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How to detect if a site lets you upload files?

I would like to be able to tell if a site lets you upload files. I can think of two main ways sites do it and ideally I'd like to be able to detect both:
Button
Drag & Drop
PhantomJS documentation has this example snippet:
var webPage = require('webpage');
var page = webPage.create();
page.uploadFile('input[name=image]', '/path/to/some/photo.jpg');
but it's not clear how I could figure out that input[name=image] actually supports uploading.
Currently, my crawlers are following all links and buttons on sites but I am not sure how to detect that "a file upload pop-up has been opened". The D&D case is even less clear to me. I need a solution for a single page and obviously I can then go and apply it to every page I pass.
UPDATE
Turns out most of the time this does the trick:
document.querySelector('input[type=file]').click()
However, D&D areas aren't always clickable and you can't always assume [ondrop] will be present. Sometimes, the drop listener is added in code:
object.addEventListener("drop", myScript);
How can I check for presence of such elements then?

You can check if a form has enctype="multipart/form-data" or not. or search for input with type=file in html page.

AFAIK the best approach to upload files with selenium is to send the file to be uploaded directly to element located by this CSS Selector input[type=file].
So in order to check if some web page supports file uploading you can by checking if that page contains input[type=file] element.
This element is normally not visible and not interactable by GUI so you can only check it's existence, not visibility etc.

Nothing can get you 100%, but i think 99% it works with input[type=file] unless user wasn't creating it at runtime using javascript.
Or you can check for form's enctype but also it isn't always works as there's a good chance that user compress and changes the file into base64, then there will be no need for enctype to be multipart/form-data.
So input[type=file] is the best way.

Is there a way to attach a dynamic image to a tweet?

I've got functionality on my website to share to twitter. It's just a simple Twitter Intent with some custom text. I'd now like to share an image with this text, not a link to the image, but the image itself like how they're shown in Twitter Cards. I'm at a loss of how to achieve this though.
I've got a web app that changes the data shown based on filters that the user engages. When they click the "share" button, I use PHP GD to generate an image using the current data shown. This image is saved on the server and the url is passed back to the javascript via ajax. Now I would like to open a "twitter share" dialog with my pre-filled text and this image. I have discovered that this is not possible with twitter intents because they don't allow images, only image urls (because actual images shown in tweets are pic.twitter.com images).
So I'm looking at Cards but it seems as though Cards are static. I was wondering if it's possible to make the card metadata dynamic by having a php file which has a hash (e.g. www.example.com/tweet.php?esd87fsduh) that is used to dynamically populate the twitter card meta tags? Or would this not work because it takes a long time for twitters bots to crawl the website again?
I basically want the simple functionality that the user clicks "tweet" and they are presented with the Twitter dialog showing dynamic text and the image based on the data filters they'd applied. Is this possible?
Thank you for your time.

Using dropzone to save multiple images that have relation with article

I'm building a website in which the user can create articles with multiple images. Of Course that images will have relation with article.
All works good using laravel (php) and mysql. The database has the relation of images and articles.
Now I would like to add a new feature so as the user can upload or remove image from article so I thought to use dropzone library.
Now using dropzone there is one big problem. The dropzone upload the images on the server without any problem, but then when I click the submit button to save the article I would like to get again that images so I can make the relation with article.
Is there any way to do that?

Jquery ajax modal form post back to parent form

I have a query and don't know where to start - I have a image select input field on a form thats populated by an jquery ajax autocomplete. What I would like to do is the following:-
If a user wants to choose an alternative image that's not currently in the dB pop up a modal/lightbox form which contains the upload/editing form.
Once posted I want to pass this data back to the original form field and refresh the data for the autocomplete.
I already have the upload and editing forms working as standalone pages I just want to incorporate the output back into the original form.
Is it possible?
Can anyone suggest modal/lighbox script that can do this?

What data are you trying to retrieve in the parent window? Assuming your using an iframe in your lightbox? If you aren't then you should just be able to set variables and call functions from your upload script output as if it were the same page.
If you are...
I don't believe there are any lightbox/modal solutions that support this, I normally incorporate a script like below in my upload script so you can monitor the success/failure of the uploaded file and the data.
(function () {
parent.myClass.imageLocation = $output_your_image_location here;
return;
)();
You can obviously edit this to handle different situations but I always use the parent keyword as I have a similar way of handling uploads in some software I've built recently.

Creating a preview page in CakePHP

I'm building a site in CakePHP, and I'd like to give a 'Preview' option for pages as they're being added or edited.
In the 'Add Page' view, for instance, I have the usual form which the user uses to create their page. There is a 'Save' button, to save the data. Next to that, I'd like to have a 'Preview' button, which opens the page in a new window.
So, either I need the controller to open a new window (and I don't think this is possible), or it needs to be a link (targetting a new window) instead of a button - but in that case, how do I POST the data so that it can be shown? Do I need to use ajax or something? I'm a total newbie in ajax, but I do have a reasonable grasp of javascript.
Thanks for any help!

If the data that you are previewing is already saved on your database, then you can have an action in your controller (maybe preview()) action that references the saved data and loads the preview. And then to use it, you can just use a regular link that targets a new page and opens it there.
This would require saving the data the user is typing to your server every few seconds, though.
If you want to use the data that is still on the page, then you can use a JavaScript function to load a lightbox and populate the contents of that lightbox with data from the fields that the user is working on. You can probably use fancybox for that.