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Getting a php variable value back with an ajax result

I'm using croppie.js to crop user uploaded imaged, once the crop is done ajax is used to upload the result. Here is the codes for that...
Page A..
$('.upload-result').on('click', function (ev) {
$uploadCrop.croppie('result', {
type: 'canvas',
size: 'viewport'
}).then(function (resp) {
$.ajax({
url: "uploadown/uploader.php",
type: "POST",
data: {"image":resp},
success: function (data) {
html = '<img id="cropresult" style="margin: 0px;" src="' + resp + '" />;
$("#uploaded-input").html(html);
}
});
});
});
Then uploader.php is..
<?php
$data = $_POST['image'];
list($type, $data) = explode(';', $data);
list(, $data) = explode(',', $data);
$data = base64_decode($data);
$imageName = time().'.png';
file_put_contents($imageName, $data);
?>
As you can see uploader.php is using time() for the $imageName variable.
I either need to pass $imageName back to Page A during upload
or
set $imageName in page A first and pass it to uploader.php at the same time as the image info.
After a few hours and many attempts having read many similar questions on here and cannot work out how to do this. Any help greatly appreciated.

Echo out the $imageName in php file, once done use it in javascript.
PHP
<?php
$data = $_POST['image'];
list($type, $data) = explode(';', $data);
list(, $data) = explode(',', $data);
$data = base64_decode($data);
$imageName = time().'.png';
if(file_put_contents($imageName, $data)){
echo $imageName;
} else {
echo " ";//In this case src will be empty
}
?>
Java script
$('.upload-result').on('click', function (ev) {
$uploadCrop.croppie('result', {
type: 'canvas',
size: 'viewport'
}).then(function (resp) {
$.ajax({
url: "uploadown/uploader.php",
type: "POST",
data: {"image":resp},
success: function (data) {
html = '<img id="cropresult" style="margin: 0px;" src="' + data + '" />';
$("#uploaded-input").html(html);
}
});
});
});
For any queries comment down.

just echo the name in php or var_dump() the array and then you will be able to access it in your javascript
all the data from the php page is addign to the variable name you give to the anonymous function you give to the success callback. for your case it will be accessed as data

Found your full exmaple here: https://websolutionstuff.com/post/crop-image-before-upload-using-croppie-plugin
Consider the following PHP.
<?php
$data = $_POST['image'];
list($type, $data) = explode(';', $data);
list(, $data) = explode(',', $data);
$data = base64_decode($data);
$imageName = time().'.png';
if(file_put_contents($imageName, $data)){
echo "Success, " . $imageName;
} else {
echo "Error, unable to Put file.";
}
?>
This will provide a response to the AJAX Script.
$('.upload-result').on('click', function (ev) {
$uploadCrop.croppie('result', {
type: 'canvas',
size: 'viewport'
}).then(function (resp) {
$.ajax({
url: "uploadown/uploader.php",
type: "POST",
data: { "image":resp },
success: function (data) {
var response = data.split(",");
var html;
if(response[0] != "Error"){
html = '<img id="cropresult" style="margin: 0px;" src="' + response[1].trim() + '" />';
$("#uploaded-input").html(html);
} else {
console.log(data);
}
}
});
});
});

Refresh page if there is change in database

I am trying to refresh my a page if there is a change in orderStatus from database using Ajax and PHP. I set the current orderStatus as predefined data and then use Ajax to get the current orderStatus from database and finally compare if they are not the same. I want to refresh the page if they are not the same.
PHP (autorefresh.php)
<?php
$orderId = $_POST["orderId"];
$query = "SELECT * FROM orderinhomeonlinecall WHERE orderId='$orderId'";
$result = mysqli_query($db, $query);
while($row = mysqli_fetch_array($result))
{
$orderStatus = $row['orderStatus'];
$data = array(
'orderStatus' => $orderStatus
);
echo json_encode($data);
}
?>
Javascript
<script type="text/javascript" >
var predefined_val = '<?php echo $orderStatus; ?>';// your predefined value.
$.document(ready(function(){
setInterval(function(){
$.ajax({
type:"POST",
url:"autorefresh.php", //put relative url here, script which will return php
data:{orderId: <?php echo $orderId; ?>}, // if any you would like to post any data
success:function(response){
var data = response; // response data from your php script
if(predefined_val !== data){
window.location.href=window.location.href;
}
}
});
},5000);// function will run every 5 seconds
}));

The below code should work, Need to mention dataType:"json" else use JSON.stringify(data) to parse response
<script type="text/javascript">
var predefined_val = '<?php echo $orderStatus; ?>';// your predefined value.
$(document).ready(function () {
setInterval(function () {
$.ajax({
type: "POST",
url: "autorefresh.php", //put relative url here, script which will return php
data: {orderId: <?php echo $orderId; ?>}, // if any you would like to post any data
dataType: "json",
success: function (response) {
var data = response; // response data from your php script
if (predefined_val !== data.orderStatus) {
window.location.href = window.location.href;
}
}
});
}, 5000);// function will run every 5 seconds
});
</script>

I have tested this by creating two files(autorefresh.php,index.php) and test db with table and it is working for me. I think the below code would be helpful, If not please share you code, i will check and fix it.
autorefresh.php
// Create connection
$db = new mysqli("localhost", "root", "","test");
$orderId = $_POST["orderId"];
$query = "SELECT * FROM orderinhomeonlinecall WHERE orderId='$orderId'";
$result = mysqli_query($db, $query);
while($row = mysqli_fetch_array($result))
{
$orderStatus = $row['orderStatus'];
$data = array(
'orderStatus' => $orderStatus
);
echo json_encode($data);
}
?>
index.php
<?php
$orderStatus ='pending';
$orderId =1;
?>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script type="text/javascript">
var predefined_val = '<?php echo $orderStatus; ?>';// your predefined value.
$(document).ready(function () {
setInterval(function () {
$.ajax({
type: "POST",
url: "autorefresh.php", //put relative url here, script which will return php
data: {orderId: <?php echo $orderId; ?>}, // if any you would like to post any data
dataType: "json",
success: function (response) {
var data = response; // response data from your php script
if (predefined_val !== data.orderStatus) {
window.location.href = window.location.href;
}
}
});
}, 5000);// function will run every 5 seconds
});
</script>

File upload by ajax $.post not working

I am really new to ajax do forgive me if the question is stupid. I have a multi step form and it has the 4 parts , and I am using $.post() ajax request to send this. while all my other details are going fine I am not able to upload my file. this is what I am trying to do
Here I am trying to catch the form values.
var data_img = new FormData();
var hello = $.each(jQuery('#pan_file')[0].files, function (i, file) {
data_img.append('file-' + i, file);
});
Then I am passing these values to the object variable.
obj_params.pan_file = hello;
And then sending it to store with ajax.post()
$.post('<?php echo base_url(); ?>get-ekyc-form', obj_params, function (msg) {
if (msg == "1") {
swal("Success!", "EKYC Form has been Submitted Successfully", "success");
window.location = '<?php echo base_url(); ?>list-active-requirement';
}
}, "json", "processData:false", "contentType:false");
return true;
And this is where I do file transfer.
if ($_FILES['file-0']['name'] != "") {
$image_data = array();
//config initialise for uploading image
$config['upload_path'] = './media/front/img/quote-docs/';
$config['allowed_types'] = 'xlsx|pdf|doc|docx';
$config['max_size'] = '5000';
$config['max_width'] = '12024';
$config['max_height'] = '7268';
$config['file_name'] = time();
//loading upload library
$this->upload->initialize($config);
$this->load->library('upload', $config);
if (!$this->upload->do_upload('file-0')) {
$error = array('error' => $this->upload->display_errors());
} else {
$data = array('upload_data' => $this->upload->data());
$image_data = $this->upload->data();
$file_name = $image_data['file-0'];
}
$file_name = $image_data['file_name'];
} else {
$file_name = '';
}
Also I am working on someone elses code so I do understand I must have made loads of mistakes. I'll be grateful if someone could help me around this.

HTML code
<input id="picture" type="file" name="pic" />
<button id="upload">Upload</button>
$('#upload').on('click', function() {
var file_data = $('#picture').prop('files')[0];
var form_data = new FormData();
form_data.append('file', file_data);
alert(form_data);
$.ajax({
url: 'upload.php', // point to server-side PHP script
dataType: 'text', // what to expect back from the PHP script, if anything
cache: false,
contentType: false,
processData: false,
data: form_data,
type: 'post',
success: function(php_script_response){
alert(php_script_response); // display response from the PHP script, if any
}
});
});
in upload.php
<?php
if ( 0 < $_FILES['file']['error'] ) {
echo 'Error: ' . $_FILES['file']['error'] . '<br>';
}
else {
move_uploaded_file($_FILES['file']['tmp_name'], 'uploads/' . $_FILES['file']['name']);
}
?>

How to pass multiple variables from a php file to ajax and use them?

I have read many answers on stack overflow but I can't find an apt answer. I want to send multiple variables from php file to a javascript file. I want to use those variables later separately. So please explain with a simple example of how to get the variables from php file and how to use them separately later.
This is my js.
<script>
function here(card_numb) {
alert("pk!");
$.ajax({
url: 'details.php',
type: "GET",
dataType: 'json',
data: ({
card_number: card_numb
}),
success: function(data) {
console.log('card_number:'+data.card_number+'book_issued:'+data.book_isued);
}
});
}
I'm getting the alert 'pk!'. But $.ajax ain't working.
This is details.php
<?php
if(isset($_GET['card_number'])){
$card_number = $_GET['card_number'];
$query = "Select * from users where card_number = '".$card_number."'";
$query_run = mysqli_query($link,$query);
$row_numb =#mysqli_num_rows($query_run);
if($row_numb == 0){
echo "<div class='bdiv1'>No such number found!</div>";
} else{
$row=mysqli_fetch_assoc($query_run);
$book1 = $row['user_name'];
$arr = array('isued_book' => $book1,'card_number' => $card_number);
echo json_encode($arr);
exit();
}
}
?>
Thank you!

somthing.js - ur jspage
<script>
function here(card_numb) {
$.ajax({
url: 'details.php',
type: 'GET',
dataType: 'json',
data: {
card_number: card_numb
},
success: function(data) {
console.log('card_number:'+data.card_number+'book_issued:'+data.isued_book);
}
});
}
success: function(result){
console.log('variable1:'+result.var1+'variable2:'+result.var2+'variable3:'+result.var3);
} });
details.php
<?php
if(isset($_GET['card_number'])){
$card_number = $_GET['card_number'];
$query = "Select * from users where card_number = ".$card_number;
$query_run = mysqli_query($link,$query);
$row_numb =#mysqli_num_rows($query_run);
if(!$query_run){
echo "<div class='bdiv1'>No such number found!</div>";
} else {
$row=mysqli_fetch_assoc($query_run);
$book1 = $row['user_name'];
$arr = array('isued_book' => $book1,'card_number' => $card_number);
echo json_encode($arr);
exit();
}
if the currect value get in $row you can get the result in console

Facing on Make Like Unlike Button in php , mysql using ajax calling

I m creating like and unlike button for my website , at my local server i used seprate file it it working fine but when i install at my website then it is not working properly.
I m Fetching some information using this code from url bar
<?php
error_reporting (0);
include "includes/session.php";
include 'database/db.php';
extract($_REQUEST);
if(isset($_GET["i"]))
{
$pid=($_GET['p']);
$lid=($_GET['i']);
}
?>
<?php
$likquery = mysql_query("select * from likes where userid=$id and postid=$lid");
if(mysql_num_rows($likquery)==1){
?>
<a class="unlike" id="<?php echo $lid ?>">UnLike</a> <span class="like_update" id="<?php echo $lid ?>"></span>
<?php }else{?>
<a class="like" id="<?php echo $lid ?>">Like</a>
<?php
}?>
AFTER this I use script
<script src="js/jquery-1.8.3.min.js" type="text/javascript"></script>
<script>
$(document).ready(function(){
$('body').on('click','.like',function(){
var postId = $(this).attr('id');
var postData = 'postid='+postId+'&uid=<?php echo $id ?>';
$.ajax({
type: "POST",
url: "like_notes",
data: postData,
cache: false,
success: function(){
$('#'+postId).text('UnLike').addClass('unlike').removeClass('like');
}
});
})
$('body').on('click','.unlike',function(){
var postId = $(this).attr('id');
var postData = 'postid='+postId+'&uid=<?php echo $id ?>';
$.ajax({
type: "POST",
url: "likeun_notes",
data: postData,
cache: false,
success: function(){
$('#'+postId).text('Like').addClass('like').removeClass('unlike');
}
});
})
});
</script>
And I m not getting any response but when i use
<script src="js/jquery-1.8.3.min.js" type="text/javascript"></script>
<script>
$(document).ready(function(){
$(".like").click(function(){
var postId = $(this).attr('id');
var postData = 'postid='+postId+'&uid=<?php echo $id ?>';
$.ajax({
type: "POST",
url: "like_notes",
data: postData,
cache: false,
success: function(){
$('#'+postId).text('UnLike').addClass('unlike').removeClass('like');
}
});
})
$(".unlike").click(function(){
var postId = $(this).attr('id');
var postData = 'postid='+postId+'&uid=<?php echo $id ?>';
$.ajax({
type: "POST",
url: "likeun_notes",
data: postData,
cache: false,
success: function(){
$('#'+postId).text('Like').addClass('like').removeClass('unlike');
}
});
})
});
</script>
only once it is changing the value

Ok, the second version works only once, because at the beginning, the event is on the button, then you re-render the button by changing it's class and text, so the events get unbinded.
Same is for the 1st version. Jquery says: Event handlers are bound only to the currently selected elements; they must exist on the page at the time your code makes the call to .on().... If new HTML is being injected into the page, select the elements and attach event handlers after the new HTML is placed into the page.
So re-bind the events after changing the button.
I suggest something like this:
function bindEvents() {
$('.like').off().on('click', function(){
var postId = $(this).attr('id');
var postData = 'postid='+postId+'&uid=' + <?php echo $id ?>;
$.ajax({
type: "POST",
url: "like_notes",
data: postData,
cache: false,
success: function(){
$('#'+postId).text('UnLike').addClass('unlike').removeClass('like');
//rebind events here
bindEvents();
}
});
$('.unlike').off().on('click', function(){
var postId = $(this).attr('id');
var postData = 'postid='+postId+'&uid=' + <?php echo $id ?>;
$.ajax({
type: "POST",
url: "likeun_notes",
data: postData,
cache: false,
success: function(){
$('#'+postId).text('Like').addClass('like').removeClass('unlike');
//rebind events here
bindEvents();
}
});
}
$(document).ready(function(){
bindEvents();
});
Also notice that in var postData = 'postid='+postId+'&uid=<?php echo $id ?>'; code, the php part won't be treated as php. It will be just a string. So replace that part with the following, assuming that the code is located inside a php file:
var postData = 'postid='+postId+'&uid=' + <?php echo $id ?>;