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How can I convert seconds to an HH-MM-SS string using JavaScript?
You can manage to do this without any external JavaScript library with the help of JavaScript Date method like following:
const date = new Date(null);
date.setSeconds(SECONDS); // specify value for SECONDS here
const result = date.toISOString().slice(11, 19);
Or, as per #Frank's comment; a one liner:
new Date(SECONDS * 1000).toISOString().slice(11, 19);
Updated (2020):
Please use #Frank's one line solution:
new Date(SECONDS * 1000).toISOString().substring(11, 16)
If SECONDS<3600 and if you want to show only MM:SS then use below code:
new Date(SECONDS * 1000).toISOString().substring(14, 19)
It is by far the best solution.
Old answer:
Use the Moment.js library.
I don't think any built-in feature of the standard Date object will do this for you in a way that's more convenient than just doing the math yourself.
hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
minutes = Math.floor(totalSeconds / 60);
seconds = totalSeconds % 60;
Example:
let totalSeconds = 28565;
let hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
let minutes = Math.floor(totalSeconds / 60);
let seconds = totalSeconds % 60;
console.log("hours: " + hours);
console.log("minutes: " + minutes);
console.log("seconds: " + seconds);
// If you want strings with leading zeroes:
minutes = String(minutes).padStart(2, "0");
hours = String(hours).padStart(2, "0");
seconds = String(seconds).padStart(2, "0");
console.log(hours + ":" + minutes + ":" + seconds);
I know this is kinda old, but...
ES2015:
var toHHMMSS = (secs) => {
var sec_num = parseInt(secs, 10)
var hours = Math.floor(sec_num / 3600)
var minutes = Math.floor(sec_num / 60) % 60
var seconds = sec_num % 60
return [hours,minutes,seconds]
.map(v => v < 10 ? "0" + v : v)
.filter((v,i) => v !== "00" || i > 0)
.join(":")
}
It will output:
toHHMMSS(129600) // 36:00:00
toHHMMSS(13545) // 03:45:45
toHHMMSS(180) // 03:00
toHHMMSS(18) // 00:18
As Cleiton pointed out in his answer, moment.js can be used for this:
moment().startOf('day')
.seconds(15457)
.format('H:mm:ss');
Here's a simple function for converting times that might help
function formatSeconds(seconds) {
var date = new Date(1970,0,1);
date.setSeconds(seconds);
return date.toTimeString().replace(/.*(\d{2}:\d{2}:\d{2}).*/, "$1");
}
This does the trick:
function secondstotime(secs)
{
var t = new Date(1970,0,1);
t.setSeconds(secs);
var s = t.toTimeString().substr(0,8);
if(secs > 86399)
s = Math.floor((t - Date.parse("1/1/70")) / 3600000) + s.substr(2);
return s;
}
(Sourced from here)
var timeInSec = "661"; //even it can be string
String.prototype.toHHMMSS = function () {
/* extend the String by using prototypical inheritance */
var seconds = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(seconds / 3600);
var minutes = Math.floor((seconds - (hours * 3600)) / 60);
seconds = seconds - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
var time = hours+':'+minutes+':'+seconds;
return time;
}
alert("5678".toHHMMSS()); // "01:34:38"
console.log(timeInSec.toHHMMSS()); //"00:11:01"
we can make this function lot shorter and crisp but that decreases the readability, so we will write it as simple as possible and as stable as possible.
or you can check this working here:
Try this:
function toTimeString(seconds) {
return (new Date(seconds * 1000)).toUTCString().match(/(\d\d:\d\d:\d\d)/)[0];
}
I think the most general (and cryptic) solution could be this
function hms(seconds) {
return [3600, 60]
.reduceRight(
(pipeline, breakpoint) => remainder =>
[Math.floor(remainder / breakpoint)].concat(pipeline(remainder % breakpoint)),
r => [r]
)(seconds)
.map(amount => amount.toString().padStart(2, '0'))
.join('-');
}
Or to copy & paste the shortest version
function hms(seconds) {
return [3600, 60]
.reduceRight(
(p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
r => [r]
)(seconds)
.map(a => a.toString().padStart(2, '0'))
.join('-');
}
Some example outputs:
> hms(0)
< "00-00-00"
> hms(5)
< "00-00-05"
> hms(60)
< "00-01-00"
> hms(3785)
< "01-03-05"
> hms(37850)
< "10-30-50"
> hms(378500)
< "105-08-20"
How it works
Algorithm
To get hours you divide total seconds by 3600 and floor it.
To get minutes you divide remainder by 60 and floor it.
To get seconds you just use the remainder.
It would also be nice to keep individual amounts in an array for easier formatting.
For example given the input of 3785s the output should be [1, 3, 5], that is 1 hour, 3 minutes and 5 seconds.
Creating pipeline
Naming the 3600 and 60 constants "breakpoints" you can write this algorithm into function as this
function divideAndAppend(remainder, breakpoint, callback) {
return [Math.floor(remainder / breakpoint)].concat(callback(remainder % breakpoint));
}
It returns an array where first item is the amount for given breakpoint and the rest of the array is given by the callback.
Reusing the divideAndAppend in callback function will give you a pipeline of composed divideAndAppend functions. Each one of these
computes amount per given breakpoint and append it to the array making your desired output.
Then you also need the "final" callback that ends this pipeline. In another words you used all breakpoints and now you have only the remainder.
Since you have already the answer at 3) you should use some sort of identity function, in this case remainder => [remainder].
You can now write the pipeline like this
let pipeline = r3 => divideAndAppend(
r3,
3600,
r2 => divideAndAppend(
r2,
60,
r1 => [r1]));
> pipeline(3785)
< [1, 3, 5]
Cool right?
Generalizing using for-loop
Now you can generalize with a variable amount of breakpoints and create a for-loop that will compose individial divideAndAppend functions into
the pipeline.
You start with the identity function r1 => [r1], then use the 60 breakpoint and finally use the 3600 breakpoint.
let breakpoints = [60, 3600];
let pipeline = r => [r];
for (const b of breakpoints) {
const previousPipeline = pipeline;
pipeline = r => divideAndAppend(r, b, previousPipeline);
}
> pipeline(3785)
< [1, 3, 5]
Using Array.prototype.reduce()
Now you can rewrite this for-loop into reducer for shorter and more functional code. In other words rewrite function composition into the reducer.
let pipeline = [60, 3600].reduce(
(ppln, b) => r => divideAndAppend(r, b, ppln),
r => [r]
);
> pipeline(3785)
< [1, 3, 5]
The accumulator ppln is the pipeline and you are composing it using the previous version of it. The initial pipeline is r => [r].
You can now inline the function divideAndAppend and use Array.prototype.reduceRight which is the same as [].reverse().reduce(...) to make the breakpoints
definitions more natural.
let pipeline = [3600, 60]
.reduceRight(
(ppln, b) => r => [Math.floor(r / b)].concat(ppln(r % b)),
r => [r]
);
Which is the final form. Then you just appy mapping to string with padded 0's on left and join the strings with : separator;
More generalizations
Wrapping the reducer into function
function decompose(total, breakpoints) {
return breakpoints.reduceRight(
(p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
r => [r]
)(total);
}
> decompose(3785, [3600, 60])
< [1, 3, 5]
you now have very general algorithm you can work with. For example:
Convert easily (the weird) us length standards
Given the standards
Unit
Divisions
1 foot
12 inches
1 yard
3 feet
1 mile
1760 yards
> decompose(123_456, [1760 * 3 * 12, 3 * 12, 12])
< [1, 1669, 1, 0]
123456 in = 1 mi, 1669 yd, 1 feet and 0 in
Or you can somewhat convert to decimal or binary representations
> decompose(123_456, [100_000, 10_000, 1000, 100, 10])
< [1, 2, 3, 4, 5, 6]
> decompose(127, [128, 64, 32, 16, 8, 4, 2])
< [0, 1, 1, 1, 1, 1, 1, 1]
Works also with floating point breakpoints
Since Javascript supports mod operator with floating point numbers, you can also do
> decompose(26.5, [20, 2.5])
< [1, 2, 1.5]
The edge case of no breakpoints is also naturally covered
> decompose(123, [])
< [123]
Here is an extension to Number class. toHHMMSS() converts seconds to an hh:mm:ss string.
Number.prototype.toHHMMSS = function() {
var hours = Math.floor(this / 3600) < 10 ? ("00" + Math.floor(this / 3600)).slice(-2) : Math.floor(this / 3600);
var minutes = ("00" + Math.floor((this % 3600) / 60)).slice(-2);
var seconds = ("00" + (this % 3600) % 60).slice(-2);
return hours + ":" + minutes + ":" + seconds;
}
// Usage: [number variable].toHHMMSS();
// Here is a simple test
var totalseconds = 1234;
document.getElementById("timespan").innerHTML = totalseconds.toHHMMSS();
// HTML of the test
<div id="timespan"></div>
Easy to follow version for noobies:
var totalNumberOfSeconds = YOURNUMBEROFSECONDS;
var hours = parseInt( totalNumberOfSeconds / 3600 );
var minutes = parseInt( (totalNumberOfSeconds - (hours * 3600)) / 60 );
var seconds = Math.floor((totalNumberOfSeconds - ((hours * 3600) + (minutes * 60))));
var result = (hours < 10 ? "0" + hours : hours) + ":" + (minutes < 10 ? "0" + minutes : minutes) + ":" + (seconds < 10 ? "0" + seconds : seconds);
console.log(result);
This function should do it :
var convertTime = function (input, separator) {
var pad = function(input) {return input < 10 ? "0" + input : input;};
return [
pad(Math.floor(input / 3600)),
pad(Math.floor(input % 3600 / 60)),
pad(Math.floor(input % 60)),
].join(typeof separator !== 'undefined' ? separator : ':' );
}
Without passing a separator, it uses : as the (default) separator :
time = convertTime(13551.9941351); // --> OUTPUT = 03:45:51
If you want to use - as a separator, just pass it as the second parameter:
time = convertTime(1126.5135155, '-'); // --> OUTPUT = 00-18-46
See also this Fiddle.
Chiming in on this old thread -- the OP stated HH:MM:SS, and many of the solutions work, until you realize you need more than 24 hours listed. And maybe you don't want more than a single line of code. Here you go:
d=(s)=>{f=Math.floor;g=(n)=>('00'+n).slice(-2);return f(s/3600)+':'+g(f(s/60)%60)+':'+g(s%60)}
It returns H+:MM:SS. To use it, simply use:
d(91260); // returns "25:21:00"
d(960); // returns "0:16:00"
...I tried to get it to use the least amount of code possible, for a nice one-liner approach.
For the special case of HH:MM:SS.MS (eq: "00:04:33.637") as used by FFMPEG to specify milliseconds.
[-][HH:]MM:SS[.m...]
HH expresses the number of hours, MM the number of minutes for a
maximum of 2 digits, and SS the number of seconds for a maximum of 2
digits. The m at the end expresses decimal value for SS.
/* HH:MM:SS.MS to (FLOAT)seconds ---------------*/
function timerToSec(timer){
let vtimer = timer.split(":")
let vhours = +vtimer[0]
let vminutes = +vtimer[1]
let vseconds = parseFloat(vtimer[2])
return vhours * 3600 + vminutes * 60 + vseconds
}
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
/* Example: 7hours, 4 minutes, 33 seconds and 637 milliseconds */
const t = "07:04:33.637"
console.log(
t + " => " +
timerToSec(t) +
"s"
)
/* Test: 25473 seconds and 637 milliseconds */
const s = 25473.637 // "25473.637"
console.log(
s + "s => " +
secToTimer(s)
)
Example usage, a milliseconds transport timer:
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
let job, origin = new Date().getTime()
const timer = () => {
job = requestAnimationFrame(timer)
OUT.textContent = secToTimer((new Date().getTime() - origin) / 1000)
}
requestAnimationFrame(timer)
span {font-size:4rem}
<span id="OUT"></span>
<br>
<button onclick="origin = new Date().getTime()">RESET</button>
<button onclick="requestAnimationFrame(timer)">RESTART</button>
<button onclick="cancelAnimationFrame(job)">STOP</button>
Example usage, binded to a media element
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
VIDEO.addEventListener("timeupdate", function(e){
OUT.textContent = secToTimer(e.target.currentTime)
}, false)
span {font-size:4rem}
<span id="OUT"></span><br>
<video id="VIDEO" width="400" controls autoplay>
<source src="https://www.w3schools.com/html/mov_bbb.mp4" type="video/mp4">
</video>
Outside the question, those functions written in php:
<?php
/* HH:MM:SS to (FLOAT)seconds ------------------*/
function timerToSec($timer){
$vtimer = explode(":",$timer);
$vhours = (int)$vtimer[0];
$vminutes = (int)$vtimer[1];
$vseconds = (float)$vtimer[2];
return $vhours * 3600 + $vminutes * 60 + $vseconds;
}
/* Seconds to (STRING)HH:MM:SS -----------------*/
function secToTimer($sec){
return explode(" ", date("H:i:s", $sec))[0];
}
After looking at all the answers and not being happy with most of them, this is what I came up with. I know I am very late to the conversation, but here it is anyway.
function secsToTime(secs){
var time = new Date();
// create Date object and set to today's date and time
time.setHours(parseInt(secs/3600) % 24);
time.setMinutes(parseInt(secs/60) % 60);
time.setSeconds(parseInt(secs%60));
time = time.toTimeString().split(" ")[0];
// time.toString() = "HH:mm:ss GMT-0800 (PST)"
// time.toString().split(" ") = ["HH:mm:ss", "GMT-0800", "(PST)"]
// time.toTimeString().split(" ")[0]; = "HH:mm:ss"
return time;
}
I create a new Date object, change the time to my parameters, convert the Date Object to a time string, and removed the additional stuff by splitting the string and returning only the part that need.
I thought I would share this approach, since it removes the need for regex, logic and math acrobatics to get the results in "HH:mm:ss" format, and instead it relies on built in methods.
You may want to take a look at the documentation here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date
below is the given code which will convert seconds into hh-mm-ss format:
var measuredTime = new Date(null);
measuredTime.setSeconds(4995); // specify value of SECONDS
var MHSTime = measuredTime.toISOString().substr(11, 8);
Get alternative method from Convert seconds to HH-MM-SS format in JavaScript
var time1 = date1.getTime();
var time2 = date2.getTime();
var totalMilisec = time2 - time1;
alert(DateFormat('hh:mm:ss',new Date(totalMilisec)))
/* ----------------------------------------------------------
* Field | Full Form | Short Form
* -------------|--------------------|-----------------------
* Year | yyyy (4 digits) | yy (2 digits)
* Month | MMM (abbr.) | MM (2 digits)
| NNN (name) |
* Day of Month | dd (2 digits) |
* Day of Week | EE (name) | E (abbr)
* Hour (1-12) | hh (2 digits) |
* Minute | mm (2 digits) |
* Second | ss (2 digits) |
* ----------------------------------------------------------
*/
function DateFormat(formatString,date){
if (typeof date=='undefined'){
var DateToFormat=new Date();
}
else{
var DateToFormat=date;
}
var DAY = DateToFormat.getDate();
var DAYidx = DateToFormat.getDay();
var MONTH = DateToFormat.getMonth()+1;
var MONTHidx = DateToFormat.getMonth();
var YEAR = DateToFormat.getYear();
var FULL_YEAR = DateToFormat.getFullYear();
var HOUR = DateToFormat.getHours();
var MINUTES = DateToFormat.getMinutes();
var SECONDS = DateToFormat.getSeconds();
var arrMonths = new Array("January","February","March","April","May","June","July","August","September","October","November","December");
var arrDay=new Array('Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday');
var strMONTH;
var strDAY;
var strHOUR;
var strMINUTES;
var strSECONDS;
var Separator;
if(parseInt(MONTH)< 10 && MONTH.toString().length < 2)
strMONTH = "0" + MONTH;
else
strMONTH=MONTH;
if(parseInt(DAY)< 10 && DAY.toString().length < 2)
strDAY = "0" + DAY;
else
strDAY=DAY;
if(parseInt(HOUR)< 10 && HOUR.toString().length < 2)
strHOUR = "0" + HOUR;
else
strHOUR=HOUR;
if(parseInt(MINUTES)< 10 && MINUTES.toString().length < 2)
strMINUTES = "0" + MINUTES;
else
strMINUTES=MINUTES;
if(parseInt(SECONDS)< 10 && SECONDS.toString().length < 2)
strSECONDS = "0" + SECONDS;
else
strSECONDS=SECONDS;
switch (formatString){
case "hh:mm:ss":
return strHOUR + ':' + strMINUTES + ':' + strSECONDS;
break;
//More cases to meet your requirements.
}
}
I just wanted to give a little explanation to the nice answer above:
var totalSec = new Date().getTime() / 1000;
var hours = parseInt( totalSec / 3600 ) % 24;
var minutes = parseInt( totalSec / 60 ) % 60;
var seconds = totalSec % 60;
var result = (hours < 10 ? "0" + hours : hours) + "-" + (minutes < 10 ? "0" + minutes : minutes) + "-" + (seconds < 10 ? "0" + seconds : seconds);
On the second line, since there are 3600 seconds in 1 hour, we divide the total number of seconds by 3600 to get the total number of hours. We use parseInt to strip off any decimal. If totalSec was 12600 (3 and half hours), then parseInt( totalSec / 3600 ) would return 3, since we will have 3 full hours. Why do we need the % 24 in this case? If we exceed 24 hours, let's say we have 25 hours (90000 seconds), then the modulo here will take us back to 1 again, rather than returning 25. It is confining the result within a 24 hour limit, since there are 24 hours in one day.
When you see something like this:
25 % 24
Think of it like this:
25 mod 24 or what is the remainder when we divide 25 by 24
None of the answers here satisfies my requirements as I want to be able to handle
Large numbers of seconds (days), and
Negative numbers
Although those are not required by the OP, it's good practice to cover edge cases, especially when it takes little effort.
It's pretty obvious is that the OP means a NUMBER of seconds when he says seconds. Why would peg your function on String?
function secondsToTimeSpan(seconds) {
const value = Math.abs(seconds);
const days = Math.floor(value / 1440);
const hours = Math.floor((value - (days * 1440)) / 3600);
const min = Math.floor((value - (days * 1440) - (hours * 3600)) / 60);
const sec = value - (days * 1440) - (hours * 3600) - (min * 60);
return `${seconds < 0 ? '-':''}${days > 0 ? days + '.':''}${hours < 10 ? '0' + hours:hours}:${min < 10 ? '0' + min:min}:${sec < 10 ? '0' + sec:sec}`
}
secondsToTimeSpan(0); // => 00:00:00
secondsToTimeSpan(1); // => 00:00:01
secondsToTimeSpan(1440); // => 1.00:00:00
secondsToTimeSpan(-1440); // => -1.00:00:00
secondsToTimeSpan(-1); // => -00:00:01
Simple function to convert seconds into in hh:mm:ss format :
function getHHMMSSFromSeconds(totalSeconds) {
if (!totalSeconds) {
return '00:00:00';
}
const hours = Math.floor(totalSeconds / 3600);
const minutes = Math.floor(totalSeconds % 3600 / 60);
const seconds = totalSeconds % 60;
const hhmmss = padTo2(hours) + ':' + padTo2(minutes) + ':' + padTo2(seconds);
return hhmmss;
}
// function to convert single digit to double digit
function padTo2(value) {
if (!value) {
return '00';
}
return value < 10 ? String(value).padStart(2, '0') : value;
}
Here is a function to convert seconds to hh-mm-ss format based on powtac's answer here
jsfiddle
/**
* Convert seconds to hh-mm-ss format.
* #param {number} totalSeconds - the total seconds to convert to hh- mm-ss
**/
var SecondsTohhmmss = function(totalSeconds) {
var hours = Math.floor(totalSeconds / 3600);
var minutes = Math.floor((totalSeconds - (hours * 3600)) / 60);
var seconds = totalSeconds - (hours * 3600) - (minutes * 60);
// round seconds
seconds = Math.round(seconds * 100) / 100
var result = (hours < 10 ? "0" + hours : hours);
result += "-" + (minutes < 10 ? "0" + minutes : minutes);
result += "-" + (seconds < 10 ? "0" + seconds : seconds);
return result;
}
Example use
var seconds = SecondsTohhmmss(70);
console.log(seconds);
// logs 00-01-10
There are lots of options of solve this problem, and obvious there are good option suggested about, But I wants to add one more optimized code here
function formatSeconds(sec) {
return [(sec / 3600), ((sec % 3600) / 60), ((sec % 3600) % 60)]
.map(v => v < 10 ? "0" + parseInt(v) : parseInt(v))
.filter((i, j) => i !== "00" || j > 0)
.join(":");
}
if you don't wants formatted zero with less then 10 number, you can use
function formatSeconds(sec) {
return parseInt(sec / 3600) + ':' + parseInt((sec % 3600) / 60) + ':' + parseInt((sec % 3600) % 60);
}
Sample Code http://fiddly.org/1c476/1
In one line, using T.J. Crowder's solution :
secToHHMMSS = seconds => `${Math.floor(seconds / 3600)}:${Math.floor((seconds % 3600) / 60)}:${Math.floor((seconds % 3600) % 60)}`
In one line, another solution that also count days :
secToDHHMMSS = seconds => `${parseInt(seconds / 86400)}d ${new Date(seconds * 1000).toISOString().substr(11, 8)}`
Source : https://gist.github.com/martinbean/2bf88c446be8048814cf02b2641ba276
var sec_to_hms = function(sec){
var min, hours;
sec = sec - (min = Math.floor(sec/60))*60;
min = min - (hours = Math.floor(min/60))*60;
return (hours?hours+':':'') + ((min+'').padStart(2, '0')) + ':'+ ((sec+'').padStart(2, '0'));
}
alert(sec_to_hms(2442542));
Have you tried adding seconds to a Date object?
Date.prototype.addSeconds = function(seconds) {
this.setSeconds(this.getSeconds() + seconds);
};
var dt = new Date();
dt.addSeconds(1234);
A sample:
https://jsfiddle.net/j5g2p0dc/5/
Updated:
Sample link was missing so I created a new one.
You can also use below code:
int ss = nDur%60;
nDur = nDur/60;
int mm = nDur%60;
int hh = nDur/60;
For anyone using AngularJS, a simple solution is to filter the value with the date API, which converts milliseconds to a string based on the requested format. Example:
<div>Offer ends in {{ timeRemaining | date: 'HH:mm:ss' }}</div>
Note that this expects milliseconds, so you may want to multiply timeRemaining by 1000 if you are converting from seconds (as the original question was formulated).
I ran into the case some have mentioned where the number of seconds is more than a day. Here's an adapted version of #Harish Anchu's top-rated answer that accounts for longer periods of time:
function secondsToTime(seconds) {
const arr = new Date(seconds * 1000).toISOString().substr(11, 8).split(':');
const days = Math.floor(seconds / 86400);
arr[0] = parseInt(arr[0], 10) + days * 24;
return arr.join(':');
}
Example:
secondsToTime(101596) // outputs '28:13:16' as opposed to '04:13:16'
String.prototype.toHHMMSS = function () {
var sec_num = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(sec_num / 3600);
var minutes = Math.floor((sec_num - (hours * 3600)) / 60);
var seconds = sec_num - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
return hours+':'+minutes+':'+seconds;
}
Usage Example
alert("186".toHHMMSS());
I have the duration of a video in seconds 634.567! I have successfully converted this to HH:MM:SS:ms format using this code:
var pad = function(num, size) { return ('000' + num).slice(size * -1); },
time = parseFloat(timeInSeconds).toFixed(3),
hours = Math.floor(time / 60 / 60),
minutes = Math.floor(time / 60) % 60,
seconds = Math.floor(time - minutes * 60),
milliseconds = time.slice(-3);
return pad(hours, 2) + ':' + pad(minutes, 2) + ':' + pad(seconds, 2) + ',' + pad(milliseconds, 3);
This returns "00:10:34,567"
Now, I would like to split this time into intervals of 5 seconds. So, it becomes an JS array that looks like this
00.00.05, 000 | 00.00.10, 000 | 00.00.15, 000 | till the very last line in the array is 00:10:34,567 (so it's all in equal parts).
How do I split the time into smaller times then push it into an array?
For that, it would be probably better to work with the original time duration timeInSeconds, iterate in steps of 5 seconds and convert the corresponding value for each step, e.g.:
var pad = function(num, size) { return ('000' + num).slice(size * -1); };
function conv(t){
var time = parseFloat(t).toFixed(3),
hours = Math.floor(time / 60 / 60),
minutes = Math.floor(time / 60) % 60,
seconds = Math.floor(time - minutes * 60),
milliseconds = time.slice(-3);
return pad(hours, 2) + ':' + pad(minutes, 2) + ':' + pad(seconds, 2) + ',' + pad(milliseconds, 3);
}
var timeInSeconds = 634.567;
//required step
var delta = 5;
/*
the condition (t < timeInSeconds + delta) in combination
with Math.min(t, timeInSeconds) ensures that the for
loop will consider the value timeInSeconds even if it
is not divisible by delta
*/
var arr = [];
for(var t = 0; t < timeInSeconds + delta; t += delta){
arr.push(conv(Math.min(t, timeInSeconds)));
}
console.log(arr);
So for example for timeInSeconds = 11.0, you would get:
[ '00:00:00,000', '00:00:05,000', '00:00:10,000', '00:00:11,000' ]
I have a Javascript timing event with an infinite loop with a stop button.
It will display numbers when start button is click.Now I want this numbers converted to something like 4 hours, 3 minutes , 50 seconds
var c = 0;
var t;
var timer_is_on = 0;
function timedCount() {
document.getElementById('txt').value = c;
c = c + 1;
t = setTimeout(function() {
timedCount()
}, 1000);
}
function doTimer() {
if (!timer_is_on) {
timer_is_on = 1;
timedCount();
}
}
function stopCount() {
clearTimeout(t);
timer_is_on = 0;
}
$(".start").on("click", function() {
//var start = $.now();
//alert(start);
//console.log(start);
doTimer();
$(".end").show();
$(".hide_div").show();
});
$(".end").on("click", function() {
stopCount();
});
.hide_div {
display: none;
}
.end {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p class="start">Start</p>
<p class="end">End</p>
<p class="hide_div">
<input type="text" id="txt" />//display numbers eg 12345
</p>
How to convert numbers like 123456 to 1 day, 4 hours, 40 min, 45 seconds?
I suggest doing this way!:
function secondsToDhms(seconds) {
seconds = Number(seconds);
var d = Math.floor(seconds / (3600*24));
var h = Math.floor(seconds % (3600*24) / 3600);
var m = Math.floor(seconds % 3600 / 60);
var s = Math.floor(seconds % 60);
var dDisplay = d > 0 ? d + (d == 1 ? " day, " : " days, ") : "";
var hDisplay = h > 0 ? h + (h == 1 ? " hour, " : " hours, ") : "";
var mDisplay = m > 0 ? m + (m == 1 ? " minute, " : " minutes, ") : "";
var sDisplay = s > 0 ? s + (s == 1 ? " second" : " seconds") : "";
return dDisplay + hDisplay + mDisplay + sDisplay;
}
Use Math like this way, Second param in parseInt is for base, which is optional
var seconds = parseInt(123456, 10);
var days = Math.floor(seconds / (3600*24));
seconds -= days*3600*24;
var hrs = Math.floor(seconds / 3600);
seconds -= hrs*3600;
var mnts = Math.floor(seconds / 60);
seconds -= mnts*60;
console.log(days+" days, "+hrs+" Hrs, "+mnts+" Minutes, "+seconds+" Seconds");
Your given seconds 123456 would be 1 days, 10 Hrs, 17 Minutes, 36 Seconds not 1 days, 4 Hrs, 40 Minutes, 45 Seconds
function countdown(s) {
const d = Math.floor(s / (3600 * 24));
s -= d * 3600 * 24;
const h = Math.floor(s / 3600);
s -= h * 3600;
const m = Math.floor(s / 60);
s -= m * 60;
const tmp = [];
(d) && tmp.push(d + 'd');
(d || h) && tmp.push(h + 'h');
(d || h || m) && tmp.push(m + 'm');
tmp.push(s + 's');
return tmp.join(' ');
}
// countdown(3546544) -> 41d 1h 9m 4s
// countdown(436654) -> 5d 1h 17m 34s
// countdown(3601) -> 1h 0m 1s
// countdown(121) -> 2m 1s
My solution with map() and reduce():
const intervalToLevels = (interval, levels) => {
const cbFun = (d, c) => {
let bb = d[1] % c[0],
aa = (d[1] - bb) / c[0];
aa = aa > 0 ? aa + c[1] : '';
return [d[0] + aa, bb];
};
let rslt = levels.scale.map((d, i, a) => a.slice(i).reduce((d, c) => d * c))
.map((d, i) => ([d, levels.units[i]]))
.reduce(cbFun, ['', interval]);
return rslt[0];
};
const TimeLevels = {
scale: [24, 60, 60, 1],
units: ['d ', 'h ', 'm ', 's ']
};
const secondsToString = interval => intervalToLevels(interval, TimeLevels);
If you call secondsToString(123456), you can get "1d 10h 17m 36s "
Here is my solution, a simple function that will round to the nearest second!
var returnElapsedTime = function(epoch) {
//We are assuming that the epoch is in seconds
var hours = epoch / 3600,
minutes = (hours % 1) * 60,
seconds = (minutes % 1) * 60;
return Math.floor(hours) + " hours, " + Math.floor(minutes) + " minutes, " + Math.round(seconds) + " seconds";
}
Came up with my own variation to some of the solutions suggested in this thread.
if (!Number.prototype.secondsToDHM) {
Number.prototype.secondsToDHM = function() {
const secsPerDay = 86400;
const secsPerHour = 3600;
const secsPerMinute = 60;
var seconds = Math.abs(this);
var minus = (this < 0) ? '-' : '';
var days = Math.floor(seconds / secsPerDay);
seconds = (seconds % secsPerDay);
var hours = Math.floor(seconds / secsPerHour);
seconds = (seconds % secsPerHour);
var minutes = Math.floor(seconds / secsPerMinute);
seconds = (seconds % secsPerMinute);
var sDays = new String(days).padStart(1, '0');
var sHours = new String(hours).padStart(2, '0');
var sMinutes = new String(minutes).padStart(2, '0');
return `${minus}${sDays}D ${sHours}:${sMinutes}`;
}
}
var a = new Number(50000).secondsToDHM();
var b = new Number(100000).secondsToDHM();
var c = new Number(200000).secondsToDHM();
var d = new Number(400000).secondsToDHM();
console.log(a);
console.log(b);
console.log(c);
console.log(d);
This answer builds upon on Andris' approach to this question, but it doesn't have trailing commas if lesser units are not present.
It also borrows from this answer dealing with joining array values only if truthy:
https://stackoverflow.com/a/19903063
I'm not a javascript god and it's probably horribly over-engineered, but hopefully readable and correct!
function sformat(s) {
// create array of day, hour, minute and second values
var fm = [
Math.floor(s / (3600 * 24)),
Math.floor(s % (3600 * 24) / 3600),
Math.floor(s % 3600 / 60),
Math.floor(s % 60)
];
// map over array
return $.map(fm, function(v, i) {
// if a truthy value
if (Boolean(v)) {
// add the relevant value suffix
if (i === 0) {
v = plural(v, "day");
} else if (i === 1) {
v = plural(v, "hour");
} else if (i === 2) {
v = plural(v, "minute");
} else if (i === 3) {
v = plural(v, "second");
}
return v;
}
}).join(', ');
}
function plural(value, unit) {
if (value === 1) {
return value + " " + unit;
} else if (value > 1) {
return value + " " + unit + "s";
}
}
console.log(sformat(60)); // 1 minute
console.log(sformat(3600)); // 1 hour
console.log(sformat(86400)); // 1 day
console.log(sformat(8991)); // 2 hours, 29 minutes, 51 seconds
If you needed to convey the duration more 'casually' in words, you could also do something like:
var remaining_duration = sformat(117);
// if a value is returned, add some prefix and suffix
if (remaining_duration !== "") {
remaining_duration = "about " + remaining_duration + " left";
}
$(".remaining_duration").text(remaining_duration);
// returns 'about 1 minute, 57 seconds left'
I further tweaked the code by Svetoslav as follows:
function convertSecondsToReadableString(seconds) {
seconds = seconds || 0;
seconds = Number(seconds);
seconds = Math.abs(seconds);
const d = Math.floor(seconds / (3600 * 24));
const h = Math.floor(seconds % (3600 * 24) / 3600);
const m = Math.floor(seconds % 3600 / 60);
const s = Math.floor(seconds % 60);
const parts = [];
if (d > 0) {
parts.push(d + ' day' + (d > 1 ? 's' : ''));
}
if (h > 0) {
parts.push(h + ' hour' + (h > 1 ? 's' : ''));
}
if (m > 0) {
parts.push(m + ' minute' + (m > 1 ? 's' : ''));
}
if (s > 0) {
parts.push(s + ' second' + (s > 1 ? 's' : ''));
}
return parts.join(', ');
}
Short answer:
var s = (Math.floor(123456/86400) + ":" + (new Date(123456 * 1000)).toISOString().substr(11, 8)).split(":");
console.log(`${s[0]} days, ${s[1]} hours, ${s[2]} minutes, ${s[3]} seconds` )
Edit:
Let me break it down in parts :
Math.floor(123456/86400)
86400 is the the total seconds in a day (60 seconds * 60 minutes * 24 hours). Dividing the inputted seconds by this value gives us number of days. We just need the whole part so we use Math.floor because the fractional piece is handled by this part:
(new Date(123456 * 1000)).toISOString().substr(11, 8)
the explanation can be found here:
Convert seconds to HH-MM-SS with JavaScript?
It just outputs hh:mm:ss, no days. So the first part and this part is a perfect combination
We concatenate using a colon (:) as a separator. The string looks like this:
'1:10:17:36'
We split it into an array with .split(":");. Then finally, we format the elements of the array for the desired output.
I've tweaked the code that Andris posted https://stackoverflow.com/users/3564943/andris
// https://stackoverflow.com/questions/36098913/convert-seconds-to-days-hours-minutes-and-seconds
function app_ste_36098913_countdown_seconds_to_hr(seconds) {
seconds = seconds || 0;
seconds = Number(seconds);
seconds = Math.abs(seconds);
var d = Math.floor(seconds / (3600*24));
var h = Math.floor(seconds % (3600*24) / 3600);
var m = Math.floor(seconds % 3600 / 60);
var s = Math.floor(seconds % 60);
var parts = new Array();
if (d > 0) {
var dDisplay = d > 0 ? d + ' ' + (d == 1 ? "day" : "days") : "";
parts.push(dDisplay);
}
if (h > 0) {
var hDisplay = h > 0 ? h + ' ' + (h == 1 ? "hour" : "hours") : "";
parts.push(hDisplay)
}
if (m > 0) {
var mDisplay = m > 0 ? m + ' ' + (m == 1 ? "minute" : "minutes") : "";
parts.push(mDisplay)
}
if (s > 0) {
var sDisplay = s > 0 ? s + ' ' + (s == 1 ? "second" : "seconds") : "";
parts.push(sDisplay)
}
return parts.join(', ', parts);
}
You will probably find using epoch timestamps more straightforward: As detailed in Convert a Unix timestamp to time in JavaScript, the basic method is like so:
<script>
// Create a new JavaScript Date object based on the timestamp
// multiplied by 1000 so that the argument is in milliseconds, not seconds.
var date1 = new Date();
alert ('easy trick to waste a few seconds...' + date1);
// var date = date2 - date1;
// Hours part from the timestamp
var hours1 = date1.getHours();
// Minutes part from the timestamp
var minutes1 = "0" + date1.getMinutes();
// Seconds part from the timestamp
var seconds1 = "0" + date1.getSeconds();
var date2 = new Date();
// Hours part from the timestamp
var hours2 = date2.getHours();
// Minutes part from the timestamp
var minutes2 = "0" + date2.getMinutes();
// Seconds part from the timestamp
var seconds2 = "0" + date2.getSeconds();
// Will display time in 10:30:23 format
// var formattedTime = hours + ':' + minutes.substr(-2) + ':' + seconds.substr(-2);
var elapsedHrs = hours2 - hours1;
var elapsedMin = minutes2.substr(-2) -minutes1.substr(-2);
var elapsedSec = seconds2.substr(-2) - seconds1.substr(-2);
var elapsedTime = elapsedHrs + ' hours, ' + elapsedMin + ' minutes, ' + elapsedSec + ' seconds';
alert ('time between timestamps: ' + elapsedTime);
</script>
Be warned that this script needs some work since for now it will give negative values for things like date1 = 12:00:00 and date2 = 12:00:05, but I'll leave that to you fo now.
You should rewrite your code to take a timestamp ( var x = new Date(); ) at the start of your timer and one whenever you are done/want to check elapsed time, and subtract the two before parsing out elapsed seconds, minutes, hours etc as required.
This is my take at the question, even if it is an old topic.
You can use a loop to compute everything for you :
function time_remaining(date1, date2) {
let seconds = (date2 - date1) / 1000
let units = ["years", "days", "h", "min", "s"]
let limit_units = [365, 24, 60, 60, 1]
const reducer = (accumulator, curr) => accumulator * curr;
let time = []
for (let i = 0; i < units.length; i++) {
let divisor = limit_units.slice(i).reduce(reducer)
let value = Math.floor(seconds / divisor)
seconds = seconds - value * divisor
time.push(value)
}
return clean_time(time, units)
}
// at this point, you have your answer. However,
// we can improve the result by removing all none
// significative null units (i.e, if your countdown is
// only about hours, minutes and seconds, it is not
// going to include years and days.)
function clean_time(time, units) {
time = time.reverse()
while (time[time.length - 1] == 0) {
time.pop()
}
return [time.reverse(), units.slice(-time.length)]
}
let date1 = Date.parse("2023-07-09T17:50:33")
console.log(time_remaining(Date.now(), date1))
I have a time as a number of milliseconds and I want to convert it to a HH:MM:SS format. It should wrap around, with milliseconds = 86400000 I want to get 00:00:00.
How about creating a function like this:
function msToTime(duration) {
var milliseconds = Math.floor((duration % 1000) / 100),
seconds = Math.floor((duration / 1000) % 60),
minutes = Math.floor((duration / (1000 * 60)) % 60),
hours = Math.floor((duration / (1000 * 60 * 60)) % 24);
hours = (hours < 10) ? "0" + hours : hours;
minutes = (minutes < 10) ? "0" + minutes : minutes;
seconds = (seconds < 10) ? "0" + seconds : seconds;
return hours + ":" + minutes + ":" + seconds + "." + milliseconds;
}
console.log(msToTime(300000))
To Convert time in millisecond to human readable format.
function msToTime(ms) {
let seconds = (ms / 1000).toFixed(1);
let minutes = (ms / (1000 * 60)).toFixed(1);
let hours = (ms / (1000 * 60 * 60)).toFixed(1);
let days = (ms / (1000 * 60 * 60 * 24)).toFixed(1);
if (seconds < 60) return seconds + " Sec";
else if (minutes < 60) return minutes + " Min";
else if (hours < 24) return hours + " Hrs";
else return days + " Days"
}
console.log(msToTime(1000))
console.log(msToTime(10000))
console.log(msToTime(300000))
console.log(msToTime(3600000))
console.log(msToTime(86400000))
I had the same problem, this is what I ended up doing:
function parseMillisecondsIntoReadableTime(milliseconds){
//Get hours from milliseconds
var hours = milliseconds / (1000*60*60);
var absoluteHours = Math.floor(hours);
var h = absoluteHours > 9 ? absoluteHours : '0' + absoluteHours;
//Get remainder from hours and convert to minutes
var minutes = (hours - absoluteHours) * 60;
var absoluteMinutes = Math.floor(minutes);
var m = absoluteMinutes > 9 ? absoluteMinutes : '0' + absoluteMinutes;
//Get remainder from minutes and convert to seconds
var seconds = (minutes - absoluteMinutes) * 60;
var absoluteSeconds = Math.floor(seconds);
var s = absoluteSeconds > 9 ? absoluteSeconds : '0' + absoluteSeconds;
return h + ':' + m + ':' + s;
}
var time = parseMillisecondsIntoReadableTime(86400000);
alert(time);
Here is my solution
let h,m,s;
h = Math.floor(timeInMiliseconds/1000/60/60);
m = Math.floor((timeInMiliseconds/1000/60/60 - h)*60);
s = Math.floor(((timeInMiliseconds/1000/60/60 - h)*60 - m)*60);
// to get time format 00:00:00
s < 10 ? s = `0${s}`: s = `${s}`
m < 10 ? m = `0${m}`: m = `${m}`
h < 10 ? h = `0${h}`: h = `${h}`
console.log(`${s}:${m}:${h}`);
This one returns time like youtube videos
function getYoutubeLikeToDisplay(millisec) {
var seconds = (millisec / 1000).toFixed(0);
var minutes = Math.floor(seconds / 60);
var hours = "";
if (minutes > 59) {
hours = Math.floor(minutes / 60);
hours = (hours >= 10) ? hours : "0" + hours;
minutes = minutes - (hours * 60);
minutes = (minutes >= 10) ? minutes : "0" + minutes;
}
seconds = Math.floor(seconds % 60);
seconds = (seconds >= 10) ? seconds : "0" + seconds;
if (hours != "") {
return hours + ":" + minutes + ":" + seconds;
}
return minutes + ":" + seconds;
}
Output:
getYoutubeLikeToDisplay(129900) = "2:10"
getYoutubeLikeToDisplay(1229900) = "20:30"
getYoutubeLikeToDisplay(21229900) = "05:53:50"
Sorry, late to the party. The accepted answer did not cut it for me, so I wrote it myself.
Output:
2h 59s
1h 59m
1h
1h 59s
59m 59s
59s
Code (Typescript):
function timeConversion(duration: number) {
const portions: string[] = [];
const msInHour = 1000 * 60 * 60;
const hours = Math.trunc(duration / msInHour);
if (hours > 0) {
portions.push(hours + 'h');
duration = duration - (hours * msInHour);
}
const msInMinute = 1000 * 60;
const minutes = Math.trunc(duration / msInMinute);
if (minutes > 0) {
portions.push(minutes + 'm');
duration = duration - (minutes * msInMinute);
}
const seconds = Math.trunc(duration / 1000);
if (seconds > 0) {
portions.push(seconds + 's');
}
return portions.join(' ');
}
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000) ));
console.log(timeConversion((60 * 60 * 1000) ));
console.log(timeConversion((60 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion( (59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion( (59 * 1000)));
The above snippets don't work for cases with more than 1 day (They are simply ignored).
For this you can use:
function convertMS(ms) {
var d, h, m, s;
s = Math.floor(ms / 1000);
m = Math.floor(s / 60);
s = s % 60;
h = Math.floor(m / 60);
m = m % 60;
d = Math.floor(h / 24);
h = h % 24;
h += d * 24;
return h + ':' + m + ':' + s;
}
Thanks to https://gist.github.com/remino/1563878
I needed time only up to one day, 24h, this was my take:
const milliseconds = 5680000;
const hours = `0${new Date(milliseconds).getHours() - 1}`.slice(-2);
const minutes = `0${new Date(milliseconds).getMinutes()}`.slice(-2);
const seconds = `0${new Date(milliseconds).getSeconds()}`.slice(-2);
const time = `${hours}:${minutes}:${seconds}`
console.log(time);
you could get days this way as well if needed.
Format as hh:mm:ss with optional padding
(1:59:59 or 01:59:59)
(1:59 or 01:59)
(Default: no padding)
Based loosely on Chand's answer.
function formatMilliseconds(milliseconds, padStart) {
function pad(num) {
return `${num}`.padStart(2, '0');
}
let asSeconds = milliseconds / 1000;
let hours = undefined;
let minutes = Math.floor(asSeconds / 60);
let seconds = Math.floor(asSeconds % 60);
if (minutes > 59) {
hours = Math.floor(minutes / 60);
minutes %= 60;
}
return hours
? `${padStart ? pad(hours) : hours}:${pad(minutes)}:${pad(seconds)}`
: `${padStart ? pad(minutes) : minutes}:${pad(seconds)}`;
}
Tests:
let s = 1000;
let m = 60*s;
let h = 60*m;
console.log(formatMilliseconds(1*h)); // 1:00:00
console.log(formatMilliseconds(1*h, true)); // 01:00:00
console.log(formatMilliseconds(59*m + 59*s)); // 59:59
console.log(formatMilliseconds(59*m + 59*s, true)); // 59:59
console.log(formatMilliseconds(9*m + 9*s)); // 9:09
console.log(formatMilliseconds(9*m + 9*s, true)); // 09:09
console.log(formatMilliseconds(5*s)); // 0:05
console.log(formatMilliseconds(5*s, true)); // 00:05
console.log(formatMilliseconds(2400*s)); // 40:00
console.log(formatMilliseconds(2400*s, true)); // 40:00
.
.
.
If you need millisecond precision, you can get the fractional part using the following:
(asSeconds % 1).toFixed(3).substring(1)
Your returns would end up looking like this (break it up for readability as necessary):
`${padStart ? pad(hours) : hours}:${pad(minutes)}:${pad(seconds)}${(asSeconds % 1).toFixed(3).substring(1)}`
There are probably better ways to do that, but this naive solution gets the job done.
Test:
let asSeconds = 59.5219;
let seconds = Math.floor(asSeconds);
console.log(`${pad(seconds)}${(asSeconds % 1).toFixed(3).substring(1)}`);
// Equivalent to above, without using `pad()`:
//console.log(`${String(seconds).padStart(2, '0')}${(asSeconds % 1).toFixed(3).substring(1)}`);
// Output: 59.522
// The following is written in Typescript, should be easy to translate to JS
function humanReadableDuration(msDuration: int): string {
const h = Math.floor(msDuration / 1000 / 60 / 60);
const m = Math.floor((msDuration / 1000 / 60 / 60 - h) * 60);
const s = Math.floor(((msDuration / 1000 / 60 / 60 - h) * 60 - m) * 60);
// To get time format 00:00:00
const seconds: string = s < 10 ? `0${s}` : `${s}`;
const minutes: string = m < 10 ? `0${m}` : `${m}`;
const hours: string = h < 10 ? `0${h}` : `${h}`;
return `${hours}h ${minutes}m ${seconds}s`;
}
This solution uses one function to split milliseconds into a parts object, and another function to format the parts object.
I created 2 format functions, one as you requested, and another that prints a friendly string and considering singular/plural, and includes an option to show milliseconds.
function parseDuration(duration) {
let remain = duration
let days = Math.floor(remain / (1000 * 60 * 60 * 24))
remain = remain % (1000 * 60 * 60 * 24)
let hours = Math.floor(remain / (1000 * 60 * 60))
remain = remain % (1000 * 60 * 60)
let minutes = Math.floor(remain / (1000 * 60))
remain = remain % (1000 * 60)
let seconds = Math.floor(remain / (1000))
remain = remain % (1000)
let milliseconds = remain
return {
days,
hours,
minutes,
seconds,
milliseconds
};
}
function formatTime(o, useMilli = false) {
let parts = []
if (o.days) {
let ret = o.days + ' day'
if (o.days !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.hours) {
let ret = o.hours + ' hour'
if (o.hours !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.minutes) {
let ret = o.minutes + ' minute'
if (o.minutes !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.seconds) {
let ret = o.seconds + ' second'
if (o.seconds !== 1) {
ret += 's'
}
parts.push(ret)
}
if (useMilli && o.milliseconds) {
let ret = o.milliseconds + ' millisecond'
if (o.milliseconds !== 1) {
ret += 's'
}
parts.push(ret)
}
if (parts.length === 0) {
return 'instantly'
} else {
return parts.join(' ')
}
}
function formatTimeHMS(o) {
let hours = o.hours.toString()
if (hours.length === 1) hours = '0' + hours
let minutes = o.minutes.toString()
if (minutes.length === 1) minutes = '0' + minutes
let seconds = o.seconds.toString()
if (seconds.length === 1) seconds = '0' + seconds
return hours + ":" + minutes + ":" + seconds
}
function formatDurationHMS(duration) {
let time = parseDuration(duration)
return formatTimeHMS(time)
}
function formatDuration(duration, useMilli = false) {
let time = parseDuration(duration)
return formatTime(time, useMilli)
}
console.log(formatDurationHMS(57742343234))
console.log(formatDuration(57742343234))
console.log(formatDuration(5423401000))
console.log(formatDuration(500))
console.log(formatDuration(500, true))
console.log(formatDuration(1000 * 30))
console.log(formatDuration(1000 * 60 * 30))
console.log(formatDuration(1000 * 60 * 60 * 12))
console.log(formatDuration(1000 * 60 * 60 * 1))
Worked for me
msToTime(milliseconds) {
//Get hours from milliseconds
var hours = milliseconds / (1000*60*60);
var absoluteHours = Math.floor(hours);
var h = absoluteHours > 9 ? absoluteHours : '0' + absoluteHours;
//Get remainder from hours and convert to minutes
var minutes = (hours - absoluteHours) * 60;
var absoluteMinutes = Math.floor(minutes);
var m = absoluteMinutes > 9 ? absoluteMinutes : '0' + absoluteMinutes;
//Get remainder from minutes and convert to seconds
var seconds = (minutes - absoluteMinutes) * 60;
var absoluteSeconds = Math.floor(seconds);
var s = absoluteSeconds > 9 ? absoluteSeconds : '0' + absoluteSeconds;
return h == "00" ? m + ':' + s : h + ':' + m + ':' + s;
}
Human-readable code for human-readable output and you can extend this to light years or nanoseconds or what have you very intuitively. Obviously you'd want to convert this to a function and re-use some of those intermediate modulo calls.
second = 1000
minute = second * 60
hour = minute * 60
day = hour * 24
test = 3 * day + 2 * hour + 11 * minute + 58 * second
console.log(Math.floor(test / day))
console.log(Math.floor(test % day / hour))
console.log(Math.floor(test % day % hour / minute))
console.log(Math.floor(test % day % hour % minute / second))
Extending on #Rick's answer, I prefer something like this:
function msToReadableTime(time){
const second = 1000;
const minute = second * 60;
const hour = minute * 60;
let hours = Math.floor(time / hour % 24);
let minutes = Math.floor(time / minute % 60);
let seconds = Math.floor(time / second % 60);
return hours + ':' + minutes + ":" + seconds;
}
Based on #Chand answer. This is the implementation in Typescript. A bit safer than coercing types in JS. If you remove the type annotation should be valid JS. Also using new string functions to normalise the time.
function displayTime(millisec: number) {
const normalizeTime = (time: string): string => (time.length === 1) ? time.padStart(2, '0') : time;
let seconds: string = (millisec / 1000).toFixed(0);
let minutes: string = Math.floor(parseInt(seconds) / 60).toString();
let hours: string = '';
if (parseInt(minutes) > 59) {
hours = normalizeTime(Math.floor(parseInt(minutes) / 60).toString());
minutes = normalizeTime((parseInt(minutes) - (parseInt(hours) * 60)).toString());
}
seconds = normalizeTime(Math.floor(parseInt(seconds) % 60).toString());
if (hours !== '') {
return `${hours}:${minutes}:${seconds}`;
}
return `${minutes}:${seconds}`;
}
I recently ran into this situation. My focus was on clean readability and reusability.
Use
(See function definition below)
timeUnits(86400000) // {days: 1, hours: 0, minutes: 0, seconds: 0, ms: 0}
Then you can use the data to do whatever you want (like build a string).
Other examples:
timeUnits(214870123) // {days: 2, hours: 11, minutes: 41, seconds: 10, ms: 123}
timeUnits('70123') // null
Function
/**
* Converts milliseconds into greater time units as possible
* #param {int} ms - Amount of time measured in milliseconds
* #return {?Object} Reallocated time units. NULL on failure.
*/
function timeUnits( ms ) {
if ( !Number.isInteger(ms) ) {
return null
}
/**
* Takes as many whole units from the time pool (ms) as possible
* #param {int} msUnit - Size of a single unit in milliseconds
* #return {int} Number of units taken from the time pool
*/
const allocate = msUnit => {
const units = Math.trunc(ms / msUnit)
ms -= units * msUnit
return units
}
// Property order is important here.
// These arguments are the respective units in ms.
return {
// weeks: allocate(604800000), // Uncomment for weeks
days: allocate(86400000),
hours: allocate(3600000),
minutes: allocate(60000),
seconds: allocate(1000),
ms: ms // remainder
}
}
It's written in such a way so that you can easily implement other units (for example, where I commented out implementation for weeks) so long as you know their worth in milliseconds.
my solution
var sunriseMills = 1517573074000; // sunrise in NewYork on Feb 3, 2018 - UTC time
var offsetCityMills = -5 * 3600 * 1000; // NewYork delay to UTC
var offsetDeviceMills = new Date().getTimezoneOffset() * 60 * 1000 ; // eg. I live in Romania (UTC+2) >> getTimezoneOffset() = 120
var textTime = new Date(sunriseMills + offsetCityMills + offsetDeviceMills)
.toLocaleTimeString('en-US', { hour: 'numeric', minute: 'numeric' });
textTime will become '7.04 AM'
A Date object can be constructed from milliseconds:
const date = new Date(0, 0, 0, 0, 0, 0, milliseconds);
In your question you say milliseconds seconds should 'wrap around' at 86400000. Since we know there are 86400000 milliseconds in a day, we can simply take the time from the date object, and ignore every other part of the date as irrelevant.
The time can then be obtained in any number of formats. The one you require matches that used in the United Kingdom, locale en-GB:
const hms = d.toLocaleTimeString('en-GB');
If you're using typescript, this could be a good thing for you
enum ETime {
Seconds = 1000,
Minutes = 60000,
Hours = 3600000,
SecInMin = 60,
MinInHours = 60,
HoursMod = 24,
timeMin = 10,
}
interface ITime {
millis: number
modulo: number
}
const Times = {
seconds: {
millis: ETime.Seconds,
modulo: ETime.SecInMin,
},
minutes: {
millis: ETime.Minutes,
modulo: ETime.MinInHours,
},
hours: {
millis: ETime.Hours,
modulo: ETime.HoursMod,
},
}
const dots: string = ":"
const msToTime = (duration: number, needHours: boolean = true): string => {
const getCorrectTime = (divider: ITime): string => {
const timeStr: number = Math.floor(
(duration / divider.millis) % divider.modulo,
)
return timeStr < ETime.timeMin ? "0" + timeStr : String(timeStr)
}
return (
(needHours ? getCorrectTime(Times.hours) + dots : "") +
getCorrectTime(Times.minutes) +
dots +
getCorrectTime(Times.seconds)
)
}
In my implementation I used Moment.js:
export default (value) =>
const duration = moment.duration(value);
const milliseconds = duration.milliseconds();
const seconds = duration.seconds();
const minutes = duration.minutes();
const hours = duration.hours();
const day = duration.days();
const sDay = `${day}d `;
const sHours = (hours < 10) ? `0${hours}h ` : `${hours}h `;
const sMinutes = (minutes < 10) ? `0${minutes}' ` : `${minutes}' `;
const sSeconds = (seconds < 10) ? `0${seconds}" ` : `${seconds}" `;
const sMilliseconds = `${milliseconds}ms`;
...
}
Once got the strings, I composed them as I want.
I works for me as i get milliseconds=1592380675409 using javascript method getTime() which returns the number of milliseconds between midnight of January 1, 1970 and the specified date.
var d = new Date();//Wed Jun 17 2020 13:27:55 GMT+0530 (India Standard Time)
var n = d.getTime();//1592380675409 this value is store somewhere
//function call
console.log(convertMillisecToHrMinSec(1592380675409));
var convertMillisecToHrMinSec = (time) => {
let date = new Date(time);
let hr = date.getHours();
let min = date.getMinutes();
let sec = date.getSeconds();
hr = (hr < 10) ? "0"+ hr : hr;
min = (min < 10) ? "0"+ min : min;
sec = (sec < 10) ? "0"+ sec : sec;
return hr + ':' + min + ":" + sec;//01:27:55
}
A refactor from #dusht to ES6+ and more functional:
const addPrefix = time => time < 10 ? '0' + time : time;
const toHours = time => addPrefix(Math.floor((time / (1000 * 60 * 60)) % 24));
const toMinutes = time => addPrefix(Math.floor((time / (1000 * 60)) % 60));
const toSeconds = (ime => addPrefix(Math.floor((time / 1000) % 60));
const toMiliseconds = time => Math.floor((time % 1000) / 100);
const milisecondToHoursAndMinute = time => {
const hours = toHours(time);
const minutes = toMinutes(time);
const seconds = toSeconds(time);
const miliseconds = toMiliseconds(time);
return `${hours}:${minutes}:${seconds}.${miliseconds}`
}
let dateTimeStr = new Date(1949778000);
dateTimeStr = Math.floor(dateTimeStr/86400000) +' days '+ dateTimeStr.getHours() +' hours '+ dateTimeStr.getMinutes() +' minutes '+ dateTimeStr.getSeconds() +' seconds';
console.log(dateTimeStr);
You don't have to calculate the days if you don't need them
"22 days 16 hours 36 minutes 18 seconds"
I don't see the need for complication in all these answers, it's easy to add zeros by adding a power of 10:
function timeToString(t) {
const value =
((t / 3600_000 % 24) | 0) * 10000 +
((t / 60_000 % 60) | 0) * 100 +
((t / 1_000 % 60) | 0);
return (1000000 + value).toString().replace(/1(..)(..)(..)/, '$1:$2:$3');
}
If anyone still need here's a modified version of one of the code snippets posted above in js by https://stackoverflow.com/a/58826445/20067539
function timeConversion(duration) {
var portions = [];
var msInDay = 1000 * 60 * 60 * 24
var days = Math.trunc(duration / msInDay);
if (days > 0 ) {
portions.push(days + (days === 1 ? " day" : " days"))
duration = duration - (days * msInDay)
}
var msInHour = 1000 * 60 * 60;
var hours = Math.trunc(duration / msInHour);
if (hours > 0) {
portions.push(hours + (hours === 1 ? ' hour' : ' hours'));
duration = duration - (hours * msInHour);
}
var msInMinute = 1000 * 60;
var minutes = Math.trunc(duration / msInMinute);
if (minutes > 0) {
portions.push(minutes + (minutes === 1 ? ' minute' : ' minutes'));
duration = duration - (minutes * msInMinute);
}
var seconds = Math.trunc(duration / 1000);
if (seconds > 0) {
portions.push(seconds + (seconds === 1 ? ' second' : ' seconds'));
}
return portions.join(' ');
}
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000)));
console.log(timeConversion((60 * 60 * 1000)));
console.log(timeConversion((60 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion((59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion((59 * 1000)));
Im trying to write a function that takes my decimal degrees (lat or long) and converts them to DMS degrees minutes seconds. I know I am meant to times the decimal point number by 60 then it's decimal again. But am a noob. Would I split the number?
function ConvertDDToDMS(DD) {
eg. DD =-42.4
D= 42;
M= 4*60;
S= .M * 60;
var DMS =
return DMS //append Direction (N, S, E, W);
}
Am I on the right track?
function ConvertDDToDMS(D, lng) {
return {
dir: D < 0 ? (lng ? "W" : "S") : lng ? "E" : "N",
deg: 0 | (D < 0 ? (D = -D) : D),
min: 0 | (((D += 1e-9) % 1) * 60),
sec: (0 | (((D * 60) % 1) * 6000)) / 100,
};
}
The above gives you an object {deg, min, sec, dir} with sec truncated to two digits (e.g. 3.14) and dir being one of N, E, S, W depending on whether you set the lng (longitude) parameter to true. e.g.:
ConvertDDToDMS(-18.213, true) == {
deg : 18,
min : 12,
sec : 46.79,
dir : 'W'
}
Or if you just want the basic string:
function ConvertDDToDMS(D){
return [0|D, 'd ', 0|(D=(D<0?-D:D)+1e-4)%1*60, "' ", 0|D*60%1*60, '"'].join('');
}
ConvertDDToDMS(-18.213) == `-18d 12' 47"`
[edit June 2019] -- fixing an 8 year old bug that would sometimes cause the result to be 1 minute off due to floating point math when converting an exact minute, e.g. ConvertDDToDMS(4 + 20/60).
[edit Dec 2021] -- Whoops. Fix #2. Went back to the original code and added 1e-9 to the value which a) bumps any slightly low floating point errors to the next highest number and b) is less than .01 sec, so has no effect on the output. Added 1e-4 to the "string" version which is the same fix, but also rounds seconds (it's close to 1/2 sec).
It's not clear how you need the output. Here's a version that returns all 3 values as a string:
function ConvertDDToDMS(dd)
{
var deg = dd | 0; // truncate dd to get degrees
var frac = Math.abs(dd - deg); // get fractional part
var min = (frac * 60) | 0; // multiply fraction by 60 and truncate
var sec = frac * 3600 - min * 60;
return deg + "d " + min + "' " + sec + "\"";
}
Update: I remove the part that did not make any sense (thanks cwolves!).
Here you have yet another implementation. It won't be as short nor efficient as the previous ones, but hopefully much easier to understand.
To get it right, first you need to understand how the calculations are done and only then attempt to implement them. For that, pseudocode is a great option, since you write down the steps in plain English or a simplified syntax that is easy to understand, and then translate it onto the programming language of choice.
I hope it's useful!
/* This is the pseudocode you need to follow:
* It's a modified version from
* http://en.wikipedia.org/wiki/Geographic_coordinate_conversion#Conversion_from_Decimal_Degree_to_DMS
function deg_to_dms ( degfloat )
Compute degrees, minutes and seconds:
deg ← integerpart ( degfloat )
minfloat ← 60 * ( degfloat - deg )
min ← integerpart ( minfloat )
secfloat ← 60 * ( minfloat - min )
Round seconds to desired accuracy:
secfloat ← round( secfloat, digits )
After rounding, the seconds might become 60. These two
if-tests are not necessary if no rounding is done.
if secfloat = 60
min ← min + 1
secfloat ← 0
end if
if min = 60
deg ← deg + 1
min ← 0
end if
Return output:
return ( deg, min, secfloat )
end function
*/
function deg_to_dms (deg) {
var d = Math.floor (deg);
var minfloat = (deg-d)*60;
var m = Math.floor(minfloat);
var secfloat = (minfloat-m)*60;
var s = Math.round(secfloat);
// After rounding, the seconds might become 60. These two
// if-tests are not necessary if no rounding is done.
if (s==60) {
m++;
s=0;
}
if (m==60) {
d++;
m=0;
}
return ("" + d + ":" + m + ":" + s);
}
Try this working perfect!!!
function truncate(n) {
return n > 0 ? Math.floor(n) : Math.ceil(n);
}
function getDMS(dd, longOrLat) {
let hemisphere = /^[WE]|(?:lon)/i.test(longOrLat)
? dd < 0
? "W"
: "E"
: dd < 0
? "S"
: "N";
const absDD = Math.abs(dd);
const degrees = truncate(absDD);
const minutes = truncate((absDD - degrees) * 60);
const seconds = ((absDD - degrees - minutes / 60) * Math.pow(60, 2)).toFixed(2);
let dmsArray = [degrees, minutes, seconds, hemisphere];
return `${dmsArray[0]}°${dmsArray[1]}'${dmsArray[2]}" ${dmsArray[3]}`;
}
var lat = 13.041107;
var lon = 80.233232;
var latDMS = getDMS(lat, 'lat');
var lonDMS = getDMS(lon, 'long');
console.log('latDMS: '+ latDMS);
console.log('lonDMS: '+ lonDMS);
Output:
latDMS: 13°2'27.99" N
lonDMS: 80°13'59.64" E
A solution with the option for specifying the decimal places in output seconds and correction of any edge cases due to rounding seconds and minutes.
// # input {deg} Numeric; degrees number to convert
// # input {dplaces} Decimal places to use for output seconds
// Default 0 places
// # return {DMS} string degrees (°) minutes (') seconds (")
//
function degToDMS (deg, dplaces=0) {
var d = Math.floor (deg); // make degrees
var m = Math.floor((deg-d)*60); // make minutes
var s = Math.round(((deg-d)*60-m)*60*Math.pow(10,dplaces))/Math.pow(10,dplaces); // Make sec rounded
s == 60 && (m++, s=0 ); // if seconds rounds to 60 then increment minutes, reset seconds
m == 60 && (d++, m=0 ); // if minutes rounds to 60 then increment degress, reset minutes
return (d + "° " + m + "' " + s+'"'); // create output DMS string
}
// ----- tests ------
console.log(degToDMS(55.23456)); // 55° 14' 4"
console.log(degToDMS(55.23456 ,3)); // 55° 14' 4.416"
console.log(degToDMS(4 + 20/60 ,2)); // 4° 20' 0"
console.log(degToDMS(89.64789 ,2)); // 89° 38' 52.4"
console.log(degToDMS(-23.1234567,3)); // -24° 52' 35.556"
This one works %100 in TypeScript:
ConvertDDToDMS(deg: number, lng: boolean): string {
var d = parseInt(deg.toString());
var minfloat = Math.abs((deg - d) * 60);
var m = Math.floor(minfloat);
var secfloat = (minfloat - m) * 60;
var s = Math.round((secfloat + Number.EPSILON) * 100) / 100
d = Math.abs(d);
if (s == 60) {
m++;
s = 0;
}
if (m == 60) {
d++;
m = 0;
}
let dms = {
dir: deg < 0 ? lng ? 'W' : 'S' : lng ? 'E' : 'N',
deg: d,
min: m,
sec: s
};
return `${dms.deg}\u00B0 ${dms.min}' ${dms.sec}" ${dms.dir}`
}
private static DecimalFormat DecimalFormat = new DecimalFormat(".##");
public static void main(String[] args){
double decimal_degrees = 22.4229541515;
System.out.println(getDMS(decimal_degrees));
}
public static String getDMS(double decimal_degrees) {
double degree = Math.floor(decimal_degrees);
double minutes = ((decimal_degrees - Math.floor(decimal_degrees)) * 60.0);
double seconds = (minutes - Math.floor(minutes)) * 60.0;
return ((int)degree)+":"+((int)minutes)+":"+decimalFormat.format(seconds);
}
INPUT : 22.4229541515 OUTPUT: 22:25:22.63
Based on above answer, i've written them into javascript and php style.
JS-
function convertDDToDMS(deg, lng){
var d = parseInt(deg);
var minfloat = Math.abs((deg-d) * 60);
var m = Math.floor(minfloat);
var secfloat = (minfloat-m)*60;
var s = Math.round(secfloat);
d = Math.abs(d);
if (s==60) {
m++;
s=0;
}
if (m==60) {
d++;
m=0;
}
return {
dir : deg<0?lng?'W':'S':lng?'E':'N',
deg : d,
min : m,
sec : s
};
}
PHP-
function convertDDtoDMS($deg, $lng){
$dd = intval($deg);
$minfloat = abs(($deg - $dd) * 60);
$mm = floor($minfloat);
$secfloat = ($minfloat - $mm) * 60;
$ss = round($secfloat);
$dd = abs($dd);
if($ss == 60){
$mm++;
$ss = 0;
}
if($mm == 60){
$dd++;
$mm = 0;
}
$dd = array(
'dir' => $deg < 0 ? ($lng ? 'W' : 'S') : ($lng ? 'E' : 'N'),
'deg' => abs($dd),
'min' => $mm,
'sec' => $ss,
);
return $dd;
}
couldnt get the script above working, after some time came up with this;
just give the dms to the script
function ConvertDMSToDEG(dms) {
var dms_Array = dms.split(/[^\d\w\.]+/);
var degrees = dms_Array[0];
var minutes = dms_Array[1];
var seconds = dms_Array[2];
var direction = dms_Array[3];
var deg = (Number(degrees) + Number(minutes)/60 + Number(seconds)/3600).toFixed(6);
if (direction == "S" || direction == "W") {
deg = deg * -1;
} // Don't do anything for N or E
return deg;
}
and visa versa just give the degrees to the script, and true of false for lat (latitude)
function ConvertDEGToDMS(deg, lat) {
var absolute = Math.abs(deg);
var degrees = Math.floor(absolute);
var minutesNotTruncated = (absolute - degrees) * 60;
var minutes = Math.floor(minutesNotTruncated);
var seconds = ((minutesNotTruncated - minutes) * 60).toFixed(2);
if (lat) {
var direction = deg >= 0 ? "N" : "S";
} else {
var direction = deg >= 0 ? "E" : "W";
}
return degrees + "°" + minutes + "'" + seconds + "\"" + direction;
}
hope this helps people..
I'm surprised all solutions are using some additional logic to handle the "rounds to 60" cases (if they're aware of it at all), but nobody thought of doing it the other way round, starting with (rounded) seconds and then using mod and int-div and not have to worry about all that:
function coordToStr(coord)
{
let seconds = Math.round(Math.abs(coord) * 3600)
let sec = Math.floor(seconds % 60)
let minutes = Math.floor(seconds / 60)
let min = minutes % 60
let deg = Math.floor(minutes / 60)
return deg + "°" + ((min < 10) ? "0" : "") + min + "'" + ((sec < 10) ? "0" : "") + sec
}
Sorry, this is without the N/S, E/W part, would need some additional method calling it.
If you want second-fractions, you could use this:
function coordToStrWithDecimals(coord)
{
let centiSecs = Math.round(Math.abs(coord) * 360000)
let frac = Math.floor(centiSecs % 100)
let seconds = Math.floor(centiSecs / 100)
let sec = Math.floor(seconds % 60)
let minutes = Math.floor(seconds / 60)
let min = minutes % 60
let deg = Math.floor(minutes / 60)
return deg + "°" + ((min < 10) ? "0" : "") + min + "'" + ((sec < 10) ? "0" : "") + sec + "." + ((frac < 10) ? "0" : "") + frac + '"'
}
just for remark, the answer
function ConvertDDToDMS(D){
return [0|D, 'd ', 0|(D<0?D=-D:D)%1*60, "' ", 0|D*60%1*60, '"'].join('');
}
does not work for angles between -1° and 0°.
Bad luck!
hc