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use javascript .on and .editableselect with one html id

I have a select input which I want to make both editable and use an ajax request that uses the on change JS function. However, only one of the function works since I have used the id of select input twice. I have tried to such for a case related to mine but the one I got is so far from addressing my problem. Its a Javascript, HTML/bootstrap issue though I am using laravel.
Here is the code:
create.blade.php
<div class="form-group">
<label>Product Name</label>
<select name="stock_name" id="stock_name" class="form-control">
<option value="" hidden>Select Product Name</option>
#foreach ($stocks as $stock)
<option value="{{ $stock->stock_name }}">{{ $stock->stock_name}}</option>
#endforeach
</select>
</div>
JS part in same file
<script>
$('#stock_name').editableSelect({
effects: 'slide',
duration: 600
});
</script>
<script>
$(document).ready(function () {
$("#stock_name").on('change', function () {
var stock_name = $(this).val();
$.ajax({
url: '/sales-price/getunitsellingprice/'+stock_name,
method: 'GET',
success: function (response) {
console.log(response);
$("#unit_selling_price").val(response);
},
});
});
});
</script>

As I know, the editable-select event listening is different than default. In order to listen to a change event, you should do like in the example below.
$(document).ready(function () {
$("#stock_name").on('select.editable-select', function (event, element) {
var stock_name = element.val();
$.ajax({
url: '/sales-price/getunitsellingprice/'+stock_name,
method: 'GET',
success: function (response) {
console.log(response);
$("#unit_selling_price").val(response);
},
});
});
});

Selection OnChange change PHP Variable

Hello StackOverflow People.
I need you help. I have this code:
<select name="type" onChange="idk?" class="form-control">
<option value="H">Week 51</option>
<option value="V">Week 52</option>
</select>
And if an user change the week i want to change the file get content :s
$Week = "";
echo file_get_contents('http://rooster.farelcollege.nl/'.$Week.'/c/c00050.htm');
Thanks!
greetings from the Netherlands =)

you can send Ajax request to the "file_get_contents" url.
This is what I am using and it works fine :)
<select name="type" class="form-control">
<option value="H">Week 51</option>
<option value="V">Week 52</option>
</select>
$(document).ready(function() {
$( ".form-control" ).change(function() {
$.ajax({
data: {
// You are not sending any post variables right? Then leave this empty :-) otherwise use it as array 'var1': 'value', 'var2': 'value2' ...
},
url: 'http://rooster.farelcollege.nl/'+$(this).val()+'/c/c00050.htm',
method: 'POST',
success: function(msg) {
alert(msg); // Optional, show text that was given by URL, can be removed
}
});
});
});
jquery.com/jquery.ajax

select option value send to php file with ajax

I have a select dropdown box
<select name="status" id="status" onchange="changeStatus()">
<option value="step_1">step_1</option>
<option value="step_2">step_2</option>
<option value="step_3">step_3</option>
<option value="step_4">step_4</option>
</select>
And my javascript
<script>
function changeStatus() {
$('select.changeStatus').change(function(){
$.ajax({
type: 'POST',
url: 'update_status.php',
data: {changeStatus: $('select.changeStatus').val()},
dataType: 'html'
});
});
});
</script>
So I want the value selected from the select dropdown box send to the php file(update_status.php)

Select id using #. Since you are already using javascript onchange event in select field so no need to use jquery change() event. jQuery use # to select id and . to select class. since you are using id="status" so you must use # to select the id. The way you are trying to collect the value of the select field in this line $('select.changeStatus').val() is wrong. Because there are no class named changeStatus there.
function changeStatus() {
$.ajax({
type: 'POST',
url: 'update_status.php',
data: {changeStatus: $('#select').val()},
dataType: 'html'
});
}

$('#status').val() is used to get value of select options.
So try this
<script>
function changeStatus() {
$.ajax({
type: 'POST',
url: 'update_status.php',
data: {changeStatus: $('#status').val()},
dataType: 'html'
});
});
</script>
or
<script>
function changeStatus() {
$.post("update_status.php", {changeStatus: $('#status').val()}, function(data, status){
});
}
</script>

You don't need to mix jQuery and inline JS
HTML - we'll use your selects name in the function. I've removed the inline function call:
<select name="status" id="status">
<option value="step_1">step_1</option>
<option value="step_2">step_2</option>
<option value="step_3">step_3</option>
<option value="step_4">step_4</option>
</select>
jQuery - I have taken the code out of the function you were calling inline, it was not needed.
<script>
$(document).ready(function() {
$('select[name="status"]').change(function(){
var status = $(this).val();
$.ajax({
type: 'POST',
url: 'update_status.php',
data: {changeStatus: status},
dataType: 'html'
});
});
});
</script>
You can directly test when the select changes and grab its value right then. Here is an EXAMPLE
I have also wrapped the jQuery in a document ready handler. Depending on where you're loading the script in your page you may need to do this to make sure that your jQuery is run as soon as the DOM elements have been loaded.

Remove the onchange field from select and put the below code to your script and this is working. Use JQuery post functionality instead.
$("#status").change( function() {
alert($( this ).val());
$.post('update_status.php', { changeStatus: $(this).val()},
function(response) {
console.log( response);
});
});

<select name="status" id="status" onchange="changeStatus(this.value)">
<option value="step_1">step_1</option>
<option value="step_2">step_2</option>
<option value="step_3">step_3</option>
<option value="step_4">step_4</option>
</select>
function changeStatus(value) {
$.ajax({
type: 'post',
url: 'update_status.php',
data: {'get_data:value'},
success: function (response) {
document.getElementById("loadto").innerHTML=response;
}
});
}
I Hope it will be helpful .....

Json submiting same data until refresh

I have a problem with submiting my "form" with json. Its not form in traditional way, i will post a code now:
$('#select').on('change', function() {
document.getElementById("info").setAttribute("data-info", this.value);
})
$('#info').on('click', function() {
var id = $(this).data('info');
add(info);
});
function add(info) {
$.ajax({
type: 'get',
cache: false,
contentType: content_type,
beforeSend: function(xhr) {xhr.overrideMimeType(content_type);},
data: {'action': 'info_add', 'info': info },
url: sitepath + 'info/all',
success: function() { update(); }
});
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<select id="select">
<option value="1">data1</option>
<option value="2">data2</option>
<option value="3">data3</option>
<option value="4">data4</option>
</select>
<div id="info">Button</div>
So as you see, when select is changed it adds "data-info" attribute to div. And when div is pressed it send data-info to php script. And the problem is that it always send the same value. But after refresh it sends fine only once and than again the same value as first. Its hard to explain but here is example:lets say that i change select to "data2" and press on div. It sends "2". But then when i change it to "data3", and press on div, it still sends "2", not "3". There is no cache set or something. Sorry for bad english and thanks in advance :)

Use jQuery for setting if you are also going to be reading it with jQuery
Change
document.getElementById("info").setAttribute("data-info", this.value);
to
$"#info").data("info", this.value);
Still wondering why you are using data atrrbutes when you are not just reading the value on demand.
add($('#select').val());

You are using confusing code, you can achieve the same using:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<select id="select">
<option value="1">data1</option>
<option value="2">data2</option>
<option value="3">data3</option>
<option value="4">data4</option>
</select>
<div id="info">Button</div>
<script>
$('.product__cart, .stock-product__cart').on('click', function() {
var info = $('#select').val();
$.ajax({
type: 'get',
cache: false,
data: {'action': 'info_add', 'info': info },
url: sitepath + 'info/all',
success: function() { update(); }
});
});
</script>

Assign javascript variable to php variable

How to pass javascript variable that came from select option to a PHP variable?
I want to set PHP variable depending on user selection.
I tried that code:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script>
$(function(){
$("select[name='sex']").change(function () {
var submitSearchData = jQuery('#extended-search').serialize();
var selectedValue=$('#sex').val();
jQuery.ajax({
type: "POST",
data: 'selected=' + selectedValue
url: "ajax.php",
success: function () {
// alert(submitSearchData);
alert(selectedValue);
}
});
});
});
</script>
<form id="extended-search" >
<div class="input-container">
<select class="select" name="sex" id="sex">
<option value="0">All</option>
<option value="1">M</option>
<option value="2">F</option>
</select>
</div>
</form>
<?php
var_dump ($_REQUEST['selected']); //that print NULL don't know why!
?>

You are passing data in wrong format. Data is passed as an object. Please refer below.
$("select[name='sex']").change(function () {
var submitSearchData = jQuery('#extended-search').serialize();
var selectedValue=$('#sex').val();
jQuery.ajax({
type: "POST",
data: {'selected': selectedValue},
url: "ajax.php",
success: function (response) {
// alert(submitSearchData);
alert(response);
}
});
});

Is not possible in the same instance of time:
yourfile -> ajax -> yourfile (here is the value, but you can't see this in your current webpage except that instead of ajax, send post form)

I hope this will help you...
dataType: "html",
data: {'selected': selectedValue},
and then u can get it via $_POST/$_REQUEST array since you have set your type to post.

$_REQUEST is null because it is not related to the ajax request you send. Try this for example:
<?php
if (isset($_POST["selected"])) {
echo $_POST["selected"];
} else {
?>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
</head>
<body>
<form id="extended-search">
<div class="input-container">
<select class="select" name="sex" id="sex">
<option value="0">All</option>
<option value="1">M</option>
<option value="2">F</option>
</select>
</div>
</form>
<script>
$(function() {
$("select[name='sex']").change(function () {
var selected = $(this).val();
$.ajax({
type: "POST",
data: {
selected: selected
},
url: "ajax.php",
success: function (data) {
alert(data);
}
});
});
});
</script>
</body>
</html>
<?php } ?>
EDIT:
I updated the script and tested it. You had some errors in your code. Hope this works for you.