We Keep Coding

How to upload image using file_get_contents in php

I am new In Reactjs and php, I have index.js (page in Reactjs/nextjs) and i am sending image data (using multipart form data) And in Php i am trying to upload image but whenever i am trying to upload image then uploaded image showing error "we dont support this format", So please tell me how can i simply upload image using "file_get_contents" method, Here is my code in php (which is uploading incorrect image or 0 byte image), i tried with 2 ways , First way/code is
$data = json_decode(file_get_contents("php://input"), TRUE);
$files=file_get_contents($_FILES["file"]["tmp_name"]);
$image = base64_decode(explode( ',', $files)[1]);
$file_name =$_FILES['file']['name'];
$file_ext = strtolower( end(explode('.',$file_name)));
define('UPLOAD_DIR', 'uploads/');
$file_ext = pathinfo($_FILES["file"]["name"], PATHINFO_EXTENSION);
$file_name = UPLOAD_DIR . uniqid() . time() . '.' . $file_ext;
move_uploaded_file($_FILES["file"]["tmp_name"], $file_name);
Second way is
$file_name =$_FILES['file']['name'];
$file_ext = strtolower( end(explode('.',$file_name)));
define('UPLOAD_DIR', 'uploads/');
$image_parts = explode(";base64,", $image);
$image_type_aux = explode("image/", $image_parts[0]);
$image_type = $image_type_aux[1];
$image_base64 = base64_decode($image_parts[1]);
$file = UPLOAD_DIR . uniqid() . '.'.$file_ext;
file_put_contents($file, $image_base64);

I have a simple upload class that I edit for each project, test it, hope it helps
class Upload
{
//300 kb
private static $MAX_FILE_SIZE = 300 * 1024;
private static $ALLOWED_FILE_TYPES = ['png', 'jpg', 'jpeg'];
private static $key;
private static $ImageFileType;
public static function uploadTeamLogo($key, $short_name, $relativePath)
{
self::$key = $key;
if (!self::isImage())
apiErrorMessage("Not an image!");
if (!self::fileTypeIsAllowed(basename($_FILES[self::$key]["name"])))
apiErrorMessage("Only png, jpg, jpeg Images are allowed!");
if (self::isSizeTooLarge())
apiErrorMessage("Max file size is 300kb!");
$image_name = $short_name . "_" . generateHash(12) . "." . self::$ImageFileType;
$target_dir = getcwd() . $relativePath . $image_name;
if (self::doUpload($target_dir))
return $image_name;
else
return false;
}
private static function isImage()
{
return getimagesize($_FILES[self::$key]["tmp_name"]) == true;
}
private static function alreadyExist($target_file)
{
return file_exists($target_file) === true;
}
private static function isSizeTooLarge()
{
return $_FILES[self::$key]["size"] > self::$MAX_FILE_SIZE === true;
}
private static function fileTypeIsAllowed($target_file)
{
self::$ImageFileType = strtolower(pathinfo($target_file, PATHINFO_EXTENSION));
foreach (self::$ALLOWED_FILE_TYPES as $type)
if (self::$ImageFileType == $type)
return true;
return false;
}
private static function doUpload($target_file)
{
return move_uploaded_file($_FILES[self::$key]["tmp_name"], $target_file) == true;
}
}
use like this:
$image_name = Upload::uploadTeamLogo($key, $short_name, $path);

Get json encode data from another ajax function

I'm using prestashop 1.6, I have an ajax function where I encode some data which I successfully retrieved on console withecho. Now I have to decode this json data in another ajax function to get a value for a specific variable. Sorry I'm a newbie with prestashop 1.6.
My first ajax function :
public function ajaxProcessAddQrVideo(){
$target_dir = _PS_IMG_DIR_.DS.'video_qr';
$id_product = Tools::getValue('id_product');
$stamp = strtotime('now');
$filename = 'video_qr_'.$id_product.'_'.$stamp.'.jpg';
$target_file = $target_dir.DS.$filename;
$upload = $_FILES['video_qr_attachment_file'];
$err = array();
$uploaded = false;
if($upload['type'] !='image/jpeg'){
array_push($err,"Veuillez entrer un fichier JPG");
}
if(empty($err)){
$uploaded = #move_uploaded_file($upload['tmp_name'], $target_file);
$this->context->smarty->assign('uploaded', $uploaded);
$this->context->smarty->assign('filename', $filename);
}
$this->json =array(
'uploaded'=>$uploaded,
'err'=>$err,
'id_product'=>$id_product,
'stamp'=>$stamp,
'file_name'=>$filename,
);
echo json_encode($this->json);
exit;
}
And I want to get the value of 'file_name' in my second ajax function:
public function ajaxProcessAddVideo(){
$img_path = json_decode($this->json,true);
$filename = $img_path['file_name'];
$id_lang = Context::getContext()->language->id;
$script = Tools::getValue('script');
$id_product = Tools::getValue('id_product');
$id_group_vid = Tools::getValue('cust_group');
//add qr_code video
$qr_code =$filename;
$err = true;
$insert = false;
$videos = array();
$vid = new MpsVideo();
$vid->id_product = $id_product;
$vid->url = $script;
$vid->cust_group = $id_group_vid;
$vid->date_add = date('Y-m-d H:i:s');
$vid->active = 1;
$vid->qrcode = $qr_code;
$is_existing = Db::getInstance()->getValue("SELECT COUNT(id_mps_video) FROM `ps_mps_video` WHERE id_product=$id_product AND url = '$script'");
if($is_existing==0){
$insert = $vid->save();
$id_group = explode(',',$id_group_vid);
$group_name = array();
foreach($id_group as $k){
$group = new Group($k);
$group_name[] = $group->name[$id_lang];
}
$vid->group_names = implode('<br/>',$group_name);
}
echo json_encode(array(
'err'=>$err,
'video_exists'=>$is_existing,
'insert'=>$insert,
'vid'=>$vid,
));
exit;
}
I don't know how to achieve this but I know its possible. If someone can help understand this, I would be very grateful.

the result of the first function is a json, that result must be read from another file and then passed to your second function. Or else the same function should read that json:
$data = file_get_contents("file/file_json_result.php");
$img_path = json_decode($data, true);

Uploading capture image and store it in a folder changing it's filename to be unique using the userID

I have this code from this reference https://github.com/jhuckaby/webcamjs/blob/master/DOCS.md?fbclid=IwAR0Q3W5mw8qWlJEdiabmyZJiw7wGJ5YDPRl2Ej0IKF3GCt_78HXeqAEjI6Y
it will display the webcam and take snapshots and make it to an image element using the data_uri but the problem is I want to get that file and store it with a declared filename into a folder here's the script I use
<script src="webcam.js"></script> <!--source code script from github for webcam config-->
<div id="my_camera" style="width:320px; height:240px;"></div>
<div id="my_result"></div>
<script type=text/javascript>
Webcam.attach( '#my_camera' );
function take_snapshot() {
Webcam.snap( function(data_uri) {
document.getElementById('my_result').innerHTML = '<img src="'+data_uri+'"/>';
} );
}
</script>
Take Snapshot
I have a button called register that functions like get all information being input and store it into the database like username first name etc together with the image taken by snapshot, here's my upload script in uploading images from a folder and I want to use it as getting the image data_uri and store it in a folder when I click the register button
<?php
session_start();
include_once'database.php';
$uid = $_SESSION['u_id'];
if (isset($_POST['submit'])){
$file = $_FILES['file'];
$fileName = $_FILES['file']['name'];
$fileTmpName = $_FILES['file']['tmp_name'];
$fileSize = $_FILES['file']['size'];
$fileError = $_FILES['file']['error'];
$fileType = $_FILES['file']['type'];
$fileExt = explode('.', $fileName);
$fileActualExt = strtolower(end($fileExt));
$allowed = array('jpg', 'jpeg', 'png');
//check if ang uploaded file allowed i upload//
if (in_array($fileActualExt, $allowed)){
if ($fileError == 0){
if ($fileSize < 1000000){
$fileNameNew = "profile".$uid.".".$fileActualExt;
$fileDestination = 'uploads/'.$fileNameNew;
move_uploaded_file($fileTmpName, $fileDestination);
$sql = "UPDATE profileimg SET status=0 WHERE userID ='$uid';";
$result = mysqli_query($conn, $sql);
header("location:../pages/userpage.php");
}
else {
echo "Your file is too big";
}
} else {
echo "There was an error uploading you file!";
}
} else {
echo "You cannot upload files of this type";
}
}
I'm going to use this function as stated in the documentation
Webcam.upload( data_uri, 'myscript.php', function(code, text) {
// Upload complete!
// 'code' will be the HTTP response code from the server, e.g. 200
// 'text' will be the raw response content
} );
} );
and have this in my php script
move_uploaded_file($_FILES['webcam']['tmp_name'], 'webcam.jpg');
any idea how should I turn this script into the one I use above in my upload.php? thanks in advance

You need to create image first by image src and then need to save that in a specific folder. You can follow below code:
file_put_contents("fileNameWithLocation.png",file_get_contents($imageSrc));
Here fileNameWithLocation.png will be $fileNameNew = "profile".$uid.".".$fileActualExt; $fileDestination = 'uploads/'.$fileNameNew; You need to make modification accordingly. And $imageSrc will be the image src which you can post via Ajax or form submission.
Hope it helps you.

this code uploads csv file only but i want xls too?

<?php
include 'model.php';
$rs=new database();
if(isset($_POST["Import"])){
echo $filename=$_FILES["file"]["tmp_name"];
if($_FILES["file"]["size"] > 0)
{
$file = fopen($filename, "r");
while (($emapData = fgetcsv($file, 10000, ",")) !== FALSE)
{
$res=$rs->insert($emapData[0],$emapData[1],$emapData[2],$emapData[3],$emapData[4],$emapData[5]);
$result=mysql_fetch_array($res);
if(! $result )
{
echo "<script type=\"text/javascript\">
alert(\"Invalid File:Please Upload CSV File.\");
window.location = \"result.php?msg=valid\"
</script>";
}
}
fclose($file);
echo "<script type=\"text/javascript\">
alert(\"CSV File has been successfully Imported.\");
window.location = \"result.php?msg=valid\"
</script>";
mysql_close($conn);
}
}
?>
this code only uploads csv file but i want to upload xls too with this code. if possible i want to upload all format of excel . and the rest of code is working fine and also i dont want to change the method.

Download PHPExcel
https://github.com/PHPOffice/PHPExcel
and create this function
function getDataFromExcel($filename)
{
$excel = PHPExcel_IOFactory::load($filename);
$sheet = $excel->getSheet(0);
$highestRow = $sheet->getHighestRow();
$sheetData = $sheet->toArray(null, true, true, true);
return $sheetData;
}
It will return data in array
if you want to know the type of file use this method
function getFileType($key)
{
//Define type
$type = 'unknow';
if(isset($_FILES[$key])) {
$file = $_FILES[$key];
$fileType = $file['type'];
if (strrpos($fileType, 'csv')) {
$type = 'csv';
} else if (($fileType == 'application/vnd.openxmlformats-officedocument.spreadsheetml.sheet') || ($fileType == 'application/vnd.ms-excel')) {
$type = 'excel';
}
}
return $type;
}

Multiple files in to folder

Hello I have a view file and controller, what makes multiple inputs where I can upload files in to folder, but its uploading only one file in to folder. I know what is problem, but I dont know how to fix this or how to do this.
My Controller:
public function uploadFile() {
$filename = '';
if ($this->request->is('post')) { // checks for the post values
$uploadData = $this->data['files'];
//print_r($this->data['files']); die;
if ( $uploadData['size'] == 0 || $uploadData['error'] !== 0) { // checks for the errors and size of the uploaded file
echo "Failide maht kokku ei tohi olla üle 5MB";
return false;
}
$filename = basename($uploadData['name']); // gets the base name of the uploaded file
$uploadFolder = WWW_ROOT. 'files'; // path where the uploaded file has to be saved
$filename = $filename; // adding time stamp for the uploaded image for uniqueness
$uploadPath = $uploadFolder . DS . $filename;
if( !file_exists($uploadFolder) ){
mkdir($uploadFolder); // creates folder if not found
}
if (!move_uploaded_file($uploadData['tmp_name'], $uploadPath)) {
return false;
}
echo "Sa sisestasid faili(d): $filename";
}
}
My View file:
<?php
echo $this->Form->create('uploadFile', array( 'type' => 'file'));
?>
<div class="input_fields_wrap">
<label for="uploadFilefiles"></label>
<input type="file" name="data[files]" id="uploadFilefiles">
</div>
<button type="button" class="add_field_button">+</button> <br><br>
<form name="frm1" method="post" onsubmit="return greeting()">
<input type="submit" value="Submit">
</form>
<?php
echo $this->Html->script('addFile');
And this script what Im using in View :
$(document).ready(function() {
var max_fields = 3;
var wrapper = $(".input_fields_wrap");
var add_button = $(".add_field_button");
var x = 1;
$(add_button).click(function(e){
e.preventDefault();
if(x < max_fields){
x++;
$(wrapper).append("<div><input type='file' name='data[files]' id='uploadFilefiles'/><a href='#' class='remove_field'>Kustuta</a></div>");
}
});
$(wrapper).on("click",".remove_field", function(e){ //user click on remove text
e.preventDefault(); $(this).parent('div').remove(); x--;
})
});
I think that, the problem is in input names. If Im doing more inputs, then the inputs names are same, and thanks to this its uploading only one file in to webroot/files folder, but I want these all.
Can anybody help me or give me some tips.
Thanks !

Here is someone with almost exactly the same issue as you have:
Create multiple Upload File dynamically
Try doing the same. I haven't programmed PHP for quite some time, but I guess you should replace data[files] to just data[], so it creates a new array item for each field. Now you are giving each field the same name.
Then you can loop over them in your controller by using:
foreach($_FILES['data'] as $file){
//do stuff with $file
}
EDIT 2:
As you are saying, you want to upload the files (not to a db). So I guess this should work:
public function uploadFile() {
$filename = '';
if ($this->request->is('post')) { // checks for the post values
$uploadData = $this->data;
foreach($uploadData as $file){
if ( $file['size'] == 0 || $file['error'] !== 0) { // checks for the errors and size of the uploaded file
echo "Failide maht kokku ei tohi olla üle 5MB";
return false;
}
$filename = basename($file['name']); // gets the base name of the uploaded file
$uploadFolder = WWW_ROOT. 'files'; // path where the uploaded file has to be saved
$filename = $filename; // adding time stamp for the uploaded image for uniqueness
$uploadPath = $uploadFolder . DS . $filename;
if( !file_exists($uploadFolder) ){
mkdir($uploadFolder); // creates folder if not found
}
if (!move_uploaded_file($file['tmp_name'], $file)) {
return false;
}
echo "Sa sisestasid faili(d): $filename";
}
}
}

Try this function:
function multi_upload($file_id, $folder="", $types="") {
$all_types = explode(",",strtolower($types));
foreach($_FILES[$file_id]['tmp_name'] as $key => $tmp_name ){
if(!$_FILES[$file_id]['name'][$key]){
$return[$key]= array('','No file specified');
continue;
}
$file_title = $_FILES[$file_id]['name'][$key];
$ext_arr = pathinfo($file_title, PATHINFO_EXTENSION);
$ext = strtolower($ext_arr); //Get the last extension
//Not really uniqe - but for all practical reasons, it is
$uniqer = substr(md5(uniqid(rand(),1)),0,5);
$file_name = $uniqer . '_' . $file_title;//Get Unique Name
if($types!=''){
if(in_array($ext,$all_types));
else {
$result = "'".$_FILES[$file_id]['name'][$key]."' is not a valid file."; //Show error if any.
$return[$key]= array('',$result);
continue;
}
}
//Where the file must be uploaded to
if($folder) $folder .= '/';//Add a '/' at the end of the folder
$uploadfile = $folder . $file_name;
$result = '';
//Move the file from the stored location to the new location
if (!move_uploaded_file($_FILES[$file_id]['tmp_name'][$key], $uploadfile)) {
$result = "Cannot upload the file '".$_FILES[$file_id]['name'][$key]."'"; //Show error if any.
if(!file_exists($folder)) {
$result .= " : Folder don't exist.";
} elseif(!is_writable($folder)) {
$result .= " : Folder not writable.";
} elseif(!is_writable($uploadfile)) {
$result .= " : File not writable.";
}
$file_name = '';
}
else {
if(!$_FILES[$file_id]['size']) { //Check if the file is made
#unlink($uploadfile);//Delete the Empty file
$file_name = '';
$result = "Empty file found - please use a valid file."; //Show the error message
}
else {
#chmod($uploadfile,0777);//Make it universally writable.
}
}
$return[$key]=array($file_name,$result);
}
return $return;
}
html: <input type="file" name="data_file[]" id="uploadFilefiles">
Call by multi_upload("data_file","upload_to_folder","pdf,jpg,txt,bmp")