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how to fix uri undefined error when trying to send request

when I'm trying to call the request in front node, I'm getting error in my backend node " RequestError: Error: Invalid URI "undefined"" , it seems like backend node request is not getting the data form my frontend node request.
knowing that uploadLink already have a value and in my browser console the frontend request looks ok
my backend request code
const ThumbnailUpload = async (req, res) => {
const { Uploadlink } = req.body;
const { selectedFile } = req.body;
const clientServerOptions = {
uri: `${Uploadlink}`,
body: JSON.stringify({
name: selectedFile,
}),
method: 'PUT',
headers: {
'Content-Type': ' application/json',
Accept: 'application/vnd.vimeo.*+json;version=3.4',
Authorization: getVimeoAuthorization(),
},
};
request(clientServerOptions, function (error, response) {
if (error) {
res.send(error);
} else {
const body = JSON.parse(response.body);
res.send(body);
}
console.log(Uploadlink);
});
};
and my frontend code is
const handleSubmit = (event) => {
event.preventDefault();
const formData = new FormData();
formData.append(
'selectedFile',
new Blob([selectedFile], { type: 'image/jpg, image/png, or image/gif' }),
);
formData.append('uploadLink', uploadLink);
const headers = {
'Content-Type': 'image/jpg, image/png, or image/gif',
Accept: 'application/vnd.vimeo.*+json;version=3.4',
};
try {
axios
.post(`${backendPostPath}/thumbnail-upload`, formData, {
headers,
})
.then((response) => {
applyThumbnial();
console.log(response);
});
} catch (error) {
console.log(error);
}
};
any advise ?

change:
const { Uploadlink } = req.body;
to:
const { uploadlink } = req.body;
make variable consistent throughout the code
EDIT
also, since you're uploading a file, you need to use upload middleware before request handler, and file will be within req.file:
route.post('/thumbnail-upload', upload.single('selectedFile'), ThumbnailUpload);
//... handler..
const selectedFile = req.file;

2 API Calls in One JavaScript

presently I am attempting to make 2 different api calls one after the other within 1 java/nodejs script. It seems after my first function runs successfully, the second one errors with the following:
FetchError: request to failed, reason: socket hang up;
type: 'system',
errno: 'ECONNRESET',
code: 'ECONNRESET'
Below is a code snippet of what I have tried thus far:
const fetch = require("node-fetch");
const formData = require("form-data");
const fs = require("fs");
//const express = require("express");
var apiName = "<LOCAL SYSTEM FILE TO UPLOAD>";
var lookupName = "<LOCAL SYSTEM FILE TO UPLOAD>";
var accessToken = "Bearer <ACCESS TOKEN>";
var url = '<URL API #1>';
var url2 = '<URL API #2>;
var headers = {
'Accept': 'application/json',
'Authorization': accessToken,
};
const form = new formData();
const buffer2 = fs.readFileSync(lookupName);
const buffer = fs.readFileSync(apiName);
const uploadAPI = function uploadAPI() {
form.append("Content-Type", "application/octect-stream");
form.append('file', buffer);
fetch(url, {method: 'POST', headers: headers, body: form})
.then(data => {
console.log(data)
})
.catch(err => {
console.log(err)
});
};
const uploadLookup = function uploadLookup() {
form.append("Content-Type", "application/octect-stream");
form.append('file', buffer2);
fetch(url2, {method: 'PUT', headers: headers, body: form})
.then(data => {
console.log(data)
})
.catch(err => {
console.log(err)
});
};
if (!apiName !== true) {
uploadAPI()
} else {}
if (!lookupName !== true) {
console.log("Uploading Lookup File");
uploadLookup()
} else {}
I tried using a "setTimeout" function which does not seem to work as I would have liked it to. My best guess is each API call would need to be it's own separate socket connection? Any help with getting me in the right direction is appreciated.

Promise.all([
fetch(url),
fetch(url2)
]).then(function (res) {
// Get a JSON object from each of the responses
return res.json();
}).then(function (data) {
// do something with both sets of data here
console.log(data);
}).catch(function (error) {
// if there's an error, log it
});

Google Drive API and file uploads from the browser

I'm trying to upload a file with the Google Drive api, and I have the metadata correct, and I want to ensure that the actual file contents make it there. I have a simple page setup that looks like this:
<div id="upload">
<h6>File Upload Operations</h6>
<input type="file" placeholder='file' name='fileToUpload'>
<button id='uploadFile'>Upload File</button>
</div>
and I have a the javascript setup where the user is prompted to sign in first, and then they can upload a file. Here's the code: (currently only uploads the file metadata....)
let uploadButton = document.getElementById('uploadFile');
uploadButton.onclick = uploadFile;
const uploadFile = () => {
let ftu = document.getElementsByName('fileToUpload')[0].files[0];
console.dir(ftu);
gapi.client.drive.files.create({
'content-type': 'application/json;charset=utf-8',
uploadType: 'multipart',
name: ftu.name,
mimeType: ftu.type,
fields: 'id, name, kind'
}).then(response => {
console.dir(response);
console.log(`File: ${ftu.name} with MimeType of: ${ftu.type}`);
//Need code to upload the file contents......
});
};
First, I'm more familiar with the back end, so getting the file in bits from the <input type='file'> tag is a bit nebulous for me. On the bright side, the metadata is there. How can I get the file contents up to the api?

So According to some resources I've found in my three day search to get this going, the file simply cannot be uploaded via the gapi client. It must be uploaded through a true REST HTTP call. So let's use fetch!
const uploadFile = () => {
//initialize file data from the dom
let ftu = document.getElementsByName('fileToUpload')[0].files[0];
let file = new Blob([ftu]);
//this is to ensure the file is in a format that can be understood by the API
gapi.client.drive.files.create({
'content-type': 'application/json',
uploadType: 'multipart',
name: ftu.name,
mimeType: ftu.type,
fields: 'id, name, kind, size'
}).then(apiResponse => {
fetch(`https://www.googleapis.com/upload/drive/v3/files/${response.result.id}`, {
method: 'PATCH',
headers: new Headers({
'Authorization': `Bearer ${gapi.client.getToken().access_token}`,
'Content-Type': ftu.type
}),
body: file
}).then(res => console.log(res));
}
The Authorization Header is assigned from calling the gapi.client.getToken().access_token function, and basically this takes the empty object from the response on the gapi call and calls the fetch api to upload the actual bits of the file!

In your situation, when you upload a file using gapi.client.drive.files.create(), the empty file which has the uploaded metadata is created. If my understanding is correct, how about this workaround? I have experienced the same situation with you. At that time, I used this workaround.
Modification points:
Retrieve access token using gapi.
File is uploaded using XMLHttpRequest.
Modified script:
Please modify the script in uploadFile().
let ftu = document.getElementsByName('fileToUpload')[0].files[0];
var metadata = {
'name': ftu.name,
'mimeType': ftu.type,
};
var accessToken = gapi.auth.getToken().access_token; // Here gapi is used for retrieving the access token.
var form = new FormData();
form.append('metadata', new Blob([JSON.stringify(metadata)], {type: 'application/json'}));
form.append('file', ftu);
var xhr = new XMLHttpRequest();
xhr.open('post', 'https://www.googleapis.com/upload/drive/v3/files?uploadType=multipart&fields=id,name,kind');
xhr.setRequestHeader('Authorization', 'Bearer ' + accessToken);
xhr.responseType = 'json';
xhr.onload = () => {
console.log(xhr.response);
};
xhr.send(form);
Note:
In this modified script, it supposes that Drive API is enabled at API console and the access token can be used for uploading file.
About fields, you are using id,name,kind. So this sample also uses them.
Reference:
gapi
If I misunderstand your question or this workaround was not useful for your situation, I'm sorry.
Edit:
When you want to use fetch, how about this sample script?
let ftu = document.getElementsByName('fileToUpload')[0].files[0];
var metadata = {
'name': ftu.name,
'mimeType': ftu.type,
};
var accessToken = gapi.auth.getToken().access_token; // Here gapi is used for retrieving the access token.
var form = new FormData();
form.append('metadata', new Blob([JSON.stringify(metadata)], {type: 'application/json'}));
form.append('file', ftu);
fetch('https://www.googleapis.com/upload/drive/v3/files?uploadType=multipart&fields=id,name,kind', {
method: 'POST',
headers: new Headers({'Authorization': 'Bearer ' + accessToken}),
body: form
}).then((res) => {
return res.json();
}).then(function(val) {
console.log(val);
});

With https://www.npmjs.com/package/#types/gapi.client.drive
const makeUploadUrl = (fileId: string, params: Record<string, boolean>) => {
const uploadUrl = new URL(
`https://www.googleapis.com/upload/drive/v3/files/${fileId}`
)
Object.entries({
...params,
uploadType: 'media',
}).map(([key, value]) => uploadUrl.searchParams.append(key, `${value}`))
return uploadUrl
}
const uploadDriveFile = async ({ file }: { file: File }) => {
const params = {
enforceSingleParent: true,
supportsAllDrives: true,
}
// create file handle
const { result } = await gapi.client.drive.files.create(params, {
// CAN'T have the upload type here!
name: file.name,
mimeType: file.type,
// any resource params you need...
driveId: process.env.DRIVE_ID,
parents: [process.env.FOLDER_ID],
})
// post the file data
await fetch(makeUploadUrl(result.id!, params), {
method: 'PATCH',
headers: new Headers({
Authorization: `Bearer ${gapi.client.getToken().access_token}`,
'Content-Type': file.type,
}),
body: file,
})
return result
})
}

getting 400 Bad Request when trying to upload to aws s3 bucket

I sign the URL on my server and send it back to the client which works fine. This is how that function looks
const aws = require('aws-sdk'),
config = require('config'),
crypto = require('crypto');
module.exports = async function(file_type) {
aws.config.update({accessKeyId: config.AWS_ACCESS_KEY, secretAccessKey: config.AWS_SECRET_KEY})
const s3 = new aws.S3();
try {
if (!file_type === "image/png") {
return ({success: false, error: 'Please provide a valid video format'});
}
let buffer = await crypto.randomBytes(12);
let key = buffer.toString('hex');
let options = {
Bucket: config.AWS_S3_BUCKET,
Key: key,
Expires: 60,
ContentType: file_type,
ACL: 'public-read',
}
let data = await s3.getSignedUrl('putObject', options);
console.log('data was', data)
return ({
success: true,
signed_request: data,
url: ('https://s3.amazonaws.com/' + config.AWS_S3_BUCKET + '/' + key),
key,
});
} catch (error) {
console.log('the error was', error)
return ({
success: false,
error: error.message,
})
}
}
So this works fine and winds up getting me a url like
https://mybucket.s3.amazonaws.com/a33b4a43f23fc41de9ddck1k?AWSAccessKeyId=ADIFJDGPMRFRGLXSYWPQ&Content-Type=image%2Fpng&Expires=1496716543&Signature=0zcx%2BFzWUoeFD02RF2CQ2o0bLmo%3D&x-amz-acl=public-read
Then when I get that url back on the client.. i send a PUT request using axios with a function like -
function uploadToS3(file, signedRequest, callback){
var options = {
headers: {
'Content-Type': file.type
}
};
axios.put(signedRequest, file, options)
.then(result =>{
console.log('the result was', result)
callback(result)
})
.catch(err =>{
callback(err)
})
}
The only I'm getting back is (400) Bad Request

I faced the same issue and after searching for hours, I was able to solve it by adding the region of my bucket to the server side backend where I was requesting a signed URL using s3.getSignedUrl().
const s3 = new AWS.S3({
accessKeyId:"your accessKeyId",
secretAccessKey:"your secret access key",
region:"ap-south-1" // could be different in your case
})
const key = `${req.user.id}/${uuid()}.jpeg`
s3.getSignedUrl('putObject',{
Bucket:'your bucket name',
ContentType:'image/jpeg',
Key:key
}, (e,url)=>{
res.send({key,url})
})
After getting the signed URL, I used axios.put() at the client side to upload the image to my s3 bucket using the URL.
const uploadConf = await axios.get('/api/uploadFile');
await axios.put(uploadConf.data.url,file, {
headers:{
'Content-Type': file.type
}
});
Hope this solves your issue.

Guess bad header you provided
Works for me
function upload(file, signedRequest, done) {
const xhr = new XMLHttpRequest();
xhr.open('PUT', signedRequest);
xhr.setRequestHeader('x-amz-acl', 'public-read');
xhr.onload = () => {
if (xhr.status === 200) {
done();
}
};
xhr.send(file);
}

Pure JavaScript Send POST Data Without a Form

Is there a way to send data using the POST method without a form and without refreshing the page using only pure JavaScript (not jQuery $.post())? Maybe httprequest or something else (just can't find it now)?

You can send it and insert the data to the body:
var xhr = new XMLHttpRequest();
xhr.open("POST", yourUrl, true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(JSON.stringify({
value: value
}));
By the way, for get request:
var xhr = new XMLHttpRequest();
// we defined the xhr
xhr.onreadystatechange = function () {
if (this.readyState != 4) return;
if (this.status == 200) {
var data = JSON.parse(this.responseText);
// we get the returned data
}
// end of state change: it can be after some time (async)
};
xhr.open('GET', yourUrl, true);
xhr.send();

The Fetch API is intended to make GET requests easy, but it is able to POST as well.
let data = {element: "barium"};
fetch("/post/data/here", {
method: "POST",
headers: {'Content-Type': 'application/json'},
body: JSON.stringify(data)
}).then(res => {
console.log("Request complete! response:", res);
});
If you are as lazy as me (or just prefer a shortcut/helper):
window.post = function(url, data) {
return fetch(url, {method: "POST", headers: {'Content-Type': 'application/json'}, body: JSON.stringify(data)});
}
// ...
post("post/data/here", {element: "osmium"});

You can use the XMLHttpRequest object as follows:
xhr.open("POST", url, true);
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");
xhr.send(someStuff);
That code would post someStuff to url. Just make sure that when you create your XMLHttpRequest object, it will be cross-browser compatible. There are endless examples out there of how to do that.

Also, RESTful lets you get data back from a POST request.
JS (put in static/hello.html to serve via Python):
<html><head><meta charset="utf-8"/></head><body>
Hello.
<script>
var xhr = new XMLHttpRequest();
xhr.open("POST", "/postman", true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(JSON.stringify({
value: 'value'
}));
xhr.onload = function() {
console.log("HELLO")
console.log(this.responseText);
var data = JSON.parse(this.responseText);
console.log(data);
}
</script></body></html>
Python server (for testing):
import time, threading, socket, SocketServer, BaseHTTPServer
import os, traceback, sys, json
log_lock = threading.Lock()
log_next_thread_id = 0
# Local log functiondef
def Log(module, msg):
with log_lock:
thread = threading.current_thread().__name__
msg = "%s %s: %s" % (module, thread, msg)
sys.stderr.write(msg + '\n')
def Log_Traceback():
t = traceback.format_exc().strip('\n').split('\n')
if ', in ' in t[-3]:
t[-3] = t[-3].replace(', in','\n***\n*** In') + '(...):'
t[-2] += '\n***'
err = '\n*** '.join(t[-3:]).replace('"','').replace(' File ', '')
err = err.replace(', line',':')
Log("Traceback", '\n'.join(t[:-3]) + '\n\n\n***\n*** ' + err + '\n***\n\n')
os._exit(4)
def Set_Thread_Label(s):
global log_next_thread_id
with log_lock:
threading.current_thread().__name__ = "%d%s" \
% (log_next_thread_id, s)
log_next_thread_id += 1
class Handler(BaseHTTPServer.BaseHTTPRequestHandler):
def do_GET(self):
Set_Thread_Label(self.path + "[get]")
try:
Log("HTTP", "PATH='%s'" % self.path)
with open('static' + self.path) as f:
data = f.read()
Log("Static", "DATA='%s'" % data)
self.send_response(200)
self.send_header("Content-type", "text/html")
self.end_headers()
self.wfile.write(data)
except:
Log_Traceback()
def do_POST(self):
Set_Thread_Label(self.path + "[post]")
try:
length = int(self.headers.getheader('content-length'))
req = self.rfile.read(length)
Log("HTTP", "PATH='%s'" % self.path)
Log("URL", "request data = %s" % req)
req = json.loads(req)
response = {'req': req}
response = json.dumps(response)
Log("URL", "response data = %s" % response)
self.send_response(200)
self.send_header("Content-type", "application/json")
self.send_header("content-length", str(len(response)))
self.end_headers()
self.wfile.write(response)
except:
Log_Traceback()
# Create ONE socket.
addr = ('', 8000)
sock = socket.socket (socket.AF_INET, socket.SOCK_STREAM)
sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
sock.bind(addr)
sock.listen(5)
# Launch 100 listener threads.
class Thread(threading.Thread):
def __init__(self, i):
threading.Thread.__init__(self)
self.i = i
self.daemon = True
self.start()
def run(self):
httpd = BaseHTTPServer.HTTPServer(addr, Handler, False)
# Prevent the HTTP server from re-binding every handler.
# https://stackoverflow.com/questions/46210672/
httpd.socket = sock
httpd.server_bind = self.server_close = lambda self: None
httpd.serve_forever()
[Thread(i) for i in range(10)]
time.sleep(9e9)
Console log (chrome):
HELLO
hello.html:14 {"req": {"value": "value"}}
hello.html:16
{req: {…}}
req
:
{value: "value"}
__proto__
:
Object
Console log (firefox):
GET
http://XXXXX:8000/hello.html [HTTP/1.0 200 OK 0ms]
POST
XHR
http://XXXXX:8000/postman [HTTP/1.0 200 OK 0ms]
HELLO hello.html:13:3
{"req": {"value": "value"}} hello.html:14:3
Object { req: Object }
Console log (Edge):
HTML1300: Navigation occurred.
hello.html
HTML1527: DOCTYPE expected. Consider adding a valid HTML5 doctype: "<!DOCTYPE html>".
hello.html (1,1)
Current window: XXXXX/hello.html
HELLO
hello.html (13,3)
{"req": {"value": "value"}}
hello.html (14,3)
[object Object]
hello.html (16,3)
{
[functions]: ,
__proto__: { },
req: {
[functions]: ,
__proto__: { },
value: "value"
}
}
Python log:
HTTP 8/postman[post]: PATH='/postman'
URL 8/postman[post]: request data = {"value":"value"}
URL 8/postman[post]: response data = {"req": {"value": "value"}}

You can use XMLHttpRequest, fetch API, ...
If you want to use XMLHttpRequest you can do the following
var xhr = new XMLHttpRequest();
xhr.open("POST", url, true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(JSON.stringify({
name: "Deska",
email: "deska#gmail.com",
phone: "342234553"
}));
xhr.onload = function() {
var data = JSON.parse(this.responseText);
console.log(data);
};
Or if you want to use fetch API
fetch(url, {
method:"POST",
body: JSON.stringify({
name: "Deska",
email: "deska#gmail.com",
phone: "342234553"
})
}).then(result => {
// do something with the result
console.log("Completed with result:", result);
}).catch(err => {
// if any error occured, then catch it here
console.error(err);
});

There is an easy method to wrap your data and send it to server as if you were sending an HTML form using POST.
you can do that using FormData object as following:
data = new FormData()
data.set('Foo',1)
data.set('Bar','boo')
let request = new XMLHttpRequest();
request.open("POST", 'some_url/', true);
request.send(data)
now you can handle the data on the server-side just like the way you deal with reugular HTML Forms.
Additional Info
It is advised that you must not set Content-Type header when sending FormData since the browser will take care of that.

Did you know that JavaScript has it's built-in methods and libs to create forms and submit them?
I am seeing a lot of replies here all asking to use a 3rd party library which I think is an overkill.
I would do the following in pure Javascript:
<script>
function launchMyForm()
{
var myForm = document.createElement("FORM");
myForm.setAttribute("id","TestForm");
document.body.appendChild(myForm);
// this will create a new FORM which is mapped to the Java Object of myForm, with an id of TestForm. Equivalent to: <form id="TestForm"></form>
var myInput = document.createElement("INPUT");
myInput.setAttribute("id","MyInput");
myInput.setAttribute("type","text");
myInput.setAttribute("value","Heider");
document.getElementById("TestForm").appendChild(myInput);
// To submit the form:
myForm.method = "POST";
myForm.action = "whatever.aspx"; // or "response.php"
myForm.submit();
// This will create an INPUT equivalent to: <INPUT id="MyInput" type="text" value="Heider" /> and then assign it to be inside the TestForm tags.
}
</script>
This way (A) you don't need to rely on 3rd parties to do the job. (B) It's all built-in to all browsers, (C) faster, (D) it works, feel free to try it out.
I hope this helps.
H

navigator.sendBeacon()
If you simply need to POST data and do not require a response from the server, the shortest solution would be to use navigator.sendBeacon():
const data = JSON.stringify({
example_1: 123,
example_2: 'Hello, world!',
});
navigator.sendBeacon('example.php', data);

The most popular answers here do not show how to get data back from the POST. Also, the popular "fetch" solutions do not work in the latest version of Chrome when sending data to the latest version of NodeJS unless you pass headers and also unwrap the response.json() promise. Also, the popular answers do not use async/await.
Here is the cleanest and most complete solution I could come up with that works.
async function postJsonData(jsonObject) {
const response = await fetch("/echo", {
method: "POST",
headers: {'Content-Type': 'application/json'},
body: JSON.stringify(jsonObject)
});
const actualResponse = await response.json();
}

Here is a nice function you (or anyone else) could use in their code:
function post(url, data) {
return new Promise((res, rej) => {
let stringified = "";
for (const [key, value] of Object.entries(data))
stringified += `${stringified != '' ? '&' : ''}${key}=${value}`
const xhr = new XMLHttpRequest();
xhr.onreadystatechange = () => {
if (xhr.readyState == 4)
if (xhr.status == 200)
res(xhr.responseText)
else
rej({ code: xhr.status, text: xhr.responseText })
}
xhr.open("POST", url, true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(stringified);
})
}

const data = { username: 'example' };
fetch('https://example.com/profile', {
method: 'POST', // or 'PUT'
headers: {
' Content-Type': 'application/json',
},
body: JSON.stringify(data),
})
.then(response => response.json())
.then(data => {
console.log('Success:', data);
})
.catch((error) => {
console.error('Error:', error);
});

You can also use this: https://github.com/floscodes/JS/blob/master/Requests.js
You can easily send a http-Request. Just use:
HttpRequest("https://example.com", method="post", data="yourkey=yourdata");
That's it! It should even work if the site is CSRF-protected.
Or just send a GET-Request by using
HttpRequest("https://example.com", method="get");

use this func of jbezz library
var makeHttpObject = function () {
try {return new XMLHttpRequest();}
catch (error) {}
try {return new ActiveXObject("Msxml2.XMLHTTP");}
catch (error) {}
try {return new ActiveXObject("Microsoft.XMLHTTP");}
catch (error) {}
throw new Error("Could not create HTTP request object.");
}
function SendData(data){
let type = (data.type ? data.type : "GET")
let DataS = data.data;
let url = data.url;
let func = (data.success ? data.success : function(){})
let funcE =(data.error ? data.error : function(){})
let a_syne = (data.asyne ? data.asyne : false);
let u = null;
try{u = new URLSearchParams(DataS).toString();}catch(e){u = Object.keys(DataS).map(function(k) {return encodeURIComponent(k) + '=' + encodeURIComponent(DataS[k])}).join('&')}
if(type == "GET"){url +="?"+u}
const xhttp = makeHttpObject();
xhttp.onload = function(){func(this.responseText)}
xmlHttp.onreadystatechange = function() {if (xmlHttp.readyState == 4)
{if(xmlHttp.status !== 200){funcE(xmlHttp.statusText)}}}
xhttp.open(type,url,a_syne);
xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhttp.send(u);
}
use this to run :
SendData({
url:"YOUR_URL",
asyne:true,
type:"POST", // or GET
data:{
username:"ali",
password:"mypass" // Your Data
},
success:function(Result){
console.log(Result)
},
error:function(e){
console.log("We Have Some Error")
}
});
Or
download jbezz and add to your page.
download link : github.com
use :
$$.api({
url:"YOUR_URL",
asyne:true,
type:"POST", // or GET
data:{
username:"ali",
password:"mypass" // Your Data
},
success:function(Result){
console.log(Result)
},
error:function(e){
console.log("We Have Some Error")
}
});