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Beautiful Soup returns only javaScript Code?

I want to scrape data from the following website. https://dell.secure.force.com/FAP/?c=de&l=de&pt=findareseller
I tried to get data from the network tab but it returns nothing. Then I tried BeautifulSoup to get some data but it returns only Javascript with empty tbody tags. But in inspect element, it shows the data in a table.
import requests
from bs4 import BeautifulSoup
url = 'https://dell.secure.force.com/FAP'
headers = {
'Connection': 'keep-alive'
}
data = {
'pt': "findareseller"
}
page = requests.get(url, params= data)
soup = BeautifulSoup(page.text, 'html.parser')
soup.find_all('table') # returns only javascript code.
Can someone help, how can I scrape the data?

soup.find_all('table') returns a list with all table elements.
So to find your specific element you should try to find some distinct properties that makes it different from all the other tables (like an id or class).
To access the elements attributes use t[0].attrs to get a list of them and for example: t[0]["width"] to access them.
Also: By using soup.select('table') instead, you can use css selectors as the string input, so you won't have to deal with beautifulsoups functions.

Thank you all.
I figure out the answer.
I use network search to fetch any search requests. I found the search URL, to confirm if the URL was right, I double-clicked it and it returns the exact same page. so I copy the bash code and past it into POSTMAN as import "RAW TEXT". I find out it actually uses post requests. After using post request, I was able to fetch the data I needed.
below is the request with POST.
response = requests.request("POST", url, headers=headers, data=payload)
then I use BeautifulSoup as soup.
st = soup.find('input')['value'] # returns data I needed

Python Beautiful Webscraping Simulate Click to Scrape All Pages

I ran into an interesting issue while trying to scrape http://www.o-review.com/database_filter_model.php?table_name=glasses&tag= containing 42 pages of data. I was able to successfully scrape the first page of information, but while trying to scrape all pages I found that the URL remains unchanged, and changing the page uses a button at the bottom of the website.
The html code in the inspector reads:
<div onclick="filter_page('1')" class="filter_nav_button round5"
style="cursor:pointer;"><img src="/images/icon_arrow_next.svg"></div>
I'm very new at scraping and python but was told I need to simulate a "click" in the javascript which I have absolutely no idea how to do, and wasn't sure if it could be hard-coded. My weak attempt to try something so far:
response = get('http://www.o-review.com/database_filter_model.php?
table_name=glasses&tag=')
soup = bs(response.text, 'html.parser')
print(soup)
for page in range(1, 42):
pages = soup.find('div', onclick_ = 'filter_page()')
Hopefully, someone has solved this issue in the past. Help would be greatly appreciated! Thanks!
Edit: Here is the code I'm trying to add:
## Find All Frame models
for find_frames in soup.find_all('a', class_ = 'round5
grid_model'):
# Each iteration grabs child text and prints it
all_models = find_frames.text
print(all_models)
This would be added where the comment was to add code! Thanks!

The request is made via POST request where you can check my previous-answer in order to know how to get the actual API
Also html.parser or lxml is the not a part of your issue.
The reason why i used lxml because it's more fast than html.parser according to documentation
import requests
from bs4 import BeautifulSoup
from pprint import pp
def main(url):
with requests.Session() as req:
for page in range(1, 44):
print("[*] - Extracting Page# {}".format(page))
data = {
"table_name": "glasses",
"family": "",
"page": "{}".format(page),
"sort": "",
"display": "list",
}
r = req.post(url, data=data)
soup = BeautifulSoup(r.text, 'lxml')
pp([x.text for x in soup.select(
'.text-clip') if x.get_text(strip=True)])
if __name__ == "__main__":
main('http://www.o-review.com/ajax/database_filter_model.php')

I saw the answer to this question and your comment. The reason αԋɱҽԃ αмєяιcαη's code works is because it sends request to the actual ajax api the sit is getting data from. You could easily use your browser's developer tools to track it down. It's not because of lxml or whatever, you just had to find the right source ;)
And of course αԋɱҽԃ αмєяιcαη should have explained some parts in his answer to clarify everything for you.

How to webscrape data from a webpage with dynamic HTML (Python)?

I'm trying to figure out how to scrape the data from the following url: https://www.aap.org/en-us/advocacy-and-policy/aap-health-initiatives/nicuverification/Pages/NICUSearch.aspx
Here is the type of data:
It appears that everything is populated from a database and loaded into the webpage via javascript.
I've done something similar in the past using selenium and PhantomJS but I can't figure out how to get these data fields in Python.
As expected, I can't use pd.read_html for this type of problem.
Is it possible to parse the results from:
from selenium import webdriver
url="https://www.aap.org/en-us/advocacy-and-policy/aap-health-initiatives/nicuverification/Pages/NICUSearch.aspx"
browser = webdriver.PhantomJS()
browser.get(url)
content = browser.page_source
Or maybe to access the actual underlying data?
If not, what are other approaches short of copy and pasting for hours?
EDIT:
Building on the answer below, from #thenullptr I have been able to access the material but only on page 1. How can I adapt this to go across all of the pages [recommendations to parse properly]? My end goal is to have this in a pandas dataframe
import requests
from bs4 import BeautifulSoup
r = requests.post(
url = 'https://search.aap.org/nicu/',
data = {'SearchCriteria.Level':'1', 'X-Requested-With':'XMLHttpRequest'},
) #key:value
html = r.text
# Parsing the HTML
soup = BeautifulSoup(html.split("</script>")[-1].strip(), "html")
div = soup.find("div", {"id": "main"})
div = soup.findAll("div", {"class":"blue-border panel list-group"})
def f(x):
ignore_fields = ['Collapse all','Expand all']
output = list(filter(bool, map(str.strip, x.text.split("\n"))))
output = list(filter(lambda x: x not in ignore_fields, output))
return output
results = pd.Series(list(map(f, div))[0])

To follow on from my last comment, the below should give you a good starting point. When looking through the XHR calls you just want to see what data is being sent and received from each one to pinpoint the one you need. The below is the raw POST data being sent to the API when doing a search, it looks like you need to use at least one and include the last one.
{
"SearchCriteria.Name": "smith",
"SearchCriteria.City": "",
"SearchCriteria.State": "",
"SearchCriteria.Zip": "",
"SearchCriteria.Level": "",
"SearchCriteria.LevelAssigner": "",
"SearchCriteria.BedNumberRange": "",
"X-Requested-With": "XMLHttpRequest"
}
Here is a simple example of how you can send a post request using the requests library, the web page will reply with the raw data so you can use BS or similar to parse it to get the information you need.
import requests
r = requests.post('https://search.aap.org/nicu/',
data = {'SearchCriteria.Name':'smith', 'X-Requested-With':'XMLHttpRequest'}) #key:value
print(r.text)
prints <strong class="col-md-8 white-text">JOHN PETER SMITH HOSPITAL</strong>...
https://requests.readthedocs.io/en/master/user/quickstart/

scrapy + selenium: <a> tag has no href, but content is loaded by javascript

I'm almost there with my first try of using scrapy, selenium to collect data from website with javascript loaded content.
Here is my code:
# -*- coding: utf-8 -*-
import scrapy
from selenium import webdriver
from scrapy.selector import Selector
from scrapy.http import Request
from selenium.webdriver.common.by import By
import time
class FreePlayersSpider(scrapy.Spider):
name = 'free_players'
allowed_domains = ['www.forge-db.com']
start_urls = ['https://www.forge-db.com/fr/fr11/players/?server=fr11']
driver = {}
def __init__(self):
self.driver = webdriver.Chrome('/home/alain/Documents/repository/web/foe-python/chromedriver')
self.driver.get('https://forge-db.com/fr/fr11/players/?server=fr11')
def start_requests(self):
for url in self.start_urls:
yield scrapy.Request(url=url, callback=self.parse)
def parse(self, response):
#time.sleep(1)
sel = Selector(text = self.driver.page_source)
players = sel.xpath('.//table/tbody/tr')
for player in players:
joueur = player.xpath('.//td[3]/a/text()').get()
guilde = player.xpath('.//td[4]/a/text()').get()
yield {
'player' : joueur,
'guild' : guilde
}
next_page_btn = self.driver.find_element_by_xpath('//a[#class="paginate_button next"]')
if next_page_btn:
time.sleep(2)
next_page_btn.click()
yield scrapy.Request(url = self.start_urls, callback=self.parse)
# Close the selenium driver, so in fact it closes the testing browser
self.driver.quit()
def parse_players(self):
pass
I want to collect user names and their relative guild and output to a csv file.
For now my issue is to proceed to NEXT PAGE and to parse again the content loaded by javascript.
if i'm able to simulate click on NEXT tag, i'm not 100% sure that code will proceed all pages and i'm not able to parse the new content using the same function.
Any idea how could i solve this issue ?
thx.

Instead of using selenium, you should try recreate the request to update the table. If you look closely at the HTML under chrometools. You can see that the request is made with parameters and a response is sent back with the data in a nice structured format.
Please see here with regards to dynamic content in scrapy. As it explains the first step to think about is it necessary to recreate browser activity ? Or can I get the information I need from reverse engineering HTTP get requests. Sometimes the information is hidden with <script></script> tags and you can use some regex or some string methods to gain what you want. Rendering the page and then using browser activity should be thought of as a last step.
Now before I go into some background on reverse engineering the requests, this website you're trying to get information from requires only to reverse engineer the HTTP requests.
Reverse Engineering HTTP requests in Scrapy
Now in terms of the actual web itself we can use chrome devtools by right clicking inspect on a page. Clicking the network tab allows you to see all requests the browser makes to render the page. In this case you want to see what happens when you click next.
Image1: here
Here you can see all the requests made when you click next on the page. I always look for the biggest sized response as that'll most likely have your data.
Image2: here
Here you can see the request headers/params etc... things you need to make a proper HTTP request. We can see that the referring URL is actually getplayers.php with all the params to get the next page added on. If you scroll down you can see all the same parameters it sends to getplayers.php. Keep this in mind, sometimes we need to send headers, cookies and parameters.
Image3: here
Here is the preview of the data we would get back from the server if we make the correct request, it's a nice neat format which is great for scraping.
Now You could copy the headers and parameters, cookies here into scrapy, but after a bit of searching and it's always worth checking this first, if just by passing in an HTTP request with the url will you get the data you want then that is the simplest way.
In this case it's true and infact you get in a nice need format with all the data.
Code example
import scrapy
class TestSpider(scrapy.Spider):
name = 'test'
allowed_domains = ['forge-db.com']
def start_requests(self):
url = 'https://www.forge-db.com/fr/fr11/getPlayers.php?'
yield scrapy.Request(url=url)
def parse(self,response):
for row in response.json()['data']:
yield {'name':row[2],'guild':row[3] }
Settings
In settings.py, you need to set ROBOTSTXT_OBEY = False The site doesn't want you to access this data so we need to set it to false. Be careful, you could end getting banned from the server.
I would also suggest a couple of other settings to be respectful and cache the results so if you want to play around with this large dataset you don't hammer the server.
CONCURRENT_REQUESTS = 1
DOWNLOAD_DELAY = 3
HTTPCACHE_ENABLED = True
HTTPCACHE_DIR = 'httpcache'
Comments on the code
We make a request to https://www.forge-db.com/fr/fr11/getPlayers.php? and if you were to print the response you get all the data from the table, it's quite a lot... Now it looks like it's in json format so we use scrapy's new feature to handle json and convert into a python dictionary. response.json() be sure that you have uptodate scrapy to take advantage of this. Otherwise you could use the json library that python provides to do the same thing.
Now you have to look at the preview data abit here but the individual rows are within response.json()['data'][i] where i in the row of data. The name and guild are within response.json()['data'][i][2] and response.json()['data'][i][3]. So looping over every response.json()['data']and grabbing the name and guild.
If the data wasn't so structured as it is here and it needed modifying I would strongly urge you to use Items or ItemLoaders for creating the fields that you can then output the data. You can modifying the extracted data more easily with ItemLoaders and you can interact with duplicates items etc using a pipeline. These are just some thoughts for in the future, I almost never use yielding a dictionary for extracting data particularly large datasets.

Python - Scrape Views Count from Instagram Video, load to JSON format

I want to scrape the number of views that specific videos on Instagram have. I'm relatively new to python but I'm guessing there must be a way given that the views can be found in the source code.
https://www.instagram.com/p/BOTU6rJhShv/ is one video I have been working with. As of this writing, it has 1759 views. Looking at the source code, 1759 is clearly listed as the "video_views" inside of a dictionary-like element:
This element sits deep inside one of the page's tag. From what I've read, the data is currently organized in a javascript form and should be converted to JSON to use in python. Here's what I have so far:
import json
import re
from urllib.request import urlopen
from bs4 import BeautifulSoup as bs
page = urlopen('https://www.instagram.com/p/BOTU6rJhShv/')
soup = bs(page.read(),"html.parser")
body = soup.find('body',{'class':''})
script = body.find('script',{'type':'text/javascript'})
print(script)
Since I print the result of script at the bottom, I know this hones in on the section of the page I want to focus on. If I could read in that information to python, I can iterate through it find the "video_views" key, but that is where I am stuck. How can I convert the information between the script tags to JSON format and load into python?

Well, since the format is always the same, you could simply do this:
data = json.loads(script.text.replace('window._sharedData = ', '')[:-1])
Update: (I'm using python 2.7, so urllib2.urlopen is used instead)
I do get consistent output from this code:
import json
import re
import urllib2
from bs4 import BeautifulSoup as bs
page = urllib2.urlopen('https://www.instagram.com/p/BOTU6rJhShv/')
soup = bs(page.read(),"html.parser")
body = soup.find('body',{'class':''})
script = body.find('script',{'type':'text/javascript'})
data = json.loads(script.text.replace('window._sharedData = ', '')[:-1])
print data
print data['entry_data']['PostPage'][0]['media']['video_views']
Currently the video_views is 1759.