I have the following router.use calls in one of my routers
router.use("/:collection/", (req) => {
return require(`./${req.params.collection}`);
});
and that calls in this example, example.js
example.js is as follows:
const header = require("../../header"); //gets our header that declares everything
const router = header.express.Router(); //makes our router for collections requests
console.log("123");
///The Following is when a name is requested
router.get("/test", (req, res, next) => {
console.log("test");
res.json({msg:"hi"});
next();
});
module.exports = router; //makes our router avialable
you'd expect when:
http://localhost:3000/api/example/test
is request that it would write in the console something to the effect of:
123
test
and I would get the response:
{msg:"hi"}
Instead the console gets just:
123
written and there is no response.
It seems the
router.get
in the example.js is never called, can someone tell me why?
I fixed it, instead of
router.use("/:collection/", (req) => {
return require(`./${req.params.collection}`);
});
I use
router.get("/:collection", (req, res) => {
//this is my other call that will do stuff in the parent file
//we don't call next because it is already matched, otherwise we call next
});
router.use("/:collection/", (req, res, next) =>{ //says if it gets here pass on the info
router.use("/:collection/", require(`./${req.params.collection}`)); //then route
next();
});
Related
I know that I can chain middleware functions after passing in the route like
const express = require('express');
const router = express.Router();
router.post('/', middlewareFunction1, middlewareFunction2, controllerFunction);
module.exports = router;
I would like to know if it's possible to call only one function (called gateway)
router.post('/', gatewayFunction1);
and this function is able to chain all those methods
const controller = require('../controllers/controller');
function gatewayFunction1(request, response, next) {
// validate route
// do other middleware stuff
// call controller.function1
}
module.exports = {
gatewayFunction1,
};
Why would I do that? I was thinking about separating the middleware logic from the routes. This gateway should just get executed after routing and before calling the router.
I tried to return an array of functions (example code)
function gatewayFunction1(request, response, next) {
return [(request, response, next) => {
console.log('called middleware 1');
next();
}, (request, response, next) => {
console.log('called middleware 2');
next();
}, (request, response, next) => {
response.status(200).json({
message: 'that worked',
});
}];
}
but when I call this api route I get no response
Could not get any response
so it keeps loading forever. Is there a way to chain these middleware functions within another function?
Your gatewayFunction1 does nothing except returns an array.
Just use router.
const express = require('express');
const gatewayFunction1 = express.Router();
gatewayFunction1.use(middlewareFunction1, middlewareFunction2, controllerFunction);
module.exports = gatewayFunction1;
Then
const gatewayFunction1 = require('...'); // where you define gatewayFunction1
router.post('/', gatewayFunction1);
Middleware should be a function and you are returning an array.If next function is not called it will get stuck. I don't like the whole idea combining them but I think the best way is to import all your middleware functions in one function and call them individually then use that function as your combined middleware.
I'm pretty new to node.js and express and I was wondering if there's a way to define a route that calls upon another route simply to collect data and not to completely reroute.
I've got a route set up as follows:
app.get("/databases/list", function(req, res) {
db.listDatabases().then(names => {
res.send(names);
});
});
Subsequently I'd like to have a different route, say:
app.get('/whatever', function(req, res) {
// here I'd like to make a call to retrieve the information from the first route
// then I'd like to do something with that information, I want to stay in the same route.
}
Is this possible?
Expanding #marcobiedermann answer, In your case simply make a controller and and use the FUNCTION in both the routes. You don't need to fetch anything.
/// --- Controller ----
class SimpleController {
constructor(db){
this.db = db;
}
listDatabase(/*maybe optional callback*/){
return this.db.listDatabases();//or something....
}
whatever(/*maybe optional callback*/){
return this.listDatabase()
.then(process)
}
}
/// --- Routes ----
const sController = new SimpleController(db);
app.get("/databases/list", function(req, res) {
sController.ListDatabase().then(names => {
res.send(names);
});
});
app.get('/whatever', function(req, res) {
sController.whatever()
.then(....)
}
Yes this is possible.
You have to fetch the data from your first endpoint.
fetch('/databases/list')
.then( … )
This requires the /databases/list route to be defined before your /whatever route.
However, I would strongly advice you to NOT do this.
You should abstract your logic into a controller and call this controller in both of your routes:
const fetchController = {
fetchData: () => {
return fetch('path/to/data/to/fetch')
.then( … )
// or database call or wherever you might get the data from
}
}
app.get('/databases/list', (req, res) => fetchController.fetchData());
app.get('/whatever', (req, res) => fetchController.fetchData());
app.get("/databases/list", async function(req, res) {
return await db.listDatabases();
});
app.get('/whatever', async function(req, res) {
const result = await fetch('path/databases/list');
console.log(result)
});
It might help you, But it's not recommended way. You can create method (common somewhere in the controller) and use that where ever you need.
I am trying to set up a securitycheck middleware that will run on the routes i add it to.
Middleware
function SecurityCheckHelper(req, res, next){
apiKey = req.query.apiKey;
security.securityCheck(apiKey).then(function(result) {
res.locals.Security = result.securitycheck;
console.log(res.locals.Security);
});
return next(); // go to routes
};
Route
app.get('/settings', SecurityCheckHelper,function(req, res, next) {
console.log(res.locals);
});
Its relatively straight forward I'm trying to pass result.securitycheck (which return true/false) into the /settings route. However res.locals is returning an empty object
Your calling next before you have run your securityCheck.
IOW: the next middleware is getting processed before you securityCheck has finished processing. securityCheck is async,.
Placing your next inside your then, will wait until the securityCheck has finished.
eg.
function SecurityCheckHelper(req, res, next){
apiKey = req.query.apiKey;
security.securityCheck(apiKey).then(function(result) {
res.locals.Security = result.securitycheck;
console.log(res.locals.Security);
next();
});
};
You need to interface security check promise with the callback.
function SecurityCheckHelper(req, res, next){
apiKey = req.query.apiKey;
security.securityCheck(apiKey)
.then(function(result) {
res.locals.Security = result.securitycheck;
console.log(res.locals.Security);
return next();
})
.catch(err => next(err));
};
I have an ExpressJS routing for my API and I want to call it from within NodeJS
var api = require('./routes/api')
app.use('/api', api);
and inside my ./routes/api.js file
var express = require('express');
var router = express.Router();
router.use('/update', require('./update'));
module.exports = router;
so if I want to call /api/update/something/:withParam from my front end its all find, but I need to call this from within another aspect of my NodeJS script without having to redefine the whole function again in 2nd location
I have tried using the HTTP module from inside but I just get a "ECONNREFUSED" error
http.get('/api/update/something/:withParam', function(res) {
console.log("Got response: " + res.statusCode);
res.resume();
}).on('error', function(e) {
console.log("Got error: " + e.message);
});
I understand the idea behind Express is to create routes, but how do I internally call them
The 'usual' or 'correct' way to handle this would be to have the function you want to call broken out by itself, detached from any route definitions. Perhaps in its own module, but not necessarily. Then just call it wherever you need it. Like so:
function updateSomething(thing) {
return myDb.save(thing);
}
// elsewhere:
router.put('/api/update/something/:withParam', function(req, res) {
updateSomething(req.params.withParam)
.then(function() { res.send(200, 'ok'); });
});
// another place:
function someOtherFunction() {
// other code...
updateSomething(...);
// ..
}
This is an easy way to do an internal redirect in Express 4:
The function that magic can do is: app._router.handle()
Testing: We make a request to home "/" and redirect it to otherPath "/other/path"
var app = express()
function otherPath(req, res, next) {
return res.send('ok')
}
function home(req, res, next) {
req.url = '/other/path'
/* Uncomment the next line if you want to change the method */
// req.method = 'POST'
return app._router.handle(req, res, next)
}
app.get('/other/path', otherPath)
app.get('/', home)
I've made a dedicated middleware for this : uest.
Available within req it allows you to req.uest another route (from a given route).
It forwards original cookies to subsequent requests, and keeps req.session in sync across requests, for ex:
app.post('/login', async (req, res, next) => {
const {username, password} = req.body
const {body: session} = await req.uest({
method: 'POST',
url: '/api/sessions',
body: {username, password}
}).catch(next)
console.log(`Welcome back ${session.user.firstname}!`
res.redirect('/profile')
})
It supports Promise, await and error-first callback.
See the README for more details
Separate your app and server files with the app being imported into the server file.
In the place you want to call your app internally, you can import you app as well as 'request' from 'supertest'. Then you can write
request(app).post('/someroute').send({
id: 'ecf8d501-5abe-46a9-984e-e081ac925def',
etc....
});`
This is another way.
const app = require('express')()
const axios = require('axios')
const log = console.log
const PORT = 3000
const URL = 'http://localhost:' + PORT
const apiPath = (path) => URL + path
app.get('/a', (req, res) => {
res.json('yoy')
})
app.get('/b', async (req, res) => {
let a = await axios.get(apiPath('/a'))
res.json(a.data)
})
app.listen(PORT)
I'm new to Express and trying to use middleware to handle a POST request. If I expose the endpoint, and make a request to the API, everything works fine.
Working Correctly
api/index.js
app.post('/api/endpoint', (req, res, next) => {
next();
});
server.js
app.use(function() {
console.log('hello'); // => hello
});
But when I try to replace the middleware function with a module that exports a function, the function never gets invoked.
Not Working
api/index.js
app.post('/api/endpoint', (req, res, next) => {
next();
});
server.js
const makeExternalRequest = require('./server/makeExternalRequest');
...
console.log(makeExternalRequest, typeof makeExternalRequest);
// => [Function] 'function'
app.use(makeExternalRequest);
server/makeExternalRequest.js
module.exports = function(err, req, res, next) {
console.log('hello', err);
}
The function in server/makeExternalRequest.js is never invoked, and nothing logs... Am I using app.use(...) incorrectly?
Express middleware requires three arguments, the third of which is a function you call when you're done to move the request along to the next handler:
module.exports = function (req, res, next) {
console.log('hello');
next();
};
Without calling the third parameter, your request will just remain pending and a response will never be sent. Also, be sure you call app.use before any handler that would return the response. If the response is sent first, then your middleware will never be reached.