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I get an empty error when submitting multiple forms with file uploads with ajax in laravel

my problem is while posting multiple forms with ajax in laravel, I am sending the form data without any problem, but I cannot send the file.
File is empty error. I've been dealing with this for 2 days, there is no method I haven't tried, please help me.
Apart from that, I added multipart to the form, but it still didn't work, I'm sharing my codes with you.
Sorry for my bad english.
I want it to upload 2 photos in the normal 4th form until the createProduct3 form, I tried to get them by doing the normal new formData() and I tried otherwise and I couldn't succeed.
It sends it to Laravel server side as [Object File].
My Form
<form class="form" id="createProduct4" method="POST" action="">
<input type="file" class="upload-box-title" id="urun-fotografi" name="urun_fotografi" value="Fotoğraf Seç">
<input type="file" class="upload-box-title" id="urun-dosyasi" name="urun_dosyasi" value="Dosya Seç">
</form>
My blade ajax:
function createProducts()
{
var dataString = $("#createProduct1, #createProduct2, #createProduct3, #createProduct4").serialize();
let photo = document.getElementById("urun-dosyasi").files[0];
let photo2 = document.getElementById("urun-fotografi").files[0];
console.log(photo,photo2);
$.ajax({
url: "{{ route('user.product.create') }}",
type: "POST",
data: dataString+"&urun_dosyasi="+photo+"&urun_fotografi="+photo2,
success: function( data ) {
},
error: function(xhr)
{
console.log(xhr);
}
});
}
Server Function
public function createProduct(Request $request)
{
$file = $request->file('urun_dosyasi');
$file2 = $request->file('urun_fotografi');
$filename = $file->getClientOriginalName();
$extension = $file->getClientOriginalExtension();
$filename2 = $file2->getClientOriginalName();
$extension2 = $file2->getClientOriginalExtension();
echo $filename,$extension."2. doc: ".$filename2.$extension;
}

Use multipart/form-data when your form includes any <input type="file"> elements :
<form ... enctype="multipart/form-data">
Ajax :
var form = $('#createProduct4')[0];
var data = new FormData(form);
$.ajax({
url: "{{ route('user.product.create') }}",
type: "POST",
enctype: 'multipart/form-data',
data: data,
processData: false,
contentType: false,
success: function (data) {
console.log("SUCCESS : ", data);
},
error: function (e) {
console.log("ERROR : ", e);
}
});

How to upload a file from frontend using query string

I have one form with some fields in AngularJs. I want to add one more field in form to upload a file, Currently I am sending data to backend as json payload, how can I upload a file that's my question, I have one idea that is by using query string...
Anyone can please let me know how can I do this thing.
My code to upload text fields -
let settings = {
"url": "https://someurl",
"method": "POST",
"timeout": 0,
"headers": {
"Content-Type": "application/json",
},
"data": JSON.stringify(data)
};
$.ajax(settings).done(function (response) {
toastr["success"]("Form submitted succesfully.", "Success!");
setTimeout(function () {
window.location.href = "success.php";
}, 1500);
}).fail(function (err) {
toastr["error"]("Cannot submit your form.", "Failed!");
}
};
I am using AngularJs for the frontend.

Two ways:
1 - Use Json: You can convert file to base64 and push to server like simple JSON
Image convert to Base64
2 - Use FormData: change content type to: 'multipart/form-data'
and use formData in body like this
How to use FormData for AJAX file upload?

Try this :
<form name="myForm" ng-submit="_post(file,data)">
<input ng-model='file' type="file"/>
<input ng-model='data.name' type="text"/>
<input ng-model='data.age' type="number"/>
<input type="submit" value='Submit'/>
</form>
var _post = function (file, jsonData) {
$http({
url: your url,
method: "POST",
headers: { 'Content-Type': undefined },
transformRequest: function (data) {
var formData = new FormData();
formData.append("model", angular.toJson(data.model));
formData.append("file", data.files);
return formData;
},
data: { model: jsonData, files: file }
}).then(function (response) {
;
});
Working fiddle

ASP.net core Razor page file upload with AJAX Post to IFormFile handler returns 404 Not Found

I have a very simple task that just needs to upload a file and have the AJAX post it to the Index page:
<input type="file" id="file-selector" accept=".txt">
Associated Javascript:
const fileSelector = document.getElementById('file-selector');
fileSelector.addEventListener('change', (event) => {
const file = event.target.files[0];
const reader = new FileReader();
reader.addEventListener('load', event => {
const txtFile = event.target.result;
$.ajax({
type: "POST",
url: "/ControlData?handler=FileUploader",
error: function (request, status, error) { alert(request.responseText); },
data: txtFile,
cache: false,
contentType: false,
processData: false,
headers: { "RequestVerificationToken": "#token" }
});
});
reader.readAsText(file);
});
Code in /Pages/ControlData/Index.cshtml.cs:
public IActionResult OnPostFileUploaderAsync(IFormFile model)
{
return null;
}
The app runs fine, the file is selected, but the POST call always gets a 404:

The app runs fine, the file is selected, but the POST call always gets a 404
Please check if you configured page route with route data parameter, like #page "{title}" etc, which cause HTTP 404 error.
https://learn.microsoft.com/en-us/aspnet/core/razor-pages/razor-pages-conventions?view=aspnetcore-5.0#configure-a-page-route
https://www.learnrazorpages.com/razor-pages/routing#route-templates
needs to upload a file and have the AJAX post it to the Index page
Code in /Pages/ControlData/Index.cshtml.cs
public IActionResult OnPostFileUploaderAsync(IFormFile model)
To post selected file to your handler OnPostFileUploaderAsync, you can try modify the code like below.
<script>
const fileSelector = document.getElementById('file-selector');
fileSelector.addEventListener('change', (event) => {
const file = event.target.files[0];
//post the selected file through formdata
//instead of using the readAsText() method to read the contents of the specified file
var txtFile = new FormData();
txtFile.append("model", file);
$.ajax({
type: "POST",
url: "/ControlData/Index?handler=FileUploader",
error: function (request, status, error) { alert(request.responseText); },
data: txtFile,
cache: false,
contentType: false,
processData: false,
headers: { "RequestVerificationToken": "#token" }
});
});
</script>
Test Result

Processing AJAX data array via PHP - no $_POST occuring? [duplicate]

I'm using jQuery and Ajax for my forms to submit data and files but I'm not sure how to send both data and files in one form?
I currently do almost the same with both methods but the way in which the data is gathered into an array is different, the data uses .serialize(); but the files use = new FormData($(this)[0]);
Is it possible to combine both methods to be able to upload files and data in one form through Ajax?
Data jQuery, Ajax and html
$("form#data").submit(function(){
var formData = $(this).serialize();
$.ajax({
url: window.location.pathname,
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
<form id="data" method="post">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<button>Submit</button>
</form>
Files jQuery, Ajax and html
$("form#files").submit(function(){
var formData = new FormData($(this)[0]);
$.ajax({
url: window.location.pathname,
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
<form id="files" method="post" enctype="multipart/form-data">
<input name="image" type="file" />
<button>Submit</button>
</form>
How can I combine the above so that I can send data and files in one form via Ajax?
My aim is to be able to send all of this form in one post with Ajax, is it possible?
<form id="datafiles" method="post" enctype="multipart/form-data">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<input name="image" type="file" />
<button>Submit</button>
</form>

The problem I had was using the wrong jQuery identifier.
You can upload data and files with one form using ajax.
PHP + HTML
<?php
print_r($_POST);
print_r($_FILES);
?>
<form id="data" method="post" enctype="multipart/form-data">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<input name="image" type="file" />
<button>Submit</button>
</form>
jQuery + Ajax
$("form#data").submit(function(e) {
e.preventDefault();
var formData = new FormData(this);
$.ajax({
url: window.location.pathname,
type: 'POST',
data: formData,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
});
Short Version
$("form#data").submit(function(e) {
e.preventDefault();
var formData = new FormData(this);
$.post($(this).attr("action"), formData, function(data) {
alert(data);
});
});

another option is to use an iframe and set the form's target to it.
you may try this (it uses jQuery):
function ajax_form($form, on_complete)
{
var iframe;
if (!$form.attr('target'))
{
//create a unique iframe for the form
iframe = $("<iframe></iframe>").attr('name', 'ajax_form_' + Math.floor(Math.random() * 999999)).hide().appendTo($('body'));
$form.attr('target', iframe.attr('name'));
}
if (on_complete)
{
iframe = iframe || $('iframe[name="' + $form.attr('target') + '"]');
iframe.load(function ()
{
//get the server response
var response = iframe.contents().find('body').text();
on_complete(response);
});
}
}
it works well with all browsers, you don't need to serialize or prepare the data.
one down side is that you can't monitor the progress.
also, at least for chrome, the request will not appear in the "xhr" tab of the developer tools but under "doc"

I was having this same issue in ASP.Net MVC with HttpPostedFilebase and instead of using form on Submit I needed to use button on click where I needed to do some stuff and then if all OK the submit form so here is how I got it working
$(".submitbtn").on("click", function(e) {
var form = $("#Form");
// you can't pass Jquery form it has to be javascript form object
var formData = new FormData(form[0]);
//if you only need to upload files then
//Grab the File upload control and append each file manually to FormData
//var files = form.find("#fileupload")[0].files;
//$.each(files, function() {
// var file = $(this);
// formData.append(file[0].name, file[0]);
//});
if ($(form).valid()) {
$.ajax({
type: "POST",
url: $(form).prop("action"),
//dataType: 'json', //not sure but works for me without this
data: formData,
contentType: false, //this is requireded please see answers above
processData: false, //this is requireded please see answers above
//cache: false, //not sure but works for me without this
error : ErrorHandler,
success : successHandler
});
}
});
this will than correctly populate your MVC model, please make sure in your Model, The Property for HttpPostedFileBase[] has the same name as the Name of the input control in html i.e.
<input id="fileupload" type="file" name="UploadedFiles" multiple>
public class MyViewModel
{
public HttpPostedFileBase[] UploadedFiles { get; set; }
}

Or shorter:
$("form#data").submit(function() {
var formData = new FormData(this);
$.post($(this).attr("action"), formData, function() {
// success
});
return false;
});

EDIT: with the new version of JQuery (3.6), you could also try using contentType function argument instead of enctype. Try contentType: multipart/form-data.
For me, it didn't work without enctype: 'multipart/form-data' field in the Ajax request. I hope it helps someone who is stuck in a similar problem.
Even though the enctype was already set in the form attribute, for some reason, the Ajax request didn't automatically identify the enctype without explicit declaration (jQuery 3.3.1).
// Tested, this works for me (jQuery 3.3.1)
fileUploadForm.submit(function (e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: $(this).attr('action'),
enctype: 'multipart/form-data',
data: new FormData(this),
processData: false,
contentType: false,
success: function (data) {
console.log('Thank God it worked!');
}
}
);
});
// enctype field was set in the form but Ajax request didn't set it by default.
<form action="process/file-upload" enctype="multipart/form-data" method="post" >
<input type="file" name="input-file" accept="text/plain" required>
...
</form>
As others mentioned above, please also pay special attention to the contentType and processData fields.

A Simple but more effective way:
new FormData() is itself like a container (or a bag). You can put everything attr or file in itself.
The only thing you'll need to append the attribute, file, fileName eg:
let formData = new FormData()
formData.append('input', input.files[0], input.files[0].name)
and just pass it in AJAX request. Eg:
let formData = new FormData()
var d = $('#fileid')[0].files[0]
formData.append('fileid', d);
formData.append('inputname', value);
$.ajax({
url: '/yourroute',
method: 'POST',
contentType: false,
processData: false,
data: formData,
success: function(res){
console.log('successfully')
},
error: function(){
console.log('error')
}
})
You can append n number of files or data with FormData.
and if you're making AJAX Request from Script.js file to Route file in Node.js beware of using
req.body to access data (ie text)
req.files to access file (ie image, video etc)

The code below works for me
$(function () {
debugger;
document.getElementById("FormId").addEventListener("submit", function (e) {
debugger;
if (ValidDateFrom()) { // Check Validation
var form = e.target;
if (form.getAttribute("enctype") === "multipart/form-data") {
debugger;
if (form.dataset.ajax) {
e.preventDefault();
e.stopImmediatePropagation();
var xhr = new XMLHttpRequest();
xhr.open(form.method, form.action);
xhr.onreadystatechange = function (result) {
debugger;
if (xhr.readyState == 4 && xhr.status == 200) {
debugger;
var responseData = JSON.parse(xhr.responseText);
SuccessMethod(responseData); // Redirect to your Success method
}
};
xhr.send(new FormData(form));
}
}
}
}, true);
});
In your Action Post Method, pass parameter as HttpPostedFileBase UploadFile and make sure your file input has same as mentioned in your parameter of the Action Method.
It should work with AJAX Begin form as well.
Remember over here that your AJAX BEGIN Form will not work over here since you make your post call defined in the code mentioned above and you can reference your method in the code as per the Requirement
I know I am answering late but this is what worked for me

Just to remind, in 2022 you don't need to use jquery. Try js standard Fetch API
var formData = new FormData(this);
fetch(url, {
method: 'POST',
body: formData
})
.then(response => {
if(response.ok) {
//success
alert(response);
} else {
throw Error('Server error');
}
})
.catch(error => {
console.log('fail', error);
});

This is a solution that I implemented
var formData = new FormData();
var files = $('input[type=file]');
for (var i = 0; i < files.length; i++) {
if (files[i].value == "" || files[i].value == null) {
return false;
}
else {
formData.append(files[i].name, files[i].files[0]);
}
}
var formSerializeArray = $("#Form").serializeArray();
for (var i = 0; i < formSerializeArray.length; i++) {
formData.append(formSerializeArray[i].name, formSerializeArray[i].value)
}
$.ajax({
type: 'POST',
data: formData,
contentType: false,
processData: false,
cache: false,
url: '/Controller/Action',
success: function (response) {
if (response.Success == true) {
return true;
}
else {
return false;
}
},
error: function () {
return false;
},
failure: function () {
return false;
}
});

---Solution for DOT NET CORE MVC Implementation---
While looking at this question I though I should right .NET CORE implementation for this because the question is not specific to any backend language.
So guys here is the standalone implementation example.
Objective :- To submit form fields including files and how we can get data in a single model at backend
HTML Code / View Code - Views/Home/Index.cshtml
#{
ViewData["Title"] = "Home Page";
}
<input type="file" id="FileUpload1" multiple />
<div>
<label>Enter First Name :</label>
<input type="text" id="nameText" maxlength="50" />
</div>
<input type="button" id="btnUpload" value="Submit Form with Files" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script>
$(document).ready(function () {
$('#btnUpload').click(function () {
// Checking whether FormData is available in browser
if (window.FormData !== undefined) {
var fileUpload = $("#FileUpload1").get(0);
var files = fileUpload.files;
// Create FormData object
var fileData = new FormData();
// Looping over all files and add it to FormData object
for (var i = 0; i < files.length; i++) {
fileData.append("files", files[i]);
}
// Adding one more key to FormData object
fileData.append('FirstName', $("#nameText").val());
$.ajax({
url: '/Home/UploadFiles',
type: "POST",
contentType: false, // Not to set any content header
processData: false, // Not to process data
data: fileData,
success: function (result) {
alert(result);
},
error: function (err) {
alert(err.statusText);
}
});
} else {
alert("FormData is not supported.");
}
});
});
</script>
Backend Code / Controller action method Controllers/HomeController.cs
public class HomeController : Controller
{
private readonly ILogger<HomeController> _logger;
private readonly IWebHostEnvironment _environment;
public HomeController(ILogger<HomeController> logger, IWebHostEnvironment environment)
{
_logger = logger;
_environment = environment;
}
public IActionResult Index()
{
return View();
}
public IActionResult Privacy()
{
return View();
}
[HttpPost]
public async Task<IActionResult> UploadFiles(MyForm myForm)
{
var files = myForm.Files;
// First Name
string name = myForm.FirstName;
// check All files
foreach (IFormFile source in files)
{
string filename = ContentDispositionHeaderValue.Parse(source.ContentDisposition).FileName.Trim('"');
filename = this.EnsureCorrectFilename(filename);
string fileWithPath = this.GetPathAndFilename(filename);
// Create directory if not exist
Directory.CreateDirectory(Path.GetDirectoryName(fileWithPath));
using (FileStream output = System.IO.File.Create(fileWithPath))
await source.CopyToAsync(output);
}
return Ok("Success");
}
[ResponseCache(Duration = 0, Location = ResponseCacheLocation.None, NoStore = true)]
public IActionResult Error()
{
return View(new ErrorViewModel { RequestId = Activity.Current?.Id ?? HttpContext.TraceIdentifier });
}
public class MyForm
{
public string FirstName { get; set; }
public IList<IFormFile> Files { get; set; }
}
private string EnsureCorrectFilename(string filename)
{
if (filename.Contains("\\"))
filename = filename.Substring(filename.LastIndexOf("\\") + 1);
return filename;
}
private string GetPathAndFilename(string filename)
{
return Path.Combine(_environment.ContentRootPath, "uploadedFiles", filename);
}
}
Full Source Code Repo: https://github.com/rj-learning/DotNetCoreFileUpload

In my case I had to make a POST request, which had information sent through the header, and also a file sent using a FormData object.
I made it work using a combination of some of the answers here, so basically what ended up working was having this five lines in my Ajax request:
contentType: "application/octet-stream",
enctype: 'multipart/form-data',
contentType: false,
processData: false,
data: formData,
Where formData was a variable created like this:
var file = document.getElementById('uploadedFile').files[0];
var form = $('form')[0];
var formData = new FormData(form);
formData.append("File", file);

you can just append them on your formdata, add your files and datas in it.you can read this..
https://developer.mozilla.org/en-US/docs/Web/API/FormData/append
for better understanding. you can separately retrieve them $_FILES for your files and $_POST for your data.

<form id="form" method="post" action="otherpage.php" enctype="multipart/form-data">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<input name="image" type="file" />
<button type='button' id='submit_btn'>Submit</button>
</form>
<script>
$(document).on("click", "#submit_btn", function (e) {
//Prevent Instant Click
e.preventDefault();
// Create an FormData object
var formData = $("#form").submit(function (e) {
return;
});
//formData[0] contain form data only
// You can directly make object via using form id but it require all ajax operation inside $("form").submit(<!-- Ajax Here -->)
var formData = new FormData(formData[0]);
$.ajax({
url: $('#form').attr('action'),
type: 'POST',
data: formData,
success: function (response) {
console.log(response);
},
contentType: false,
processData: false,
cache: false
});
return false;
});
</script>
///// otherpage.php
<?php
print_r($_FILES);
?>

Upload to Image Server using jQuery as Relay

Problem:
I have a situation where I'd like to upload a file (pdf, image, etc.) to an API Endpoint that accepts one of these types of files. However, the file is located on another web service somewhere. I'm trying to devise a clever solution that will allow me to (a) download the remote file (and store it as bytes in memory or something) then (b) upload that file through the API.
I have jQuery code that demonstrates how to upload a local file using jQuery with no backend code, but I'd like to extend it to allow me to upload something that is stored remotely.
Constraints:
I don't want to use any backend infrastructure on my image uploading page (ie. no php, python, ruby, etc.)
I don't want the end user of my form to need to download the file to their machine and upload the file as a two-step process.
What I've got so far:
I've seen some solutions on SO that kind-of connect the dots here in terms of downloading a file as a bytearray, but nothing that demonstrates how you might upload that.
Download File from Bytes in JavaScript
jQuery-only File Upload to Stripe API*
Keep in mind, Stripe is the example I have, but I'd like to try and replicate this on say Imgur or another API (if I can get this working). Hopefully someone else has some ideas!
$('#fileinfo').submit(function(event) {
event.preventDefault();
var data = new FormData();
var publishableKey = 'pk_test_***';
data.append('file', $('#file-box')[0].files[0]);
data.append('purpose', 'identity_document');
$.ajax({
url: 'https://uploads.stripe.com/v1/files',
data: data,
headers: {
'Authorization': 'Bearer ' + publishableKey,
// 'Stripe-Account': 'acct_STRIPE-ACCOUNT-ID'
},
cache: false,
contentType: false,
processData: false,
type: 'POST',
}).done(function(data) {
$('#label-results').text('Success!');
$('#upload-results').text(JSON.stringify(data, null, 3));
}).fail(function(response, type, message) {
$('#label-results').text('Failure: ' + type + ', ' + message);
$('#upload-results').text(JSON.stringify(response.responseJSON, null, 3));
});
return false;
});

I actually got this working for Stripe by doing this:
https://jsfiddle.net/andrewnelder/up59zght/
var publishableKey = "pk_test_xxx"; // Platform Publishable Key
var stripeAccount = "acct_xxx"; // Connected Account ID
$(document).ready(function () {
$('#file-upload').on('submit', function (e) {
e.preventDefault();
console.log('Clicked!');
var route = $('#file-route').val(); // URL OF FILE
var fname = route.split("/").slice(-1)[0].split("?")[0];
var blob = fetchBlob(route, fname, uploadBlob);
});
});
function fetchBlob(route, fname, uploadBlob) {
console.log('Fetching...')
var oReq = new XMLHttpRequest();
oReq.open("GET", route, true);
oReq.responseType = "blob";
oReq.onload = function(e) {
var blob = oReq.response;
console.log('Fetched!')
uploadBlob(fname, blob);
};
oReq.send();
}
function uploadBlob(fname, blob) {
var fd = new FormData();
fd.append('file', blob);
fd.append('purpose', 'identity_document');
console.log('Uploading...');
$.ajax({
url: 'https://uploads.stripe.com/v1/files',
data: fd,
headers: {
'Authorization': 'Bearer ' + publishableKey,
'Stripe-Account': stripeAccount
},
cache: false,
contentType: false,
processData: false,
type: 'POST',
}).done(function(data) {
console.log('Uploaded!')
}).fail(function(response, type, message) {
console.log(message);
});
}