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Async Promise returns undefined or zone aware promise

When calling a function that returns a promise, comes back as undefined unless async operators are removed, then returns ZoneAwarePromise, but contains no data.
I know the query returns data when the function executes, it however does not seem to pass that data to the actual return part of the function call.
I have looked at several Stack questions that have not answered this question including this question:
Async/Await with Request-Promise returns Undefined
This is using a REST endpoint to pull data, the console.logs do show the data is correct, however return comes back as undefined
this.allPeople.forEach(async person => {
const dodString = await this.getRelatedRecords(person); //undefined
}
This is the main function that returns a promise / data
async getRelatedRecords(person) {
// function truncated for clarity
// ...
//
console.warn('This async should fire first');
selPeopleTable.relationships.forEach(relationship => {
allRelationshipQueries.push(
arcgisService.getRelatedTableData(
selPeopleTable.url, [person[oidField.name]], relationship.id, relationship.name),
);
});
await Promise.all(allRelationshipQueries).then(allResults => {
console.log('Inside the Promise');
// The Specific node I am looking for
const data = allResults[1].results.relatedRecordGroups[0].relatedRecords[0].attributes.dod;
console.log(data); // Shows correctly as the data I am looking for
return data;
}).catch(function(data){
console.log('there might be data missing', data);
});
}
Removing the ASYNC operators cause the getRelatedRecords() to fire after the containing function and / or return a 'ZoneAwarePromise' which contains no data. I need getRelatedRecords() to fire first, then to run the rest of the code.
I can provide more snippets if need be.
Zone Aware Promise
When the Async operators are (I think) setup correctly

You need to return this as well:
await Promise.all(allRelationshipQueries).then(allResults => {
console.log('Inside the Promise');
// The Specific node I am looking for
const data = allResults[1].results.relatedRecordGroups[0].relatedRecords[0].attributes.dod;
console.log(data); // Shows correctly as the data I am looking for
return data;
})
return in the above block is returning but all of this is in the scope of the arrow function which is then(allResults => { so you also need to return this function like this:
return await Promise.all(allRelationshipQueries).then(allResults => {
Approach #2:
Second way would be to store that into variable like this:
let dataToReturn = await Promise.all(allRelationshipQueries).then(allResults => {
console.log('Inside the Promise');
// The Specific node I am looking for
const data = allResults[1].results.relatedRecordGroups[0].relatedRecords[0].attributes.dod;
console.log(data); // Shows correctly as the data I am looking for
return data;
}).catch(function(data){
console.log('there might be data missing', data);
});
return dataToReturn;

Get undefined when returning a value from an array - Node JS

I'm new to NodeJS and I get some difficulties with its asynchronous nature.
I'm requesting some data using a async function. My second function is used to retrieve an ID while knowing the name (both info are stored in the data returned by the first function).
Everytime I get the 'Found it' in the console, but the return is executed before the loop is over and I get an 'undefined'.
Should I use a callback or use async & await ? Even after lot of research about async & await and callbacks I can't figure a way to make it work !
async function getCustomers() {
try {
var customers = await axios({
//Query parameters
});
return customers;
}
catch (error) {
console.log(error);
}
}
function getCustomerId(customerName){
var customerId = null;
getCustomers().then(function(response){
for (const i of response.data){
console.log(i['name']);
if(i['name'] == customerName){
console.log('Found it !'); //This got displayed in the console
customerId = i['id'];
return customerId; //This never return the desired value
}
}
});
}
console.log(getCustomerId('abcd'));
Thanks for any help provided !

You're printing the output of getCustomerId, but it doesn't return anything.
Try returning the Promise with:
return getCustomers().then(function(response) {...});
And then, instead of:
console.log(getCustomerId('abcd'));
You should try:
getCustomerId('abcd').then(function(id) {console.log(id);})
So that you are sure that the Promise is resolved before trying to display its output

Why do i get undefined, even when using a promise?

I am trying to use a promise to call a function getTweets.
Not using an AJAX call, but a simple promise 'call' from 1 javascript file to another.
The function works, but i keep getting 'undefined'.
I have read dozens of questions here on stackoverflow and have spent days
to understand promises, but still can't solve it.
var Twit = require('twit') // Imports the Twitter library
require('dotenv').config() // to get the environment vars into the app
// This is the function:
function getTweets (screen_name) {
let T = new Twit({ /* <twitter key and token here> */ });
T.get('statuses/user_timeline', { screen_name: screen_name, count: 3}, function (err, data, response) {
let myTweets = [];
for (let i in data) {
let text = data[i].text;
myTweets.push(text);
}
return myTweets;
})
}
module.exports.getTweets = getTweets;
And this is the promise that tries to get the tweets:
var promise = tweets.getTweets('dizid');
promise.then(
console.log(myTweets),
console.log(err))
// gives error: promise.then(
// ^
// TypeError: Cannot read property 'then' of undefined
Any help greatly appreciated.

Your problem is that you never return anything from your getTweets() function even though it needs to return a promise. The function calls T.get() and pass it a callback function. You return from this callback function but this doesn't do anything, it doesn't mean that this value gets returned from getTweets().
This is a pretty common mistake when it comes to working with asynchronous calls. What needs to be done is to make getTweets() return a promise that gets resolved when it should.
When working with asynchronous calls that don't implement the promise interface, you need to wrap this call with a new promise. Your getTweets() function should then look like this:
function getTweets (screen_name) {
let T = new Twit({ /* <twitter key and token here> */ });
return new Promise(function(resolve, reject) {
T.get('statuses/user_timeline', { screen_name: screen_name, count: 3}, function (err, data, response) {
if (err) {
reject(err); // Reject the promise since there was an error
} else {
let myTweets = [];
for (let i in data) {
let text = data[i].text;
myTweets.push(text);
}
resolve(myTweets); // Resolve the promise with the result
}
});
});
}
However, it seems the Twit API does support the promise interface, so instead of providing a callback function you can just use the promise created by T.get(). HMR's answer explains how to do this.
Another mistake you've made is with this code:
promise.then(
console.log(myTweets),
console.log(err))
The way you've written it, it reads "Run console.log(myTweets) and console.log(err), then invoke promise.then() with the result of the former as the first argument and the result of the latter as the second argument.
then() takes callback functions (which get invoked depending on the resolving/rejection of the promise) as arguments, so the code should look like this:
promise.then(
function(myTweets) {
console.log(myTweets);
},
function(err) {
console.log(err);
});
Async/await
If you're interested in taking things further, the modern approach to working with asynchronous code is async/await, which is syntactic sugar for promises that lets you write asynchronous code more similar to regular synchronous code.
A function marked as async will implicitly return a promise, but you write it as if you return a regular value. Using the await keyword inside an async function will implicitly wait for a promise to resolve and unwrap the resolved value. The main practical benefits of this is that you can use asynchronous calls in loops and handle errors with regular try-catch blocks. Your getTweets() function would look like this using async/await:
async function getTweets(screen_name) {
let T = new Twit({ /* <twitter key and token here> */ });
const data = await T.get('statuses/user_timeline', { screen_name: screen_name, count: 3});
// Let's also use map() instead of a for loop
let myTweets = data.map(function(item) { return item.text; });
return myTweets;
}

Since get seems to return a promise you don't need to use a callback. Get Tweets can look something like this:
// in getTweets
return T.get(
'statuses/user_timeline',
{ screen_name: screen_name, count: 3}
).then(
function (data) {
console.log("data:",JSON.stringify(data,undefined,2));
return data.map(item=>item.text);
}
)
// exports the function getTweets so that other modules can use it
module.exports.getTweets = getTweets;
If that didn't work please let us know what the output of the program is (update question).
You can call getTweets like so:
tweets.getTweets('dizid')
.then(
myTweets=>
console.log(myTweets),
err=>
console.log(err)
)

I think you forget add function like
promise.then(function(res){
//code
}

Your .then() should include a call back function.
promise.then( res => {
console.log(res);
});
edit: I'm using an ES6 syntax for arrow functions, in case you're new to that.

Accessing data returned from another function in JavaScript

I am trying to get the promise returned from another function. Here is my code:
function getData(){
var result = [];
return new Promise(function(resolve){
var query = firebase.database().ref('groups');
query.once('value').then(data => {
data.forEach(snapshot => {
var gdata = snapshot.val();
var grp = snapshot.key;
result.push(grp);
});
});
resolve(result);
});
}
I managed to print out the data for 'grp' variable from the function above. In my second fuction where I tried to access the data returned from promise:
However, from the second function, when I tried to print out in the .then(), nothing is actually printed out. Why is it so?
Thanks!

First, firebase already returns a Promise, so there's no need to create a new one. You should put the data into result and return the promise directly.
function getData() {
var query = firebase.database().ref('groups');
return query.once('value').then(data => {
let res = [];
data.forEach(snapshot => {
var gdata = snapshot.val();
var grp = snapshot.key;
res.push(grp);
});
return res;
});
}
You can then simply chain that
function plotData() {
return getData().then(data => {
data.forEach(console.log);
});
}

The bad news: If you need to use a .then() function to get the value you want (as with your firebase method) then you have to return a promise from your function. This is the case even for your inner function.
The good news is that .then() can be used to "convert" the return value of a function; and will even unravel returned promises for you (if, say, you decide you need to perform a second database call before you have your answer)
function getData(){
var query = firebase.database().ref('groups');
return query.once('value').then(data => {
var result = [];
data.forEach(snapshot => {
var gdata = snapshot.val();
var grp = snapshot.key;
result.push(grp);
});
return result;
});
resolve(result);
}
Take note how I return result inside of the .then() function. Since I'm returning the result of .then(), this will then evaluate to a promise that, rather than purely returning data, will return result.
I'm less certain what you're doing with the second block. You shouldn't need the Promise.all or map around getData unless you actually intend to call it multiple times; and given that your list is empty, it seems like it's not called at all.
DISCLAIMER: I know the promises concept well, but not firebase. If firebase has unique aspects to it that change how this should work, I may be wrong.

You resolve the promise too early. But don't create new promises if you don't need to:
function getData(){
var result = [];
var query = firebase.database().ref('groups');
return query.once('value').then(data => {
return data.map(snapshot => snapshot.key);
});
}

list.map() does not resolve, it is not a promise... Promise.all needs to receive a promise.
You probably wanted to invoke getData() there.

How do I wait for a promise to finish before returning the variable of a function?

I'm still struggling with promises, but making some progress thanks to the community here.
I have a simple JS function which queries a Parse database. It's supposed to return the array of results, but obviously due to the asynchronous nature of the query (hence the promises), the function returns before the results, leaving me with an undefined array.
What do I need to do to make this function wait for the result of the promise?
Here's my code:
function resultsByName(name)
{
var Card = Parse.Object.extend("Card");
var query = new Parse.Query(Card);
query.equalTo("name", name.toString());
var resultsArray = [];
var promise = query.find({
success: function(results) {
// results is an array of Parse.Object.
console.log(results);
//resultsArray = results;
return results;
},
error: function(error) {
// error is an instance of Parse.Error.
console.log("Error");
}
});
}

Instead of returning a resultsArray you return a promise for a results array and then then that on the call site - this has the added benefit of the caller knowing the function is performing asynchronous I/O. Coding concurrency in JavaScript is based on that - you might want to read this question to get a broader idea:
function resultsByName(name)
{
var Card = Parse.Object.extend("Card");
var query = new Parse.Query(Card);
query.equalTo("name", name.toString());
var resultsArray = [];
return query.find({});
}
// later
resultsByName("Some Name").then(function(results){
// access results here by chaining to the returned promise
});
You can see more examples of using parse promises with queries in Parse's own blog post about it.

What do I need to do to make this function wait for the result of the promise?
Use async/await (NOT Part of ECMA6, but
available for Chrome, Edge, Firefox and Safari since end of 2017, see canIuse)
MDN
async function waitForPromise() {
// let result = await any Promise, like:
let result = await Promise.resolve('this is a sample promise');
}
Added due to comment:
An async function always returns a Promise, and in TypeScript it would look like:
async function waitForPromise() {
// let result = await any Promise, like:
let result: Promise<string> = await Promise.resolve('this is a sample promise');
}

You're not actually using promises here. Parse lets you use callbacks or promises; your choice.
To use promises, do the following:
query.find().then(function() {
console.log("success!");
}, function() {
console.log("error");
});
Now, to execute stuff after the promise is complete, you can just execute it inside the promise callback inside the then() call. So far this would be exactly the same as regular callbacks.
To actually make good use of promises is when you chain them, like this:
query.find().then(function() {
console.log("success!");
return new Parse.Query(Obj).get("sOmE_oBjEcT");
}, function() {
console.log("error");
}).then(function() {
console.log("success on second callback!");
}, function() {
console.log("error on second callback");
});

You don't want to make the function wait, because JavaScript is intended to be non-blocking.
Rather return the promise at the end of the function, then the calling function can use the promise to get the server response.
var promise = query.find();
return promise;
//Or return query.find();