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how can validate a mx server (similar to a domain) in the form of mx*.m**p.com by Regex? The first star can be any number without its length pre-defined 1, 11, 111, 1111, without leading 0s. The 2nd and 3rd stars are single letters in range of 0-9 and a-Z.
Examples:
mx1.m0bp.com
mx321.maBp.com
^mx[1-9][0-9]*\.m[0-9a-zA-Z]{2}p\.com$
^ indicates the start of the string
mx are the expected characters
[1-9] The number must not have a leading zero, so it must start with 1-9
[0-9]* Followed by zero or more other digits
\. The dot must be escaped as it has a special meaning
[0-9a-zA-Z]{2} Exactly two characters with the given range
p\.com again the next expected characters with another escaped dot
$ indicates the end of the string
Including the ^ and $ means you won't get a match from foomx1.m0bp.com or mx1.m0bp.comfoo
You can use the below regex to test the domain:
mx[0-9]+\.m[0-9a-zA-Z]{2}p\.com
console.log(/mx[0-9]+\.m[0-9a-zA-Z]{2}p\.com/gi.test("mx1.m0bp.com"))
console.log(/mx[0-9]+\.m[0-9a-zA-Z]{2}p\.com/gi.test("mx321.maBp.com"))
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I'm trying to validate an input with regEx in Vue, which I don't have any idea how to make one and couldn't find online how to match what I want to do.
The thing is I'm trying to validate a price that should be a float with 2 decimal numbers, and it can be 1 number before the . or 9 digits. For example:
0.50
1.00
99999.99
999999999.00
I tried this:
v => (/\d{1,3}(?:[.,]\d{3})*(?:[.,]\d{2})/.test(v))
But doesn't work.
Sorry if my english is not very good. I appreciate the help!
To match 1-9 digits before the dot, and 2 decimal numbers:
^\d{1,9}\.\d{1,2}$
See a regex101 demo.
What do you want? Check the value for matching a number from 0 to 999999999 in the integer part and no more than 2 numbers after "."?
A template assuming that the entire string being checked from the beginning (^) to the end ($) consists of
mandatory initial part, which is either 0 or contains from 1 to 9 digits, and does not start with "0" ;
optional ending of "." and two digits:
^([1-9]\d{0,8}|0)(.\d{1,2})?$
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I've been thinking of using this regex for phone numbers: /(\+\d{1,3})?(\d{9,10})$/
and I want to exclude these weird number patterns, as example the following regular expressions:
longer repeat "123123123": /\b(\d+)\1+\b/
repeat number "111111111": ^(\d)\1+$
I tried with this but i dont have idea of how to combine with the phone number regular expression: ^(\d)(?!\1+$)\d*$
You can use a negative lookahead to exclude all lines matching your forbidden pattern.
^(?!(\d+)\1+$)(\+\d{1,3})?(\d{9,10})$
^ // start of line
(?! // negative lookahead
(\d+)\1+$ // matches repeating groups of numbers
)
(\+\d{1,3})? // optional area code
(\d{9,10}) // phone number
$ // end of line
https://regex101.com/r/gaA9UN/3
Note that single repeated digits are already covered by the repeating groups pattern, since a single digit is recognized as a group of length one.
Update
With the updated requirement to also disallow leading repeating groups followed by non-repeating numbers, here's an updated version:
^(?!(\d{2,})\1+)(?!(\d+)\2{3,})(\+\d{1,3})?(\d{9,10})$
^ // start of line
(?!(\d{3,})\1+) // disallow three or more leading repeating digits
(?!(\d+)\2{3,}) // disallow 1 or 2 leading digits from
// repeating 4 or more times
(\+\d{1,3})? // optional area code
(\d{9,10}) // phone number
$ // end of line
https://regex101.com/r/gaA9UN/4
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The Phone Number Should Start with +65, Followed By 6|8|9 with Total of 11 Digits For Ex : +6598798765
Thank You
/\+65(6|8|9)\d{7}/g
\+ matches the character + literally (case sensitive)
65 matches the characters 65 literally (case sensitive)
1st Capturing Group (6|8|9)
1st Alternative 6 (6 matches the character 6 literally (case sensitive))
2nd Alternative 8 (8 matches the character 8 literally (case sensitive))
3rd Alternative 9 (9 matches the character 9 literally (case sensitive))
\d{7} matches a digit (equal to [0-9])
{7} Quantifier — Matches exactly 7 times
You should use the cap(^) to indicate start of a string and EOS($) to specify the end of string.
var re=/^\+65(6|8|9)\d{7}$/;
var true_mob = "+6561234567";
var false_mob = "+6512345678";
console.log(re.test(true_mob));
console.log(re.test(false_mob));
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I don't know how to handle the conditions I have listed below.
I can do one scenario at a time, but not sure how to encompass all restrictions on one field:
Allows 1, 2 or 3 total digits in the field
If user enters only 1 digit
It can only be a 5
If user enters 2 digits
‐ First digit can be 1-9
‐ Second digit can only be 0 or 5
If user enters 3 digits
‐ First digit can only be a 1
‐ Second digit can be 0-5
• If second digit is 0-4, third digit can only be 0 or 5
• If second digit is a 5, third digit can only be 0
Furthermore, if possible:
Each scenario can be followed by the characters .00 or not(the .00 should be optional for entry)
Use the alternation | token and…
You can use the alternation token | in conjunction with beginning ^ and end $ of line tokens to capture 1-, 2-, or 3-digit matches.
You can then optionally match the .00 string with a non-capturing group (?:) and the optional ? token to match zero or one of that group.
Update:
/^5(?:\.00)?$|^[1-9][05](?:\.00)?$|^1[0-4][05](?:\.00)?$|^150(?:\.00)?$/gm
Commenter bobble bubble provided this more concise version.
/^(?:5|[1-9][05]|1[0-4][05]|150)(?:\.00)?$/gm
Source: Regexper.com
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I want to ignore square brackets when using javascript regex [duplicate]
(4 answers)
Closed 8 years ago.
I have a very simple form with this regex pattern set on my first/last name fields ng-pattern="/^[a-zA-z]{2,30}$/" and both fields accept this value as being valid e.g. Tester\^*&^%. The first/last name should only accept alpha character a-zA-Z with a minimum of 2 characters and a max of 30.
Here is the wrong thing.
^[a-zA-z]{2,30}$
^
|
It would match \^ symbols because these symbols are comes under the range from A to z.
Modified regex.
^[a-zA-Z]{2,30}$