i neeed to merge two arrays: Categories and Products. Each product has a category object. I need to organize by category, include the category object and keep the empty categories. GroupBy function include only one parameter.
const Categories= [
{id: 1, 'name': 'category1'}
{id: 2, 'name': 'category2'},
{id: 3, 'name': 'category3'},
{id: 4, 'name': 'category4'},
]
const Products= [
{id: 1, 'name': 'product1', category: {id: 1, name: 'category1'}},
{id: 2, 'name': 'product2', category: {id: 1, name: 'category1'}},
{id: 3, 'name': 'product3', category: {id: 2, name: 'category2'}},
{id: 4, 'name': 'product4', category: {id: 2, name: 'category2'}},
]
expected result
const result = [
{
category: {id: 1, name: 'category1'},
products:[{id:1, name: 'produt1'}, {id: 2, name: 'produto1'} ]
},
{
category: {id: 2, name: 'category2'},
products:[{id:3, name: 'produt3'}, {id: 4, name: 'produto4'} ]
},
{
category: {id: 3, name: 'category3'},
products:[]
},
{
category: {id: 4, name: 'category4'},
products:[]
},
]
attempts:
for (i = 0; i < categoriesJson.length; i++) {
categoriesJson[i] = _.assign({}, categoriesJson[i], { products: [] })
for (j = 0; j < productsJson.length; j++) {
if(productsJson[j].categoryId.objectId === categoriesJson[i].objectId){
categoriesJson[i].products.push(productsJson[j])
}
}
}
Concat the Categories (formatted by to a Product format) to the Products, group by the category.id, and then map each group - category is taken from the 1st item, while products are the the items in groups, without the category, and empty items are rejected:
const Products = [{"id":1,"name":"product1","category":{"id":1,"name":"category1"}},{"id":2,"name":"product2","category":{"id":1,"name":"category1"}},{"id":3,"name":"product3","category":{"id":2,"name":"category2"}},{"id":4,"name":"product4","category":{"id":2,"name":"category2"}}]
const Categories = [{"id":1,"name":"category1"},{"id":2,"name":"category2"},{"id":3,"name":"category3"},{"id":4,"name":"category4"}]
const result = _(Products)
.concat(Categories.map(category => ({ category })))
.groupBy('category.id')
.map(group => ({
category: _.head(group).category,
products: _(group)
.map(o => _.omit(o, 'category'))
.reject(_.isEmpty)
.value()
}))
.value()
console.log(result)
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.js"></script>
And the same idea with lodash/fp. Wrap the _.flow() with the _.useWith() function, and preformat the Categories (2nd param) to fit the Categories. The rest is similar to the lodash chain.
const { useWith, identity, flow, concat, groupBy, map, head, omit, reject, isEmpty } = _
const formatProducts = flow(map(omit('category')), reject(isEmpty))
const fn = useWith(flow(
concat,
groupBy('category.id'),
map(group => ({
category: head(group).category,
products: formatProducts(group)
}))
), [identity, map(category => ({ category }))])
const Products = [{"id":1,"name":"product1","category":{"id":1,"name":"category1"}},{"id":2,"name":"product2","category":{"id":1,"name":"category1"}},{"id":3,"name":"product3","category":{"id":2,"name":"category2"}},{"id":4,"name":"product4","category":{"id":2,"name":"category2"}}]
const Categories = [{"id":1,"name":"category1"},{"id":2,"name":"category2"},{"id":3,"name":"category3"},{"id":4,"name":"category4"}]
const result = fn(Products, Categories)
console.log(result)
<script src='https://cdn.jsdelivr.net/g/lodash#4(lodash.min.js+lodash.fp.min.js)'></script>
If lodash is not a requirement in the solution, this is how I did it with plain javascript;
const Categories= [
{id: 1, 'name': 'category1'},
{id: 2, 'name': 'category2'},
{id: 3, 'name': 'category3'},
{id: 4, 'name': 'category4'}
];
const Products= [
{id: 1, 'name': 'product1', category: {id: 1, name: 'category1'}},
{id: 2, 'name': 'product2', category: {id: 1, name: 'category1'}},
{id: 3, 'name': 'product3', category: {id: 2, name: 'category2'}},
{id: 4, 'name': 'product4', category: {id: 2, name: 'category2'}},
];
const result = [];
for (let index in Categories) {
let category_id = Categories[index].id;
result.push({
category: Categories[index],
products: GetProductsWithCategoryId(category_id)
});
}
function GetProductsWithCategoryId(category_id) {
let products = [];
for (let index in Products) {
if (Products[index].category.id == category_id) {
products.push({
id: Products[index].id,
name: Products[index].name
});
}
}
return products;
}
console.log("result:", result);
Using reduce, create a mappedProducts object which groups the Products based on the category.id. Like this:
{
"1": [{ id: 1, name: "product1" }, { id: 2, name: "product2" }],
"2": [{ id: 3, name: "product3" }, { id: 4, name: "product4" }]
}
Then, map the Categories array and get the output for each category
const Categories=[{id:1,name:"category1"},{id:2,name:"category2"},{id:3,name:"category3"},{id:4,name:"category4"},],
Products=[{id:1,name:"product1",category:{id:1,name:"category1"}},{id:2,name:"product2",category:{id:1,name:"category1"}},{id:3,name:"product3",category:{id:2,name:"category2"}},{id:4,name:"product4",category:{id:2,name:"category2"}}];
const mappedProducts = Products.reduce((acc, { category, ...rest }) => {
acc[category.id] = acc[category.id] || [];
acc[category.id].push(rest)
return acc;
}, {})
const output = Categories.map(category => ({
category,
products: mappedProducts[category.id] || []
}))
console.log(output)
In a single function. Lodash is not necessary:
const Categories = [
{ id: 1, name: "category1" },
{ id: 2, name: "category2" },
{ id: 3, name: "category3" },
{ id: 4, name: "category4" }
];
const Products = [
{ id: 1, name: "product1", category: { id: 1, name: "category1" } },
{ id: 2, name: "product2", category: { id: 1, name: "category1" } },
{ id: 3, name: "product3", category: { id: 2, name: "category2" } },
{ id: 4, name: "product4", category: { id: 2, name: "category2" } }
];
function combine(categories, products) {
return categories.reduce((list, category) => {
const nextItem = {
category,
products: [
products.filter(p => p.category.id === category.id).map(
({ id, name }) => ({
id,
name
})
)
]
};
list.push(nextItem);
return list;
}, []);
}
const result = combine(Categories, Products)
Now for your information, if you had a huge list of categories and/or products, this wouldn't be the ideal solution as there is a lot of looping involved. Instead, you would cache products in such a way that you only ever need to look at a given product once (rather than looking at every product for every category). With a small data set, this optimization isn't necessary.
Related
i'm react beginner, for some reason when i console log i get two japans any advices ?
these are my data:
options initial value (comes from props) is:
[{ id: 1, name: 'Japan' },{ id: 4, name: 'Australia' }, { id: 5, name: 'Poland' }];
and from redux i'm getting this:
[{ id: 1, name: 'Japan' }, { id: 2, name: 'America' }, { id: 3, name: 'Sweden' }];
but my expected out put is :
[{ id: 1, name: 'Japan' },{ id: 4, name: 'Australia' }, { id: 5, name: 'Poland' }, { id: 2, name: 'America' }, { id: 3, name: 'Sweden' }]
const getUnselectedValues = useSelector(UnselectedValues);
const [options, setOptions] = useState(
props.selectedValues
? (
[...props.selectedValues, ...getUnselectedValues]
).filter((e ) => e)
: [...getUnselectedValues]
);
console.log('options:', options)
Try it:
const [options, setOptions] = useState(
props.selectedValues
? Object.values([...props.selectedValues, ...getUnselectedValues].reduce((acc, {id, name}) =>(acc[id] ??= {id, name}, acc),{}))
: [...getUnselectedValues]
);
Approach:
Iterate through the merged array and build a dictionary by using reduce() where the key is the id and the value is {id, value}
In every iteration look up in the dictionary whether has the key in it or not. If the key is not present that means it's a unique entry and inserts it. If the key is already in the dictionary that means the entry is not unique so no need to insert it again.
Here is an example in Vanilla JS so you can play around:
const selectedValues = [{ id: 1, name: 'Japan' },{ id: 4, name: 'Australia' }, { id: 5, name: 'Poland' }];
const getUnselectedValues = [{ id: 1, name: 'Japan' }, { id: 2, name: 'America' }, { id: 3, name: 'Sweden' }];
const res = Object.values([...selectedValues, ...getUnselectedValues].reduce((acc, {id, name}) =>(acc[id] ??= {id, name}, acc),{}));
console.log(res);
Using filter():
const selectedValues = [{ id: 1, name: 'Japan' },{ id: 4, name: 'Australia' }, { id: 5, name: 'Poland' }];
const getUnselectedValues = [{ id: 1, name: 'Japan' }, { id: 2, name: 'America' }, { id: 3, name: 'Sweden' }];
const res = [...selectedValues, ...getUnselectedValues.filter(({id, name}) => !selectedValues.find(it => it.id === id))];
console.log(res);
I have a following array
const _array = [{id: 1, name: 'Adam'}, {id:3, name: 'Crystal'}, {id:2, name: 'Bob'}, {id: 4, name: 'Daisy'}];
How to write a single line of code in typescript to get item where name equal to Crystal from the array?
You can use array find method like following:
const _array = [
{ id: 1, name: "Adam" },
{ id: 3, name: "Crystal" },
{ id: 2, name: "Bob" },
{ id: 4, name: "Daisy" },
];
const item = _array.find((item) => item.name === "Crystal");
console.log(item);
Output
{ id: 3, name: 'Crystal' }
I have a structure in which the number of arrangements can vary:
array1 = [
{local: {id: 1, name: 'local1'}},
{local: {id: 2, name: 'local2'}},
{local: {id: 3, name: 'local3'}},
{local: {id: 4, name: 'local4'}},
{local: {id: 5, name: 'local5'}}
];
array2 = [
{local: {id: 1, name: 'local1'}},
{local: {id: 3, name: 'local3'}},
{local: {id: 3, name: 'local4'}},
{local: {id: 3, name: 'local5'}},
];
array3 = [
{local: {id: 1, name: 'local1'}},
{local: {id: 3, name: 'local2'}},
{local: {id: 3, name: 'local3'}},
{local: {id: 3, name: 'local5'}},
];
I need to create a new array from these, in which this new array is ordered first by the ids that are repeated in all the arrays and then the ones that are not repeated, should be something like this:
newArray = [
{local: {id: 1, name: 'local1'}},
{local: {id: 3, name: 'local3'}},
{local: {id: 5, name: 'local5'}},
{local: {id: 2, name: 'local2'}},
{local: {id: 4, name: 'local4'}}
]
Someone who can help me please!!
Converting all the arrays to objects for fast searching.
const array1 = [{
local: {
id: 1,
name: 'local1'
}
},
{
local: {
id: 2,
name: 'local2'
}
},
{
local: {
id: 3,
name: 'local3'
}
},
{
local: {
id: 4,
name: 'local4'
}
},
{
local: {
id: 5,
name: 'local5'
}
}
];
const array2 = [{
local: {
id: 1,
name: 'local1'
}
},
{
local: {
id: 3,
name: 'local3'
}
},
{
local: {
id: 3,
name: 'local4'
}
},
{
local: {
id: 3,
name: 'local5'
}
},
];
const array3 = [{
local: {
id: 1,
name: 'local1'
}
},
{
local: {
id: 3,
name: 'local2'
}
},
{
local: {
id: 3,
name: 'local3'
}
},
{
local: {
id: 3,
name: 'local5'
}
},
];
const obj1 = array1.reduce((acc, item) => {
acc[item.local.id] = item;
return acc;
}, {});
const obj2 = array2.reduce((acc, item) => {
acc[item.local.id] = item;
return acc;
}, {});
const obj3 = array3.reduce((acc, item) => {
acc[item.local.id] = item;
return acc;
}, {});
const result = {
...obj3,
...obj2,
...obj1
};
const output = [];
const temp = [];
for (let key in result) {
if (obj1[key] && obj2[key] && obj3[key]) {
output.push(result[key]);
} else temp.push(result[key]);
}
console.log([...output, ...temp]);
I would do it like this (may not be the optimum solution):
/* Same Arrays as yours */ const array1=[{local:{id:1,name:"local1"}},{local:{id:2,name:"local2"}},{local:{id:3,name:"local3"}},{local:{id:4,name:"local4"}},{local:{id:5,name:"local5"}}],array2=[{local:{id:1,name:"local1"}},{local:{id:3,name:"local3"}},{local:{id:3,name:"local4"}},{local:{id:3,name:"local5"}}],array3=[{local:{id:1,name:"local1"}},{local:{id:3,name:"local2"}},{local:{id:3,name:"local3"}},{local:{id:3,name:"local5"}}];
function myFunc(arrays) {
// All items, with duplicates
const allItems = [].concat.apply([], arrays);
// All IDs, without duplicates thanks to `Set`
const allIDs = Array.from(
allItems.reduce((set, item) => set.add(item.local.id), new Set())
);
// Helper function used for sorting
const isInAllArrays = id => arrays.every(
arr => arr.some(item => item.local.id === id)
);
// Sort the IDs based on whether they are in all arrays or not
allIDs.sort((a, b) => {
const _a = isInAllArrays(a), _b = isInAllArrays(b);
if (_a !== _b) return _a ? -1 : 1;
return 0;
});
// Map all IDs to the first element with this ID
return allIDs.map(id => allItems.find(item => item.local.id === id));
}
const newArray = myFunc([array1, array2, array3]);
// Just for readability in the demo below
console.log(JSON.stringify(newArray).split('},{').join('},\n{'));
1) Traverse all arrays and build an object with keys as id and value include object and also maintain the frequency of occurrence (count).
2) Now, Object.values of above object and sort them based on 'count'.
You will get most frequent items at top.
const sort = (...arrs) => {
const all = {};
arrs
.flat()
.forEach(
(obj) =>
(all[obj.local.id] =
obj.local.id in all
? { ...all[obj.local.id], count: all[obj.local.id].count + 1 }
: { ...obj, count: 1 })
);
return Object.values(all)
.sort((a, b) => b.count - a.count)
.map(({ count, ...rest }) => rest);
};
array1 = [
{ local: { id: 1, name: "local1" } },
{ local: { id: 2, name: "local2" } },
{ local: { id: 3, name: "local3" } },
{ local: { id: 4, name: "local4" } },
{ local: { id: 5, name: "local5" } },
];
array2 = [
{ local: { id: 1, name: "local1" } },
{ local: { id: 3, name: "local3" } },
{ local: { id: 3, name: "local4" } },
{ local: { id: 3, name: "local5" } },
];
array3 = [
{ local: { id: 1, name: "local1" } },
{ local: { id: 3, name: "local2" } },
{ local: { id: 3, name: "local3" } },
{ local: { id: 3, name: "local5" } },
];
console.log(sort(array1, array2, array3))
I have 2 arrays:
0: {id: 2, name: "TMA"}
1: {id: 3, name: "Hibbernate"}
0: {id: 1, name: "FB.DE"}
1: {id: 2, name: "TMA"}
2: {id: 3, name: "Hibbernate"}
3: {id: 4, name: "Event.it A"}
4: {id: 5, name: "Projket 2"}
5: {id: 6, name: "Projekt 1"}
I want to compare them and delete the objects with the id 2 and 3 cause both arrays have them and thats the similarity.
This is my Code so far:
const projectListOutput = projectsOfPersonArray.filter(project => data.includes(project));
console.log(projectListOutput);
But every time i run this projectListOutput is empty.
When using includes dont compare objects, Just build data as array of strings. Remaining code is similar to what you have.
arr1 = [
{ id: 2, name: "TMA" },
{ id: 3, name: "Hibbernate" },
];
arr2 = [
{ id: 1, name: "FB.DE" },
{ id: 2, name: "TMA" },
{ id: 3, name: "Hibbernate" },
{ id: 4, name: "Event.it A" },
{ id: 5, name: "Projket 2" },
{ id: 6, name: "Projekt 1" },
];
const data = arr1.map(({ id }) => id);
const result = arr2.filter(({ id }) => !data.includes(id));
console.log(result);
Your data array probably does not contain the exact same object references than projectsOfPersonArray. Look at the code below:
[{ foo: 'bar' }].includes({ foo: 'bar' });
// false
Objects look equal, but they don't share the same reference (= they're not the same).
It's safer to use includes with primitive values like numbers or strings. You can for example check the ids of your objects instead of the full objects.
You compare different objects, so every object is unique.
For filtering, you need to compare all properties or use a JSON string, if the order of properties is equal.
var exclude = [{ id: 2, name: "TMA" }, { id: 3, name: "Hibbernate" }],
data = [{ id: 2, name: "TMA" }, { id: 3, name: "Hibbernate" }, { id: 1, name: "FB.DE" }, { id: 2, name: "TMA" }, { id: 3, name: "Hibbernate" }, { id: 4, name: "Event.it A" }, { id: 5, name: "Projket 2" }, { id: 6, name: "Projekt 1" }],
result = data.filter(project =>
!exclude.some(item => JSON.stringify(item) === JSON.stringify(project))
);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
You can do something similar to the next:
const source = [{
id: 1,
name: "FB.DE"
},
{
id: 2,
name: "TMA"
},
{
id: 3,
name: "Hibbernate"
},
{
id: 4,
name: "Event.it A"
},
{
id: 5,
name: "Projket 2"
},
{
id: 6,
name: "Projekt 1"
}
]
const toRemove = [{
id: 2,
name: "TMA"
},
{
id: 3,
name: "Hibbernate"
}
]
/**create object where keys is object "id" prop, and value is true**/
const toRemoveMap = toRemove.reduce((result, item) => ({
...result,
[item.id]: true
}), {})
const result = source.filter(item => !toRemoveMap[item.id])
You can make function from it:
function removeArrayDuplicates (sourceArray, duplicatesArray, accessor) {
const toRemoveMap = duplicatesArray.reduce((result, item) => ({
...result,
[item[accessor]]: true
}), {});
return sourceArray.filter(item => !toRemoveMap[item[accessor]])
}
removeArrayDuplicates(source, toRemove, 'id')
Or even better, you can make it work with a function instead of just property accessor:
function removeDuplicates (sourceArray, duplicatesArray, accessor) {
let objectSerializer = obj => obj[accessor];
if(typeof accessor === 'function') {
objectSerializer = accessor;
}
const toRemoveMap = duplicatesArray.reduce((result, item) => ({
...result,
[objectSerializer(item)]: true
}), {});
return sourceArray.filter(item => !toRemoveMap[objectSerializer(item)])
}
removeDuplicates(source, toRemove, (obj) => JSON.stringify(obj))
This function will help you merge two sorted arrays
var arr1 = [
{ id: 2, name: 'TMA' },
{ id: 3, name: 'Hibbernate' },
]
var arr2 = [
{ id: 1, name: 'FB.DE' },
{ id: 2, name: 'TMA' },
{ id: 3, name: 'Hibbernate' },
{ id: 4, name: 'Event.it A' },
{ id: 5, name: 'Projket 2' },
]
function mergeArray(array1, array2) {
var result = []
var firstArrayLen = array1.length
var secondArrayLen = array2.length
var i = 0 // index for first array
var j = 0 // index for second array
while (i < firstArrayLen || j < secondArrayLen) {
if (i === firstArrayLen) { // first array doesn't have any other members
while (j < secondArrayLen) { // we copy rest members of first array as a result
result.push(array2[j])
j++
}
} else if (j === secondArrayLen) { // second array doesn't have any other members
while (i < firstArrayLen) { // we copy the rest members of the first array to the result array
result.push(array1[i])
i++
}
} else if (array1[i].id < array2[j].id) {
result.push(array1[i])
i++
} else if (array1[i].id > array2[j].id) {
result.push(array2[j])
j++
} else {
result.push(array1[i])
i++
j++
}
}
return result
}
console.log(mergeArray(arr1,arr2));
I have a complex array's like shown below
sectionDetail = [{id: 1, name:'ma'}, {id: 2, name:'na'}, {id: 3, name:'ra'}, {id: 4, name:'ka'}, {id: 5, name:'pa'}];
abc = [{id:'1', name:'zam', sections:['1',4]}, {id:'2', name:'dam', sections:['3']}, {id:'3', name:'nam', sections:['2','4']}];
Now I have to loop through the abc with respect to sections to replace the array elements with their respective sectionDetail values
I have tried by looping it to a new variable but my sections is getting replaced every time. below is the code i tried.
const matchingBoost = [];
const getCategoryBasedBoostList = [];
abc.forEach((item, i) => {
sectionDetail.forEach((val, index) => {
item.section.forEach((value, x) => {
if (value == val.Id) {
matchingBoost.push(val);
}
});
});
getCategoryBasedBoostList.push({
Name: item.Name,
Boost: matchingBoost
});
});
so basically I'm looking for a new array something like this
xyz = [{name:'zam', sections:[{id: 1, name:'ma'}, {id: 4, name:'ka'}]},
{name:'dam', sections:[{id: 3, name:'ra'}]}, {name:'nam', sections:[{id: 2, name:'na'}, {id: 4, name:'ka'}]}];
hoping I made sense and hoping for some response.
You can basically filter the sections from sectionDetail based on whether the object.id inside it is included in the sections of abc. I have mapped the indexes to number in both cases since one was string and the other was integer.
sectionDetail = [{id: 1, name:'ma'}, {id: 2, name:'na'}, {id: 3, name:'ra'}, {id: 4, name:'ka'}, {id: 5, name:'pa'}];
abc = [{id:'1', name:'zam', sections:['1',4]}, {id:'2', name:'dam', sections:['3']}, {id:'3', name:'nam', sections:['2','4']}];
xyz = abc.map(item => ({...item, sections: sectionDetail.filter(sect => item.sections.map(id => parseInt(id)).includes(parseInt(sect.id)))}));
console.log(xyz);
You could take a Map and then map the data with the items of sectionDetail.
var sectionDetail = [{ id: 1, name: 'ma' }, { id: 2, name: 'na' }, { id: 3, name: 'ra' }, { id: 4, name: 'ka' }, { id: 5, name: 'pa' }],
data = [{ id: '1', name: 'zam', sections: ['1', 4] }, { id: '2', name: 'dam', sections: ['3'] }, { id: '3', name: 'nam', sections: ['2', '4'] }],
map = new Map(sectionDetail.map(o => [o.id, o])),
result = data.map(({ name, sections }) =>
({ name, sections: sections.map(id => map.get(+id)) })
);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
So you want to remove the id from the abc objects and replace the sections array elements with the corresponding details objects? This looks like a job for forEach and map! The code I'm about to show also does a little bit of pre-processing of the sections array to make the overall code more efficient.
const sections = sectionDetail.reduce((result, section) => {
result[section.id] = section;
return result;
}, {});
abc.forEach(item => {
delete item.id;
item.sections = item.sections.map(id => sections[id]);
});
Try like this:
const sectionDetail = [
{ id: 1, name: 'ma' },
{ id: 2, name: 'na' },
{ id: 3, name: 'ra' },
{ id: 4, name: 'ka' },
{ id: 5, name: 'pa' }];
const abc = [
{ id: '1', name: 'zam', sections: ['1', 4] },
{ id: '2', name: 'dam', sections: ['3'] },
{ id: '3', name: 'nam', sections: ['2', '4'] }
];
const desired = abc.map(({id, name, sections}) => {
return {id, name, sections : sectionDetail.filter(f => {
return sections.map(s => +s).includes(f.id)
})};
})
console.log(desired);
where +s is casting to Number type.