I have this form:
<form id='form'>
Begin time<input id="begintime" type="text" name="begintime"><br>
End time<input id="endtime" type="text" name="endtime"><br>
<input name="submit" type="submit" value="Submit">
</form>
on my website it looks like this:
the thing is that I don't want the web page to refresh. so I made this ajax post:
$(function () {
$('#form').on('submit', function (e) {
e.preventDefault();
var begin = $("#begintime").val();
var end = $("#endtime").val();
$.ajax({
type: 'post',
url: '',
data: {begin: begin, end: end},
success: function (result) {
$( result ).appendTo('p');
}
});
});
});
But every time is click on submit this happens:
also I use this to get the data:
<p>
<?php
$begin = $_POST['begin'];
$end = $_POST['end'];
?>
</p>
I have tried this:
$('p').empty();
I put tihs inside of ajax code this is the result is the same. What am I doing wrong? please help. and thank you.
Try the code below instead. It will clear everything inside the p tag and append the form to i
success: function (result) {
$('p').html(result);
}
You should just change the HTML, not append it like so
...
success: function (result) {
$('p').html(result);
}
...
Related
Im working on trying to get a button to run a php script with AJAX. To be clear I am really new to javaScript and PHP so my code might be completely wrong. I think that the problem is in my button click code not so much the ajax code. Any help is great
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
$(".submit").click(function myCall() {
var subdata = $("#form").serializeArray();
var request = $.ajax({
url: "construct_new.php",
type: "GET",
data: subdata
});
return false;
});
</script>
<div>
<form id="form">
Name of Product: <input type="text" name="productName" value="Enter Here">
<input type="button" name="submit" value="Submit" class="submit">
</form>
</div>
You need a DOM ready wrapper around the jQuery because it executes before the element exists (or is rendered by the browser).
You can use either $(function(){ }) or $(document).ready(function(){ });.
$(function(){
$(".submit").click(function myCall() {
var subdata = $("#form").serializeArray();
var request = $.ajax({
url: "construct_new.php",
type: "GET",
data: subdata
});
return false;
});
});
In this case, you don't need serializeArray() but simply serialize().
There is no success or complete function defined and so you wouldn't see anything when submitting this, unless of course you watch the developer console/net tab.
Also, using a form's submit event is preferred to the submit button's click event.
$(function(){
$("#form").submit(function myCall() {
var subdata = $(this).serialize();
var request = $.ajax({
url: "construct_new.php",
type: "GET",
data: subdata,
success : function(response){
console.log("success!");
}
});
return false;
});
});
Put your jQuery inside a document ready like this, and prevent the default action (to submit the form):
<script type="text/javascript">
$(document).ready(function(){
$(".submit").click(function(e) {
e.preventDefault();
var subdata = $("#form").serializeArray();
$.get("construct_new.php",{data: subdata}, function(){
console.log(data); // whatever returned by php
});
});
});
</script>
Document ready makes sure page has finished loading everything. e.preventDefault() stops the default action (for a form, submission, for an a tag, following the link).
what's up guys? look... I have a comment system for my web page... and I've been dealing with this little problem for a entire week. I really need some help here x_x ... the thing is that when a user leave a comment on my page, this comment is showed automatically thanks to ajax, that's ok...
each comment can be voted. and here's my problem... these divs that contain the forms for voting are build dynamically and the thing is that when I do click on the button for sending the form in any comment... the resulting data appears in all the comments! instead of appear in the specific one where the submit button was clicked, so I don't know what to do at this point, I hope you can give me a hand. this is my code
the form:
<label > Vote </label>
<form action="vote.php" method="POST" class="form-vote" id="form-vote">
<button class="icon-thumbs-up" id="icon-thumbs-up"></button>
<input hidden="hidden" type="text" name="num-comment" id="num-comment" value="'.$d['id'].'" >
<input hidden="hidden" type="text" name="point" id="point" value="'.$d['point'].'" >
<p id="actual-points" class="actual-points"> '.$d['point'].'</p>
<div id="result" class="result"> </div>
</form>
the script:
<script type="text/javascript">
$(document).ready function() {
$('.form-vote')on('submit', function() {
$.ajax({
type: 'POST',
url: $(this).attr('action'),
data: $(this).serialize(),
success: function(data) {
$('.actual-points').hide();
$('.result').html(data).fadeIn('slow');
}
})
return false;
});
})
</script>
Have you tried saving the 'this' object of the original event and using it inside the success function like this:
$('.form-vote')on('submit', function(e) {
e.preventDefault();
var $form = $(this); // Save here
$.ajax({
type: 'POST',
url: $(this).attr('action'),
data: $(this).serialize(),
success: function(data) {
// use here
$form.find('.actual-points').hide();
$form.find('.result').html(data).fadeIn('slow');
}
})
return false;
});
change this:
$('.result').html(data).fadeIn('slow');
to this:
$(this).find('.result').html(data).fadeIn('slow');
I've looked at many posts here on SO and I thought that what I have would work in terms of sending form data using AJAX without refreshing the page. Unfortunately it's not working and I'm at a loss to see what it going wrong so here is my code:
profile.php
<script>
$(function () {
$('form#commentform').on('commentsubmit', function(e) {
$.ajax({
type: 'post',
url: 'insertcomment.php',
data: $(this).serialize(),
success: function () {
alert('MUST ALERT TO DETERMINE SUCCESS PAGE');
$("#comment").val('');
}
});
e.preventDefault();
});
});
</script>
<form id='commentform' method='post'>
<textarea class='comment' id='comment'></textarea>
<input type='hidden' name='activityid' value='$activityid'>
//$activityid is the ID of the status so the database knows what status ID to connect the comment with
<input type='submit' name='commentsubmit' value='Comment'>
</form>
insertcomment.php
<?php
include 'header.php';
$activityid=htmlspecialchars($_POST['activityid'], ENT_QUOTES);
$comment=htmlspecialchars($_POST['comment'], ENT_QUOTES);
$commentsql=$conn->prepare('INSERT INTO wp_comments (user_id, activity_id, comment, datetime) VALUES (:userid, :friendid, :comment, CURRENT_TIMESTAMP)');
$commentsql->bindParam(':userid', $_SESSION['uid']);
$commentsql->bindParam(':activityid', $activityid);
$commentsql->bindParam(':comment', $comment);
$commentsql->execute();
include 'bottom.php';
?>
The end result hopefully is that the comment gets inserted into the database without refreshing the page and then the text area is reset.
As of right now when I click the comment submit button it refreshes the page.
try this:
$(document).ready(function(){
$('form#commentform').submit(function( e ) {
var postData = $(this).serializeArray();
$.ajax({
type: 'post',
url: 'insertcomment.php',
data: postData,
success: function () {
alert('MUST ALERT TO DETERMINE SUCCESS PAGE');
$("#comment").val('');
}
});
e.preventDefault();
});
});
i need help..why does my code not working?what is the proper way to get the data from a form.serialize? mines not working.. also am doing it right when passing it to php? also my php code looks awful and does not look like a good oop
html
<form action="" name="frm" id="frm" method="post">
<input type="text" name="title_val" value="" id="title_val"/>
post topic
</form>
<div id="test">
</div>
Javascript
$( document ).ready(function() {
$('#save').click(function() {
var form = $('#frm');
$.ajax({
url: 'topic.php',
type:'get',
data: form.serializeArray(),
success: function(response) {
$('#test').html(response);
}
});
});
});
Php
<?php
class test{
public function test2($val){
return $val;
}
}
$test = new test();
echo $test->test2($_POST['title_val']);
?>
OUTPUT
You're telling your ajax call to send the variables as GET variables, then trying to access them with the $_POST hyperglobal. Change GET to POST:
type:'post',
Also, it should be noted that you are binding your ajax call to the click on your submit button, so your form will still be posting. You should bind on the form's submit function instead and use preventDefault to prevent the form posting.
$('#frm').submit(function(e) {
e.preventDefault(); // stop form processing normally
$.ajax({
url: 'topic.php',
type: 'post',
data: $(this).serializeArray(),
success: function(response) {
$('#test').html(response);
}
});
});
Here is my html form
<div id=create>
<form action=index.php method=get id=createform>
<input type=text name=urlbox class=urlbox>
<input type=submit id=createurl class=button value=go>
</form>
</div>
<div id=box>
<input type=text id=generated value="your url will appear here">
</div>
Here is the javascript im trying to use to accomplish this;
$(function () {
$("#createurl").click(function () {
var urlbox = $(".urlbox").val();
var dataString = 'url=' + urlbox;
if (urlbox == '') {
alert('Must Enter a URL');
}else{
$("#generated").html('one moment...');
$.ajax({
type: "GET",
url: "api-create.php",
data: dataString,
cache: false,
success: function (html) {
$("#generated").prepend(html);
}
});
}return false;
});
});
when i click the submit button, nothing happens, no errors, and the return data from api-create.php isnt shown.
the idea is that the new data from that php file will replace the value of the textbox in the #box div.
i am using google's jquery, and the php file works when manually doing the get request, so ive narrowed it down to this
Because you're binding to the submit click instead of the form's submit.. try this instead:
$('#createForm').submit(function() {
// your function stuff...
return false; // don't submit the form
});
Dan's answer should fix it.
However, if #createurl is not a submit/input button, and is a link styled with css etc., you can do this:
$('#createurl').click(function () {
$('#createForm').submit();
});
$('#createForm').submit(function () {
// all your function calls upon submit
});
There is great jQuery plugin called jQuery Form Plugin. All you have to do is just:
$('#createform').ajaxForm(
target: '#generated'
});