So in the API response example below, focusing on env_variables, I am trying grab the value for secret. I am stuck because as you can see, the name and value are not nested together. I am not familiar with how to grab the value based on the name in this example.
api response:
{
"id": 1146,
"job": {
"name": "jobname1",
},
"env_variables": [
{
"name": {
"name": "test1"
},
"value": {
"value": "10.13.6"
}
},
{
"name": {
"name": "test1"
},
"value": {
"value": "10.13.6"
}
},
],
},
{
"id": 1147,
"job": {
"name": "jobname2",
},
"env_variables": [
{
"name": {
"name": "secret"
},
"value": {
"value": "10.13.7"
}
},
{
"name": {
"name": "test5"
},
"value": {
"value": "10.13.6"
}
},
],
}
js
jobs: []
apiEndpoint = "test.com/api"
fetch(this.apiEndpoint)
.then(response => response.json())
.then(body => {
for(let i=0; i<body.length; i++){
this.jobs.push({
'build_id': JSON.stringify(body[i].id),
'secret': //not sure how to pull the value (10.13.7)
})
}
})
You need nested loops, since there are two nested arrays: the top level of the response is an array of objects, and env_variables contains an array of objects.
fetch(this.apiEndpoint)
.then(response => response.json())
.then(body => {
for (let i = 0; i < body.length; i++) {
let env = body[i].env_variables;
for (let j = 0; j < env.length; j++) {
if (env[j].name.name == "secret") {
this.jobs.push({
'build_id': JSON.stringify(body[i].id),
'secret': env[j].value.value
})
}
}
}
})
You can do something like this inside .then(body=>...
const body = [{ //it looks like brackets [] were lost in OP
"id": 1146,
"job": {
"name": "jobname1",
},
"env_variables": [{
"name": {
"name": "test1"
},
"value": {
"value": "10.13.6"
}
},
{
"name": {
"name": "test1"
},
"value": {
"value": "10.13.6"
}
},
],
},
{
"id": 1147,
"job": {
"name": "jobname2",
},
"env_variables": [{
"name": {
"name": "secret"
},
"value": {
"value": "10.13.7"
}
},
{
"name": {
"name": "test5"
},
"value": {
"value": "10.13.6"
}
},
],
}
];
let secret = null;
body.forEach(b => {
let el = b.env_variables.find(e => e.name.name == 'secret');
if (el) { //found
secret = el.value.value;
return false; //exit forEach
}
});
console.log(secret);
You could also do something like this with Array.forEach and Array.find:
let data = [{ "id": 1146, "job": { "name": "jobname1", }, "env_variables": [{ "name": { "name": "test1" }, "value": { "value": "10.13.6" } }, { "name": { "name": "test1" }, "value": { "value": "10.13.6" } }, ], }, { "id": 1147, "job": { "name": "jobname2", }, "env_variables": [{ "name": { "name": "secret" }, "value": { "value": "10.13.7" } }, { "name": { "name": "test5" }, "value": { "value": "10.13.6" } }, ], } ]
let jobs = []
data.forEach(({id, env_variables}) => jobs.push({
build_id: id,
secret: ((env_variables.find(({name}) =>
name.name === 'secret') || {}).value || {}).value || 'N/A'
// ... other props
}))
console.log(jobs)
Assuming your result is an array, you could do something like this:
let secrets = results.reduce((result, item) => {
let secret = item["env_variables"].find((v) => {return v.name.name === "secret"})
if(secret){
result.push({id:item.id, secret: secret.value.value});
}
return result;
}, []);
This would return an array of objects like {id: 1, secret: ""} for each object in your result set that has a secret.
If you don't care whether the secret is present or not, you could modify the code slightly like this:
let secrets = results.reduce((result, item) => {
let secret = item["env_variables"].find((v) => {return v.name.name === "secret"})
result.push({id:item.id, secret: secret ? secret.value.value : ""});
return result;
}, []);
Which just leaves with you an empty string on the levels where there is no secret.
Related
How to combine JSON objects in the same response that has the same key and value with javascript? This is my data for example:
{
"data": [
{
"name": "A",
"description": {
"location": "location1",
"floor": "floor1",
},
},
{
"name": "A",
"description": {
"location": "location2",
"floor": "floor1",
},
},
{
"name": "B",
"description": {
"location": "location3",
"floor": "floor3",
},
},
]
}
And turn it into this:
{
"data": [
{
"name": "A",
"description": {
"location": ["location1","location2"],
"floor": "floor1",
},
},
{
"name": "B",
"description": {
"location": "location3",
"floor": "floor3",
},
},
]
}
Basically I am someone who is new to learning javascript. Any help would be very helpful, thank you.
You can do:
const data = {data: [{name: 'A',description: {location: 'location1',floor: 'floor1',},},{name: 'A',description: {location: 'location2',floor: 'floor1',},},{name: 'B',description: {location: 'location3',floor: 'floor3',},},],}
const result = {
data: data.data.reduce((a, { name, description }) => {
const index = a.findIndex((d) => d.name === name)
if (index >= 0) {
let location = a[index].description.location
location = Array.isArray(location) ? location : [location]
a[index].description.location = [...location, description.location]
} else {
a.push({ name, description })
}
return a
}, []),
}
console.log(result)
const list = {
"data": [
{
"name": "A",
"description": {
"location": "location1",
"floor": "floor1",
},
},
{
"name": "A",
"description": {
"location": "location2",
"floor": "floor1",
},
},
{
"name": "B",
"description": {
"location": "location3",
"floor": "floor3",
},
},
]
};
const consolidatedData = [];
for (const ele of list.data) {
const isExist = consolidatedData.find(x => x.name === ele.name);
if (!isExist) {
consolidatedData.push({
...ele
})
} else {
const objectKey = consolidatedData.findIndex(x => x.name === ele.name);
if (objectKey > -1) {
const description = consolidatedData[objectKey].description;
const newDes = ele.description;
if (newDes.location !== description.location) {
const data = consolidatedData[objectKey].description;
const added = [data.location, ele.description.location];
delete consolidatedData[objectKey].description.location
consolidatedData[objectKey].description["location"] = added
}
if (newDes.floor !== description.floor){
const data = consolidatedData[objectKey].floor;
const added = [data.floor, ele.description.floor];
delete consolidatedData[objectKey].description.floor
consolidatedData[objectKey].description["floor"] = added
}
}
}
}
console.log(JSON.stringify(consolidatedData, null, 2));
Here is a solution that uses an intermediate bucket object. The desired result object is then constructed from the bucket object:
const input = { "data": [ { "name": "A", "description": { "location": "location1", "floor": "floor1", }, }, { "name": "A", "description": { "location": "location2", "floor": "floor1", }, }, { "name": "B", "description": { "location": "location3", "floor": "floor3", }, }, ] };
let buckets = input.data.reduce((acc, obj) => {
if(!acc[obj.name]) {
acc[obj.name] = {
locations: {},
floors: {}
};
}
acc[obj.name].locations[obj.description.location] = true;
acc[obj.name].floors[obj.description.floor] = true;
return acc;
}, {});
console.log('buckets: ', buckets);
let result = {
data: Object.keys(buckets).map(name => {
let locations = Object.keys(buckets[name].locations);
let floors = Object.keys(buckets[name].floors);
return {
name: name,
description: {
location: locations.length == 1 ? locations[0] : locations,
floor: floors.length == 1 ? floors[0] : floors
}
}
})
};
console.log('result:', result);
Notes:
buckets object:
is created using an array .reduce()
array .reduce() docs: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce
locations and floors are collected using objects instead of arrays, this is to avoid duplicate names
result object:
is using Object.keys(buckets) to get the array of names
.map() transforms each name into the desired object
your unusual array or string value for location and floor is constructed with a conditional
Check for the decimal id and group them accordingly.
Below are the sample and recommended JSON's
Sample JSON
{
"results": [
{
"name": "Download",
"id": "1.1.1"
},
{
"name": "Download",
"id": "1.2"
},
{
"name": "Download",
"id": "1.3.2"
},
{
"name": "Download",
"id": "2"
},
{
"name": "Download",
"id": "2.3"
},
{
"name": "Download",
"id": "3.2"
},
{
"name": "Download",
"id": "3.5"
},
{
"name": "Download",
"id": "4.2"
}
]
}
Would like to iterate and Re-structure the above JSON into below recommended format.
Logic: Should check the id(with and without decimals) and group them based on the number.
For Example:
1, 1.1, 1.2.3, 1.4.5 => data1: [{id: 1},{id: 1.1}....]
2, 2.3, 2.3.4 => data2: [{id: 2},{id: 2.3}....]
3, 3.1 => data3: [{id: 3},{id: 3.1}]
Recommended JSON
{
"results": [
{
"data1": [
{
"name": "Download",
"id": "1.1.1"
},
{
"name": "Download",
"id": "1.2"
},
{
"name": "Download",
"id": "1.3.2"
}
]
},
{
"data2": [
{
"name": "Download",
"id": "2"
},
{
"name": "Download",
"id": "2.3"
}
]
},
{
"data3": [
{
"name": "Download",
"id": "3.2"
},
{
"name": "Download",
"id": "3.5"
}
]
},
{
"data4": [
{
"name": "Download",
"id": "4.2"
}
]
}
]
}
I have tried the below solution but it doesn't group the object
var formatedJSON = [];
results.map(function(d,i) {
formatedJSON.push({
[data+i]: d
})
});
Thanks in advance.
You can use reduce like this. The idea is to create a key-value pair for each data1, data2 etc so that values in this object are the values you need in the final array. Then use Object.values to get those as an array.
const sampleJson = {"results":[{"name":"Download","id":"1.1.1"},{"name":"Download","id":"1.2"},{"name":"Download","id":"1.3.2"},{"name":"Download","id":"2"},{"name":"Download","id":"2.3"},{"name":"Download","id":"3.2"},{"name":"Download","id":"3.5"},{"name":"Download","id":"4.2"}]}
const grouped = sampleJson.results.reduce((a, v) => {
const key = `data${parseInt(v.id)}`;
(a[key] = a[key] || {[key]: []})[key].push(v);
return a;
},{});
console.log({results: Object.values(grouped)})
One liner / Code-golf:
let s={"results":[{"name":"Download","id":"1.1.1"},{"name":"Download","id":"1.2"},{"name":"Download","id":"1.3.2"},{"name":"Download","id":"2"},{"name":"Download","id":"2.3"},{"name":"Download","id":"3.2"},{"name":"Download","id":"3.5"},{"name":"Download","id":"4.2"}]},k;
console.log({results:Object.values(s.results.reduce((a,v)=>(k=`data${parseInt(v.id)}`,(a[k] = a[k]||{[k]:[]})[k].push(v),a),{}))})
Here you go:
var data = {
"results": [
{
"name": "Download",
"id": "1.1.1"
},
{
"name": "Download",
"id": "1.2"
},
{
"name": "Download",
"id": "1.3.2"
},
{
"name": "Download",
"id": "2"
},
{
"name": "Download",
"id": "2.3"
},
{
"name": "Download",
"id": "3.2"
},
{
"name": "Download",
"id": "3.5"
},
{
"name": "Download",
"id": "4.2"
}
]
};
let newSet = new Set();
data.results.forEach(e => {
let key = e.id.substring(0, e.id.indexOf('.'));
console.log(key);
if (newSet.has(key) == false) {
newSet.add(key);
newSet[key] = [];
}
newSet[key].push(e.id);
});
console.log(newSet);
Here's how you'd do it:
var data = {
"results": [
{
"name": "Download",
"id": "1.1.1"
},
{
"name": "Download",
"id": "1.2"
},
{
"name": "Download",
"id": "1.3.2"
},
{
"name": "Download",
"id": "2"
},
{
"name": "Download",
"id": "2.3"
},
{
"name": "Download",
"id": "3.2"
},
{
"name": "Download",
"id": "3.5"
},
{
"name": "Download",
"id": "4.2"
}
]
};
var newData = {
"results": {}
};
data.results.forEach(item => {
var num = item.id.slice(0, 1);
if (newData.results["data" + num]) {
newData.results["data" + num].push(item);
} else {
newData.results["data" + num] = [item];
}
})
data = newData;
console.log(data);
What this does is it iterates through each item in results, gets the number at the front of this item's id, and checks if an array of the name data-{num} exists. If the array exists, it's pushed. If it doesn't exist, it's created with the item.
let input = getInput();
let output = input.reduce((acc, curr)=>{
let {id} = curr;
let majorVersion = 'name' + id.split('.')[0];
if(!acc[majorVersion]) acc[majorVersion]= [];
acc[majorVersion].push(curr);
return acc;
},{})
console.log(output)
function getInput(){
return [
{
"name": "Download",
"id": "1.1.1"
},
{
"name": "Download",
"id": "1.2"
},
{
"name": "Download",
"id": "1.3.2"
},
{
"name": "Download",
"id": "2"
},
{
"name": "Download",
"id": "2.3"
},
{
"name": "Download",
"id": "3.2"
},
{
"name": "Download",
"id": "3.5"
},
{
"name": "Download",
"id": "4.2"
}
]
}
One solution with RegEx for finer control as it would differentiate easily between 1 and 11.
Also this will make sure that even if the same version comes in end(say 1.9 in end) it will put it back in data1.
let newArr2 = ({ results }) =>
results.reduce((acc, item) => {
let key = "data" + /^(\d+)\.?.*/.exec(item.id)[1];
let found = acc.find(i => key in i);
found ? found[key].push(item) : acc.push({ [key]: [item] });
return acc;
}, []);
I'm facing some issue in for loop while creating an object from array of object.I have an array as this in node js app:
[
{
"Material": "113/133",
"Name": [
{
"name": "WELD1",
"value": 27520
},
{
"name": "WELD2",
"value": 676992
},
{
"name": "WELD3",
"value": 421
}
]
},
{
"Material": "150/300",
"Name": [
{
"name": "WELD1",
"value": 1441
},
{
"name": "WELD2",
"value": 555
},
{
"name": "WELD3",
"value": 100992
}
]
}
]
I want to return object like this which contains all the Material as array, Name and there value in array of object like this:
{
Material: ["113/133", "150/300"],
datasets: [
{
label: "WELD1",
data: [27520,1441]
},
{
label: "WELD2",
data: [676992,555]
},
{
label: "WELD3",
data: [100,20,0]
}
]
}
I want to get result using for loop.
you can use .reduce() and do something like this:
var arr = [
{
"Material": "113/133",
"Name": [
{
"name": "WELD1",
"value": 27520
},
{
"name": "WELD2",
"value": 676992
},
{
"name": "WELD3",
"value": 421
}
]
},
{
"Material": "150/300",
"Name": [
{
"name": "WELD1",
"value": 1441
},
{
"name": "WELD2",
"value": 555
},
{
"name": "WELD3",
"value": 100992
}
]
}
];
var newArr = arr.reduce((acc, ob) => {
for (var key in ob)
if(typeof acc[key] === 'object')
acc[key] = acc[key] ? acc[key].concat(ob[key]) : [ob[key]];
else
acc[key] ? acc[key].push(ob[key]) : acc[key] = [ob[key]];
return acc;
}, {});
console.log(newArr);
let array = [
{
"Material": "113/133",
"Name": [
{
"name": "WELD1",
"value": 27520
},
{
"name": "WELD2",
"value": 676992
},
{
"name": "WELD3",
"value": 421
}
]
},
{
"Material": "150/300",
"Name": [
{
"name": "WELD1",
"value": 1441
},
{
"name": "WELD2",
"value": 555
},
{
"name": "WELD3",
"value": 100992
}
]
}
]
let answer = {Material: [], datasets: []}
array.forEach(x => {
answer.Material.push(x.Material);
x.Name.forEach(na => {
let object = answer.datasets.find(obj => obj.label === na.name) || {label: "", data: []};
if(object.label === ""){
object.label = na.name;
object.data.push(na.value);
answer.datasets.push(object);
}else{
object.data.push(na.value)
}
});
});
console.log(answer);
The above is alternative solution using forEach instead of reduce
Use of Array.reduce to build your new data structure using data you have
const start = [{
"Material": "113/133",
"Name": [{
"name": "WELD1",
"value": 27520
},
{
"name": "WELD2",
"value": 676992
},
{
"name": "WELD3",
"value": 421
}
]
},
{
"Material": "150/300",
"Name": [{
"name": "WELD1",
"value": 1441
},
{
"name": "WELD2",
"value": 555
},
{
"name": "WELD3",
"value": 100992
}
]
}
];
const end = start.reduce((tmp, {
Material,
Name,
}) => {
// Handle the material
// If it do not exist in the array, push it
if (!tmp.Material.includes(Material)) {
tmp.Material.push(Material);
}
// Handle the datasets
// Look at each Name
Name.forEach(({
name,
value,
}) => {
// Can we find the label?
const labelFind = tmp.datasets.find(y => y.label === name);
// If we can't find the label, create a new dataset
if (!labelFind) {
tmp.datasets.push({
label: name,
data: [
value,
],
});
return;
}
// If we has found it push new value in the dataset
labelFind.data.push(value);
});
return tmp;
}, {
Material: [],
datasets: [],
});
console.log(end);
// This is the old fashioned way.
// Iterate over whole array,
// make a map, push value where 'name' is found in map
// later iterate over this map - dataMap - and form required datasets array.
var Material = [];
var dataMap = {};
arr.forEach(obj => {
Material.push(obj.Material);
obj.Name.forEach(item => {
if(dataMap[item.name]){
dataMap[item.name].push(item.value);
}
else {
dataMap[item.name] = [item.value];
}
});
});
var datasets = [];
Object.keys(dataMap).forEach(label => {
datasets.push({
label: label,
data: dataMap[label]
});
});
var result = {
Material: Material,
datasets: datasets
}
console.log(result);
I would like to fetch only specific objects from the below JSON such as only those JSON objects which have a classDefinition = "com.sap.bpm.wfs.UserTask". Please suggest on how to do this:
var metadata = {
"contents": {
"83eaead8-cfae-459b-9bdd-8b12e32d6715": {
"classDefinition": "com.sap.bpm.wfs.StartEvent",
"id": "startevent1",
"name": "StartEvent1"
},
"13583ac9-596d-4375-b9e1-e5f6f21e829f": {
"classDefinition": "com.sap.bpm.wfs.EndEvent",
"id": "endevent1",
"name": "EndEvent1"
},
"6c2b0935-444b-4299-ac8e-92973ce93558": {
"classDefinition": "com.sap.bpm.wfs.UserTask",
"subject": "Upload document",
"description": "{context.description}",
"priority": "MEDIUM",
"isHiddenInLogForParticipant": false,
"userInterface": "sapui5://html5apps/saptest/com.sap.test",
"recipientUsers": "I311520, I310811",
"id": "usertask1",
"name": "UserTask1"
},
"6728bf81-3d4e-4ae3-a428-1700a2096d34": {
"classDefinition": "com.sap.bpm.wfs.SequenceFlow",
"id": "sequenceflow1",
"name": "SequenceFlow1",
"sourceRef": "83eaead8-cfae-459b-9bdd-8b12e32d6715",
"targetRef": "6c2b0935-444b-4299-ac8e-92973ce93558"
},
"aa99931e-2523-44c3-86b3-d522acdbde10": {
"classDefinition": "com.sap.bpm.wfs.ui.Diagram",
"symbols": {
"760f0725-3400-4d48-b082-5c69ad79d697": {},
"aa9a0d10-63be-4af8-9ac2-4d2b648a18fc": {},
"7fbd11bb-cf82-4a27-97d7-e80dda2014ee": {},
"20c66c48-6058-465e-b500-d69d6e54c028": {},
"2e8f324c-5361-4512-a09a-fc7693f206ba": {}
}
}
}
};
First, metadata.contents property should rather be an array.
If you really cannot change it to an array, then use Object.keys(metadata.contents)
For example:
Object.keys(metadata.contents)
.map(x => metadata.contents[x])
.filter(x => x.classDefinition == 'com.sap.bpm.wfs.UserTask')
var metadata = {
"contents": {
"83eaead8-cfae-459b-9bdd-8b12e32d6715": {
"classDefinition": "com.sap.bpm.wfs.StartEvent",
},
"13583ac9-596d-4375-b9e1-e5f6f21e829f": {
"classDefinition": "com.sap.bpm.wfs.EndEvent",
},
"6c2b0935-444b-4299-ac8e-92973ce93558": {
"classDefinition": "com.sap.bpm.wfs.UserTask",
"subject": "Upload document",
"description": "{context.description}",
"priority": "MEDIUM",
"isHiddenInLogForParticipant": false,
"userInterface": "sapui5://html5apps/saptest/com.sap.test",
"recipientUsers": "I311520, I310811",
"id": "usertask1",
"name": "UserTask1"
},
"6728bf81-3d4e-4ae3-a428-1700a2096d34": {
"classDefinition": "com.sap.bpm.wfs.SequenceFlow",
},
"aa99931e-2523-44c3-86b3-d522acdbde10": {
"classDefinition": "com.sap.bpm.wfs.ui.Diagram",
}
}
}
var filtered = Object.keys(metadata.contents)
.map(x => metadata.contents[x])
.filter(x => x.classDefinition == 'com.sap.bpm.wfs.UserTask')
console.log(filtered)
A simple for loop can be used to get the desired fields:
var temp = [];
for (var index in metadata.contents) {
if (metadata.contents[index].classDefinition == "com.sap.bpm.wfs.UserTask") {
temp.push(metadata.contents[index]);
}
}
Or you can do one by one
var metadata = {
"contents": {
"83eaead8-cfae-459b-9bdd-8b12e32d6715": {
"classDefinition": "com.sap.bpm.wfs.StartEvent",
"id": "startevent1",
"name": "StartEvent1"
},
"13583ac9-596d-4375-b9e1-e5f6f21e829f": {
"classDefinition": "com.sap.bpm.wfs.EndEvent",
"id": "endevent1",
"name": "EndEvent1"
},
"6c2b0935-444b-4299-ac8e-92973ce93558": {
"classDefinition": "com.sap.bpm.wfs.UserTask",
"subject": "Upload document",
"description": "{context.description}",
"priority": "MEDIUM",
"isHiddenInLogForParticipant": false,
"userInterface": "sapui5://html5apps/saptest/com.sap.test",
"recipientUsers": "I311520, I310811",
"id": "usertask1",
"name": "UserTask1"
},
"6728bf81-3d4e-4ae3-a428-1700a2096d34": {
"classDefinition": "com.sap.bpm.wfs.SequenceFlow",
"id": "sequenceflow1",
"name": "SequenceFlow1",
"sourceRef": "83eaead8-cfae-459b-9bdd-8b12e32d6715",
"targetRef": "6c2b0935-444b-4299-ac8e-92973ce93558"
},
"aa99931e-2523-44c3-86b3-d522acdbde10": {
"classDefinition": "com.sap.bpm.wfs.ui.Diagram",
"symbols": {
"760f0725-3400-4d48-b082-5c69ad79d697": {},
"aa9a0d10-63be-4af8-9ac2-4d2b648a18fc": {},
"7fbd11bb-cf82-4a27-97d7-e80dda2014ee": {},
"20c66c48-6058-465e-b500-d69d6e54c028": {},
"2e8f324c-5361-4512-a09a-fc7693f206ba": {}
}
}
}
}
var content = metadata["contents"];
var subContent = content["6c2b0935-444b-4299-ac8e-92973ce93558"];
var classDef = subContent["classDefinition"];
alert(classDef);
I want to check if a value doesn't exist in the given object, by filtering an array of string.
I want to check if the values in the keys array are contained in the JSON object I'm looping. If one of the values isn't, I have to do something else, but only if the non-existent value (in resArray) is contained in the keys array.
JSON here
Here's what I tried:
var keys = [
"total_kills",
"total_deaths",
"total_planted_bombs",
"total_defused_bombs",
"total_kills_knife",
"total_kills_headshot",
"total_wins_pistolround",
"total_wins_map_de_dust2",
"last_match_wins",
"total_shots_fired",
"total_shots_hit",
"total_rounds_played",
"total_kills_taser",
"last_match_kills",
"last_match_deaths",
"total_kills_hegrenade",
];
var resArray = stats.playerstats.stats;
var statsArray = [];
for (var i = 0; i < keys.length; i++) {
for(var j = 0; j < resArray.length; j++){
//if the value in keys array exists, do something
if(resArray[j]["name"] === keys[i]){
//do something
}
if(<value doesn't exist)>)
//do something else.
}
}
Solved:
function contains(obj, key, value) {
return obj.hasOwnProperty(key) && obj[key] === value;
}
var resArray = stats.playerstats.stats;
var statsArray = [];
for (var i = 0; i < keys.length; i++) {
resArray.some(function(found){
if(contains(found, "name", keys[i])){
statsArray.push(found);
}
});
if(typeof statsArray[i] == 'undefined'){
console.log("Not present in array: " + keys[i]);
statsArray.push({"name": keys[i], "value": 'None'});
}
}
Thanks to everyone has replied to this thread.
Your example insinuates that you're creating a new array based off the stats and conditional presence of your provided keys. An easy way to build this array would be to use Array.prototype.map to enumerate over your stats array. Next, in each iteration's callback you can pass the name property as an argument to keys.indexOf to check if that particular name is present in your keys array.
var statsArray = stats.map(function(stat) {
if (keys.indexOf(stat.name) > -1) {
return stat;
} else {
return stat.name + ' not found.';
}
});
This will yield a new array which will contain either the stat object or a not regarding its absence in keys. However, you can return whatever your heart desires, as long as it's a valid array item.
Here's a working example with a small chunk of your dataset (but will work with your original dataset):
var keys = [
"total_kills",
"total_deaths",
"total_planted_bombs",
"total_defused_bombs",
"total_kills_knife",
"total_kills_headshot",
"total_wins_pistolround",
"total_wins_map_de_dust2",
"last_match_wins",
"total_shots_fired",
"total_shots_hit",
"total_rounds_played",
"total_kills_taser",
"last_match_kills",
"last_match_deaths",
"total_kills_hegrenade",
];
var stats = [{
"name": "total_kills",
"value": 25305
}, {
"name": "total_deaths",
"value": 27474
}, {
"name": "total_time_played",
"value": 1822419
}, {
"name": "total_planted_bombs",
"value": 1397
}, {
"name": "total_defused_bombs",
"value": 239
}, {
"name": "total_wins",
"value": 11477
}, {
"name": "total_damage_done",
"value": 3783962
}, {
"name": "total_money_earned",
"value": 65159500
}, {
"name": "total_rescued_hostages",
"value": 1
}, {
"name": "total_kills_knife",
"value": 278
}, {
"name": "total_kills_hegrenade",
"value": 168
}, {
"name": "total_kills_glock",
"value": 699
}, {
"name": "total_kills_deagle",
"value": 1289
}, {
"name": "total_kills_elite",
"value": 37
}, {
"name": "total_kills_fiveseven",
"value": 165
}, {
"name": "total_kills_xm1014",
"value": 78
}, {
"name": "total_kills_mac10",
"value": 154
}, {
"name": "total_kills_ump45",
"value": 330
}, {
"name": "total_kills_p90",
"value": 1105
}, {
"name": "total_kills_awp",
"value": 6934
}, {
"name": "total_kills_ak47",
"value": 4528
}, {
"name": "total_kills_aug",
"value": 137
}, {
"name": "total_kills_famas",
"value": 540
}, {
"name": "total_kills_g3sg1",
"value": 116
}, {
"name": "total_kills_m249",
"value": 50
}, {
"name": "total_kills_headshot",
"value": 7112
}, {
"name": "total_kills_enemy_weapon",
"value": 2308
}, {
"name": "total_wins_pistolround",
"value": 843
}, {
"name": "total_wins_map_cs_assault",
"value": 9
}, {
"name": "total_wins_map_cs_italy",
"value": 15
}, {
"name": "total_wins_map_cs_office",
"value": 11
}, {
"name": "total_wins_map_de_aztec",
"value": 71
}, {
"name": "total_wins_map_de_cbble",
"value": 373
}, {
"name": "total_wins_map_de_dust2",
"value": 4857
}, {
"name": "total_wins_map_de_dust",
"value": 25
}, {
"name": "total_wins_map_de_inferno",
"value": 777
}, {
"name": "total_wins_map_de_nuke",
"value": 247
}, {
"name": "total_wins_map_de_train",
"value": 47
}, {
"name": "total_weapons_donated",
"value": 2466
}, {
"name": "total_broken_windows",
"value": 30
}, {
"name": "total_kills_enemy_blinded",
"value": 566
}, {
"name": "total_kills_knife_fight",
"value": 67
}, {
"name": "total_kills_against_zoomed_sniper",
"value": 2284
}, {
"name": "total_dominations",
"value": 270
}, {
"name": "total_domination_overkills",
"value": 225
}, {
"name": "total_revenges",
"value": 207
}, {
"name": "total_shots_hit",
"value": 83704
}, {
"name": "total_shots_fired",
"value": 399207
}, {
"name": "total_rounds_played",
"value": 23419
}, {
"name": "total_shots_deagle",
"value": 12137
}, {
"name": "total_shots_glock",
"value": 21299
}, {
"name": "total_shots_elite",
"value": 777
}, {
"name": "total_shots_fiveseven",
"value": 3385
}, {
"name": "total_shots_awp",
"value": 22667
}];
var statsArray = stats.map(function(stat) {
if(keys.indexOf(stat.name) > -1) {
return stat;
} else {
return stat.name + ' not present in keys';
}
});
console.log(statsArray);
You can achieve what you want by using a combination of array functions. For example:
let stats = data.playerstats.stats;
let matches = stats.filter(i => keys.indexOf(i.name) >= 0);
let matchKeys = matches.map(k => k.name);
let negatives = keys.filter(i => matchKeys.indexOf(i) < 0);
Then you can just loop through the matches/negatives to do what you want with them.
Fiddle here.