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How to display values in JS from a PHP array that was posted from jQuery

I have a button called rename that when pushed, executes in jQuery a rename.php file. Inside that php file the program selects data from a mysql, creates an array with that data, and processes an array in to json_encode($array);. How can I then get that json encoded array and echo it out into javascript?
I'm trying to echo the array out so that javascript displays my images src's.
This is my second line of ajax so I just wrote the javascript out as if it were php because I'm not sure of the commands or structure in js.
$.ajax
(
{
url:"test4.php",
type: "GET",
data: $('form').serialize(),
success:function(result)
{
/*alert(result);*/
document.getElementById("images_to_rename").innerHTML = foreach(jArray as array_values)
{
"<img src=\""array_values['original_path']"/"array_values['media']"/>";
}
}
}
);
and my jQuery php file:
<?php
include 'db/mysqli_connect.php';
$username = "slick";
if(empty($_GET['image_name']))
{
echo '<div class="refto" id="refto">image_name is empty</div>';
}
else
{
echo '<div class="refto" id="refto">image_name is not empty</div>';
foreach($_GET['image_name'] as $rowid_rename)
{
//echo '<br><p class="colourful">rowid_refto: '.$rowid_refto.'</p><br>';
$active = 1;
$command = "Rename";
$stmt = $mysqli->prepare("UPDATE ".$username." SET active=?, command=? WHERE rowid=?");
$stmt->bind_param("isi", $active, $command, $rowid_rename);
$stmt->execute();
$stmt->close();
}
//go to database, get parameters of sort
$command = "Rename";
$active = 1;
$stmt = $mysqli->prepare("SELECT original_path, media FROM " . $username . " WHERE active=? and command=?");
$stmt->bind_param("is", $active, $command);
$stmt->execute();
$result = $stmt->get_result();
while($row = $result->fetch_assoc())
{
$arri[] = $row;
}
foreach($arri as $rows) //put them into workable variables
{
$rowt = $rows['original_path'];
$rowy = $rows['media'];
//echo 'rows[\'original_path\'] = '.$rows['original_path'].''.$rows['media'].'';
}
$stmt->close();
echo json_encode($arri);
?>
<script type="text/javascript">
var jArray= <?php echo json_encode($arri); ?>;
</script>
<?php
}
echo "something2";
?>
My PHP file is a jQuery url:"test4.php", type: "GET", and is not the main file. The main file is called main.php and the test4.php is something that's called in jQuery when the user clicks on rename.
Somebody suggested console log so here's what chrome says:
<div class="refto" id="refto">image_name is not empty</div>[{"original_path":"Downloads","media":"shorter.jpg"},{"original_path":"Album 2","media":"balls.jpg"}] <script type="text/javascript">
var jArray= [{"original_path":"Downloads","media":"shorter.jpg"},{"original_path":"Album 2","media":"balls.jpg"}];
</script>
something2

Your ajax php file isn't render in browser, then the variable jArray is undefined. With your case, let return php file to json and you can get it as variable in result.
<?php
include 'db/mysqli_connect.php';
$username = "slick";
if (empty($_GET['image_name'])) {
//echo '<div class="refto" id="refto">image_name is empty</div>';
} else {
//echo '<div class="refto" id="refto">image_name is not empty</div>';
foreach ($_GET['image_name'] as $rowid_rename) {
//echo '<br><p class="colourful">rowid_refto: '.$rowid_refto.'</p><br>';
$active = 1;
$command = "Rename";
$stmt = $mysqli->prepare("UPDATE " . $username . " SET active=?, command=? WHERE rowid=?");
$stmt->bind_param("isi", $active, $command, $rowid_rename);
$stmt->execute();
$stmt->close();
}
//go to database, get parameters of sort
$command = "Rename";
$active = 1;
$stmt = $mysqli->prepare("SELECT original_path, media FROM " . $username . " WHERE active=? and command=?");
$stmt->bind_param("is", $active, $command);
$stmt->execute();
$result = $stmt->get_result();
while ($row = $result->fetch_assoc()) {
$arri[] = $row;
}
foreach ($arri as $rows) { //put them into workable variables
$rowt = $rows['original_path'];
$rowy = $rows['media'];
//echo 'rows[\'original_path\'] = '.$rows['original_path'].''.$rows['media'].'';
}
$stmt->close();
echo json_encode($arri);
//stop render here
die();
}
?>
php file need return only json string. Then we'll get result as json variable in javascript.
And Js:
$.ajax
(
{
url:"test4.php",
type: "GET",
data: $('form').serialize(),
success:function(result)
{
var jArray = JSON.parse(result);
/*alert(result);*/
var txt = "";
jArray.forEach(function(array_values){
txt += `<img src=\""array_values.original_path."/"array_values.media"/>`;
})
document.getElementById("images_to_rename").innerHTML = txt;
}
}
);

load JSON data attributes from external php page

Hi I try to load a JSON data from a php link in a js file whith this
$.getJSON('link to rempl.php', function(data) {
cn =data.nom;
});
this is the code of rempl.php
<?php
header('Content-Type: text/plain; charset=utf-8');
require_once ('connectDB.php');
if ($_POST['nom']== 0){
header("Location: http://localhost/geopp/editer.php");
}else{
$id = $_POST['nom'];
}
$sql = "SELECT id , id_archi , nom , archithect , adresse , date_construction , dateconst , resume FROM patri where id=".$id.";";
$req = mysqli_query ($link,$sql);
$feature = array();
//echo "lon\tlat\ttitle\tdescription\ticon";
while ($row = mysqli_fetch_assoc($req)) {
$res['id_archi'] = $row['id_archi'];
$res['id'] = $row['id'];
$res['date'] = $row['dateconst'];
$res['nom'] = $row['nom'];
$res['archithect'] = $row['archithect'];
$res['adresse'] = $row['adresse'];
$res['date_construction'] = $row['date_construction'];
$res['resume'] = $row['resume'];
$feature[] = json_encode($res);
}
echo implode(', ',$feature);
header("Location: http://localhost/geopp/empl.php");
?>
but when I alert the variable cn it show me undefined and thanks for helping me.

Having trouble in sending the results from pdo to ajax

I want to do is if the user successfully registered the pdo will provide an information and send it to ajax and the ajax will message if the user is registered or not. It was working properly after i put this condition in my pdo and now it wont insert no more and ajax tells "error registering user!" all the time.
script:
<script type="text/javascript">
$(document).ready(function() {
$('#submit').click(function (e) {
e.preventDefault();
var data = {};
data.name = $('#name').val();
data.age = $('#age').val();
data.gender = $('#gender').val();
data.address = $('#address').val();
data.image = $('#imgInp').val();
$.ajax({
type: "POST",
url: "user.php",
data: data,
cache: false,
success: function (response) {
if (Number(response) == 1)
{
alert("User successfully registered");
}
else
{
alert("Error registering user!");
}
}
});
return false;
});
});
</script>
user.php:
<?php
$host = "localhost";
$user = "root";
$pass = "";
$db = "test";
$dbc = new PDO("mysql:host=" . $host . ";dbname=" . $db, $user, $pass);
$dbc->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$name = #$_POST['name'];
$age = #$_POST['age'];
$address = #$_POST['address'];
$gender = #$_POST['gender'];
$imageName = #$_FILES['image']['name'];
$q = "INSERT INTO students(name, age, address, gender, imageName ) VALUES(:name, :age, :address, :gender, :image)";
$query = $dbc->prepare($q);
$query->bindParam(':name', $name);
$query->bindParam(':age', $age);
$query->bindParam(':address', $address);
$query->bindParam(':gender', $gender);
$query->bindParam(':image', $imageName);
$results = $query->execute();
$results ? echo "1"; : echo "2"; ;
?>

It seems that you have error in :
$results ? echo "1"; : echo "2"; ;
yours demo
try like this :
echo $results ? "1" : "2";
working demo
you can see here a tutorial.

How to properly load one ajax request after another

I am creating a messaging system for a website that I am making. Basically, it consists of clicking one button and two Ajax Requests afterwards. I am not even sure I am going about this the right way. On click of the button the first Ajax starts to call. The first ajax request loads a file that loads the style of the messages and retrieves them from a database. The problem I am having is that the first request sometimes takes to long to finish and the other request does not get complete. Another problem I am having is that if I put an "animation delay" type thing on it then it will look like the page it running slow. You can run an example at "http://www.linkmesocial.com/linkme.php?activeTab=mes" you must type or copy and past the whole length for it to work otherwise you will redirect to the login page. Any advice would be AWESOME! If there is some easier way to set up a messaging system please feel free to give me some advice or direct me to a tutorial. THANK YOU SO MUCH!
I would also like the know if this is a good practice. Please :)
My Original file. On click of class "mes_tab" a form is submitted. also the function mes_main() is called.
session_start();
$username = $_SESSION['user'];
$messages = mysqli_query($con, "SELECT * FROM messages WHERE recipient='$username'");
echo "<div id=\"mes_main-bar_top\" class=\"center\">Messages</div>";
echo "<div id=\"mes_main\">";
echo "<table id=\"mes_main-allView\" class=\"left\">";
echo "<td class=\"mes_tab-change\" >^</td>";
$from=array("","","", "", "", "", "", "");
for ($msgCount = 0; $msgCount < 8; $msgCount++){
$row = mysqli_fetch_array($messages);
$from[$msgCount] = $row['sender'];
for ($prev = 0; $prev < $msgCount; $prev++)
{
if ($from[$msgCount] == $from[$prev] )
{
$cont = true;
break;
}
}
if ($cont)
{
$cont = false;
continue;
}
if ($row['message'] == ""){
break;
}
echo "<tr><td class=\"mes_tab\" onclick=\"mes_main('" . $row['sender'] . "')\">";
echo "<h3 class=\"center\">" . $row['sender'] . "</h3>";
echo "<form id=\"" . $row['sender'] . "\" >";
echo "<input name=\"sender\" value=\"" . $row['sender'] . "\" hidden/>";
echo "<input name=\"id\" value=\"" . $row['id'] . "\" hidden/>";
echo "</form>";
echo "</td></tr>";
}
if ($msgCount == 8)
{
echo "<td id=\"mes_tab-change_bottom\" class=\"mes_tab-change\">V</td>";
}
echo "</table> <!-- end mes_main-allView -->";
echo "<div id=\"mes_main-mesView\" class=\"right\">";
echo "</div> <!-- end mes_main-mesView -->";
echo "</div> <!-- end mes_main -->";
mes_main() function from above. The two ajax functions inside are what I am referring to in the post above.
function mes_main(x)
{
var sender = x;
$( sender ).submit(function( event ) {
event.preventDefault();
});
ajax_req_mes("scripts/home/php/mes_load.php?" + sender , "mes_main-mesView");
ajax_req_mes("scripts/home/php/mes_content.php?" + sender ,"mes_content");
}
mes_load.php
the $sender var is created by passing the sender username through the URL. That is why I do php explode on the url.
session_start();
$username = $_SESSION['user'];
$url = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$sender = explode('?', $url);
$recieved = mysqli_query($con, "SELECT * FROM messages WHERE recipient='$username' AND sender='$sender[1]'");
$sent = mysqli_query($con, "SELECT * FROM messages WHERE recipient='$sender[1]' AND sender='$username'");
echo "<div id=\"mes_content\"></div>";
echo "<div id=\"mes_field\" class=\"right\"></div>";
mes_content.php
session_start();
$username = $_SESSION['user'];
$url = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$sender = explode('?', $url);
$recieved = mysqli_query($con, "SELECT * FROM messages WHERE recipient='$username' AND sender='$sender[1]'");
$sent = mysqli_query($con, "SELECT * FROM messages WHERE recipient='$sender[1]' AND sender='$username'");
echo "<table id=\"mesView-table\">";
$REC = array();
$SENT = array();
$ID = array();
for ($i = 0; $i < 25; $i++)
{
$rec = mysqli_fetch_array($recieved);
$sent = mysqli_fetch_array($sent);
if ($rec['id'] > 0)
{
$REC[$i] = $rec['id'];
}
if ($sent['id'] > 0)
{
$SENT[$i] = $sent['id'];
}
}
$ID = array_merge($SENT, $REC);
sort($ID);
for ($x = 0; $x < count($ID); $x++)
{
$key = $ID[$x];
$result = mysqli_query($con, "SELECT * FROM messages WHERE id = '$key'");
$res = mysqli_fetch_array($result);
if (in_array($key, $REC))
{
echo "<tr><td class='mes_recieved'>";
echo $res['message'];
echo "</tr></td>";
}
elseif (in_array($key, $SENT))
{
echo "<tr><td class='mes_sent'>";
echo $res['message'];
echo "</tr></td>";
}
}
echo "</table>";

Set async to false in your ajax requests!That's how the second one will wait for completing the first one and then start.
Also you can catch the on success and on error for the purposes you have.

Just use the "success" and "error" callbacks.
Also you could use the "done" callback
But, IMO, for that kind of problem I think a better alternative would be using Websockets
EDIT:
Here is some example of how you could do it:
jQuery.ajax({
type : "POST",
data : {msg:"your message"}
url : "http://fu.com/myfile.php",
success: function(response){
//Do something with your response
}
}).done(secondCall());
function secondCall(){
jQuery.ajax({
type : "POST",
data : {data:"data"}
url : "http://fu.com/myfile.php",
success: function(response){
//Do something with your response
}
});
}
EDIT2:
For visibility, here is a tutorial using websockets: http://www.sanwebe.com/2013/05/chat-using-websocket-php-socket

Fetch multiple data from a php file using AJAX and insert them in different input fields

I am using AJAX in order to access data from a php file.
I have problem with the format of retrieved data from database, please help.
So, this is my ajax function splice. It retrieves data from find_account.php
function processReqChange() {
// only if req shows "loaded"
if (req.readyState == 4) {
// only if "OK"
if (req.status == 200) {
form_prof.prof_id.value = req.responseText;
form_prof.prof_name.value = req.responseText;
form_prof.prof_username.value = req.responseText;
form_prof.prof_password.value = req.responseText;
}
else {
alert("Problem in retrieving the XML data:\n" + req.statusText);
}
}
}
find_account.php
<?php
include("connect.php");
session_start();
$account = $_GET['account'];
$query = "SELECT * FROM profs WHERE profs_name = '".$account."'";
$result = mysql_query($query);
$num = mysql_num_rows($result);
if(empty($num))
{
echo 'DATA NOT FOUND';
}
else
{
$arr = mysql_fetch_array($result);
$id = $arr['profs_number'];
$name = $arr['profs_name'];
$username = $arr['profs_username'];
$password = $arr['profs_password'];
}
header("Content-type: text/plain");
echo $id;
echo $name;
echo $username;
echo $password;
?>
and I have 4 input boxes in my HTML from where the req.responseText puts the value
and everytime I search the name in the input field for example:
Search: [ Dorothy Perkins ]
The output goes like [id,name,username,password]:
[20111Dorothy Perkinsdperkins#mail.com123456] [same with 1st field] [same] [same]
Wherein I want it to be like...
[20111] [Dorothy Pekins] [dperkins#mail.com] [123456]
Where [ ] are input fields.
Please help me arrange my format, I am so confused. I am new to this.

You can encode return values in json before sending back.
In PHP
<?php
include("connect.php");
session_start();
$account = $_GET['account'];
$query = "SELECT * FROM profs WHERE profs_name = '".$account."'";
$result = mysql_query($query);
$num = mysql_num_rows($result);
if(empty($num))
{
$returnValues = 'DATA NOT FOUND';
}
else
{
$arr = mysql_fetch_array($result);
$returnValues = json_encode($arr);
}
echo $returnValues;
?>
In Javascript
function processReqChange() {
// only if req shows "loaded"
if (req.readyState == 4) {
// only if "OK"
if (req.status == 200) {
req = JSON.parse(reg);
form_prof.prof_id.value = req.id;
form_prof.prof_name.value = req.name;
form_prof.prof_username.value = req.username;
form_prof.prof_password.value = req.password;
}
else {
alert("Problem in retrieving the XML data:\n" + req.statusText);
}
}
}

You have to write the data in some format from your PHP code (XML, json, or simply separate the values with a comma), and parse it from your javascript.
For example, in PHP:
echo $id . "," . $name . "," . $username . "," . $password;
And then in the javascript:
values = req.responseText.split(",");
form_prof.prof_id.value = values[0]
form_prof.prof_name.value = values[1];
form_prof.prof_username.value = values[2];
form_prof.prof_password.value = values[3];
Of course you may have to do something more complicated if the values may contain a comma.

You can try this
$account = $_GET['account'];
$query = "SELECT * FROM profs WHERE profs_name = '".$account."'";
$result = mysql_query($query, MYSQLI_STORE_RESULT);
while($arr = $result->fetch_array(MYSQLI_ASSOC)) {
$returnValues = json_encode($arr);
break;
}
echo $returnValues;
Note that column names are used as associative index for $arr
Hope it works.