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Matching patterns not within a set of opening and closing characters e.g {}, ()

I have this string pattern below
str = "nums#1#2#3{#4}#5"
Its there a way I can match all the #\d+ patterns excluding the ones within the curly braces.
I am currently achieving the desired result by replace the curly braces and everything withing them with an empty string before matching.
str = str.replace(/\{[^}]*\}/g, '');
match = str.match(/#\d+/g);
Its there a way to do this in javascript regular expression without the first replacement?

Assuming { and } are balanced, you can use this negative lookahead to match numbers not within {...}:
var str = "nums#1#2#3{#4}#5";
var arr = str.match(/#\d+(?![^{]*})/g)
console.log(arr)
//=> ["#1", "#2", "#3", "#5"]
(?![^{]*} is a negative lookahead that asserts after a number we don't have a } ahead before matching a {

The way is to capture all that you don't want before, example:
var result = txt.replace(/((?:{[^}]*}|[^#{]|#(?!\d))*)(#\d+)/g, '$1 number:$2 ');

Yes, use this one : (?!{)#\d(?!})
Demo

var str = "nums#1#2#3{#4}#5";
var result=str.match(/#\d+(?!})/g);
console.log(result);
you can write like this too.

Add condition to regex and convert it from js to vb.net

I have this regex expression(match either English or Hebrew chars, but not combined):
/^(?:[\u0590-\u05FF\uFB1D-\uFB40]+|[\w]+)$/i
It works ok, I just need to also add limitaion so no numbers would be allow.
This should match: abc, אבג
This should not be match: a1, 1b, aא,
The same limitation also need to be added to this regex expression:
/^(?:[\u0590-\u05FF\uFB1D-\uFB40 ]+|[\w ]+)$/i
Its purpose is the same as the first one, only that spaces are allowed.
This should match: abcx, abcx ascx, דגהק ,שגד דשגב
This should not be match: asaceדגעההת, ascasv אקיכרעקכ, as3, a3s, אב3ע
Also, if someone can help me to convert the new regex expression I requested,
and also this on:
/^05\d{8}$/i
from JavaScript to VB, I'd be most grateful.

Just use [A-Za-z] instead of \w if you don't want to allow numbers. If you are using the /i flag, you can also just use [a-z].
var regex = /^(?:[\u0590-\u05FF\uFB1D-\uFB40 ]+|[a-zA-Z ]+)$/i;
var texts = ["abcx", "abcx ascx", "דגהק" ,"שגד דשגב", "asaceדגעההת", "ascasv אקיכרעקכ", "as3", "a3s", "אב3ע"];
for(var i=0; i<texts.length; i++) {
var text = texts[i];
console.log(text + ": ", !!text.match(regex));
}

regex lookbehind in javascript

i im trying to match some words in text
working example (what i want) regex101:
regex = /(?<![a-z])word/g
text = word 1word !word aword
only the first three words will be matched which is what i want to achieve.
but the look behind will not work in javascript :(
so now im trying this regex101:
regex = /(\b|\B)word/g
text = word 1word !word aword
but all words will match and they may not be preceded with an other letter, only with an integer or special characters.
if i use only the smaller "\b" the 1word wont matchand if i only use the "\B" the !word will not match
Edit
The output should be ["word","word","word"]
and the 1 ! must not be included in the match also not in another group, this is because i want to use it with javascript .replace(regex,function(match){}) which should not loop over the 1 and !
The code i use it for
for(var i = 0; i < elements.length; i++){
text = elements[i].innerHTML;
textnew = text.replace(regexp,function(match){
matched = getCrosslink(match)[0];
return "<a href='"+matched.url+"'>"+match+"</a>";
});
elements[i].innerHTML = textnew;
}

Capturing the leading character
It's difficult to know exactly what you want without seeing more output examples, but what about looking for either starts with boundary or starts with a non-letter. Like this for example:
(\bword|[^a-zA-Z]word)
Output: ['word', '1word', '!word']
Here is a working example
Capturing only the "word"
If you only want the "word" part to be captured you can use the following and fetch the 2nd capture group:
(\b|[^a-zA-Z])(word)
Output: ['word', 'word', 'word']
Here is a working example
With replace()
You can use specific capture groups when defining the replace value, so this will work for you (where "new" is the word you want to use):
var regex = /(\b|[^a-zA-Z])(word)/g;
var text = "word 1word !word aword";
text = text.replace(regex, "$1" + "new");
output: "new 1new !new aword"
Here is a working example
If you are using a dedicated function in replace, try this:
textnew = text.replace(regexp,function (allMatch, match1, match2){
matched = getCrosslink(match2)[0];
return "<a href='"+matched.url+"'>"+match2+"</a>";
});
Here is a working example

You can use the following regex
([^a-zA-Z]|\b)(word)
Simply use replace like as
var str = "word 1word !word aword";
str.replace(/([^a-zA-Z]|\b)(word)/g,"$1"+"<a>$2</a>");
Regex

Regex to capture typed information in TypeScript

I'm new to Regex, took some tutorials, having a hard time getting this right.
I'm working on a language support for TypeScript for a text editor, and I need a regex that matches JUST the typing information in a function. For example:
function asdf(param1:type1, param2:type2, param3:type3) {...}
In that, my regex should match 'type1', 'type2', 'type3' etc.
Here's what I'm trying:
\(.+?:(\w).+?\)
Breaks down like this:
\( look for starting parenthesis
.+?: any number of characters up to the colon
(\w) capture group: the next word
.+? There may be additional words after this
\) Close parentheses for the end of the function parameters.
Not sure what I'm doing wrong, but like I said I'm new to regex. Currently it captures the entire stuff, from beginning parens to closing parens. I need it to match JUST the single words after the colon.
NOTE: I want to make sure it only matches words after colons inside parens, so that it doesn't match object key/data combos, which look similar in Javascript.
Thanks!

Try thus
var STRIP_COMMENTS = /((\/\/.*$)|(\/\*[\s\S]*?\*\/))/mg;
var ARGUMENT_NAMES = /([^\s,]+)/g;
function getParamNames(func) {
var fnStr = func.toString().replace(STRIP_COMMENTS, '')
var result = fnStr.slice(fnStr.indexOf('(')+1, fnStr.indexOf(')')).match(ARGUMENT_NAMES)
if(result === null)
result = []
for(i=0; i< result.length; i++)
result[i]=result[i].split(":")[1];
return result
}
how to use
getParamNames("function asdf(param1:type1, param2:type2, param3:type3) {...}");
reference
How to get function parameter names/values dynamically from javascript

How do I make a regular expression that matches everything on a line after a given character?

If I have a String in JavaScript
key=value
How do I make a RegEx that matches key excluding =?
In other words:
var regex = //Regular Expression goes here
regex.exec("key=value")[0]//Should be "key"
How do I make a RegEx that matches value excluding =?
I am using this code to define a language for the Prism syntax highlighter so I do not control the JavaScript code doing the Regular Expression matching nor can I use split.

Well, you could do this:
/^[^=]*/ // anything not containing = at the start of a line
/[^=]*$/ // anything not containing = at the end of a line
It might be better to look into Prism's lookbehind property, and use something like this:
{
'pattern': /(=).*$/,
'lookbehind': true
}
According to the documentation this would cause the = character not to be part of the token this pattern matches.

use this regex (^.+?)=(.+?$)
group 1 contain key
group 2 contain value
but split is better solution

.*=(.*)
This will match anything after =
(.*)=.*
This will match anything before =
Look into greedy vs ungreedy quantifiers if you expect more than one = character.
Edit: as OP has clarified they're using javascript:
var str = "key=value";
var n=str.match(/(.*)=/i)[1]; // before =
var n=str.match(/=(.*)/i)[1]; // after =

var regex = /^[^=]*/;
regex.exec("key=value");