Is there a way to get an array of all the selected values inside a div with a particular class name when having more than one div with the same class name?
<div class="mydiv">
<select name="first">
<option value="1">One</option>
<option value="2">Two</option>
</select>
<select name="second" ">
<option value="1">One</option>
<option value="2">Two</option>
</select> </div>
<div class="mydiv">
<select name="first">
<option value="1">One</option>
<option value="2">Two</option>
</select>
<select name="second" ">
<option value="1">One</option>
<option value="2">Two</option>
</select> </div>
If i do this: $(".mydiv").each(function (){ });
I will be looping(twice in total as I have two divs with class mydiv) through both divs which is what I want. Now I would like to get the selected values in each div for each select(first and second).
You can use map().
Following assumes you want a sub array for each <div>
let res = $('.mydiv').map(function(){
return [$(this).find('select').map(function(){
return $(this).val()
}).get()]
}).get()
console.log(res)
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="mydiv">
<select name="first">
<option value="1" selected>One</option>
<option value="2">Two</option>
</select>
<select name="second">
<option value="1">One</option>
<option value="2" selected>Two</option>
</select>
</div>
<div class="mydiv">
<select name="first">
<option value="1">One</option>
<option value="2" selected>Two</option>
</select>
<select name="second">
<option value="1">One</option>
<option value="2" selected>Two</option>
</select>
</div>
For a flat array just do :
let res = $('.mydiv select').map(function(){
return $(this).val();
}).get();
Related
I have 2 select boxes. When I select an option on selectbox1, it automatically changes the corresponding value on selectbox2 regardless of value but order.
The thing is, the code is working fine until after a few tries. Then even if I change the option on selectbox1, it doesn't update the one on selectbox2.
To reproduce the issue; go through A to E, then repeat.
Code:
$(".firstSelectBox").change(function(e) {
var selectedOption = $("option:selected", this);
var idx = $(this).children().index(selectedOption)
var secChildIdx = $(".secondSelectBox").children()[idx];
$(".secondSelectBox").find(":selected").removeAttr('selected');
$(secChildIdx).attr("selected", "selected");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.2/jquery.min.js"></script>
<div class="control-group">
<div class="controls">
<label>First Selectbox</label><br/>
<select class="firstSelectBox validate[required]">
<option value="1">Select A</option>
<option value="2">Select B</option>
<option value="3">Select C</option>
<option value="4">Select D</option>
<option value="5">Select E</option>
</select>
</div>
</div>
<br />
<div class="control-group">
<div class="controls">
<label>Second Selectbox</label><br />
<select class="secondSelectBox validate[required]">
<option value="A">Select 1</option>
<option value="B">Select 2</option>
<option value="C">Select 3</option>
<option value="D">Select 4</option>
<option value="E">Select 5</option>
</select>
</div>
</div>
Also JSFiddle version: https://jsfiddle.net/153w074d/
No need for all that code, just work with selectedIndex:
$(".firstSelectBox").change(function(e) {
var selectedIndex = $(this).get(0).selectedIndex;
$(".secondSelectBox").get(0).selectedIndex = selectedIndex;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.2/jquery.min.js"></script>
<div class="control-group">
<div class="controls">
<label>First Selectbox</label><br/>
<select class="firstSelectBox validate[required]">
<option value="1">Select A</option>
<option value="2">Select B</option>
<option value="3">Select C</option>
<option value="4">Select D</option>
<option value="5">Select E</option>
</select>
</div>
</div>
<br />
<div class="control-group">
<div class="controls">
<label>Second Selectbox</label><br />
<select class="secondSelectBox validate[required]">
<option value="A">Select 1</option>
<option value="B">Select 2</option>
<option value="C">Select 3</option>
<option value="D">Select 4</option>
<option value="E">Select 5</option>
</select>
</div>
</div>
What happened in your original code is that, in some way, the selected attributes are being messed around. Try this: Change to each option from A to E, then start over from A, the selection stops working. Then inspect the second select to see that there are more than one option with selected="selected" attribute. Not sure what caused that tho.
#DontVoteMeDown's answer will certainly work, but the reason you're having this issue is because of the discrepancy between .prop and .attr. Both are similar, but don't refer to the same, identical underlying value.
If you change the below two lines to use the .prop value instead of .attr, your code will work. See the working code example below.
$(".secondSelectBox").find(":selected").removeAttr('selected'); // change to .removeProp
$(secChildIdx).attr("selected", "selected"); // change to .prop
$(".firstSelectBox").change(function(e) {
var selectedOption = $("option:selected", this);
var idx = $(this).children().index(selectedOption)
var secChildIdx = $(".secondSelectBox").children()[idx];
$(".secondSelectBox").find(":selected").removeProp('selected');
$(secChildIdx).prop("selected", "selected");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.2/jquery.min.js"></script>
<div class="control-group">
<div class="controls">
<label>First Selectbox</label><br/>
<select class="firstSelectBox validate[required]">
<option value="1">Select A</option>
<option value="2">Select B</option>
<option value="3">Select C</option>
<option value="4">Select D</option>
<option value="5">Select E</option>
</select>
</div>
</div>
<br />
<div class="control-group">
<div class="controls">
<label>Second Selectbox</label><br />
<select class="secondSelectBox validate[required]">
<option value="A">Select 1</option>
<option value="B">Select 2</option>
<option value="C">Select 3</option>
<option value="D">Select 4</option>
<option value="E">Select 5</option>
</select>
</div>
</div>
You can also use prop to select option.
$(".firstSelectBox").change(function(e) {
var selectedIndex = $(this).get(0).selectedIndex;
$('.secondSelectBox option:eq('+selectedIndex+')').prop('selected', true);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="control-group">
<div class="controls">
<label>First Selectbox</label><br/>
<select class="firstSelectBox validate[required]">
<option value="1">Select A</option>
<option value="2">Select B</option>
<option value="3">Select C</option>
<option value="4">Select D</option>
<option value="5">Select E</option>
</select>
</div>
</div>
<br />
<div class="control-group">
<div class="controls">
<label>Second Selectbox</label><br />
<select class="secondSelectBox validate[required]">
<option value="A">Select 1</option>
<option value="B">Select 2</option>
<option value="C">Select 3</option>
<option value="D">Select 4</option>
<option value="E">Select 5</option>
</select>
</div>
</div>
So I'm trying to build a quickbuy of products with different variants in my list of products. The product has a set of avaialble options, that are collected from the select option with jQuery, passed to a input field and then submitted to the cart. The products are listed out by a loop. When I'm at the single product page it works fine, since all the option values are required.
But once in the list of products, it gets the options from all the products and passes them to all the submit fields. How can I scope a jquery function to work on only one product at a time
In the example below, I want the field to have only the values from the select options relevant to the product. Not th evalues from both product options.
$(document).ready(function() {
$(".variant-selected")
.change(function() {
var str = "";
$("select option:selected").each(function() {
str += $(this).val() + ".";
});
$("input[name='variant']").val(str.slice(0, -1));
})
.trigger("change");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="prod1">
<h2>
Shirt
</h2>
<select class="variant-selected" name="select1">
<option value="1" selected>Red</option>
<option value="2">Blue</option>
<option value="3">Green</option>
</select>
<select class="variant-selected" name="select2">
<option value="A" selected>Large</option>
<option value="B">Medium</option>
<option value="C">Small</option>
</select>
<form class="addtocart">
<input type="text" value="" name="variant">
</form>
</div>
<div id="prod2">
<h2>Jeans
</h2>
<select class="variant-selected" name="select1">
<option value="4" selected>Orange</option>
<option value="5">Teal</option>
<option value="6">Forest</option>
</select>
<select class="variant-selected" name="select2">
<option value="D" selected>Large</option>
<option value="E">Medium</option>
<option value="F">Small</option>
</select>
<form class="addtocart">
<input type="text" value="" name="variant">
</form>
</div>
here you have
$(document).ready(function() {
$(".variant-selected")
.change(function() {
var str = "";
$(this).parent().find("select option:selected").each(function() {
str += $(this).val() + ".";
});
$(this).parent().find("input[name='variant']").val(str.slice(0, -1));
})
.trigger("change");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="prod1">
<h2>
Shirt
</h2>
<select class="variant-selected" name="select1">
<option value="1" selected>Red</option>
<option value="2">Blue</option>
<option value="3">Green</option>
</select>
<select class="variant-selected" name="select2">
<option value="A" selected>Large</option>
<option value="B">Medium</option>
<option value="C">Small</option>
</select>
<form class="addtocart">
<input type="text" value="" name="variant">
</form>
</div>
<div id="prod2">
<h2>Jeans
</h2>
<select class="variant-selected" name="select1">
<option value="4" selected>Orange</option>
<option value="5">Teal</option>
<option value="6">Forest</option>
</select>
<select class="variant-selected" name="select2">
<option value="D" selected>Large</option>
<option value="E">Medium</option>
<option value="F">Small</option>
</select>
<form class="addtocart">
<input type="text" value="" name="variant">
</form>
</div>
I am attempting to select a dropdown option (out of several dropdowns on the page) by its value. I'm posting below code I think is relevant but if more is needed please let me know!
HTML
<form class="controls" id="Filters">
<fieldset>
<select id="select1" class="dropdowns">
<option selected="selected" value=".default1">Default 1</option>
<option value=".option1">Option 1</option>
<option value=".option2">Option 2</option>
</select>
</fieldset>
<fieldset>
<select id="select2" class="dropdowns">
<option selected="selected" value=".default2">Default 2</option>
<option value=".option3">Option 3</option>
<option value=".option4">Option 4</option>
</fieldset>
<fieldset>
<select id="select3" class="dropdowns">
<option selected="selected" value=".default3">Default 3</option>
<option value=".option5">Option 5</option>
<option value=".option6">Option 6</option>
</fieldset>
</form>
jQuery
var example = ".option3";
var example = ".option3";
$('#Filters').find('.dropdowns').val(example).click();
<form class="controls" id="Filters">
<fieldset>
<select id="select1" class="dropdowns">
<option selected="selected" value=".default1">Default 1</option>
<option value=".option1">Option 1</option>
<option value=".option2">Option 2</option>
</select>
</fieldset>
<fieldset>
<select id="select2" class="dropdowns">
<option selected="selected" value=".default2">Default 2</option>
<option value=".option3">Option 3</option>
<option value=".option4">Option 4</option>
</select>
</fieldset>
<fieldset>
<select id="select3" class="dropdowns">
<option selected="selected" value=".default3">Default 3</option>
<option value=".option5">Option 5</option>
<option value=".option6">Option 6</option>
</select>
</fieldset>
</form>
enter code here $('#Filters').find('.dropdowns').val(example).click();
This works, selects the correct dropdown option and the dropdown initiates the filtering process (I'm using MixItUp), but it deselects all other dropdowns making them blank instead of their default values, which should be (in this example) Default 1, Default 2, Default 3, etc. (except of course the dropdown that contains the correct value).
I'm hoping to have jQuery code find the dropdown option with the correct value (example = ".option3") but not affect the other dropdowns and make sure they're still on their default initial values.
I haven't been able to find answers to my problem anywhere so any help would be appreciated!
If I got your point you can use .find('option[value="'+example+'"]').prop('selected', true);
Demo
var example = ".option3";
$('#Filters').find('option[value="'+example+'"]').prop('selected', true);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form class="controls" id="Filters">
<fieldset>
<select id="select1" class="dropdowns">
<option selected="selected" value=".default1">Default 1</option>
<option value=".option1">Option 1</option>
<option value=".option2">Option 2</option>
</select>
</fieldset>
<fieldset>
<select id="select2" class="dropdowns">
<option selected="selected" value=".default2">Default 2</option>
<option value=".option3">Option 3</option>
<option value=".option4">Option 4</option>
</fieldset>
<fieldset>
<select id="select3" class="dropdowns">
<option selected="selected" value=".default3">Default 3</option>
<option value=".option5">Option 5</option>
<option value=".option6">Option 6</option>
</fieldset>
</form>
find does not deselect your selects. val does.
What happens is, $('#Filters') finds the form object. Then .find('.dropdowns') finds all the select objects within it. Then .val(example) sets the value of all of those select objects to .option3. However, that value happens to be invalid for most of them.
What I assume you want is to find only the select objects that actually can take your value, and set the value for those only:
var example = ".option3";
$('#Filters').find('.dropdowns:has(option[value="' + example + '"])').val(example);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form class="controls" id="Filters">
<fieldset>
<select id="select1" class="dropdowns">
<option selected="selected" value=".default1">Default 1</option>
<option value=".option1">Option 1</option>
<option value=".option2">Option 2</option>
</select>
</fieldset>
<fieldset>
<select id="select2" class="dropdowns">
<option selected="selected" value=".default2">Default 2</option>
<option value=".option3">Option 3</option>
<option value=".option4">Option 4</option>
</select>
</fieldset>
<fieldset>
<select id="select3" class="dropdowns">
<option selected="selected" value=".default3">Default 3</option>
<option value=".option5">Option 5</option>
<option value=".option6">Option 6</option>
</select>
</fieldset>
</form>
(Hopefully your option values won't have crazy things like quotes inside them.)
Please find below solution, I hope this will help you.
var example = ".option3";
$('#Filters').find('.dropdowns').val(example).prop('selected',true);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form class="controls" id="Filters">
<fieldset>
<select id="select1" class="dropdowns">
<option selected="selected" value=".default1">Default 1</option>
<option value=".option1">Option 1</option>
<option value=".option2">Option 2</option>
</select>
</fieldset>
<fieldset>
<select id="select2" class="dropdowns">
<option selected="selected" value=".default2">Default 2</option>
<option value=".option3">Option 3</option>
<option value=".option4">Option 4</option>
</select>
</fieldset>
<fieldset>
<select id="select3" class="dropdowns">
<option selected="selected" value=".default3">Default 3</option>
<option value=".option5">Option 5</option>
<option value=".option6">Option 6</option>
</select>
</fieldset>
</form>
You need to be more specific when selecting your dropdown.
Use the dropdown ID to select it, then choose a value using val(), then trigger a click event, ei.:
var example = ".option3"; $('#Filters').find('.dropdowns #select2 ').val(example).click();
Otherwise you're assigning the value "option3" for all three dropdowns, which is why #select1 and #select3 look empty.
I am look for a way to make it so that when the user selects an item form all the select (for which the value of the option is not nil) the div with id "js-market" is shown.
This is my html code:
<form class="js-chose">
<div class="col-md-6 col-xm-12">
<div class="form-group js-select">
<label>Select a Market</label>
<select class="form-control">
<option value='' disabled selected>Chose a Market</option>
<%Item.all.each do |item|%>
<option value="<%=item.id%>"><%=item.name.capitalize%></option>
<%end%>
</select>
</div>
</div>
<div class="col-md-6 col-xm-12">
<div class="form-group">
<label>Enter Market with:</label>
<select class="form-control js-select">
<option value='' disabled selected>Chose a Company</option>
<%Company.where(user_id: current_user.id).each do |company|%>
<option value="<%=company.id%>"><%=company.name%></option>
<%end%>
</select>
</div>
</div>
</form>
In short I need to make jQuery show the div with id="js-market" when both selects have been filled by the user and get the values of the selected items and assign them to a variable.
Thank you. Please let me know if I wasn't clear enough.
Example that works with multiple select elements
Link to jsfiddle
var counter = $('.select').length;
$('.select').change(function() {
$.each($('.select'),function(i,e) {
var t = $(this);
if (t.val() == undefined || t.val() == '') {
$('#js-market').fadeOut();
return;
}
if (i+1 == counter) {
$('#js-market').fadeIn();
}
});
});
#js-market {
display: none;
}
<select class="select">
<option value="">No Value</option>
<option value="value1">Value 1</option>
<option value="value2">Value 2</option>
<option value="value3">Value 3</option>
<option value="value1">Value 4</option>
</select>
<select class="select">
<option value="">No Value</option>
<option value="value1">Value 1</option>
<option value="value2">Value 2</option>
<option value="value3">Value 3</option>
<option value="value1">Value 4</option>
</select>
<select class="select">
<option value="">No Value</option>
<option value="value1">Value 1</option>
<option value="value2">Value 2</option>
<option value="value3">Value 3</option>
<option value="value1">Value 4</option>
</select>
<div id="js-market">Lorem ipsum</div>
See this fiddle
You can do this by onchange() event in javascript. In the fiddle specified above, what I do is that, I've placed 2 select boxes and a div with id demo will be shown only if two of the select boxes are selected.
HTML
<select id="mySelect1" onchange="myFunction()">
<option value="0">--Select--</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
<select id="mySelect2" onchange="myFunction()">
<option value="0">--Select--</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
<div id="demo"></div>
JS
function myFunction() {
if (document.getElementById("mySelect1").value > 0 && document.getElementById("mySelect2").value > 0) {
document.getElementById("demo").style.display = "block";
} else document.getElementById("demo").style.display = "none";
}
i have a dropdown in the header and whatever the value is selected in the header should reflect the same in the detail dropdown, how should i do that? any leads?
$("#myddl").change(function()
{
//update all the dropdown list...
});
http://jsfiddle.net/abuhamzah/4QvfP/
Header:
<br />
<select id="myddl" name="myddl">
<option value="1">One</option>
<option value="2">Twooo</option>
<option value="3">Three</option>
</select>
<p>Detail</p>
<br />
<select id="Select1" name="myddl">
<option value="1">One</option>
<option value="2">Twooo</option>
<option value="3">Three</option>
</select>
<br />
<select id="Select2" name="myddl">
<option value="1">One</option>
<option value="2">Twooo</option>
<option value="3">Three</option>
</select>
<br />
<select id="Select3" name="myddl">
<option value="1">One</option>
<option value="2">Twooo</option>
<option value="3">Three</option>
</select>
<br />
<select id="Select4" name="myddl">
<option value="1">One</option>
<option value="2">Twooo</option>
<option value="3">Three</option>
</select>
<br />
<select id="Select5" name="myddl">
<option value="1">One</option>
<option value="2">Twooo</option>
<option value="3">Three</option>
</select>
Something along these lines will work. It wraps your "Detail" selects in a container to make selection somewhat simpler.
http://jsfiddle.net/qMXSR/2/
$("#myddl").change(function()
{
$('.detail').find('select').val($(this).val());
});
Use $.on to bind to the "change" event. From here we target all select elements whose id begins with Select - which includes all of those below. Then we set their value(s) to that of the current one.
$("#myddl").on("change", function(o){
$("select[id^=Select]").val(o.target.value);
});
This code will do it:
$(document).ready(function()
{
$("#myddl").live('change', function()
{
$("#Select1, #Select2, #Select3, #Select4, #Select5").val($(this).val());
});
});
The updated JS Fiddle is here: http://jsfiddle.net/leniel/4QvfP/7/
$(function(){
$('#myddl').change(function(){
var value = $(this).val();
$('select[name=myddl] option[value='+value+']').attr('selected', 'selected');
});
})
In the onchange of the first dropdown, you can jQuery select the other dropdowns and use a .each() to iterate and set the other options.