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Javascript regex parse complex url string

I need to parse a complex URL string to fetch specific values.
From the following URL string:
/api/rss/feeds?url=http://any-feed-url-a.com?filter=hot&format=rss&url=http://any-feed-url-b.com?filter=rising&format=rss
I need to extract this result in array format:
['http://any-feed-url-a.com?filter=hot&format=rss', 'http://any-feed-url-b.com?filter=rising&format=rss']
I tried already with this one /url=([^&]+)/ but I can't capture all correctly all the query parameters. And I would like to omit the url=.
RegExr link
Thanks in advance.

This regex works for me: url=([a-z:/.?=-]+&[a-z=]+)
also, you can test this: /http(s)?://([a-z-.?=&])+&/g
const string = '/api/rss/feeds?url=http://any-feed-url.com?filter=hot&format=rss&url=http://any-feed-url.com?filter=latest&format=rss'
const string2 = '/api/rss/feeds?url=http://any-feed-url.com?filter=hot&format=rss&next=parm&url=http://any-feed-url.com?filter=latest&format=rss'
const regex = /url=([a-z:/.?=-]+&[a-z=]+)/g;
const regex2 = /http(s)?:\/\/([a-z-.?=&])+&/g;
console.log(string.match(regex))
console.log(string2.match(regex2))

have you tried to use split method ? instead of using regex.
const urlsArr = "/api/rss/feeds?url=http://any-feed-url-a.com?filter=hot&format=rss&url=http://any-feed-url-b.com?filter=rising&format=rss".split("url=");
urlsArr.shift(); // removing first item from array -> "/api/rss/feeds?"
console.log(urlsArr)
)
which is going to return ["/api/rss/feeds?", "http://any-feed-url-a.com?filter=hot&format=rss&", "http://any-feed-url-b.com?filter=rising&format=rss"] then i am dropping first item in array
if possible its better to use something else then regex CoddingHorror: regular-expressions-now-you-have-two-problems

You can matchAll the url's, then map the capture group 1 to an array.
str = '/api/rss/feeds?url=http://any-feed-url-a.com?filter=hot&format=rss&url=http://any-feed-url-b.com?filter=rising&format=rss'
arr = [...str.matchAll(/url=(.*?)(?=&url=|$)/g)].map(x => x[1])
console.log(arr)
But matchAll isn't supported by older browsers.
But looping an exec to fill an array works also.
str = '/api/rss/feeds?url=http://any-feed-url-a.com?filter=hot&format=rss&url=http://any-feed-url-b.com?filter=rising&format=rss'
re = /url=(.*?)(?=&url=|$)/g;
arr = [];
while (m = re.exec(str)) {
arr.push(m[1]);
}
console.log(arr)

If your input is better-formed in reality than shown in the question and you’re targeting a modern JavaScript environment, there’s URL/URLSearchParams:
const input = '/api/rss/feeds?url=http://any-feed-url-a.com?filter=hot%26format=rss&url=http://any-feed-url-b.com?filter=rising%26format=rss';
const url = new URL(input, 'http://example.com/');
console.log(url.searchParams.getAll('url'));
Notice how & has to be escaped as %26 for it to make sense.
Without this input in a standard form, it’s not clear which rules of URLs are still on the table.

javascript only get last number in chain

I have a bunch of numbers coming back from an api. It looks like this
1,2,3,4,5,6
Now i'm only wanting the last digit to be displayed rather than all of them.
How would i go about doing this? I need to add .slice on the end but im not sure what to put in the ()
Thanks
Sam

try this
.slice(-1)[0]
or
.slice(-1).pop()

var str = "1,2,3,4,5,6";
var _lastNum = str.slice(-1*(str.length - str.lastIndexOf(",")-1)); // Will return 6;

By far, voids answer seems to be the most comfortable and shortest one. But if you attempt to use at least one of the numbers at any time again, you may use something like this:
var str = "1,2,3,4,5,6"
str = str.split(',')
var lastNum = str[str.length-1]
As RobG wrote, you could also do
var lastNum = str.pop()

Array.shift() and modify value in a single line?

This Javascript code removes the first file name from a file list and then removes its extension:
var fileNoExt = filelist.shift();
fileNoExt = fileNoExt.substr(0, fileNoExt.lastIndexOf('.'));
I'm curious - is it possible to turn this code into a one-liner?

How about using a regex?
If you want to enforce an extension after the ., use
var fileNoExt = filelist.shift().replace(/\.[^.]+$/, '');
otherwise, use
var fileNoExt = filelist.shift().replace(/\.[^.]*$/, '');
The second one matches my_crazy_file. and my_crazy_file.extension while the first only matches my_crazy_file.extension.

Here's a one-liner:
var filelist = ['file.name.ext', 'some.another.string']
filelist.shift().split('.').slice(0, -1).join('.') // 'file.name'

"is it possible to turn this code into a one-liner?"
Yes,
var fileNoExt = filelist[0].substr(0, filelist.shift().lastIndexOf('.'));
but why? It's clearer on two lines.

remove full path, keep filename only

Trying to remove the full url that is being returned to imgurl:
Usually returns something like http://localhost/wordpress/wp-content/uploads/filename.jpg
or http://localhost/wordpress/wp-content/uploads/images/filename.jpg
I'd like to strip off everything except filename.jpg and return it to
ahng_photos_upload_image. Strip off everything to the last forward-slash.
How can I do that with Jquery?
window.send_to_editor = function(html) {
imgurl = jQuery('img',html).attr('src');
jQuery('#ahng_photos_upload_image').val(imgurl);
tb_remove();
}

You don't need jQuery for that, just plain old JavaScript will do :)
alert('http://localhost/wordpress/wp-content/uploads/filename.jpg'.split('/').pop());​​
In your case:
var filename = imgurl.split('/').pop();

you can use a regular expression in order to achieve this..
var file = imgUrl.replace(/^.*[\\\/]/, '');
Now the file would consist of only the file name ..

If you're pretty confident that the URLs don't have funny stuff like hashes or parameters, a regex like this would do it:
var filename = imgurl.replace(/^.*\/([^/]*)$/, "$1");
Also: don't forget to declare "imgurl" with var, and you should probably use .prop() instead of .attr() if your version of jQuery is 1.6 or newer:
var imgurl = jQuery('img', html).prop('src');
Also jQuery internally turns the two-argument form of the function into this:
var imgurl = jQuery(html).find('img').prop('src');
so you might as well code it that way.

One further option:
var filename = imgurl.substring(imgurl.lastIndexOf('/') + 1);
JS Fiddle demo.

Here you have
var filename = imgurl.split('/').slice(-1);
Good luck!

Try this one:
imgurl.split('/').slice(-1);
Edit: Look at the version of #Andy who uses the pop() method, the latter being faster than slice(-1).

Note that if you don't know if you have forward or backward slashes, you are better off using the RE version of split:
"path".split(/[\/\\]/).slice(-1)

Here is an answer that will work when your file name is like ./file.jpg
var extension = fileName.slice((fileName.lastIndexOf(".") - 1 >>> 0) + 2);
var baseName = fileName.replace(/^.*\/([^/]*)$/, "$1");
var path = fileName.replace(/(^.*\/)([^/]*)$/, "$1");

How to substring in jquery

How can I use jquery on the client side to substring "nameGorge" and remove "name" so it outputs just "Gorge"?
var name = "nameGorge"; //output Gorge

No jQuery needed! Just use the substring method:
var gorge = name.substring(4);
Or if the text you want to remove isn't static:
var name = 'nameGorge';
var toRemove = 'name';
var gorge = name.replace(toRemove,'');

Using .split(). (Second version uses .slice() and .join() on the Array.)
var result = name.split('name')[1];
var result = name.split('name').slice( 1 ).join(''); // May be a little safer
Using .replace().
var result = name.replace('name','');
Using .slice() on a String.
var result = name.slice( 4 );

Standard javascript will do that using the following syntax:
string.substring(from, to)
var name = "nameGorge";
var output = name.substring(4);
Read more here: http://www.w3schools.com/jsref/jsref_substring.asp

That's just plain JavaScript: see substring and substr.

You don't need jquery in order to do that.
var placeHolder="name";
var res=name.substr(name.indexOf(placeHolder) + placeHolder.length);

var name = "nameGorge";
name.match(/[A-Z].*/)[0]

Yes you can, although it relies on Javascript's inherent functionality and not the jQuery library.
http://www.w3schools.com/jsref/jsref_substr.asp
The substr function will allow you to extract certain parts of the string.
Now, if you're looking for a specific string or character to use to find what part of the string to extract, you can make use of the indexOf function as well.
http://www.w3schools.com/jsref/jsref_IndexOf.asp
The question is somewhat vague though; even just link text with 'name' will achieve the desired result. What's the criteria for getting your substring, exactly?

How about the following?
<script charset='utf-8' type='text/javascript'>
jQuery(function($) { var a=$; a.noConflict();
//assumming that you are using an input text
// element with the text "nameGorge"
var itext_target = a("input[type='text']:contains('nameGorge')");
//gives the second part of the split which is 'Gorge'
itext_target.html().split("nameGorge")[1];
...
});
</script>