Looking for a cascading dropdown i found this piece of code here, which is working almost perfect for me, but i need to keep the default option in the second select-menu after changing the value in the first one.
https://stackoverflow.com/a/28902561/10391817
function filterCity() {
var province = $("#province").find('option:selected').text(); // stores province
$("#option-container").children().appendTo("#city"); // moves <option> contained in #option-container back to their <select>
var toMove = $("#city").children("[data-province!='" + province + "']"); // selects city elements to move out
toMove.appendTo("#option-container"); // moves city elements in #option-container
$("#city").removeAttr("disabled"); // enables select
};
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<select class="select" id="province" onchange="filterCity();">
<option value="1">RM</option>
<option value="2">FI</option>
</select>
<select class="select" id="city" disabled>
<option>SELECT CITY</option>
<option data-province="RM" value="1">ROMA</option>
<option data-province="RM" value="2">ANGUILLARA SABAZIA</option>
<option data-province="FI" value="3">FIRENZE</option>
<option data-province="FI" value="4">PONTASSIEVE</option>
</select>
<span id="option-container" style="visibility: hidden; position:absolute;"></span>
You can try this code.
<select class="select" id="province">
<option value="1">RM</option>
<option value="2">FI</option>
</select>
<select class="select" id="city" disabled>
<option data-province="DEF">SELECT CITY</option>
<option data-province="RM" value="1">ROMA</option>
<option data-province="RM" value="2">ANGUILLARA SABAZIA</option>
<option data-province="FI" value="3">FIRENZE</option>
<option data-province="FI" value="4">PONTASSIEVE</option>
</select>
<span id="option-container" style="visibility: hidden; position:absolute;"></span>
<script>
$('#province').on('change', function() {
var province = $("#province").find('option:selected').text();
$("#city option[data-province!='" + province + "']").hide();
$("#city option[data-province='" + province + "']").show();
$("#city option[data-province='DEF'").show().prop('selected', true);
$("#city").removeAttr("disabled");
});
</script>
https://jsfiddle.net/sg0t23bc/5/
Related
I have 3 dropdowns in a form:
<select id="1" required>
<option value="">Select type</option>
<option value="1">Car</option>
<option value="2">Truck</option>
<option value="3">Some other option</option>
</select>
<select id="2" required>
<option value="">Select option</option>
<option value="1">Small Car</option>
<option value="2">Big Car</option>
</select>
<select id="3" required>
<option value="">Select option</option>
<option value="1">Small Truck</option>
<option value="2">Big Car</option>
</select>
I need the second and third dropdown to appear/disappear based on selection of the first dropdown. 2 and 3 have to be hidden on page load, or when value 3 is selected on dropdown 1, but not just hidden from view, rather completely non-existant. I say this because jquery .show and .hide only makes an element disappear from display, it still stays inside the code and because of the "required" attribute inside those hidden dropdowns, form cannot submit.
I have tried this as well as many other answers I found, but had no luck...
<script>
$("#1").change(function () {
if ($(this).val() == '1') {
$('#2').show();
$('#3').hide();
} else if ($(this).val() == '2') {
$('#3').show();
$('#2').hide();
} else {
$("#2").hide();
$('#3').hide();
}
})
</script>
Please help...
Edit:
Something along those lines:
<form id="form">
<select id="1" required>
<option value="">Select type</option>
<option value="1">Car</option>
<option value="2">Truck</option>
<option value="3">Some other option</option>
</select>
<div id="here">
<select id="2" required>
<option value="">Select option</option>
<option value="1">Small Car</option>
<option value="2">Big Car</option>
</select>
<select id="3" required>
<option value="">Select option</option>
<option value="1">Small Truck</option>
<option value="2">Big Car</option>
</select>
</div>
</form>
$("#1").change(function () {
if ($(this).val() == '1') {
$('#2').appendTo( "#here" );
$('#3').remove();
} else if ($(this).val() == '2') {
$('#3').appendTo( "#here" );
$('#2').remove();
} else {
$('#2').remove();
$('#3').remove();
}
})
I am not very good at jquery. This does what I want, but only once. I dont know how to bring them back once removed. For example, if I selected from #1: 1(Car) and from #2: 1(Small Car), #3 will be removed. But if i now decide to choose another option on #1 nothing happens. Also, on load, all 3 are shown, I wanted to keep #2 and #3 hidden until an option on #1 is selected.
Here's one way to go about it. Instead of using numbers as ID's, why not use a data-attribute. Each time a select option is chosen the code will show the next one in the sequence.
$(document).ready(() => {
$('select[data-order=1]').show()
let selects = $('select[data-order]');
selects.change(function() {
// get number
let num = +$(this).data('order');
// show the next select and hide all selects after that
selects.each(function(i,o) {
let thisNum = +$(o).data('order');
if (thisNum === num + 1) $(o).show().val(''); // show and reset the value
else if (thisNum > num + 1) $(o).hide();
})
})
})
select[data-order] {
display: none;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form id="form">
<select data-order='1' id="1" required>
<option value="">Select type</option>
<option value="1">Car</option>
<option value="2">Truck</option>
<option value="3">Some other option</option>
</select>
<select data-order='2' id="2">
<option value="">Select option</option>
<option value="1">Small Car</option>
<option value="2">Big Car</option>
</select>
<select data-order='3' id="3">
<option value="">Select option</option>
<option value="1">Small Truck</option>
<option value="2">Big Car</option>
</select>
</form>
I have 2 select option
Select 1
<select id="header_mselect" name="header_mselect" class="form-control col-tablefont">
<option selected="true" value="0">Select</option>
<option value="1">Approved</option>
<option value="2">Disapproved</option>
<option value="3">Hold</option>
</select>
Select 2
<select id="footer_mselect" name="footer_mselect" class="form-control col-tablefont">
<option selected="true" value="0">Select</option>
<option value="1">Approved</option>
<option value="2">Disapproved</option>
<option value="3">Hold</option>
</select>
And this my code in header change
$('#header_mselect').on('change', function() {
var svalue = $('#header_mselect :selected').val();
var stext = $('#header_mselect :selected').text();
$('#footer_mselect').find('option[text="' + stext + '"]').val();
});
My problem here is that i want to set the value or the option of 2nd select based on 1st select during selecting the option on the 1st one but its not working whats wrong?
Try select the element with the desired value directly rather than using a loop (and use the proper selector; you have no orderselect in your code):
$('#header_mselect').on('change', function() {
var svalue = $('#header_mselect :selected').val();
var stext = $('#header_mselect :selected').text();
$('#footer_mselect > option[value="' + svalue + '"]').prop('selected', true);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="header_mselect" name="header_mselect" class="form-control col-tablefont">
<option selected="true" value="0">Select</option>
<option value="1">Approved</option>
<option value="2">Disapproved</option>
<option value="3">Hold</option>
</select>
<select id="footer_mselect" name="footer_mselect" class="form-control col-tablefont">
<option selected="true" value="0">Select</option>
<option value="1">Approved</option>
<option value="2">Disapproved</option>
<option value="3">Hold</option>
</select>
You can select the second select box option using
$('#footer_mselect').find('option[text="' + stext + '"]').prop('selected', true);
You can set the value of the first to the second, since both of the dropdowns share the same set of values.
Get the selected option's value using val() on the first dropdown itself.
Set the value to the second dropdown using val() again.
Find a working demo below:
$('#header_mselect').on('change', function() {
var svalue = $(this).val();
$('#footer_mselect').val(svalue);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="header_mselect" name="header_mselect" class="form-control col-tablefont">
<option selected="true" value="0">Select</option>
<option value="1">Approved</option>
<option value="2">Disapproved</option>
<option value="3">Hold</option>
</select>
<select id="footer_mselect" name="footer_mselect" class="form-control col-tablefont">
<option selected="true" value="0">Select</option>
<option value="1">Approved</option>
<option value="2">Disapproved</option>
<option value="3">Hold</option>
</select>
I am using the following js and html code to display the lists.
MAIN PROBLEM is that when the sub-categories & categories become to many, the categories change but the sub-categries are not displaying from a certain cagory going downwards. Problem is on desktop/laptops. Working correctly on mobile device. Am not god at javascript
<script type="text/javascript">
$(function() {
$('#vehicle').on('change', function() {
var vehileType = $('#vehicle').val();
$('#vehicle-type option').hide();
$('#vehicle-type option[vehicle="'+vehileType+'"]').show();
});
});
</script>
<select id="vehicle" required name="brand">
<option value="">Select Make</option>
<option value="ABT">ABT</option>
<option value="AC">AC</option>
</select>
<select name="model" id="vehicle-type" class="form-control">
<option vehicle="ABT" value="ABT">ABT</option>
<option vehicle="ABT" value="ABT1">ABT1</option>
<option vehicle="AC" value="AC">AC</option>
<option vehicle="AC" value="AC1">AC1</option>
</select>
First I put vehicle options to custom variable var vehicleTypeOptions = $('#vehicle-type option[vehicle="' + vehileType + '"]');
Then after show I add this $('#vehicle-type').val(vehicleTypeOptions.first().val()); so it will set the value of first vehicle type option
I also put .trigger('change') for a #vehicle so it will set vehicle types by the vehicle make so you don't have to manually set one option
Here is a working demo:
$(function() {
$('#vehicle').on('change', function() {
var vehileType = $('#vehicle').val();
var vehicleTypeOptions = $('#vehicle-type option[vehicle="' + vehileType + '"]');
$('#vehicle-type option').not(vehicleTypeOptions).hide();
vehicleTypeOptions.show();
$('#vehicle-type').val(
vehicleTypeOptions.first().val()
);
}).trigger('change');
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="vehicle" required name="brand">
<option value="">Select Make</option>
<option value="ABT">ABT</option>
<option value="AC">AC</option>
</select>
<select name="model" id="vehicle-type" class="form-control">
<option vehicle="ABT" value="ABT">ABT</option>
<option vehicle="ABT" value="ABT1">ABT1</option>
<option vehicle="AC" value="AC">AC</option>
<option vehicle="AC" value="AC1">AC1</option>
</select>
I need to change the 3rd field automatically depending on first two field. ( it would be best if I change 3rd field and then first 2 fields changes also )
I need a Jquery solution. Anyone can help me please?
<select id="First">
<option val="car">car</option>
<option val="phone">phone</option>
</select>
<select id="Second">
<option val="car">car</option>
<option val="phone">phone</option>
<option val="boll">boll</option>
</select>
<hr>
<select id="ChangeItAutomatically">
<option val="carcar">car car</option>
<option val="carphone">car phone</option>
<option val="carboll">car boll</option>
<option val="phonecar">phone car</option>
<option val="phonephone">phone phone</option>
<option val="phonecarboll">phone boll</option>
</select>
Is this what you're looking for?
$(document).ready(function() {
// on change for the 3rd select
$("#ChangeItAutomatically").on("change", function() {
// get the value and split on space
var value = $(this).val().split(" ");
// select the other two selects based on the values
$("#First").val(value[0]);
$("#Second").val(value[1]);
});
// on change for the first two selects
$("#First, #Second").on("change", function() {
// set the value of the 3rd select based on the combination of values of the first two
$("#ChangeItAutomatically").val($("#First").val() + " " + $("#Second").val());
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="First">
<option val="car">car</option>
<option val="phone">phone</option>
</select>
<select id="Second">
<option val="car">car</option>
<option val="phone">phone</option>
<option val="boll">boll</option>
</select>
<hr>
<select id="ChangeItAutomatically">
<option val="car car">car car</option>
<option val="car phone">car phone</option>
<option val="car boll">car boll</option>
<option val="phone car">phone car</option>
<option val="phone phone">phone phone</option>
<option val="phone boll">phone boll</option>
</select>
I have this select; to select countries and add to a new select multiple with a limit of 5 countries, but I just want to add 1 country by select or more countries if i do a multiple select.
My mistake is in my function addC(), when I want to add more than 1 country in my select, it add the several countries in 1 option tag like this:
<option>South KoreaUSAJapan</option>
What I can modify to display the following way if i do a multiple select?:
<option>South Korea</option>
<option>USA</option>
<option>Japan</option>
My code:http://jsbin.com/osesem/4/edit
function addC() {
if ($("#agregarProvincia option").length < 5) {
var newC = ($("#countries option:selected").text());
$("#addCountry").append("<option>" + newC + "</option>");
}
}
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<label for="provincia2"><b>¿Country?</b></label><br>
<span>
<select multiple="multiple" size="5" id="countries">
<option value="1">South Korea</option>
<option value="2">USA</option>
<option value="2">Japan</option>
<option value="3">Italy</option>
<option value="4">Spain</option>
<option value="5">Mexico</option>
<option value="6">England</option>
<option value="7">Phillipins</option>
<option value="8">Portugal</option>
<option value="9">France</option>
<option value="10">Germany</option>
<option value="11">Hong Kong</option>
<option value="12">New Zeland</option>
<option value="13">Ireland</option>
<option value="14">Panama</option>
<option value="15">Norwey</option>
<option value="16">Sweeden</option>
<option value="17">India</option>
<option value="18">Morroco</option>
<option value="19">Russia</option>
<option value="20">China</option>
</select>
</span>
<div class="addremover">
<input class="add" type="button" onclick="addC()" value="Addd »" />
<br/>
</div>
<span>
<select id="addCountry" multiple="multiple" size="5">
</select>
</span>
use each function to loop through the text and append it..
try this
function addC() {
if ($("#agregarProvincia option").length < 5) {
var newC = ($("#countries option:selected"));
newC.each(function(){
$("#addCountry").append("<option>" + $(this).text() + "</option>");
})
}
}
JSbin here
Or just clone the selected <option>'s
function addC() {
if ($('#countries option:selected').size() < 5)
{
$('#addCountry').append($('#countries option:selected').clone());
}
else
{
alert('you can only select 5');
}
}