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Javascript to send form to PHP

I am trying to get my HTML form to pass through Javascript that will then pass it to PHP that will send it to MySQL.
However I either get the page to load the JS file in the browser, or the PHP file to load in the browser.
Here is my HTML form:
<div class="form" id="form" onclick="submitForm()">
<form id='contactform' action="js/contactform.js" method="post" onSubmit="submitForm()">
<input type="text" id="name" placeholder="Name" autofocus required><br>
<input type="text" id="email" placeholder="Email" required><br>
<input type="tel" id="telephone" placeholder="Telephone"><br>
Enquiry : <input type="radio" id="subject" value="enquiry" required>
Booking : <input type="radio" id="subject" value="booking" required><br>
<textarea id="message" required rows="20" cols="20" placeholder="Enter your message and I will try to get back to you within 2 days."></textarea><br>
<input type="submit" name="submit" value="Submit" class="submitbutton"/>
<input type="reset" name="clearbutton" value="Clear" class="clearbutton"/>
</form>
<div id="outcome"></div>
I want the outcome of the form submit placed into the "outcome" div
My JS code:
function getOutput() {
getRequest(
'php/getinfo.php',
drawOutput,
drawError
);
return false;
}
// handles drawing an error message
function drawError () {
var container = document.getElementById("content");
container.innerHTML = 'Bummer: there was an error!';
}
// handles the response, adds the html
function drawOutput(responseText) {
var container = document.getElementById("content");
container.innerHTML = responseText;
}
// helper function for cross-browser request object
function getRequest(url, success, error) {
var req = false;
try{
// most browsers
req = new XMLHttpRequest();
} catch (e){
// IE
try{
req = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
// try an older version
try{
req = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
return false;
}
}
}
if (!req) return false;
if (typeof success != 'function') success = function () {};
if (typeof error!= 'function') error = function () {};
req.onreadystatechange = function(){
if(req .readyState == 4){
return req.status === 200 ?
success(req.responseText) : error(req.status)
;
}
}
req.open("GET", url, true);
req.send(null);
return req;
}
function submitForm(){
var name = document.getElementById('name').value;
var booking = document.getElementById('subject').value;
var enquiry = document.getElementById('subject').value;
var email = document.getElementById('email').value;
var telephone = document.getElementById('telephone').value;
var message = document.getElementById('message').value;
getRequest(
'php/form.php?' + params, //URL for the PHP file
procesOutput,
processError
);
return false;
}
function processOutput(){
var container = document.getElementById('outcome');
container.innerHTML = responseText;
}
function processError(){
alert("There has been an error, please try again");
}
and my PHP code:
$con=mysqli_connect("DBLocation","Username","Password",'DBName');
if (mysqli_connect_errno()){
die("Error: " . mysqli_connect_error());
}
$result = mysqli_query($con,"INSERT INTO `Contact`(`Name`, `Email`, `Telephone`, `Enquiry`, `Booking`, `Message`) VALUES ([value-2],[value-3],[value-4],[value-5],[value-6],[value-7])");
if ($conn->query($sql) === TRUE){
echo "Thank you for contacting us, I will replay to you soon!";
}
else {
echo "I'm sorry but an Error has occured. Please try again shortly";
}
mysql_close($conn);
?>
I've had a look at w3schools pages and some other questions on here but I can't seem to get my head around it.

A couple of things, first off what is getRequest? Second off, where is responseText defined? Third, I would check your console as I'm pretty sure there is an error in submitForm. I see lots of getElementByIds, but none of your inputs have ids associated with them:
<input type="text" name="name" placeholder="Name" autofocus required>
Should be:
<input type="text" id="name" placeholder="Name" autofocus required>

I believe you want to use Ajax, which you can easily use with jQuery.
I believe the answer for your question is right on this page: https://learn.jquery.com/ajax/ajax-and-forms/
If jQuery is new for you, you might want to read a little about jQuery: https://learn.jquery.com/about-jquery/
If you don't want to use jQuery, you can use directly XMLHttpRequest in javascript instead.

Here is a demo in JSFiddle.
Remove onClick, onSubmit, action="js/contactform.js" method="post" attributes as you don't need them. Capture the form submit in js. How to? - link
Add id's on the form elements so than you can select them like:
var name = document.getElementById('name').value;
Make a $.post request with jQuery (How to? - Link) and handle the success and failure callbacks. (I don't understand why are you making a post request, I would recommend you a $.get request.

Ajax acting as GET method even though is POST method

Hello I have encountered a problem while coding in Javascript and PHP (Ajax non jquery). I am trying to upload a file over Ajax, and handle it in PHP.
This is my code:
index.html
<html>
<head>
<title>PHP AJAX Upload</title>
<script type="text/javascript">
function upload() {
// 1. Create XHR instance - Start
var dat= "bla";
document.getElementById("div2").innerHTML = "working";
if (window.XMLHttpRequest) {
xhr = new XMLHttpRequest();
}
else if (window.ActiveXObject) {
xhr = new ActiveXObject("Msxml2.XMLHTTP");
}
else {
throw new Error("Ajax is not supported by this browser");
}
var rad = document.getElementById('fajl');
var filee = rad.files[0];
var formData = new FormData();
formData.append('rad',filee)
formData.append('var',dat)
xhr.open('POST', 'upload.php');
xhr.send(formData);
xhr.onload = function () {
if (xhr.readyState === 4 && xhr.status == 200) {
document.getElementById("div2").innerHTML = xhr.responseText;
//alert(xhr.readyState);
//alert(xhr.status);
}
}
}
</script>
</head>
<body>
<form id="uploadForm" enctype="multipart/form-data">
<label>Upload File:</label><br/>
<input name="rad" id="fajl" type="file" class="inputFile" />
<input type="submit" value="Submit" class="btnSubmit" onclick="upload()" />
<div id="div2">
</div>
</form>
</body>
</html>
upload.php
<?php
if(is_array($_FILES)) {
if(is_uploaded_file($_FILES['rad']['tmp_name'])) {
$sourcePath = $_FILES['rad']['tmp_name'];
$targetPath = "images/".$_FILES['rad']['name'];
if(move_uploaded_file($sourcePath,$targetPath)) {
echo ("uspjeh<br>");
}}
}
$podatak=$_POST['var'];
echo "$podatak"
?>
Problem is that I dont see PHP script response in my div2 element. Ajax behaves wierd and it puzzles me. I have put JavaScript alert command under xhr.readyState condition (now commented). When I do that then I see the output, but when I close alert dialog, the browser automaticly reloads page and makes the URL like i'm using GET method (i'm using POST) and then server output dissapears. (rad in ?rad=... is the name of my input element)
When I'm not using alert command then I don't see output at all, because page redirects really fast. What am I misiing?

It's because you are using a submit button and that's submitting the form. By default form methods are GET requests. Change to just a button instead:
<input type="button" value="Submit" class="btnSubmit" onclick="upload()" />

The default form action (submitting) is being carried out.
To stop this add return false to your click handler:
onclick="upload(); return false;"

Problems with XMLHttpRequest and PHP

I'm fairly new to both JavaScript and PHP, so I hope this problem isn't as complex as it seems to me. I'm trying to send data from a form to a PHP file using XMLHttpRequest, and then display the output of the PHP as an alert. Here's the HTML and JavaScript:
<form onSubmit="password_Check()">
<input type="password" size="40" name="password" id="pass">
<input type="submit" value="Go">
</form>
<script type="text/javascript">
function password_Check() {
var url = "test.php";
var pass = $("#pass").val();
var xhr = new XMLHttpRequest();
xhr.open("GET", url+"?pass="+pass, true);
xhr.onreadystatechange = function() {
if(xhr.readyState == 4 && xhr.status == 200) {
alert(xhr.responseText);
}
}
}
</script>
And here's the PHP:
<?php
$pass = $_GET["pass"];
echo "The password is $pass! We've done it!";
?>
I've tried all sorts of ways to do this, like $.post, $.get, $.ajax, and an xhr using POST. But I can't seem to get this to work. Now it just appends "?password=(whatever I put)" onto the end of the current url, which does nothing, but it shows it's doing something.

In your code you are missing the send part where you actually trigger the request. If you are not triggering the request then there is no point of the event listeners which listen for the state changes.
do it like
xhr.onreadystatechange = function() {
if(xhr.readyState == 4 && xhr.status == 200) {
alert(xhr.responseText);
}
}
xhr.send();
Also in your question you are mentioning about jquery ajax, with $.get your code could be as simple as
$("#form1").on("submit",function(e){
e.preventDefault();
var url = "test.php?pass=" + $("#pass").val();
$.get(url,function(data){
//handle data here
});
});

You forgot to execute the request. xhr.send():
Also note that since you're having an XMLHTTPRequest, you need to prevent the default behavior (which is the form is going to be submitted) by using .preventDefault();
<form id="form1">
<input type="password" size="40" name="password" id="pass">
<input type="submit" value="Go">
</form>
<script type="text/javascript">
// handle the submission event
document.getElementById('form1').addEventListener('submit', function(e){
e.preventDefault(); // prevent from submitting
var url = "test.php";
var pass = document.getElementById('pass').value; // be faithful!, just use plain javascript
var xhr = new XMLHttpRequest();
var params = '?pass='+pass;
xhr.open("GET", url+params, true);
xhr.onreadystatechange = function() {
if(xhr.readyState == 4 && xhr.status == 200) {
alert(xhr.responseText);
}
}
xhr.send(); // send it
});
</script>

If you are using jQuery then better use jQuery's ajax functions instead of xhr by yourself!
Also if you are submitting the password, better not submit it using GET request as it will be visible in the URL. Instead always use POST when handling Passwords!
Client side:
<form action="/index.php" id="myform" method="post">
<input type="password" size="40" name="password" id="pass">
<input type="submit" value="Go">
</form>
<script type="text/javascript">
$('#myform').on('submit', function() {
$.ajax({
type: $(this).attr('method'), //Taking for the form attribute
url: $(this).attr('action'),
data: $(this).serialize(), //Takes care of all input fields in the form! No need to pass one by one!
success: function(response) {
if(response == 'success') {
window.location.href = '/url-to-goto'; //Set your redirect url here
}
else {
//Handle invalid password here
alert(response);
}
}
});
return false;
});
</script>
Server side:
<?php
//If you are handling password, better to put it in the post body instead of url for security reasons
if($_SERVER['REQUEST_METHOD'] == 'POST') {
//Check password here
if(isset($_POST['password']) && $_POST['password'] == '123') {
die('success'); //successful! redirect user!
}
die('Invalid password!');
}
?>
Hope that helps you better understand!

Ajax Not Loading Asynchronous. Refreshing Page when form submitted

I have been trying to learn ajax and from what I can see my code is correct however it always refreshes the page when it echo's the returned json string. Any help would be greatly appreciated!
<script>
// Get XML HTTP Type
function get_XmlHttp() {
var xmlHttp = null;
if(window.XMLHttpRequest) {
xmlHttp = new XMLHttpRequest();
}else if(window.ActiveXObject) {
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}
return xmlHttp;
}
function ajaxSuccess () {
alert(this.responseText);
}
function ajaxrequest(oFormElement) {
//Get The Correct XMLHTTP Object
var request = new XMLHttpRequest();
request.open(oFormElement.method, oFormElement.action, true);
request.setRequestHeader("Content-type","application/x-www-form-urlencoded");
request.send(new FormData(oFormElement));
return false;
request.onreadystatechange = function() {
if (request.readyState == 4 && request.status == 200) {
alert("done");
document.getElementById('comment_form').innerHTML = request.responseText;
}
}
}
</script>
<form action="<?php echo $add_comment; ?>" method="post" enctype="multipart/form-data" id="comment_form" onsubmit="ajaxrequest(this);">
<input name="user_id" type="hidden" value="<?php echo $user_id; ?>">
<input name="user_message_id" type="hidden" value="<?php echo $user_message_id; ?>">
<textarea id="new_comment" name="new_comment" cols="100" rows="5"></textarea>
<input type="submit" value="post request"/>
</form>

You have to stop the event from happening. there is a common used function this in javascript:
e.preventDefault; // e is the event that you need to pass to your function.
or Change <input type="submit" value="post request"/>
to
<input type="button" onclick="ajaxrequest(this);" value="post request"/>
what is going to happen is your form is only going to be processed by javascript and page will mot reload due to the form submission.
Just modify this approach for yourself and it should fix your issue.

Use Jquery library http://api.jquery.com/jQuery.ajax/, but if u wanna build your own script. consult w3c documentation http://www.w3schools.com/ajax/ajax_xmlhttprequest_send.asp

As Pointy pointed out, you might want to prevent the default click event of the submit button from firing
submitForm( event ) {
event.preventDefault();
}
http://api.jquery.com/event.preventDefault/ <- My bad...
Just for clarification, is that your complete code?

JSONRequest.post not functioning

I am developing a web page and the purpose is to perform an http POST from form input elements, in JSON format. While the JSON element to be sent is formed properly, the request is never performed. Here is the code I have been using.
Form
<form id="input" action="javascript:snifForm()" >
User ID:
<input type="text" name="userId" id="userId" required>
Name:
<input type="text" name="name" id="name" required>
<div class="form-submit"><input type="submit" value="Submit" color="#ffffff" > </div></p>
</form>
Javascript (JSON.js, JSONRequest.js and JSONRequestError.js are imported)
<script type="text/javascript">
var requestNumber;
function snifForm()
{
var a1=document.getElementById("userId").value;
var a2=document.getElementById("name").value;
var toSend= {interactions: {id_user:a1, id_name:a2}};
var jToSend=JSON.stringify(toSend);
requestNumber = JSONRequest.post(
"http://someurl.com",
jToSend,
function (requestNumber, value, exception) {
if (value) {
processResponse(value);
alert(value);
} else {
processError(exception);
}
}
);
alert(requestNumber);
}
</script>
I also tried the more classic form:
var xmlhttp = new XMLHttpRequest();
var out;
xmlhttp.onreadystatechange = function() {
if(xmlhttp.readyState == 4 && xmlhttp.status == 200) {
out = xmlhttp.responseText;
alert(out);
}
else alert('nothing');
}
xmlhttp.open("POST", "the_same_url", true);
xmlhttp.setRequestHeader("Content-type", "application/json");
xmlhttp.setRequestHeader("Connection", "close");
xmlhttp.send(jToSend);
After checking the server logs, no post is done ever :/

You should be attaching the event to the submit action of the form and you need to make sure to cancel the submit action.
I would not add the events directly to the form, but it is
<form id="input" onsubmit="snifForm(); return false;">