Writing a React hook to handle multiple divs visibility on mouse click - javascript

Just started to learn about Reack hooks but I cannot figure out if it is possible to write a simple hook (or should I use some other approach, e.g. useEffect along with useState) in order to control visibility of multiple elements by clicking on different buttons on page.
Let's say I have a simple app with 2 buttons and 2 "modal" windows:
const App = () => {
const [firstModalOpen, toggleFirstModal] = useState(false);
const [secondModalOpen, toggleSecondModal] = useState(false);
return (
<div>
<button onClick={() => toggleFirstModal(true)}>Open First Modal</button>
<button onClick={() => toggleSecondModal(true)}>Open Second Modal</button>
<FirstModal
{...props}
show={firstModalOpen}
toggleModal={toggleFirstModal}
/>
<SecondModal
{...props}
show={secondModalOpen}
toggleModal={toggleSecondModal}
/>
</div>
)
}
const FirstModal = (props) => {
const { toggleModal, ...rest } = props;
return (
<Modal
{ ...rest }
show={firstModalOpen}
onHide={() => props.toggleModal(false)}
>
First modal content...
</Modal>
)
}
const SecondModal = (props) => {
const { toggleModal, ...rest } = props;
return (
<Modal
{ ...rest }
show={secondModalOpen}
onHide={() => props.toggleModal(false)}
>
Second modal content...
</Modal>
)
}
// state hook attempt
const useToggleModal = () => (init) => {
const [show, setToggleModal] = useState(init);
const toggleModal = () => setToggleModal(!show);
return { show, toggleModal };
};
Since those are react-bootstrap modal windows, they use show and onHide properties to determine/handle visibility and I have to pass rest prop to avoid some side-effects.
If I'd use my hook attempt in my app, I'd handle both modals on any button click so I came up with the idea to pass a string (to both, buttons and modals) which would tell which modal exactly to handle, but that approach for some reason looked a bit wrong.
Is there a "smarter" way in React to handle this internally instead of passing strings around?

If you have multiple modals and only one of them needs to open at once, then you must use a single state which stores which modal is opened, kind of like a string having the id of the modal. However if you want to open multiple modals, you would store the isOpen prop differently
For the first case you would write your code like
const App = () => {
const [openModal, toggleModal] = useState('');
return (
<div>
<button onClick={() => toggleModal('first')}>Open First Modal</button>
<button onClick={() => toggleModal('second')}>Open Second Modal</button>
<FirstModal
{...props}
show={openModal === 'first'}
toggleModal={toggleModal}
/>
<SecondModal
{...props}
show={secondModalOpen}
toggleModal={toggleModal}
/>
</div>
)
}
const FirstModal = (props) => {
const { toggleModal, ...rest } = props;
return (
<Modal
{ ...rest }
show={firstModalOpen}
onHide={() => props.toggleModal('first')}
>
First modal content...
</Modal>
)
}
const SecondModal = (props) => {
const { toggleModal, ...rest } = props;
return (
<Modal
{ ...rest }
show={secondModalOpen}
onHide={() => props.toggleModal('second')}
>
Second modal content...
</Modal>
)
}
For the second case it would be as you have written in your example, the only optimisation you can do for the second case is to store an array of modal objects and render them dynamically or let each modal handle its own toggle states and use useImperativeHandle to provide methods which parent can call to child modals like
const App = () => {
const firstRef = useRef(null);
const secondRef = useRef(null);
return (
<div>
<button onClick={() => this.firstRef.current.toggleModal()}>Open First Modal</button>
<button onClick={() => this.secondRef.current.toggleModal()}>Open Second Modal</button>
<FirstModal
{...props}
ref={firstRef}
/>
<SecondModal
{...props}
ref={secondRef}
/>
</div>
)
}
const FirstModal = forwardRef((props, ref) => {
const { showModal, toggleModal } = useToggleModal(false, ref);
return (
<Modal
{ ...rest }
show={showModal}
onHide={toggleModal}
>
First modal content...
</Modal>
)
})
const SecondModal = forwardRef((props, ref) => {
const { showModal, toggleModal } = useToggleModal(false, ref);
return (
<Modal
{ ...props }
show={showModal}
onHide={toggleModal}
>
Second modal content...
</Modal>
)
})
// state hook attempt
const useToggleModal = (init, ref) => {
const [show, setToggleModal] = useState(init);
const toggleModal = () => setToggleModal(!show);
useImperativeHandle(ref, () => ({
toggleModal
}))
return { show, toggleModal };
};

Related

How to call from outside a hook in a component included by another component?

I have a very basic react component like this
const Message = (props) => {
const [show, setShow] = useState(false);
return (
<p show={show}>My Message</p>
);
};
I want to use this component from another one, and I want to be able to show the first one by clicking on a button in the second one
const OtherComponent = (props) => {
return (
<>
<Message />
<Button onClick={setShow(true)}>Open Message</Button>
</>
);
};
of course this code does not work, is there a way to achieve this or is Redux my only option?
Move state to parent
const Message = ({ show }) => {
return (
<p show={show}>My Message</p>
);
};
const OtherComponent = (props) => {
const [show, setShow] = useState(false);
return (
<>
<Message show={show} />
<Button onClick={setShow(true)}>Open Message</Button>
</>
);
};

Input element losing it's focus after key press when it's controlled from outside the Modal (which uses Portal)

[Solved] My input component is losing focus as soon as I press any key only when its value is controlled from outside the portal
NOTE: I am sorry. While writing this, I found the problem in my code, but I decided to post this anyway
[Reason] I was inlining the close function, so the useEffect hook got triggered every time close changed when the component was rendered again due to state changes and thus calling the activeElement.blur() on each keystroke.
Portal
const root = document.getElementById('root')
const modalRoot = document.getElementById('modal-root')
const Portal = ({ children, className, drawer = false }) => {
const element = React.useMemo(() => document.createElement('div'), [])
React.useEffect(() => {
element.className = clsx('modal', className)
modalRoot.appendChild(element)
return () => {
modalRoot.removeChild(element)
}
}, [element, className])
return ReactDOM.createPortal(children, element)
}
Modal
const Modal = (props) => {
const { children, show = false, close, className } = props
const backdrop = React.useRef(null)
const handleTransitionEnd = React.useCallback(() => setActive(show), [show])
const handleBackdropClick = React.useCallback(
({ target }) => target === backdrop.current && close(),
[]
)
const handleKeyUp = React.useCallback(
({ key }) => ['Escape'].includes(key) && close(),
[]
)
React.useEffect(() => {
if (backdrop.current) {
window.addEventListener('keyup', handleKeyUp)
}
if (show) {
root.setAttribute('inert', 'true')
document.body.style.overflow = 'hidden'
document.activeElement.blur?.() // ! CULPRIT
}
return () => {
root.removeAttribute('inert')
document.body.style.overflow = 'auto'
window.removeEventListener('keyup', handleKeyUp)
}
}, [show, close])
return (
<>
{show && (
<Portal className={className}>
<div
ref={backdrop}
onClick={handleBackdropClick}
onTransitionEnd={handleTransitionEnd}
className={clsx('backdrop', show && 'active')}>
<div className="content">{children}</div>
</div>
</Portal>
)}
</>
)
}
Custom Textfield
const TextField = React.forwardRef(
({ label, className, ...props }, ref) => {
return (
<div className={clsx('textfield', className)}>
{label && <label>{label}</label>}
<input ref={ref} {...props} />
</div>
)
}
)
I was inlining the close function, so the useEffect hook got triggered every time close changed when the component was rendered again due to state changes and thus calling the activeElement.blur() on each keystroke.
In Modal.jsx
...
React.useEffect(() => {
...
if (show) {
root.setAttribute('inert', 'true')
document.body.style.overflow = 'hidden'
document.activeElement.blur?.() // ! CULPRIT
}
...
}, [show, close]) // as dependency
...
<Modal
show={show}
close={() => setShow(false)} // this was inlined
className="some-modal"
>
...
</Modal>
TAKEAWAY
Do not inline functions
Usually there is no reason to pass a function (pointer) as dependency

How to render a popup by calling a function?

I want to render an element in React just by calling a function.
Usually you'd use a component (let's say a Popup) that takes a boolean from state to make it appear or not and change it with some callback handler. Something like this:
import React, { useState } from "react";
import Popup from "somecomponentlibrary";
import { Button } from "pathtoyourcomponents";
export const SomeComponent = () => {
const [open, setOpen] = useState(false);
return (
<>
<Button onClick={() => { setOpen(true); }}>
this opens a modal
</Button>
<Popup type={"info"} open={open} timeout={1000}>
text within modal
<Button onClick={() => { setOpen(false); }}></Button>
</Popup>
</>
);
};
I was wondering if instead of returning it in the component as above I could just call some method to just show it on the screen like that:
import React from "react";
import { Button, popup } from "pathtoyourcomponents";
export const SomeComponent = () => {
return (
<>
<Button onClick={() => { popup.info("text within modal", 1000); }}>
this opens a modal
</Button>
</>
);
};
How do I write the popup function in order to render a Popup component in the DOM in such way?
You can use ReactDOM.render to render the popup when the function is called:
const node = document.createElement("div");
const popup = (message, {type, timeout}) => {
document.body.appendChild(node);
const PopupContent = () => {
return (
<Popup type={type} open={true} timeout={timeout}>
{message}
<button
onClick={clear}
>Close</button>
</Popup >
);
};
const clear = () => {
ReactDOM.unmountComponentAtNode(node);
node.remove();
}
ReactDOM.render(<PopupContent/>, node);
};
Then call the popup function:
<Button onClick={() => { popup("text within modal", {type: "info", timeout: 1000}); }}>
this opens a modal
</Button>
I made an imperative API for a popup a while back, it allows you to await it until it closes, and even receive input to the caller (you might as well send back the button the user pressed):
const PopupContext = createContext()
export const PopupProvider = ({children}) => {
const [open, setOpen] = useState(false)
const [input, setInput] = useState('')
const resolver = useRef()
const handleOpen = useCallback(() => {
const { promise, resolve } = createDeferredPromise()
resolver.current = resolve
setInput('')
setOpen(true)
return promise
}, [])
const handleClose = useCallback(() => {
resolver.current?.(input)
setOpen(false)
}, [])
return <PopupContext.Provider value={handleOpen}>
{children}
<Popup type={"info"} open={open} timeout={1000} onClose={handleClose}>
<input value={input} onChange={e => setValue(e.target.value)}/>
<Button onClick={handleClose}/>
</Popup>
</PopupContext.Provider>
}
export const usePopup = () => {
const context = useContext(PopupContext);
if (!context)
throw new Error('`usePopup()` must be called inside a `PopupProvider` child.')
return context
}
// used to let await until the popup is closed
const createDeferredPromise = func => {
let resolve, reject
const promise = new Promise((res, rej) => {
resolve = res
reject = rej
func?.(resolve, reject)
})
return { promise, resolve, reject }
}
You can wrap you app with the provider:
return <PopupProvider>
<App/>
</PopupProvider>
And use it inside your functional components:
const MyComponent = props => {
const popup = usePopup()
return <Button onClick={e => {
const input = await popup()
console.log('popup closed with input: ' + input)
}/>
}
You can do much more interesting stuff, as pass prompt text to the popup function to show in the popup etc. I'll leave this up to you.
You might also want to memoize your top level component being wrapped to avoid rerendering the entire application on popup open/close.
The popup can be rendered as a new separate React app but can still be made to share state with the main app like below.
import React, { useEffect } from "react";
import { render, unmountComponentAtNode } from "react-dom";
const overlay = {
top: "0",
height: "100%",
width: "100%",
position: "fixed",
backgroundColor: "rgb(0,0,0)"
};
const overlayContent = {
position: "relative",
top: "25%",
textAlign: "center",
margin: "30px",
padding: "20px",
backgroundColor: "white"
};
let rootNode;
let containerNode;
function Modal({ children }) {
useEffect(() => {
return () => {
if (rootNode) {
rootNode.removeChild(containerNode);
}
containerNode = null;
};
}, []);
function unmountModal() {
if (containerNode) {
unmountComponentAtNode(containerNode);
}
}
return (
<div style={overlay}>
<div style={overlayContent}>
{children}
<button onClick={unmountModal}>Close Modal</button>
</div>
</div>
);
}
/* additional params like props/context can be passed */
function renderModal(Component) {
if (containerNode) {
return;
}
containerNode = document.createElement("div");
rootNode = document.getElementById("root");
containerNode.setAttribute("id", "modal");
rootNode.appendChild(containerNode);
render(<Modal>{Component}</Modal>, containerNode);
}
const App = () => {
const ModalBody = <p>This is a modal</p>;
return (
<div>
<button onClick={() => renderModal(ModalBody)}>Open Modal</button>
</div>
);
};
render(<App />, document.getElementById("root"));
Yes, I think you can make it.
for example:
Use popup component
import React, { useState } from "react";
import Popup from "somecomponentlibrary";
import { Button } from "pathtoyourcomponents";
export const SomeComponent = () => {
const [open, setOpen] = useState(false);
return (
<>
<Button onClick={() => { setOpen(true); }}>
this opens a modal
</Button>
<Popup type={"info"} open={open} timeout={1000}>
text within modal
<Button onClick={() => { setOpen(false); }}></Button>
</Popup>
</>
);
};
Define pop-up component
const Popup = (props) => {
return(
<div style={{zIndex:props.open?"-100":"100", transition: `all ${props.timeout /
1000}s`, opacity: props.open?1:0}}>
{props.children}
</div>
)
}
I think you can customize the animation effect you like.

Invalid Hook Call for React?

I'm trying to update the state of my component, but for some reason it keeps saying Uncaught Error: Invalid hook call. Hooks can only be called inside of the body of a function component.
I'm trying to have a modal that opens onclick of a <div>. Within that modal is a text input that will update the state (notes). For some reason it's saying invalid hook call - why is that?
const openTestModal = () => {
let [notes, setNotes] = useState("");
let [openModal, setOpenModal] = useState(true);
let modalBody =
<div>
<TextInput
value={notes}
onChange={(value) => setNotes(value)}
/>
</div>
return (
<Modal
open={openModal}
onCancel={() => setOpenModal(false)}
onConfirm={() => console.log('works')}
body={modalBody}
/>
)
};
const TestHooks = () => {
return (
<div onClick={() => openTestModal()}>
Test
</div>
)
};
Seems like you tried to render testModal in react as an event, which's not a way to go, at all. Instead you must render your testModal as component, like that, so click on Test div will open your modal:
const TestModal = () => {
const [notes, setNotes] = useState("");
const modalBody = (
<div>
<TextInput
value={notes}
onChange={(value) => setNotes(value)}
/>
</div>
)
return (
<Modal
open={openModal}
onCancel={() => setOpenModal(false)}
onConfirm={() => console.log('works')}
body={modalBody}
/>
)
};
const TestHooks = () => {
const [openModal, setOpenModal] = useState(false);
return (
<React.Fragment>
<TestModal openModal={openModal} setOpenModal={setOpenModal} />
<div onClick={() => setOpenModal(true)}>
Test
</div>
<React.Fragment>
)
};
Hope it helps :)
It's not working because your testHooks is calling to setState from a separate component. Add you testHooks code into your openTestModal component. It would work as is if TestHooks was a child of openTestModal as well.

Can i set state in parent from child using useEffect hook in react

I have a set of buttons in a child component where when clicked set a corresponding state value true or false. I have a useEffect hook in this child component also with dependencies on all these state values so if a button is clicked, this hook then calls setFilter which is passed down as a prop from the parent...
const Filter = ({ setFilter }) => {
const [cycling, setCycling] = useState(true);
const [diy, setDiy] = useState(true);
useEffect(() => {
setFilter({
cycling: cycling,
diy: diy
});
}, [cycling, diy]);
return (
<Fragment>
<Row>
<Col>
<Button block onClick={() => setCycling(!cycling)}>cycling</Button>
</Col>
<Col>
<Button block onClick={() => setdIY(!DIY)}>DIY</Button>
</Col>
</Row>
</Fragment>
);
};
In the parent component I display a list of items. I have two effects in the parent, one which does an initial load of items and then one which fires whenever the filter is changed. I have removed most of the code for brevity but I think the ussue I am having boils down to the fact that on render of my ItemDashboard the filter is being called twice. How can I stop this happening or is there another way I should be looking at this.
const ItemDashboard = () => {
const [filter, setFilter] = useState(null);
useEffect(() => {
console.log('on mount');
}, []);
useEffect(() => {
console.log('filter');
}, [filter]);
return (
<Container>..
<Filter setFilter={setFilter} />
</Container>
);
}
I'm guessing, you're looking for the way to lift state up to common parent.
In order to do that, you may bind event handlers of child components (passed as props) to desired callbacks within their common parent.
The following live-demo demonstrates the concept:
const { render } = ReactDOM,
{ useState } = React
const hobbies = ['cycling', 'DIY', 'hiking']
const ChildList = ({list}) => (
<ul>
{list.map((li,key) => <li {...{key}}>{li}</li>)}
</ul>
)
const ChildFilter = ({onFilter, visibleLabels}) => (
<div>
{
hobbies.map((hobby,key) => (
<label {...{key}}>{hobby}
<input
type="checkbox"
value={hobby}
checked={visibleLabels.includes(hobby)}
onChange={({target:{value,checked}}) => onFilter(value, checked)}
/>
</label>))
}
</div>
)
const Parent = () => {
const [visibleHobbies, setVisibleHobbies] = useState(hobbies),
onChangeVisibility = (hobby,visible) => {
!visible ?
setVisibleHobbies(visibleHobbies.filter(h => h != hobby)) :
setVisibleHobbies([...visibleHobbies, hobby])
}
return (
<div>
<ChildList list={visibleHobbies} />
<ChildFilter onFilter={onChangeVisibility} visibleLabels={visibleHobbies} />
</div>
)
}
render (
<Parent />,
document.getElementById('root')
)
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.12.0/umd/react.production.min.js"></script><script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.11.0/umd/react-dom.production.min.js"></script><div id="root"></div>
Yes, you can, useEffect in child component which depends on the state is also how you typically implement a component which is controlled & uncontrolled:
const NOOP = () => {};
// Filter
const Child = ({ onChange = NOOP }) => {
const [counter, setCounter] = useState(0);
useEffect(() => {
onChange(counter);
}, [counter, onChange]);
const onClick = () => setCounter(c => c + 1);
return (
<div>
<div>{counter}</div>
<button onClick={onClick}>Increase</button>
</div>
);
};
// ItemDashboard
const Parent = () => {
const [value, setState] = useState(null);
useEffect(() => {
console.log(value);
}, [value]);
return <Child onChange={setState} />;
};

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