Related
My code:
let AuthUser = data => {
return google.login(data.username, data.password).then(token => { return token } )
}
And when i try to run something like this:
let userToken = AuthUser(data)
console.log(userToken)
I'm getting:
Promise { <pending> }
But why?
My main goal is to get token from google.login(data.username, data.password) which returns a promise, into a variable. And only then preform some actions.
The promise will always log pending as long as its results are not resolved yet. You must call .then on the promise to capture the results regardless of the promise state (resolved or still pending):
let AuthUser = function(data) {
return google.login(data.username, data.password).then(token => { return token } )
}
let userToken = AuthUser(data)
console.log(userToken) // Promise { <pending> }
userToken.then(function(result) {
console.log(result) // "Some User token"
})
Why is that?
Promises are forward direction only; You can only resolve them once. The resolved value of a Promise is passed to its .then or .catch methods.
Details
According to the Promises/A+ spec:
The promise resolution procedure is an abstract operation taking as
input a promise and a value, which we denote as [[Resolve]](promise,
x). If x is a thenable, it attempts to make promise adopt the state of
x, under the assumption that x behaves at least somewhat like a
promise. Otherwise, it fulfills promise with the value x.
This treatment of thenables allows promise implementations to
interoperate, as long as they expose a Promises/A+-compliant then
method. It also allows Promises/A+ implementations to “assimilate”
nonconformant implementations with reasonable then methods.
This spec is a little hard to parse, so let's break it down. The rule is:
If the function in the .then handler returns a value, then the Promise resolves with that value. If the handler returns another Promise, then the original Promise resolves with the resolved value of the chained Promise. The next .then handler will always contain the resolved value of the chained promise returned in the preceding .then.
The way it actually works is described below in more detail:
1. The return of the .then function will be the resolved value of the promise.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return "normalReturn";
})
.then(function(result) {
console.log(result); // "normalReturn"
});
2. If the .then function returns a Promise, then the resolved value of that chained promise is passed to the following .then.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return new Promise(function(resolve, reject) {
setTimeout(function() {
resolve("secondPromise");
}, 1000)
})
})
.then(function(result) {
console.log(result); // "secondPromise"
});
I know this question was asked 2 years ago, but I run into the same issue and the answer for the problem is since ES2017, that you can simply await the functions return value (as of now, only works in async functions), like:
let AuthUser = function(data) {
return google.login(data.username, data.password)
}
let userToken = await AuthUser(data)
console.log(userToken) // your data
The then method returns a pending promise which can be resolved asynchronously by the return value of a result handler registered in the call to then, or rejected by throwing an error inside the handler called.
So calling AuthUser will not suddenly log the user in synchronously, but returns a promise whose then registered handlers will be called after the login succeeds ( or fails). I would suggest triggering all login processing by a then clause of the login promise. E.G. using named functions to highlight the sequence of flow:
let AuthUser = data => { // just the login promise
return google.login(data.username, data.password);
};
AuthUser(data).then( processLogin).catch(loginFail);
function processLogin( token) {
// do logged in stuff:
// enable, initiate, or do things after login
}
function loginFail( err) {
console.log("login failed: " + err);
}
If that situation happens for a multiple values like an array.
[
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> }
]
You can use Promise.all() this will resolve all promises.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise/all
See the MDN section on Promises. In particular, look at the return type of then().
To log in, the user-agent has to submit a request to the server and wait to receive a response. Since making your application totally stop execution during a request round-trip usually makes for a bad user experience, practically every JS function that logs you in (or performs any other form of server interaction) will use a Promise, or something very much like it, to deliver results asynchronously.
Now, also notice that return statements are always evaluated in the context of the function they appear in. So when you wrote:
let AuthUser = data => {
return google
.login(data.username, data.password)
.then( token => {
return token;
});
};
the statement return token; meant that the anonymous function being passed into then() should return the token, not that the AuthUser function should. What AuthUser returns is the result of calling google.login(username, password).then(callback);, which happens to be a Promise.
Ultimately your callback token => { return token; } does nothing; instead, your input to then() needs to be a function that actually handles the token in some way.
Your Promise is pending, complete it by
userToken.then(function(result){
console.log(result)
})
after your remaining code.
All this code does is that .then() completes your promise & captures the end result in result variable & print result in console.
Keep in mind, you cannot store the result in global variable.
Hope that explanation might help you.
I had the same issue earlier, but my situation was a bit different in the front-end. I'll share my scenario anyway, maybe someone might find it useful.
I had an api call to /api/user/register in the frontend with email, password and username as request body. On submitting the form(register form), a handler function is called which initiates the fetch call to /api/user/register. I used the event.preventDefault() in the beginning line of this handler function, all other lines,like forming the request body as well the fetch call was written after the event.preventDefault(). This returned a pending promise.
But when I put the request body formation code above the event.preventDefault(), it returned the real promise. Like this:
event.preventDefault();
const data = {
'email': email,
'password': password
}
fetch(...)
...
instead of :
const data = {
'email': email,
'password': password
}
event.preventDefault();
fetch(...)
...
Try this
var number1 = document.getElementById("number1");
var number2 = document.getElementById("number2");
startAsync.addEventListener("click", function() {
if (number1.value > 0 && number2.value > 0) {
asyncTest(parseInt(number1.value), parseInt(number2.value)).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
} else {
asyncTest(1, 2).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
}
});
async function asyncTest(a, b) {
return await (a + b);
};
<button id="startAsync">start Async function</button><br />
<input type="number" id="number1" /><br />
<input type="number" id="number2" /><br />
<span id="promiseResolved"></span><br />
Im my case (JS) I forgot to add await
My code:
let AuthUser = data => {
return google.login(data.username, data.password).then(token => { return token } )
}
And when i try to run something like this:
let userToken = AuthUser(data)
console.log(userToken)
I'm getting:
Promise { <pending> }
But why?
My main goal is to get token from google.login(data.username, data.password) which returns a promise, into a variable. And only then preform some actions.
The promise will always log pending as long as its results are not resolved yet. You must call .then on the promise to capture the results regardless of the promise state (resolved or still pending):
let AuthUser = function(data) {
return google.login(data.username, data.password).then(token => { return token } )
}
let userToken = AuthUser(data)
console.log(userToken) // Promise { <pending> }
userToken.then(function(result) {
console.log(result) // "Some User token"
})
Why is that?
Promises are forward direction only; You can only resolve them once. The resolved value of a Promise is passed to its .then or .catch methods.
Details
According to the Promises/A+ spec:
The promise resolution procedure is an abstract operation taking as
input a promise and a value, which we denote as [[Resolve]](promise,
x). If x is a thenable, it attempts to make promise adopt the state of
x, under the assumption that x behaves at least somewhat like a
promise. Otherwise, it fulfills promise with the value x.
This treatment of thenables allows promise implementations to
interoperate, as long as they expose a Promises/A+-compliant then
method. It also allows Promises/A+ implementations to “assimilate”
nonconformant implementations with reasonable then methods.
This spec is a little hard to parse, so let's break it down. The rule is:
If the function in the .then handler returns a value, then the Promise resolves with that value. If the handler returns another Promise, then the original Promise resolves with the resolved value of the chained Promise. The next .then handler will always contain the resolved value of the chained promise returned in the preceding .then.
The way it actually works is described below in more detail:
1. The return of the .then function will be the resolved value of the promise.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return "normalReturn";
})
.then(function(result) {
console.log(result); // "normalReturn"
});
2. If the .then function returns a Promise, then the resolved value of that chained promise is passed to the following .then.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return new Promise(function(resolve, reject) {
setTimeout(function() {
resolve("secondPromise");
}, 1000)
})
})
.then(function(result) {
console.log(result); // "secondPromise"
});
I know this question was asked 2 years ago, but I run into the same issue and the answer for the problem is since ES2017, that you can simply await the functions return value (as of now, only works in async functions), like:
let AuthUser = function(data) {
return google.login(data.username, data.password)
}
let userToken = await AuthUser(data)
console.log(userToken) // your data
The then method returns a pending promise which can be resolved asynchronously by the return value of a result handler registered in the call to then, or rejected by throwing an error inside the handler called.
So calling AuthUser will not suddenly log the user in synchronously, but returns a promise whose then registered handlers will be called after the login succeeds ( or fails). I would suggest triggering all login processing by a then clause of the login promise. E.G. using named functions to highlight the sequence of flow:
let AuthUser = data => { // just the login promise
return google.login(data.username, data.password);
};
AuthUser(data).then( processLogin).catch(loginFail);
function processLogin( token) {
// do logged in stuff:
// enable, initiate, or do things after login
}
function loginFail( err) {
console.log("login failed: " + err);
}
If that situation happens for a multiple values like an array.
[
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> }
]
You can use Promise.all() this will resolve all promises.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise/all
See the MDN section on Promises. In particular, look at the return type of then().
To log in, the user-agent has to submit a request to the server and wait to receive a response. Since making your application totally stop execution during a request round-trip usually makes for a bad user experience, practically every JS function that logs you in (or performs any other form of server interaction) will use a Promise, or something very much like it, to deliver results asynchronously.
Now, also notice that return statements are always evaluated in the context of the function they appear in. So when you wrote:
let AuthUser = data => {
return google
.login(data.username, data.password)
.then( token => {
return token;
});
};
the statement return token; meant that the anonymous function being passed into then() should return the token, not that the AuthUser function should. What AuthUser returns is the result of calling google.login(username, password).then(callback);, which happens to be a Promise.
Ultimately your callback token => { return token; } does nothing; instead, your input to then() needs to be a function that actually handles the token in some way.
Your Promise is pending, complete it by
userToken.then(function(result){
console.log(result)
})
after your remaining code.
All this code does is that .then() completes your promise & captures the end result in result variable & print result in console.
Keep in mind, you cannot store the result in global variable.
Hope that explanation might help you.
I had the same issue earlier, but my situation was a bit different in the front-end. I'll share my scenario anyway, maybe someone might find it useful.
I had an api call to /api/user/register in the frontend with email, password and username as request body. On submitting the form(register form), a handler function is called which initiates the fetch call to /api/user/register. I used the event.preventDefault() in the beginning line of this handler function, all other lines,like forming the request body as well the fetch call was written after the event.preventDefault(). This returned a pending promise.
But when I put the request body formation code above the event.preventDefault(), it returned the real promise. Like this:
event.preventDefault();
const data = {
'email': email,
'password': password
}
fetch(...)
...
instead of :
const data = {
'email': email,
'password': password
}
event.preventDefault();
fetch(...)
...
Try this
var number1 = document.getElementById("number1");
var number2 = document.getElementById("number2");
startAsync.addEventListener("click", function() {
if (number1.value > 0 && number2.value > 0) {
asyncTest(parseInt(number1.value), parseInt(number2.value)).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
} else {
asyncTest(1, 2).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
}
});
async function asyncTest(a, b) {
return await (a + b);
};
<button id="startAsync">start Async function</button><br />
<input type="number" id="number1" /><br />
<input type="number" id="number2" /><br />
<span id="promiseResolved"></span><br />
Im my case (JS) I forgot to add await
My code:
let AuthUser = data => {
return google.login(data.username, data.password).then(token => { return token } )
}
And when i try to run something like this:
let userToken = AuthUser(data)
console.log(userToken)
I'm getting:
Promise { <pending> }
But why?
My main goal is to get token from google.login(data.username, data.password) which returns a promise, into a variable. And only then preform some actions.
The promise will always log pending as long as its results are not resolved yet. You must call .then on the promise to capture the results regardless of the promise state (resolved or still pending):
let AuthUser = function(data) {
return google.login(data.username, data.password).then(token => { return token } )
}
let userToken = AuthUser(data)
console.log(userToken) // Promise { <pending> }
userToken.then(function(result) {
console.log(result) // "Some User token"
})
Why is that?
Promises are forward direction only; You can only resolve them once. The resolved value of a Promise is passed to its .then or .catch methods.
Details
According to the Promises/A+ spec:
The promise resolution procedure is an abstract operation taking as
input a promise and a value, which we denote as [[Resolve]](promise,
x). If x is a thenable, it attempts to make promise adopt the state of
x, under the assumption that x behaves at least somewhat like a
promise. Otherwise, it fulfills promise with the value x.
This treatment of thenables allows promise implementations to
interoperate, as long as they expose a Promises/A+-compliant then
method. It also allows Promises/A+ implementations to “assimilate”
nonconformant implementations with reasonable then methods.
This spec is a little hard to parse, so let's break it down. The rule is:
If the function in the .then handler returns a value, then the Promise resolves with that value. If the handler returns another Promise, then the original Promise resolves with the resolved value of the chained Promise. The next .then handler will always contain the resolved value of the chained promise returned in the preceding .then.
The way it actually works is described below in more detail:
1. The return of the .then function will be the resolved value of the promise.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return "normalReturn";
})
.then(function(result) {
console.log(result); // "normalReturn"
});
2. If the .then function returns a Promise, then the resolved value of that chained promise is passed to the following .then.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return new Promise(function(resolve, reject) {
setTimeout(function() {
resolve("secondPromise");
}, 1000)
})
})
.then(function(result) {
console.log(result); // "secondPromise"
});
I know this question was asked 2 years ago, but I run into the same issue and the answer for the problem is since ES2017, that you can simply await the functions return value (as of now, only works in async functions), like:
let AuthUser = function(data) {
return google.login(data.username, data.password)
}
let userToken = await AuthUser(data)
console.log(userToken) // your data
The then method returns a pending promise which can be resolved asynchronously by the return value of a result handler registered in the call to then, or rejected by throwing an error inside the handler called.
So calling AuthUser will not suddenly log the user in synchronously, but returns a promise whose then registered handlers will be called after the login succeeds ( or fails). I would suggest triggering all login processing by a then clause of the login promise. E.G. using named functions to highlight the sequence of flow:
let AuthUser = data => { // just the login promise
return google.login(data.username, data.password);
};
AuthUser(data).then( processLogin).catch(loginFail);
function processLogin( token) {
// do logged in stuff:
// enable, initiate, or do things after login
}
function loginFail( err) {
console.log("login failed: " + err);
}
If that situation happens for a multiple values like an array.
[
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> }
]
You can use Promise.all() this will resolve all promises.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise/all
See the MDN section on Promises. In particular, look at the return type of then().
To log in, the user-agent has to submit a request to the server and wait to receive a response. Since making your application totally stop execution during a request round-trip usually makes for a bad user experience, practically every JS function that logs you in (or performs any other form of server interaction) will use a Promise, or something very much like it, to deliver results asynchronously.
Now, also notice that return statements are always evaluated in the context of the function they appear in. So when you wrote:
let AuthUser = data => {
return google
.login(data.username, data.password)
.then( token => {
return token;
});
};
the statement return token; meant that the anonymous function being passed into then() should return the token, not that the AuthUser function should. What AuthUser returns is the result of calling google.login(username, password).then(callback);, which happens to be a Promise.
Ultimately your callback token => { return token; } does nothing; instead, your input to then() needs to be a function that actually handles the token in some way.
Your Promise is pending, complete it by
userToken.then(function(result){
console.log(result)
})
after your remaining code.
All this code does is that .then() completes your promise & captures the end result in result variable & print result in console.
Keep in mind, you cannot store the result in global variable.
Hope that explanation might help you.
I had the same issue earlier, but my situation was a bit different in the front-end. I'll share my scenario anyway, maybe someone might find it useful.
I had an api call to /api/user/register in the frontend with email, password and username as request body. On submitting the form(register form), a handler function is called which initiates the fetch call to /api/user/register. I used the event.preventDefault() in the beginning line of this handler function, all other lines,like forming the request body as well the fetch call was written after the event.preventDefault(). This returned a pending promise.
But when I put the request body formation code above the event.preventDefault(), it returned the real promise. Like this:
event.preventDefault();
const data = {
'email': email,
'password': password
}
fetch(...)
...
instead of :
const data = {
'email': email,
'password': password
}
event.preventDefault();
fetch(...)
...
Try this
var number1 = document.getElementById("number1");
var number2 = document.getElementById("number2");
startAsync.addEventListener("click", function() {
if (number1.value > 0 && number2.value > 0) {
asyncTest(parseInt(number1.value), parseInt(number2.value)).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
} else {
asyncTest(1, 2).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
}
});
async function asyncTest(a, b) {
return await (a + b);
};
<button id="startAsync">start Async function</button><br />
<input type="number" id="number1" /><br />
<input type="number" id="number2" /><br />
<span id="promiseResolved"></span><br />
Im my case (JS) I forgot to add await
I am trying to make 2 HTTP requests and in the first call I try to create a record and then according to its results (response from the API method) I want to execute or omit the second call that updates another data. However, although I can catch the error in catchError block, I cannot get the response in the switchMap method of the first call. So, what is wrong with this implementation according to teh given scenario? And how can I get the response of the first result and continue or not to the second call according to this first response?
let result;
let statusCode;
this.demoService.create(...).pipe(
catchError((err: any) => { ... }),
switchMap(response => {
// I am trying to get the response of first request at here
statusCode = response.statusCode;
if(...){
return this.demoService.update(...).pipe(
catchError((err: any) => { ... }),
map(response => {
return {
result: response
}
}
)
)}
}
))
.subscribe(result => console.log(result));
The question is still vague to me. I'll post a more generic answer to make few things clear
There are multiple things to note
When an observable emits an error notification, the observable is considered closed (unless triggered again) and none of the following operators that depend on next notifications will be triggered. If you wish to catch the error notifications inside the switchMap, you could return a next notification from the catchError. Something like catchError(error => of(error)) using RxJS of function. The notification would then be caught by the following switchMap.
You must return an observable from switchMap regardless of your condition. In this case if you do not wish to return anything when the condition fails, you could return RxJS NEVER. If you however wish to emit a message that could be caught by the subscriptions next callback, you could use RxJS of function. Replace return NEVER with return of('Some message that will be emitted to subscription's next callback');
import { of, NEVER } from 'rxjs';
import { switchMap, catchError, map } from 'rxjs/operators';
this.demoService.create(...).pipe(
catchError((err: any) => { ... }),
switchMap(response => {
statusCode = response.statusCode;
if (someCondition) {
return this.demoService.update(...).pipe( // emit `update()` when `someCondition` passes
catchError((err: any) => { ... }),
map(response => ({ result: response }))
);
}
// Show error message
return NEVER; // never emit when `someCondition` fails
}
)).subscribe({
next: result => console.log(result),
error: error => console.log(error)
});
You can implement with iif
this.demoService
.create(...)
.pipe(
// tap first to be sure there's actually a response to process through
tap(console.log),
// You can use any condition in your iif, "response.user.exists" is just a sample
// If the condition is true, it will run the run the update$ observable
// If not, it will run the default$
// NOTE: All of them must be an observable since you are inside the switchMap
switchMap(response =>
iif(() =>
response.user.exists,
this.demoService.update(response.id), // Pass ID
of('Default Random Message')
)
),
catchError((err: any) => { ... })
);
Using fetch API and async/await, is it possible to continue polling indefinitely, regardless of availability of a URL? I anticipate that a URL might become available eventually, so I want to keep trying until a condition is met. Tried to come up with a minimum viable code sample and I'm not sure I pulled it off:
// this is just a placeholder. It will eventually be a function
// that evaluates something real.
// Assume validContinue gets updated elsewhere.
function shouldContinue() {
return validContinue;
}
async function wonderPoll(someUrl) {
// just a delay mechanism
function wait(ms = 1000) {
return new Promise(resolve => {
setTimeout(resolve, ms);
});
}
// the actual individual poll
async function pollingFunction(url) {
const response = await fetch(url, {
cache: 'no-store'
});
if (response.ok) {
return response;
} else {
Promise.reject(response);
}
}
// allegedly keep polling until condition is met.
// But the rejected Promise is breaking out!
while (shouldContinue()) {
await wait();
result = await pollingFunction(someUrl);
}
// when the fetch hits a rejected state, we never get here!
console.log('done with the while loop, returning last successful result')
return result;
}
const sampleUrl = 'https://get.geojs.io/v1/ip/country.json?ip=8.8.8.8';
const sampleUrl2 = 'http://totallybroken_fo_sho';
// swap the URL to test
wonderPoll(sampleUrl)
.then((result) => {
console.log('got a result', result)
})
.catch((err) => {
console.log('got an error', err)
});
I see what's happening (I think). The parent call ultimately executes the polling function, which rejects on the Promise. The condition to continue is still theoretically met, but the rejection breaks out of the While loop and sends to rejection directly up. This propagates all the way up to the catch method of the original/initial Promise. It doesn't even hit any code that would have come after the While loop in the case of resolved Promises.
What I don't know is how to prevent that from happening. I think I don't understand the syntax for intercepting and resolving the promise. When I replace Promise.reject in the response parser with Promise.resolve(response), it still ends up rejecting up to the top.
If the URL I provide is valid, it will continue until the condition is no longer met.
Here's a fiddle: https://jsfiddle.net/gregpettit/qf495bjm/5/
To use the fiddle, the "stop" button simulates the condition being met, and I've provided two different URLs that have to be manually swapped (by passing someUrl or someUrl2) to test.
Expected results:
with good URL, continuous polling (will have to dig into network in dev tools) until condition is met (by pressing Stop!) and then the calling function's 'then' can show the result.
with bad URL, continuous polling until condition is met, and then calling function's 'catch' shows the error
Actual results:
positive test case is OK
negative test case goes directly to the catch
You can try…catch it to prevent breaking out of loop.
while (shouldContinue()) {
try {
await wait();
result = await pollingFunction(someUrl);
} catch (e) {}
}
Change the code in while loop to try/catch so you can catch the error
result can hold a value when there's no error, or a reason when there is an error
Once the loop is stopped, you either return the value, or throw with the reason
As below
async function wonderPoll(someUrl) {
// just a delay mechanism
function wait(ms = 1000) {
return new Promise(resolve => {
setTimeout(resolve, ms);
});
}
// the actual individual poll
async function pollingFunction(url) {
const response = await fetch(url, {
cache: 'no-store'
});
if (response.ok) {
return response;
} else {
Promise.reject(response);
}
}
// allegedly keep polling until condition is met. But the rejected Promise is breaking out!
while (shouldContinue()) {
try {
await wait();
const value = await pollingFunction(someUrl);
result = {value};
} catch (reason) {
result = {reason};
}
}
// when the fetch hits a rejected state, we never get here!
console.log('done with the while loop, returning last successful result')
if (result.reason) {
throw result.reason;
}
return result.value;
}
Running example https://jsfiddle.net/twkbo9pg/
the example includes status in the result, but that is unnecessary (I borrowed code from my Promise.allSettled polyfill and forgot to remove that property)
you might want to check out observable streams! If you're going to have a lot of data coming in over time, that's rxjs's whole thing.
There's actually a few ways to do this if this feels janky (it kinda does haha).
import { ajax } from "rxjs/ajax";
import { duration } from "moment-timezone"; // I copied this from some old code... whatever.
import { catchError, map, share, switchMap } from "rxjs/operators";
const baseUrl = "http://foo.bar"
const base = (method, headers = {}) => ({
method,
headers: {
Accept: "application/json",
...headers,
},
crossDomain: true,
withCredentials: true,
})
const ajaxGet = url => ajax({ ...base("GET"), url })
export const userEpic = timer(0, duration(5, "minutes").asMilliseconds()).pipe(
switchMap(() =>
ajaxGet(`${baseUrl}/users`).pipe(
map(({ response }) => getUsersSuccess(response)),
catchError(e => of(getUsersError(e))),
)
),
share()
)
Two things
} else {
Promise.reject(response);
}
should return that. It's working "by accident" right now.
} else {
return Promise.reject(response);
}
Secondly, result = await pollingFunction(someUrl); might want to add .catch to it:
result = await pollingFunction(someUrl).catch(_=>null); or whatever can be tested for in the enclosing while
But I think you can simplify the whole thing thus:
export async function wonderPoll(someUrl) {
while (shouldContinue()) {
await wait();
const response = await fetch(someUrl, { cache: 'no-store' });
if (response.ok)
return response;
}
return Promise.reject(); // only if !shouldContinue()
}