about $.get() callback function argument - javascript

When I use Ajax for asynchronous communication, I may use the $.get() method, which is often used in callback functions as follows:
$.get('http://example.com', function(result) {
console.log(result);
})
I just wonder about 'result' parameter.
Where did that parameter that says 'result' come from?
It doesn't matter if I put any name in it, so I can't put a second or third argument in that function? If it can be put in, how should it be handled?

When you define a function, you can give the parameters any name you like (so long as they are valid identifiers):
function foo(a, b, c) { }
When the function is called, the arguments are passed to those parameters in order:
foo(1, 2, 3);
It is exactly the same for:
function(result) {
console.log(result);
}
The only difference is that the function is called by code written by someone else (which is part of the jQuery library).
The documentation tells you what arguments are passed:
success Type: Function( PlainObject data, String textStatus, jqXHR jqXHR ) A callback function that is executed
if the request succeeds. Required if dataType is provided, but you can
use null or jQuery.noop as a placeholder.

The callback will be invoked when the query is succeeded, then jQuery will pass the data to the first argument, and the following arguments is textStatus and jqXHR. For more you can check the documentation here: https://api.jquery.com/jQuery.get/

Related

How does javascript function call work?

I have this piece of code below:
It makes a GET call to an URL, gets some object, and appends an image to an HTML tag.
function getDataFromApi(searchTerm, callback) {
const URL1 = `some url`;
const design = {
url: URL1,
data: {
"dog breed name": searchTerm
},
type: 'GET',
success: callback
};
$.ajax(design);
}
function displaySearchData(data) {
const allResultsLength = data.message.length;
const ranNum = Math.floor(Math.random() * allResultsLength);
const dogResults = data.message[ranNum];
$(`.js-search-results`).html(`<img src = ${dogResults}>`);
}
function watchSubmit() {
$('.js-search-form').submit(event => {
event.preventDefault();
let queryTarget = $(event.currentTarget).find('.js-query');
let query = queryTarget.val();
queryTarget.val("");
getDataFromApi(query, displaySearchData);
});
}
$(watchSubmit);
I get the getDataFromApi and watchSubmit but getDataFromApi(query, displaySearchData); isn't intuitive to me at all.
I've been writing Java, and it doesn't make sense to me how displaySearchData is getting called without the parameter - it seems that line should be getDataFromApi(query, displaySearchData(data));.
Can someone please explain how this is getting compiled & executed (basically how this is a legitimate syntax) in javascript?
Somewhere in the good'ol jquery, there lies this piece of code:
$.ajax = function(config){
...
// get the response from XHR request,
// and save it in, say, 'response'
...
// now check, if the response is OK 200
// and if so, execute next line
// which is basically - calling your displaySearchData method
config.success(response);
...
}
now, config is your design object, which has a property success which carries the reference to your displaySearchData method.
The data argument of method displaySearchData will now carry the reference to variable response passed in the method invocation config.success(response).
EDIT: the argument callback also carries forward the reference of the method displaySearchData to getDataFromApi
Concept to be noted:
functions can be passed in Javascript as arguments to another function, in which case we only need the referring variable to be passed as argument. Invocation parentheses () are not required.
function A(data){...};
function b(referenceToFunctionA){
...
referenceToFunctionA(someData);
...
};
// correct
b(A);
// wrong, because adding () after any function reference variable
// invokes the method immediately.
// in this particular case the returned value of the method A
// is passed as argument instead of the reference to method A itself.
b(A());
Welcome to JavaScript My Friend. Get ready to experience more magical weirdness as you continue to work on JS. Good luck.
What you need to look at is in the function getDataFromApi().
In that function, you have a "callback" parameter. This parameter is later added into $.ajax. This is a jQuery function that will provide some callback when a certain condition is matched (like before sending a request, when the response has been received,...). This $.ajax callback provide you with 3 parameters, one of them is data (which are being used, textStatus, and jqXHR. Usually, you only need to pay attention to the data since it contains the response from where you are requesting data.
So when the $.ajax success, the "callback" function will be called, which is the displaySearchData. And since $.ajax callback provides you with the data parameter, you can add them to the parameters of displaySearchData. Do note that you can add the extra 2 provided parameters if needed.
You can have a look at that function here: jQuery Ajax

Understanding callback function parameters

I've been trying to understand callback functions and I'm unsure where the data variable/object is actually coming from in this example:
$.get( "ajax/test.html", function( data ) {
console.log(data);
});
I think of this function being defined as something like this:
$.get = function(url, callback) {
// send request to url
callback(data); // execute callback function... but where is data coming from/being defined?
};
I've been trying to understand callback functions and I'm unsure where
the data variable/object is actually coming from in this example:
you invoked jquery function $.get() and gave a handle to your anonymous function as a parameter. jquery did all the work on invoking ajax methods, getting the response (data) and finally invoke your anonymous function (which you passed on to it as parameter). data variable is then passed on to this anonymous function by the same jquery function.

Passing parameters to a function in Ajax

I'm following a tutorial on using Ajax with JavaScript, and this was the code we're making:
$('document').ready(function(){
$.ajax({
url: "AwesomeText.html",
type: "GET",
datatype: "Html"
})
.done(Success)
});
function Success(result){
$("p").append(result);
}
I got how it worked but there is one thing that confused me. We made a Success function to append the requested HTML file to the paragraph in the page, and then we passed a parameter called result, so from what I understand I can name the parameter anything and pass it as an argument and it will work. I took out success and passed in x as an argument and it still worked..
so my question is how does JQuery know it should store the requested HTML document in this parameter we're creating in this function? what if I have other functions will Jquery store the requested file to every function in it's parameter? I don't get how JQuery knows.
Also, there is a .done function in there, is that the same function that's explained here:
https://api.jquery.com/deferred.done/
why is it called deferred?
Default .done() callbacks will have 3 arguments passed through so based on your need you can use any of them in your success function with your own name.
three arguments passed are data, textStatus ,jqXHR
so your success function's first argument would be the response of the ajax call,i.e data recieved from the server,
second argument would be the status and third argument would the the jqueryXmlHttpRequest object.
based on your need you can access these objects in the same order
When you pass url to ajax it basically fetches that url and returns whatever it got at that url, AwesomeText.html in your case
and then it sends the content of that url to success function as a first parameter
Documentation
success = Type: Function( Anything data, String textStatus, jqXHR jqXHR
)
deferred .done(fn) method makes calling some method after the method on which .done was called [You can say Promise ] which makes synchronous calls
You can check following question for understanding the promises and .done() method
jQuery deferreds and promises - .then() vs .done()
The .done method accepts a "success" function as input.
Success: Function( Anything data, String textStatus, jqXHR jqXHR )
A function to be called if the request succeeds. The function gets
passed three arguments: The data returned from the server, formatted
according to the dataType parameter or the dataFilter callback
function, if specified; a string describing the status; and the jqXHR
(in jQuery 1.4.x, XMLHttpRequest) object. As of jQuery 1.5, the
success setting can accept an array of functions. Each function will
be called in turn.
So, the first argument (call it whatever - data / result / x / etc) will contain the reply of the server.
Source: http://api.jquery.com/jquery.ajax/

Assigning arguments to function parameters

I have edited this question to clarify that this question does not relate to how to return a value from an ajax function call. It is asking why, when only 2 arguments are passed to $getJSON, the 2nd argument appears to be treated as though it were the 3ed. Having said that, please consider the following snippet of code:
<script>
var fName;
$.getJSON("work1.json", json);
function json(data)
{
fName = data['fname'];
}
</script>
Note that the $.getJASON function (which has one mandatory and 2 optional parameters) is given only 2 arguments. The first parameter is the mandatory "url" parameter. It is my understanding that the 2nd parameter is for data sent to the server and the 3ed parameter specifies the function to run if the request succeeds. Since only 2 arguments are passed, I would think that they would be for the 1st and 2nd parameters respectively. The first one is clearly the url. The 2nd one is behaving as though it were the 3ed parameter. Why is that? I thought that arguments passed to a function were assigned to the function's parameters in sequential order until exhausted. What am I missing?
I thought that arguments passed to a function were assigned to the function's parameters in sequential order until exhausted.
Yes, they are. However, jQuery checks whether the second argument is a function, and uses that as the callback in case
getJSON: function( url, data, callback ) {
return jQuery.get( url, data, callback, "json" );
},
get: function( url, data, callback, type ) {
// Shift arguments if data argument was omitted
if ( jQuery.isFunction( data ) ) {
type = type || callback;
callback = data;
data = undefined;
}
return jQuery.ajax({
url: url,
type: method,
dataType: type,
data: data,
success: callback
});
}
(from https://github.com/jquery/jquery/blob/master/src/ajax.js#L766)

Explaining jQuery AJAX Success Method

Im trying to use this jQuery script and this is confusing me:
function CallService()
{
$.ajax({
type : varType, //GET or POST or PUT or DELETE verb
url : varUrl, // Location of the service
data : varData, //Data sent to server
contentType : varContentType, // content type sent to server
dataType : varDataType, //Expected data format from server
processdata : varProcessData, //True or False
success : function(msg) {//On Successfull service call
ServiceSucceeded(msg);
},
error: ServiceFailed// When Service call fails
});
}
The bit im confused about is the sucess object. The jQuery documentation says:
success(data, textStatus, jqXHR)Function, Array
A function to be called if the request succeeds. The function gets passed three arguments: The data returned from the server, formatted according to the dataType parameter; a string describing the status; and the jqXHR (in jQuery 1.4.x, XMLHttpRequest) object. As of jQuery 1.5, the success setting can accept an array of functions. Each function will be called in turn. This is an Ajax Event.
But this method signature looks nothing like the:
success : function(msg) {//On Successfull service call
ServiceSucceeded(msg);
}
Object that we seem to be passing in.
Questions:
1) What does function(msg){ServiceSucceeded(msg)} mean?
2) What is 'msg' in this context?
3) How on earth am I meant to know how to structure the method sugnature for sucess?
Perfectly reasonable question. :-) In JavaScript, you don't necessarily have to call a function with as many args as it defines, and you don't have to define as many args as you may get called with. Which can be confusing if you're used to more constrained environments. :-)
Answering specifics:
1) What does function(msg){ServiceSucceeded(msg)} mean?
It defines a function (an anonymous one) that accepts one named argument (msg) and calls ServiceSucceded passing in that arg. jQuery will call the function with the three arguments defined by the jQuery documentation for the success function, but this particular success function is only using the first of those (data). More about named functions vs. anonymous functions here.
2) What is 'msg' in this context?
The first argument to the function. jQuery's docs call this first argument data, but you can call it whatever you like.
3) How on earth am I meant to know how to structure the method sugnature for sucess?
You did the right thing, it's in the jQuery documentation.
This thing about function arguments can be confusing, so let's do some examples:
function foo(arg) {
alert(arg);
}
That's perfectly clear, I'm defining a function called foo that takes a single named argument, arg. And thus:
foo("Hi there"); // alerts "Hi there"
But I can also do this:
foo(); // alerts "undefined"
There, I didn't give any arguments for foo, and so within foo, arg is undefined.
I can also do this:
foo("Hi there", "again"); // alerts "Hi there"
I'm calling foo with two arguments, but foo only makes use of one of them.
I could define foo to use as many arguments as you pass in:
function foo() {
var index;
for (index = 0; index < arguments.length; ++index) {
alert(arguments[index]);
}
}
arguments is an automatic thing all functions have, which is a pseudo-array (it's not really an Array) of the actual arguments the function was called with. And so:
foo("Hi there", "again"); // alerts "Hi there", and then alerts "again"
You can even mix named and unnamed arguments:
function foo(arg) {
var index;
alert(arg);
for (index = 1; index < arguments.length; ++index) {
alert("[" + arguments[index] + "]");
}
}
So now
foo("Hi there", "again"); // alerts "Hi there" and then alerts "[again]"
Note the [] around the second alert, because I started looping with index 1 rather than zero.
arguments and named args are connected:
function foo(arg) {
alert("arg = " + arg);
alert("arguments[0] = " + arguments[0]);
arg = "Updated";
alert("arg = " + arg);
alert("arguments[0] = " + arguments[0]);
}
If I do foo("Hi");, that shows these alerts:
arg = Hi
arguments[0] = Hi
arg = Updated
arguments[0] = Updated
(It goes the other way, too, if you update arguments[0].)
The function is passed 3 parameters: data, status, and the jqXHR object. data is what is returned from the AJAX call, status is the HTTP status code (I think), and jqXHR is a jQuery wrapped XHR object.
In this script, they only care about the data parameter, and not the other two.
So using success: function(msg), they only get the data parameter. The other two are sent, but ignored.
ServiceSucceeded is just a function that is being called with the data parameter sent to it.
success: ServiceSucceeded could have also worked here.
It means the success handler invokes ServiceSucceeded with the response of the request.
msg contains the response from the request. msg maps to data in the jQuery documentation.
You need to look into the jQuery documentation for finding the signature.
This is an anonymous function.
It's like a regular function, but without a name.
msg is the function's first parameter.
By reading the documentation.
jquery Ajax is a way for you to communicate with the server (PHP, ASP, whatever). Let's assume you use PHP. the function "callService()" send a request to "varUrl" (validation.php, i.e) and get (or POST -> varType) the content (varContentType -> valdation.php?id=1231&whatever=soemthing). The purpose of this is to get some server side data without reloading the page. If you want the validation.php to echo some html, then the dataType in the Ajax function must be "html". See jquery.com for more info on dataType.
The success parameter is a function handler for the server response. Success is called if you get a response from the server corresponding to the dataType you asked (html, json, text, whatever). In that perticular case, if the server respond correctly, the function "ServiceSucceeded" is called with the attribute "msg" which is the server response you asked for.
1) That function is called if the AJAX request is successful i.e. a success status code is returned by the server being contacted.
2) I would assume that 'msg' is the data returned from the server. The other two arguments are not supplied and therefore not used.
3) Use the Jquery documentation, and fiddle around until you get what you want.
Even though the success function is defined as taking three parameters (as per the documentation you quoted), those three parameters are not mandatory - Javascript is very forgiving about this sort of thing; if you miss a parameter from a function call, it simply gets set to underfined, so as long as you don't try to use it, JS won't throw any errors.
The code you've provided only gives one parameter - msg - but in JS, this is perfectly valid; it just means that msg will be the data parameter defined in the docs, and textStatus and jqXHR will be undefined.
This is fine, as long as in your success function you don't actually want to use either of those parameters. If you want to use them, then pass them, but if not, it's fine to drop them. You're writing the success function, so you get to decide which of the three parameters to use.

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