output[key] = callback.call(this, newObject);
return output;
}, {});
}
This is less elegant as it requires to know which objects are passed.
Is there a way in ES6 to use the spread syntax to deep copy an object?
Use JSON for deep copy
var newObject = JSON.parse(JSON.stringify(oldObject))
var oldObject = {
name: 'A',
address: {
street: 'Station Road',
city: 'Pune'
}
}
var newObject = JSON.parse(JSON.stringify(oldObject));
newObject.address.city = 'Delhi';
console.log('newObject');
console.log(newObject);
console.log('oldObject');
console.log(oldObject);
No such functionality is built-in to ES6. I think you have a couple of options depending on what you want to do.
If you really want to deep copy:
Use a library. For example, lodash has a cloneDeep method.
Implement your own cloning function.
Alternative Solution To Your Specific Problem (No Deep Copy)
However, I think, if you're willing to change a couple things, you can save yourself some work. I'm assuming you control all call sites to your function.
Specify that all callbacks passed to mapCopy must return new objects instead of mutating the existing object. For example:
mapCopy(state, e => {
if (e.id === action.id) {
return Object.assign({}, e, {
title: 'new item'
});
} else {
return e;
}
});
This makes use of Object.assign to create a new object, sets properties of e on that new object, then sets a new title on that new object. This means you never mutate existing objects and only create new ones when necessary.
mapCopy can be really simple now:
export const mapCopy = (object, callback) => {
return Object.keys(object).reduce(function (output, key) {
output[key] = callback.call(this, object[key]);
return output;
}, {});
}
Essentially, mapCopy is trusting its callers to do the right thing. This is why I said this assumes you control all call sites.
From MDN
Note: Spread syntax effectively goes one level deep while copying an array. Therefore, it may be unsuitable for copying multidimensional arrays as the following example shows (it's the same with Object.assign() and spread syntax).
Personally, I suggest using Lodash's cloneDeep function for multi-level object/array cloning.
Here is a working example:
const arr1 = [{ 'a': 1 }];
const arr2 = [...arr1];
const arr3 = _.clone(arr1);
const arr4 = arr1.slice();
const arr5 = _.cloneDeep(arr1);
const arr6 = [...{...arr1}]; // a bit ugly syntax but it is working!
// first level
console.log(arr1 === arr2); // false
console.log(arr1 === arr3); // false
console.log(arr1 === arr4); // false
console.log(arr1 === arr5); // false
console.log(arr1 === arr6); // false
// second level
console.log(arr1[0] === arr2[0]); // true
console.log(arr1[0] === arr3[0]); // true
console.log(arr1[0] === arr4[0]); // true
console.log(arr1[0] === arr5[0]); // false
console.log(arr1[0] === arr6[0]); // false
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.js"></script>
I often use this:
function deepCopy(obj) {
if(typeof obj !== 'object' || obj === null) {
return obj;
}
if(obj instanceof Date) {
return new Date(obj.getTime());
}
if(obj instanceof Array) {
return obj.reduce((arr, item, i) => {
arr[i] = deepCopy(item);
return arr;
}, []);
}
if(obj instanceof Object) {
return Object.keys(obj).reduce((newObj, key) => {
newObj[key] = deepCopy(obj[key]);
return newObj;
}, {})
}
}
You can use structuredClone() like the following:
const myOriginal = {
title: "Full Stack JavaScript Developer",
info: {
firstname: "Abolfazl",
surname: "Roshanzamir",
age: 34
}
};
const myDeepCopy = structuredClone(myOriginal);
structuredClone()
You can use structuredClone() that is a built-in function for deep-copying.
Structured cloning addresses many (although not all) shortcomings of the JSON.stringify() technique.
Structured cloning can handle cyclical data structures,
support many built-in data types, and is generally more robust and often faster.
However, it still has some limitations that may catch you off-guard:
1-Prototypes : If you use structuredClone() with a class instance,
you’ll get a plain object as the return value, as structured cloning discards the object’s prototype chain.
2-Functions: If your object contains functions, they will be quietly discarded.
3- Non-cloneables: Some values are not structured cloneable, most notably Error and DOM nodes. It will cause structuredClone() to throw.
const myDeepCopy = structuredClone(myOriginal);
JSON.stringify
If you simply want to deep copy the object to another object,
all you will need to do is JSON.stringify the object and parse it using JSON.parse afterward.
This will essentially perform deep copying of the object.
let user1 = {
name: 'Abolfazl Roshanzamir',
age: 34,
university: {
name: 'Shiraz Bahonar University'
}
};
let user2 = JSON.parse(JSON.stringify(user1));
user2.name = 'Andy Madadian';
user2.university.name = 'Kerman Bahonar University'
console.log(user2);
// { name: 'Andy Madadian', age: 33, university: { name: 'Kerman Bahonar University' } }
console.log(user1);
// { name: 'Abolfazl Roshanzamir', age: 33, university: { name: 'Shiraz Bahonar University' } }
Spread operator / Object.assign()
One way to create a shallow copy in JavaScript using the object spread operator ... or Object.assign() like the following:
const myShallowCopySpread = {...myOriginal};
const myShallowCopyObjectAssign=Object.assign({},obj)
Performance
When it comes to performance the creator Surma has pointed out that JSON.Parse() can be a bit faster for small objects. But when you have a large object, complex object
structuredClone() starts to get significantly faster.
Browser support is pretty fantastic And even is supported by Node.js.
const a = {
foods: {
dinner: 'Pasta'
}
}
let b = JSON.parse(JSON.stringify(a))
b.foods.dinner = 'Soup'
console.log(b.foods.dinner) // Soup
console.log(a.foods.dinner) // Pasta
Using JSON.stringify and JSON.parse is the best way. Because by using the spread operator we will not get the efficient answer when the json object contains another object inside it. we need to manually specify that.
Here's my deep copy algorithm.
const DeepClone = (obj) => {
if(obj===null||typeof(obj)!=='object')return null;
let newObj = { ...obj };
for (let prop in obj) {
if (
typeof obj[prop] === "object" ||
typeof obj[prop] === "function"
) {
newObj[prop] = DeepClone(obj[prop]);
}
}
return newObj;
};
// use: clone( <thing to copy> ) returns <new copy>
// untested use at own risk
function clone(o, m){
// return non object values
if('object' !==typeof o) return o
// m: a map of old refs to new object refs to stop recursion
if('object' !==typeof m || null ===m) m =new WeakMap()
var n =m.get(o)
if('undefined' !==typeof n) return n
// shallow/leaf clone object
var c =Object.getPrototypeOf(o).constructor
// TODO: specialize copies for expected built in types i.e. Date etc
switch(c) {
// shouldn't be copied, keep reference
case Boolean:
case Error:
case Function:
case Number:
case Promise:
case String:
case Symbol:
case WeakMap:
case WeakSet:
n =o
break;
// array like/collection objects
case Array:
m.set(o, n =o.slice(0))
// recursive copy for child objects
n.forEach(function(v,i){
if('object' ===typeof v) n[i] =clone(v, m)
});
break;
case ArrayBuffer:
m.set(o, n =o.slice(0))
break;
case DataView:
m.set(o, n =new (c)(clone(o.buffer, m), o.byteOffset, o.byteLength))
break;
case Map:
case Set:
m.set(o, n =new (c)(clone(Array.from(o.entries()), m)))
break;
case Int8Array:
case Uint8Array:
case Uint8ClampedArray:
case Int16Array:
case Uint16Array:
case Int32Array:
case Uint32Array:
case Float32Array:
case Float64Array:
m.set(o, n =new (c)(clone(o.buffer, m), o.byteOffset, o.length))
break;
// use built in copy constructor
case Date:
case RegExp:
m.set(o, n =new (c)(o))
break;
// fallback generic object copy
default:
m.set(o, n =Object.assign(new (c)(), o))
// recursive copy for child objects
for(c in n) if('object' ===typeof n[c]) n[c] =clone(n[c], m)
}
return n
}
Here is the deepClone function which handles all primitive, array, object, function data types
function deepClone(obj){
if(Array.isArray(obj)){
var arr = [];
for (var i = 0; i < obj.length; i++) {
arr[i] = deepClone(obj[i]);
}
return arr;
}
if(typeof(obj) == "object"){
var cloned = {};
for(let key in obj){
cloned[key] = deepClone(obj[key])
}
return cloned;
}
return obj;
}
console.log( deepClone(1) )
console.log( deepClone('abc') )
console.log( deepClone([1,2]) )
console.log( deepClone({a: 'abc', b: 'def'}) )
console.log( deepClone({
a: 'a',
num: 123,
func: function(){'hello'},
arr: [[1,2,3,[4,5]], 'def'],
obj: {
one: {
two: {
three: 3
}
}
}
}) )
function deepclone(obj) {
let newObj = {};
if (typeof obj === 'object') {
for (let key in obj) {
let property = obj[key],
type = typeof property;
switch (type) {
case 'object':
if( Object.prototype.toString.call( property ) === '[object Array]' ) {
newObj[key] = [];
for (let item of property) {
newObj[key].push(this.deepclone(item))
}
} else {
newObj[key] = deepclone(property);
}
break;
default:
newObj[key] = property;
break;
}
}
return newObj
} else {
return obj;
}
}
const cloneData = (dataArray) => {
newData= []
dataArray.forEach((value) => {
newData.push({...value})
})
return newData
}
a = [{name:"siva"}, {name:"siva1"}] ;
b = myCopy(a)
b === a // false`
I myself landed on these answers last day, trying to find a way to deep copy complex structures, which may include recursive links. As I wasn't satisfied with anything being suggested before, I implemented this wheel myself. And it works quite well. Hope it helps someone.
Example usage:
OriginalStruct.deep_copy = deep_copy; // attach the function as a method
TheClone = OriginalStruct.deep_copy();
Please look at https://github.com/latitov/JS_DeepCopy for live examples how to use it, and also deep_print() is there.
If you need it quick, right here's the source of deep_copy() function:
function deep_copy() {
'use strict'; // required for undef test of 'this' below
// Copyright (c) 2019, Leonid Titov, Mentions Highly Appreciated.
var id_cnt = 1;
var all_old_objects = {};
var all_new_objects = {};
var root_obj = this;
if (root_obj === undefined) {
console.log(`deep_copy() error: wrong call context`);
return;
}
var new_obj = copy_obj(root_obj);
for (var id in all_old_objects) {
delete all_old_objects[id].__temp_id;
}
return new_obj;
//
function copy_obj(o) {
var new_obj = {};
if (o.__temp_id === undefined) {
o.__temp_id = id_cnt;
all_old_objects[id_cnt] = o;
all_new_objects[id_cnt] = new_obj;
id_cnt ++;
for (var prop in o) {
if (o[prop] instanceof Array) {
new_obj[prop] = copy_array(o[prop]);
}
else if (o[prop] instanceof Object) {
new_obj[prop] = copy_obj(o[prop]);
}
else if (prop === '__temp_id') {
continue;
}
else {
new_obj[prop] = o[prop];
}
}
}
else {
new_obj = all_new_objects[o.__temp_id];
}
return new_obj;
}
function copy_array(a) {
var new_array = [];
if (a.__temp_id === undefined) {
a.__temp_id = id_cnt;
all_old_objects[id_cnt] = a;
all_new_objects[id_cnt] = new_array;
id_cnt ++;
a.forEach((v,i) => {
if (v instanceof Array) {
new_array[i] = copy_array(v);
}
else if (v instanceof Object) {
new_array[i] = copy_object(v);
}
else {
new_array[i] = v;
}
});
}
else {
new_array = all_new_objects[a.__temp_id];
}
return new_array;
}
}
Cheers#!
I would suggest using the spread operator. You'll need to spread a second time if you need to update the second level. Attempting to update the newObject using something like newObject.address.city will throw an error if address did not already exist in oldObject.
const oldObject = {
name: 'A',
address: {
street: 'Station Road',
city: 'Pune'
}
}
const newObject = {
...oldObject,
address: {
...oldObject.address,
city: 'Delhi'
}
}
console.log(newObject)
This is a very old question but I think in 2022 there are many ways to solve this. However, if you want a simple, fast and vanilla JS solution check this out:
const cloner = (o) => {
let idx = 1
const isArray = (a) => a instanceof Array
const isObject = (o) => o instanceof Object
const isUndefined = (a) => a === undefined
const process = v => {
if (isArray(v)) return cloneArray(v)
else if (isObject(v)) return cloneObject(v)
else return v
}
const register = (old, o) => {
old.__idx = idx
oldObjects[idx] = old
newObjects[idx] = o
idx++
}
const cloneObject = o => {
if (!isUndefined(o.__idx)) return newObjects[o.__idx]
const obj = {}
for (const prop in o) {
if (prop === '__idx') continue
obj[prop] = process(o[prop])
}
register(o, obj)
return obj
}
const cloneArray = a => {
if (!isUndefined(a.__idx)) return newObjects[a.__idx]
const arr = a.map((v) => process(v))
register(a, arr)
return arr
}
const oldObjects = {}
const newObjects = {}
let tmp
if (isArray(o)) tmp = cloneArray(o)
else if (isObject(o)) tmp = cloneObject(o)
else return o
for (const id in oldObjects) delete oldObjects[id].__idx
return tmp
}
const c = {
id: 123,
label: "Lala",
values: ['char', 1, {flag: true}, [1,2,3,4,5], ['a', 'b']],
name: undefined
}
const d = cloner(c)
d.name = "Super"
d.values[2].flag = false
d.values[3] = [6,7,8]
console.log({ c, d })
It's recursive and self-contained, all the functions needed are defined in the function cloner().
In this snippet we are handling Array and Object types if you want to add more handlers you can add specify handlers like Date and clone it like new Date(v.getTime())
For me Array and Object are the types that I use the most in my implementations.
I am trying to create a single JavaScript object from an array of objects.
Some values in the object remain the same, while the numerical or float values need to be summed up to form the new single object.
How can this be achieved?
[{
'visit_date': '2013-02-02',
'house_number': '22',
'price': 12.98,
'count_value': 21.554,
'variance': -23.434343434
},
{
'visit_date': '2013-02-02',
'house_number': '22',
'price': 34.78,
'count_value': 1.34,
'variance': -23.434343434
},
{
'visit_date': '2013-02-02',
'house_number': '22',
'price': 61.41,
'count_value':1.94,
'variance': -12.977677874
}]
You can use the reduce function to achieve it
var result = a.reduce(function (acc, c) {
acc.visit_date = c.visit_date;
acc.house_number = c.house_number;
acc.price += c.price;
acc.count_value += c.count_value;
acc.variance += c.variance;
return acc;
}, {
'visit_date': '',
'house_number': '',
'price': 0,
'count_value': 0,
'variance': 0
});
The result will be
{
visit_date: "2013-02-02",
house_number: "22",
price: 109.17,
count_value: 24.834,
variance: -59.846364742
}
Loop through the array, use a for-in loop on each object, and for entries where typeof value === "number", sum them up. Presumably do something useful when they aren't numbers, but you haven't said what. :-)
Sorry, missed the jQuery tag. It can be shorter with jQuery's each:
var dest = {};
$.each(source, function(index, entry) {
$.each(entry, function(key, value) {
if (typeof value === "number") {
dest[key] = key in dest ? dest[key] + value : value;
}
else {
// do something useful with non-numbers
}
});
});
each will loop through the array elements if you give it an array, or through the properties of an object if you give it a non-array object. So in the above, the outer each loops through your array, and the inner each loops through each object's properties.
The in operator on this line:
dest[key] = key in dest ? dest[key] + value : value;
...tells us whether dest already has a key with that name: If so, we add the value to it. If not, we create a new property for that key using the value.
Original non-jQuery:
Roughly:
var dest = {};
var entry;
var index;
var key;
var value;
for (index = 0; index < source.length; ++index) {
entry = source[index];
for (key in entry) {
value = entry[key];
if (typeof value === "number") {
dest[key] = key in dest ? dest[key] + value : value;
}
else {
// do something useful with non-numbers
}
}
}
Something like this perhaps? http://jsfiddle.net/tQLy5/1/
function aToObject(a) {
var o = {}, l = a.length;
while (l--) {
for (key in a[l]) {
if (o.hasOwnProperty(key) && typeof (o[key]) === 'number') {
o[key] += a[l][key];
} else {
o[key] = a[l][key];
}
}
}
return o;
}
Just iterate over the whole array and then over the properties of the objects in array. If the property is number you add them together, otherwise you just assign the property to the new object.
My application has a large array of objects, which I stringify and save them to the disk. Unfortunately, when the objects in the array are manipulated, and sometimes replaced, the properties on the objects are listed in different orders (their creation order?). When I do JSON.stringify() on the array and save it, a diff shows the properties getting listed in different orders, which is annoying when trying to merge the data further with diff and merging tools.
Ideally I would like to sort the properties of the objects in alphabetical order prior to performing the stringify, or as part of the stringify operation. There is code for manipulating the array objects in many places, and altering these to always create properties in an explicit order would be difficult.
Suggestions would be most welcome!
A condensed example:
obj = {}; obj.name="X"; obj.os="linux";
JSON.stringify(obj);
obj = {}; obj.os="linux"; obj.name="X";
JSON.stringify(obj);
The output of these two stringify calls are different, and showing up in a diff of my data, but my application doesn't care about the ordering of properties. The objects are constructed in many ways and places.
The simpler, modern and currently browser supported approach is simply this:
JSON.stringify(sortMyObj, Object.keys(sortMyObj).sort());
However, this method does remove any nested objects that aren't referenced and does not apply to objects within arrays. You will want to flatten the sorting object as well if you want something like this output:
{"a":{"h":4,"z":3},"b":2,"c":1}
You can do that with this:
var flattenObject = function(ob) {
var toReturn = {};
for (var i in ob) {
if (!ob.hasOwnProperty(i)) continue;
if ((typeof ob[i]) == 'object') {
var flatObject = flattenObject(ob[i]);
for (var x in flatObject) {
if (!flatObject.hasOwnProperty(x)) continue;
toReturn[i + '.' + x] = flatObject[x];
}
} else {
toReturn[i] = ob[i];
}
}
return toReturn;
};
var myFlattenedObj = flattenObject(sortMyObj);
JSON.stringify(myFlattenedObj, Object.keys(myFlattenedObj).sort());
To do it programmatically with something you can tweak yourself, you need to push the object property names into an array, then sort the array alphabetically and iterate through that array (which will be in the right order) and select each value from the object in that order. "hasOwnProperty" is checked also so you definitely have only the object's own properties. Here's an example:
var obj = {"a":1,"b":2,"c":3};
function iterateObjectAlphabetically(obj, callback) {
var arr = [],
i;
for (i in obj) {
if (obj.hasOwnProperty(i)) {
arr.push(i);
}
}
arr.sort();
for (i = 0; i < arr.length; i++) {
var key = obj[arr[i]];
//console.log( obj[arr[i]] ); //here is the sorted value
//do what you want with the object property
if (callback) {
// callback returns arguments for value, key and original object
callback(obj[arr[i]], arr[i], obj);
}
}
}
iterateObjectAlphabetically(obj, function(val, key, obj) {
//do something here
});
Again, this should guarantee that you iterate through in alphabetical order.
Finally, taking it further for the simplest way, this library will recursively allow you to sort any JSON you pass into it: https://www.npmjs.com/package/json-stable-stringify
var stringify = require('json-stable-stringify');
var obj = { c: 8, b: [{z:6,y:5,x:4},7], a: 3 };
console.log(stringify(obj));
Output
{"a":3,"b":[{"x":4,"y":5,"z":6},7],"c":8}
I don't understand why the complexity of the current best answers is needed, to get all the keys recursively. Unless perfect performance is needed, it seems to me that we can just call JSON.stringify() twice, the first time to get all the keys, and the second time, to really do the job. That way, all the recursion complexity is handled by stringify, and we know that it knows its stuff, and how to handle each object type:
function JSONstringifyOrder(obj, space)
{
const allKeys = new Set();
JSON.stringify(obj, (key, value) => (allKeys.add(key), value));
return JSON.stringify(obj, Array.from(allKeys).sort(), space);
}
Or if you want to support older browsers:
function JSONstringifyOrder(obj, space)
{
var allKeys = [];
var seen = {};
JSON.stringify(obj, function (key, value) {
if (!(key in seen)) {
allKeys.push(key);
seen[key] = null;
}
return value;
});
allKeys.sort();
return JSON.stringify(obj, allKeys, space);
}
I think that if you are in control of the JSON generation (and it sounds like you are), then for your purposes this might be a good solution: json-stable-stringify
From the project website:
deterministic JSON.stringify() with custom sorting to get
deterministic hashes from stringified results
If the JSON produced is deterministic you should be able to easily diff/merge it.
You can pass a sorted array of the property names as the second argument of JSON.stringify():
JSON.stringify(obj, Object.keys(obj).sort())
JSON.stringify() replacer function for having object keys sorted in output (supports deeply nested objects).
const replacer = (key, value) =>
value instanceof Object && !(value instanceof Array) ?
Object.keys(value)
.sort()
.reduce((sorted, key) => {
sorted[key] = value[key];
return sorted
}, {}) :
value;
// Usage
// JSON.stringify({c: 1, a: { d: 0, c: 1, e: {a: 0, 1: 4}}}, replacer);
GitHub Gist page here.
Update 2018-7-24:
This version sorts nested objects and supports array as well:
function sortObjByKey(value) {
return (typeof value === 'object') ?
(Array.isArray(value) ?
value.map(sortObjByKey) :
Object.keys(value).sort().reduce(
(o, key) => {
const v = value[key];
o[key] = sortObjByKey(v);
return o;
}, {})
) :
value;
}
function orderedJsonStringify(obj) {
return JSON.stringify(sortObjByKey(obj));
}
Test case:
describe('orderedJsonStringify', () => {
it('make properties in order', () => {
const obj = {
name: 'foo',
arr: [
{ x: 1, y: 2 },
{ y: 4, x: 3 },
],
value: { y: 2, x: 1, },
};
expect(orderedJsonStringify(obj))
.to.equal('{"arr":[{"x":1,"y":2},{"x":3,"y":4}],"name":"foo","value":{"x":1,"y":2}}');
});
it('support array', () => {
const obj = [
{ x: 1, y: 2 },
{ y: 4, x: 3 },
];
expect(orderedJsonStringify(obj))
.to.equal('[{"x":1,"y":2},{"x":3,"y":4}]');
});
});
Deprecated answer:
A concise version in ES2016.
Credit to #codename , from https://stackoverflow.com/a/29622653/94148
function orderedJsonStringify(o) {
return JSON.stringify(Object.keys(o).sort().reduce((r, k) => (r[k] = o[k], r), {}));
}
This is same as Satpal Singh's answer
function stringifyJSON(obj){
keys = [];
if(obj){
for(var key in obj){
keys.push(key);
}
}
keys.sort();
var tObj = {};
var key;
for(var index in keys){
key = keys[index];
tObj[ key ] = obj[ key ];
}
return JSON.stringify(tObj);
}
obj1 = {}; obj1.os="linux"; obj1.name="X";
stringifyJSON(obj1); //returns "{"name":"X","os":"linux"}"
obj2 = {}; obj2.name="X"; obj2.os="linux";
stringifyJSON(obj2); //returns "{"name":"X","os":"linux"}"
A recursive and simplified answer:
function sortObject(obj) {
if(typeof obj !== 'object')
return obj
var temp = {};
var keys = [];
for(var key in obj)
keys.push(key);
keys.sort();
for(var index in keys)
temp[keys[index]] = sortObject(obj[keys[index]]);
return temp;
}
var str = JSON.stringify(sortObject(obj), undefined, 4);
You can sort object by property name in EcmaScript 2015
function sortObjectByPropertyName(obj) {
return Object.keys(obj).sort().reduce((c, d) => (c[d] = obj[d], c), {});
}
You can add a custom toJSON function to your object which you can use to customise the output. Inside the function, adding current properties to a new object in a specific order should preserve that order when stringified.
See here:
https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/JSON/stringify
There's no in-built method for controlling ordering because JSON data is meant to be accessed by keys.
Here's a jsfiddle with a small example:
http://jsfiddle.net/Eq2Yw/
Try commenting out the toJSON function - the order of the properties is reversed. Please be aware that this may be browser-specific, i.e. ordering is not officially supported in the specification. It works in the current version of Firefox, but if you want a 100% robust solution, you may have to write your own stringifier function.
Edit:
Also see this SO question regarding stringify's non-deterministic output, especially Daff's details about browser differences:
How to deterministically verify that a JSON object hasn't been modified?
I took the answer from #Jason Parham and made some improvements
function sortObject(obj, arraySorter) {
if(typeof obj !== 'object')
return obj
if (Array.isArray(obj)) {
if (arraySorter) {
obj.sort(arraySorter);
}
for (var i = 0; i < obj.length; i++) {
obj[i] = sortObject(obj[i], arraySorter);
}
return obj;
}
var temp = {};
var keys = [];
for(var key in obj)
keys.push(key);
keys.sort();
for(var index in keys)
temp[keys[index]] = sortObject(obj[keys[index]], arraySorter);
return temp;
}
This fixes the issue of arrays being converted to objects, and it also allows you to define how to sort arrays.
Example:
var data = { content: [{id: 3}, {id: 1}, {id: 2}] };
sortObject(data, (i1, i2) => i1.id - i2.id)
output:
{content:[{id:1},{id:2},{id:3}]}
I just rewrote one of mentioned examples to use it in stringify
const stringifySort = (key, value) => {
if (!value || typeof value !== 'object' || Array.isArray(value)) return value;
return Object.keys(value).sort().reduce((obj, key) => (obj[key]=value[key], obj), {});
};
JSON.stringify({name:"X", os:"linux"}, stringifySort);
The accepted answer does not work for me for nested objects for some reason. This led me to code up my own. As it's late 2019 when I write this, there are a few more options available within the language.
Update: I believe David Furlong's answer is a preferable approach to my earlier attempt, and I have riffed off that. Mine relies on support for Object.entries(...), so no Internet Explorer support.
function normalize(sortingFunction) {
return function(key, value) {
if (typeof value === 'object' && !Array.isArray(value)) {
return Object
.entries(value)
.sort(sortingFunction || undefined)
.reduce((acc, entry) => {
acc[entry[0]] = entry[1];
return acc;
}, {});
}
return value;
}
}
JSON.stringify(obj, normalize(), 2);
--
KEEPING THIS OLDER VERSION FOR HISTORICAL REFERENCE
I found that a simple, flat array of all keys in the object will work. In almost all browsers (not Edge or Internet explorer, predictably) and Node 12+ there is a fairly short solution now that Array.prototype.flatMap(...) is available. (The lodash equivalent would work too.) I have only tested in Safari, Chrome, and Firefox, but I see no reason why it wouldn't work anywhere else that supports flatMap and standard JSON.stringify(...).
function flattenEntries([key, value]) {
return (typeof value !== 'object')
? [ [ key, value ] ]
: [ [ key, value ], ...Object.entries(value).flatMap(flattenEntries) ];
}
function sortedStringify(obj, sorter, indent = 2) {
const allEntries = Object.entries(obj).flatMap(flattenEntries);
const sorted = allEntries.sort(sorter || undefined).map(entry => entry[0]);
return JSON.stringify(obj, sorted, indent);
}
With this, you can stringify with no 3rd-party dependencies and even pass in your own sort algorithm that sorts on the key-value entry pairs, so you can sort by key, payload, or a combination of the two. Works for nested objects, arrays, and any mixture of plain old data types.
const obj = {
"c": {
"z": 4,
"x": 3,
"y": [
2048,
1999,
{
"x": false,
"g": "help",
"f": 5
}
]
},
"a": 2,
"b": 1
};
console.log(sortedStringify(obj, null, 2));
Prints:
{
"a": 2,
"b": 1,
"c": {
"x": 3,
"y": [
2048,
1999,
{
"f": 5,
"g": "help",
"x": false
}
],
"z": 4
}
}
If you must have compatibility with older JavaScript engines, you could use these slightly more verbose versions that emulate flatMap behavior. Client must support at least ES5, so no Internet Explorer 8 or below.
These will return the same result as above.
function flattenEntries([key, value]) {
if (typeof value !== 'object') {
return [ [ key, value ] ];
}
const nestedEntries = Object
.entries(value)
.map(flattenEntries)
.reduce((acc, arr) => acc.concat(arr), []);
nestedEntries.unshift([ key, value ]);
return nestedEntries;
}
function sortedStringify(obj, sorter, indent = 2) {
const sortedKeys = Object
.entries(obj)
.map(flattenEntries)
.reduce((acc, arr) => acc.concat(arr), [])
.sort(sorter || undefined)
.map(entry => entry[0]);
return JSON.stringify(obj, sortedKeys, indent);
}
An additional solution that works for nested objects as well:
const myFunc = (key) =>
JSON.stringify(key, (_, v) =>
v.constructor === Object ? Object.entries(v).sort() : v
);
const jsonFunc = JSON.stringify;
const obj1 = {
key1: "value1",
key2: {
key3: "value2",
key4: "value3",
},
};
const obj2 = {
key2: {
key4: "value3",
key3: "value2",
},
key1: "value1",
};
console.log(`JSON: ${jsonFunc(obj1) === jsonFunc(obj2)}`);
console.log(`My: ${myFunc(obj1) === myFunc(obj2)}`);
Works with lodash, nested objects, any value of object attribute:
function sort(myObj) {
var sortedObj = {};
Object.keys(myObj).sort().forEach(key => {
sortedObj[key] = _.isPlainObject(myObj[key]) ? sort(myObj[key]) : myObj[key]
})
return sortedObj;
}
JSON.stringify(sort(yourObj), null, 2)
It relies on Chrome's and Node's behaviour that the first key assigned to an object is outputted first by JSON.stringify.
After all, it needs an Array that caches all keys in the nested object (otherwise it will omit the uncached keys.) The oldest answer is just plain wrong, because second argument doesn't care about dot-notation. So, the answer (using Set) becomes.
function stableStringify (obj) {
const keys = new Set()
const getAndSortKeys = (a) => {
if (a) {
if (typeof a === 'object' && a.toString() === '[object Object]') {
Object.keys(a).map((k) => {
keys.add(k)
getAndSortKeys(a[k])
})
} else if (Array.isArray(a)) {
a.map((el) => getAndSortKeys(el))
}
}
}
getAndSortKeys(obj)
return JSON.stringify(obj, Array.from(keys).sort())
}
Try:
function obj(){
this.name = '';
this.os = '';
}
a = new obj();
a.name = 'X',
a.os = 'linux';
JSON.stringify(a);
b = new obj();
b.os = 'linux';
b.name = 'X',
JSON.stringify(b);
I made a function to sort object, and with callback .. which actually create a new object
function sortObj( obj , callback ) {
var r = [] ;
for ( var i in obj ){
if ( obj.hasOwnProperty( i ) ) {
r.push( { key: i , value : obj[i] } );
}
}
return r.sort( callback ).reduce( function( obj , n ){
obj[ n.key ] = n.value ;
return obj;
},{});
}
and call it with object .
var obj = {
name : "anu",
os : "windows",
value : 'msio',
};
var result = sortObj( obj , function( a, b ){
return a.key < b.key ;
});
JSON.stringify( result )
which prints {"value":"msio","os":"windows","name":"anu"} , and for sorting with value .
var result = sortObj( obj , function( a, b ){
return a.value < b.value ;
});
JSON.stringify( result )
which prints {"os":"windows","value":"msio","name":"anu"}
If objects in the list does not have same properties, generate a combined master object before stringify:
let arr=[ <object1>, <object2>, ... ]
let o = {}
for ( let i = 0; i < arr.length; i++ ) {
Object.assign( o, arr[i] );
}
JSON.stringify( arr, Object.keys( o ).sort() );
function FlatternInSort( obj ) {
if( typeof obj === 'object' )
{
if( obj.constructor === Object )
{ //here use underscore.js
let PaireStr = _( obj ).chain().pairs().sortBy( p => p[0] ).map( p => p.map( FlatternInSort ).join( ':' )).value().join( ',' );
return '{' + PaireStr + '}';
}
return '[' + obj.map( FlatternInSort ).join( ',' ) + ']';
}
return JSON.stringify( obj );
}
// example as below. in each layer, for objects like {}, flattened in key sort. for arrays, numbers or strings, flattened like/with JSON.stringify.
FlatternInSort( { c:9, b: { y: 4, z: 2, e: 9 }, F:4, a:[{j:8, h:3},{a:3,b:7}] } )
"{"F":4,"a":[{"h":3,"j":8},{"a":3,"b":7}],"b":{"e":9,"y":4,"z":2},"c":9}"
Extending AJP's answer, to handle arrays:
function sort(myObj) {
var sortedObj = {};
Object.keys(myObj).sort().forEach(key => {
sortedObj[key] = _.isPlainObject(myObj[key]) ? sort(myObj[key]) : _.isArray(myObj[key])? myObj[key].map(sort) : myObj[key]
})
return sortedObj;
}
Surprised nobody has mentioned lodash's isEqual function.
Performs a deep comparison between two values to determine if they are
equivalent.
Note: This method supports comparing arrays, array buffers, booleans,
date objects, error objects, maps, numbers, Object objects, regexes,
sets, strings, symbols, and typed arrays. Object objects are compared
by their own, not inherited, enumerable properties. Functions and DOM
nodes are compared by strict equality, i.e. ===.
https://lodash.com/docs/4.17.11#isEqual
With the original problem - keys being inconsistently ordered - it's a great solution - and of course it will just stop if it finds a conflict instead of blindly serializing the whole object.
To avoid importing the whole library you do this:
import { isEqual } from "lodash-es";
Bonus example:
You can also use this with RxJS with this custom operator
export const distinctUntilEqualChanged = <T>(): MonoTypeOperatorFunction<T> =>
pipe(distinctUntilChanged(isEqual));
Here is a clone approach...clone the object before converting to json:
function sort(o: any): any {
if (null === o) return o;
if (undefined === o) return o;
if (typeof o !== "object") return o;
if (Array.isArray(o)) {
return o.map((item) => sort(item));
}
const keys = Object.keys(o).sort();
const result = <any>{};
keys.forEach((k) => (result[k] = sort(o[k])));
return result;
}
If is very new but seems to work on package.json files fine.
Don't be confused with the object monitoring of Chrome debugger. It shows sorted keys in object, even though actually it is not sorted. You have to sort the object before you stringify it.
Before I found libs like fast-json-stable-stringify (haven't tested it in production myself), I was doing it this way:
import { flatten } from "flat";
import { set } from 'lodash/fp';
const sortJson = (jsonString) => {
const object = JSON.parse(jsonString);
const flatObject = flatten(object);
const propsSorted = Object.entries(flatObject).map(([key, value]) => ({ key, value })).sort((a, b) => a.key.localeCompare(b.key));
const objectSorted = propsSorted.reduce((object, { key, value }) => set(key, value, object), {});
return JSON.stringify(objectSorted);
};
const originalJson = JSON.stringify({ c: { z: 3, x: 1, y: 2 }, a: true, b: [ 'a', 'b', 'c' ] });
console.log(sortJson(originalJson)); // {"a":true,"b":["a","b","c"],"c":{"x":1,"y":2,"z":3}}
There is Array.sort method which can be helpful for you. For example:
yourBigArray.sort(function(a,b){
//custom sorting mechanism
});