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Javascript foreach question: how to pick out the number element to form new array

I have some tasks to handle in my daily jobs, so I need to do it in a automatic way. My task is:
there will be some messages sent to my IM, and I need to append the first, second & third number to each links with a "|".
if there only 2 numbers in the number line, a 0 is needed in the first place.
For example, in the cleanResult example, I need it to be done like:
finalResult = ["https://www.example.com/firstlink|500",
"https://www.example.com/firstlink|150",
"https://www.example.com/firstlink|30",
"https://www.exmaple.com/secondlink|600",
"https://www.exmaple.com/secondlink|150",
"https://www.exmaple.com/secondlink|30",
"https://www.example.com/thirdlink|500",
"https://www.example.com/thirdlink|150",
"https://www.example.com/thirdlink|30",
"https://www.example.com/forthlink|600",
"https://www.example.com/forthlink|100",
"https://www.example.com/forthlink|20",
"https://www.example.com/fithlink|0",
"https://www.example.com/fithlink|200",
"https://www.example.com/fithlink|50"
]
Here's the codes I had done so far:
const urlRegex = /(https?\:\/\/)?([^\.\s]+)?[^\.\s]+\.[^\s]+/gi;
const digitRegex = /^(?=.*\d)[\d ]+$/;
cleanResult = ["https://www.example.com/firstlink",
"https://www.exmaple.com/secondlink",
"https://www.example.com/thirdlink",
"500 150 30",
"https://www.example.com/forthlink",
"600 100 20",
"https://www.example.com/fithlink",
"200 50"
]
cleanResult.forEach((item, index) => {
if (item.match(digitRegex)) {
//codes I don't know how to do...
}
})

Are elements in cleanResult always either a URL or a number? In that case, you could just check the first character of the string to see if it's a number (basically a non-url). If it's not a URL, then we know it's numbers, and we can do something with the URL, which should the the previous element:
// If it's a URL, we will store it here for future use
let currentURL = ''
cleanResult.forEach((item, index) => {
// Get the first character of this string
const first = item[0]
if (!Number.isInteger(first)) {
// This is NOT a number, so must be a URL,
// let's store it in our variable to use in the next loop
currentURL = item
} else {
// This IS a number, which means we need to do a few things:
// 1. Split into separate numbers
// 2. Create a new URL pattern from each number
// 3. Push to finalResult
// 1. Split by tab delimiter (?)
// splits by tab, and returns an array
const numbers = item.split('\t')
// 2. Create a new URL pattern from each number
numbers.forEach((n) {
// This should now give you the URL + | + the number:
// ex: https://example.com/firstlink|500
const newURL = currentURL + '|' + n
// 3. push to the finalResult array
finalResult.push(newURL)
})
}
})
I haven't tested it, but this is the process that I generally use: break it into smaller tasks and take it one step at a time. I also didn't use regex, just to make it easier. We're assuming that you will receive either a URL or a list of numbers separated by a tab. This means you can afford to keep it a bit simple.
I'm sure there are way more efficient ways to do it and in a lot fewer lines, but if you're just learning JS or programming, there is nothing wrong with being extra verbose so that you can understand early concepts.

Javascipt replacing exact numbers in an array

am trying to replace numbers in an array but am facing an issue which am not really able to correctly manage regarding how to correctly target the just one data I really have to change.
I'll make an example to have more accuracy on describing it.
Imagine my data array look like that:
["data", "phone numbers", "address"]
I can change numbers via following script but my first problem is that it makes no differences between the number it find in columns, for example "phone numbers" from "address" (at the moment am not using it, but should I include a ZIP code in the address it would be really be a problem)
Beside, my second and current problem with my script, is that obviosuly in the same "phone numnbers" a number may appear more times while I'd like to affect only the first block of the data - let's say to add/remove the country code (or even replace it with it's country vexillum) which I normally have like that "+1 0000000000" or "+54 0000000000"
So if a number is for example located in EU it really make this script useless: Spain is using "+34" while France "+33" and it wouldn't succeded in any case becouse it recognize only "+3" for both.
I've found some one else already facing this problems which seems to solved it wrapping the values inside a buondaries - for example like that "\b"constant"\b" - but either am wronging syntax either it does not really apply to my case. Others suggest to use forEach or Array.prototype.every which I failed to understand how to apply at this case.
Should you have other ideas about that am open to try it!
function phoneUPDATES(val)
{
var i= 0;
var array3 = val.value.split("\n");
for ( i = 0; i < array3.length; ++i) {
array3[i] = "+" + array3[i];
}
var arrayLINES = array3.join("\n");
const zero = "0";
const replaceZERO = "0";
const one = "1";
const replaceONE = "1";
const result0 = arrayLINES.replaceAll(zero, replaceZERO);
const result1 = result0.replaceAll(one, replaceONE);
const result2 = result1.replaceAll(two, replaceTWO);
const result3 = result2.replaceAll(thre, replaceTHREE);
const result4 = result3.replaceAll(four, replaceFOUR);
const result5 = result4.replaceAll(five, replaceFIVE);
const result6 = result5.replaceAll(six, replaceSIX);
const result7 = result6.replaceAll(seven, replaceSEVEN);
const result8 = result7.replaceAll(eight, replaceEIGHT);
const result9 = result8.replaceAll(nine, replaceNINE);
const result10 = result9.replaceAll(ten, replaceTEN);
const result11 = result10.replaceAll(eleven, replaceELEVEN);

Why not use a regex replace, you could do something like /(\+\d+ )/g which will find a + followed by one or more digits followed by a space, and then you can strip out the match:
const phoneNumbers = [, "+54 9876543210"]
console.log(phoneNumbers.map((num) => num.replaceAll(/(\+\d+ )/g, '')))
If you need to only target the second element in an array, i'd imagine your data looks like
const data = [["data", "+1 1234567890, +1 5555555555", "address"], ["data", "+11 111111111, +23 23232323", "address"]];
console.log(data.map((el) => {
el[1] = el[1].replaceAll(/(\+\d+ )/g, '');
return el;
}))

ok, this almost is cheating but I really didn't thought it before and, by the way does, not even actually solve the problems but jsut seems to work around it.
If I call the replacemente in decreasing order that problem just does not show up becouse condition of replacement involving higher numbers are matched before the smaller one.
but should some one suggest a complete "true code comply" solution is wellcome

Facing issue in restricting the amount of splits

I have used the below code to split my string.
splitter.map((item1) => {
let splitter1 = item1.split("=")[0].trimLeft();
let splitter2 = item1.split("=")[1].trimRight();
});
where item1 contains string as
Labor_Agreement=0349BP
Default_Hours=5/8
Probation_Period=>=12 Months
The issue I am facing is to restrict the amount of splits. Because the above code will fail in case of third string , i.e. Probation_Period=>=12 Months
I tried giving parameter to restrict the amount of split in split method above, but that is giving syntax error.

An easy to understand solution would consist of first finding the first = character, and slicing you array twice to get the right portion :
const strings = [
'Labor_Agreement=0349BP',
'Default_Hours=5/8',
'Probation_Period=>=12 Months',
];
strings.map(item => {
const chSplit = item.indexOf('=');
const splitter1 = item.slice(0, chSplit).trim();
const splitter2 = item.slice(chSplit + 1).trim();
console.log(splitter1, splitter2);
});

VueJS: Computed Calculation Assistance

I need to be able to convert a string (IP address) such as this 10.120.0.1 to a string (ISIS Network ID) such as this 49.0001.0101.2000.0001.00. The middle section 010 1.20 00.0 001 corresponds to the first string (I've spaced them out to show the IP address is inside it). You can see that there are 4 digits in each ISIS Network ID hextet that need to correspond to 3 digits in the IP Address octet. A number of 53 for example would have a leading 0 to make 3 digits.
All the IP addresses start with 10.120. so I just need to inject the last 2 octets from the IP Address into the ISIS Network ID.
I need this to be dynamic so when someone types in another ip address into a loopbackIP input, it automatically updates the isisNetworkID field.
I have this:
49.0001.0101.{{ isisNetworkID }}.00
This needs to take the value from an input v-model="loopbackIP" that I have and translate the remaining values to sit in the middle of that isisNetworkID following this format - xxxx.xxxx.
I've got this computed calculation but I'm not sure how to make 4 digits equal 3...
const loopbackIP = '10.120.0.1';
const isisNetworkID = computed(() => {
let idaho = '10.120.';
if (loopbackIP.indexOf(idaho)) {
return loopbackIP.slice(7);
} else {
console.log('Nothing is happening');
}
});
I hope this makes sense...

I think I understand what you're trying to achieve. Let's break it down into digestible parts. You have an IP address of:
10.120.0.1
And you want to transform it such that each part is padded to 3 digits:
['010', '120', '000', '001']
This can be done by splitting the string by the . character, and the using String.prototype.padStart(). We then join the array back into a string:
'010120000001'
||||
^^^^ -> to be deleted
We know that the first 4 digits is not needed, since it's already part of your template, so we can remove them using String.prototype.substring(4). That leaves us with:
'20000001'
Now it is just the matter of splitting it into 4 characters per item:
['2000', '0001']
...and rejoining it with . character:
'2000.0001'
...and interpolating it back into the string. I have a proof-of-concept example below, which should output the desired string:
const loopbackIP = '10.120.0.1';
const parts = loopbackIP.split('.').map(x => x.padStart(3, '0'));
// Remove the first 4 characters
let isisNetworkId = parts.join('');
isisNetworkId = isisNetworkId.substring(4);
const output = `49.0001.0101.${isisNetworkId.match(/.{4}/g).join('.')}.00`;
console.log(output);
So if you want to translate it to your VueJS code, it should look no different that this:
const loopbackIP = '10.120.0.1';
const isisNetworkID = computed(() => {
const loopbackIP = '10.120.0.1';
const parts = loopbackIP.split('.').map(x => x.padStart(3, '0'));
let isisNetworkId = parts.join('');
isisNetworkId = isisNetworkId.substring(4);
// Rejoin, split into items of 4-character long, rejoin by period
return isisNetworkId.match(/.{4}/g).join('.');
});

Leading and trailing zeros in numbers

I am working on a project where I require to format incoming numbers in the following way:
###.###
However I noticed some results I didn't expect.
The following works in the sense that I don't get an error:
console.log(07);
// or in my case:
console.log(007);
Of course, it will not retain the '00' in the value itself, since that value is effectively 7.
The same goes for the following:
console.log(7.0);
// or in my case:
console.log(7.000);
JavaScript understands what I am doing, but in the end the actual value will be 7, which can be proven with the following:
const leadingValue = 007;
const trailingValue = 7.00;
console.log(leadingValue, trailingValue); // both are exactly 7
But what I find curious is the following: the moment I combine these two I get a syntax error:
// but not this:
console.log(007.000);
1) Can someone explain why this isn't working?
I'm trying to find a solution to store numbers/floats with the exact precision without using string.
2) Is there any way in JS/NodeJS or even TypeScript to do this without using strings?
What I currently want to do is to receive the input, scan for the format and store that as a separate property and then parse the incoming value since parseInt('007.000') does work. And when the user wants to get this value return it back to the user... in a string.. unfortunately.

1) 007.000 is a syntax error because 007 is an octal integer literal, to which you're then appending a floating point part. (Try console.log(010). This prints 8.)
2) Here's how you can achieve your formatting using Intl.NumberFormat...
var myformat = new Intl.NumberFormat('en-US', {
minimumIntegerDigits: 3,
minimumFractionDigits: 3
});
console.log(myformat.format(7)); // prints 007.000

Hi
You can use an aproach that uses string funtions .split .padStart and .padEnd
Search on MDN
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padStart
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padEnd
Here you have an example:
const x = 12.1;
function formatNumber( unformatedNumber) {
const desiredDecimalPad = 3;
const desiredNonDecimalPad = 3;
const unformatedNumberString = unformatedNumber.toString();
const unformatedNumberArr = unformatedNumberString.split('.');
const decimalStartPadded = unformatedNumberArr[0].padStart(desiredDecimalPad, '0');
const nonDecimalEndPadded = unformatedNumberArr[1].padEnd(desiredNonDecimalPad, '0');
const formatedNumberString = decimalStartPadded + '.' + nonDecimalEndPadded;
return formatedNumberString;
}
console.log(formatNumber(x))